(X+2b)(x-4b) simplified

Answer:

2100

Step-by-step explanation:

In how many ways can a group of 10 people be divided into three groups consisting of 2,3, and 5 people?

First, you need to choose 4 people to fill the first group.

The number of ways is (104) which equals to 210.

Then, pick 3 more people out of the remaining 6 to be in the second group. And then, pick 3 more out of the remaining 3.

However, we need to divide it by 2, since we don’t really care on the order of selection of group.

(63)(33)/2=10

So, there are 210 x 10 = 2100 ways

Answer:

hmmm I read JeremyBrooks answer... I think that it might be different...

i think it is 2520

of the 10 you first choose 2

10 choose 2 = 45 ways

in each of the 45 "chooses" you now

pick a group of 3 of the 8 left

8 choose 3 = that is 56

of the five people left you choose 5

5 choose 5 = 1

so the possibilities are 45*56 * 1 = 2520

Step-by-step explanation:

Answer: [tex]-\frac{9}{2}, -4, -3, -\frac{11}{4}, -2[/tex]

Step-by-step explanation:

slope = m

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{-7-9}{-1-(-5)}=-4[/tex]

y = mx + b, (-5,9), (-1,-7), m = -4; (does not matter which point you plug in)

[tex]y=mx+b\\9=-4(-5)+b\\9=20+b\\b=-11\\y=-4x-11[/tex]

(now plug in each y value into the equation above)

[tex]7=-4x-11\\18=-4x\\x=-\frac{9}{2}\\\\5=-4x-11\\16=-4x\\x=-4\\\\1=-4x-11\\12=-4x\\x=-3\\\\0=-4x-11\\11=-4x\\x=-\frac{11}{4} \\\\-3=-4x-11\\8=-4x\\x=-2[/tex]

Answer:

a) 0.0081 = 0.81% probability that he receives no job offer

b) He expects to get 2.8 job offers.

c) 0.0837 = 8.37% probability that more than half of the firms he applied do not make him any offer.

d) Each job must be independent of other jobs. Additionaly, if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal approximation to the binomial distribution can be used.

e) 0.2401 = 24.01% probability of him securing more than 3 offers.

Step-by-step explanation:

For each application, there are only two possible outcomes. Either he gets an offer, or he does not. The probability of getting an offer for a job is independent of any other job, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

In which [tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.

[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]

And p is the probability of X happening.

He can expect to receive a job offer from 70% of the firms to which he applies.

This means that [tex]p = 0.7[/tex]

The student decides to apply to only four firms.

This means that [tex]n = 4[/tex]

(a) What is the probability that he receives no job offer?

This is [tex]P(X = 0)[/tex]. So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{4,0}.(0.7)^{0}.(0.3)^{4} = 0.0081[/tex]

0.0081 = 0.81% probability that he receives no job offer.

(b) How many job offers he expects to get?

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

In this question:

[tex]E(X) = 4(0.7) = 2.8[/tex]

He expects to get 2.8 job offers.

(c) What is the probability that more than half of the firms he applied do not make him any offer?

Less than 2 offers, which is:

[tex]P(X < 2) = P(X = 0) + P(X = 1)[/tex]

So

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 0) = C_{4,0}.(0.7)^{0}.(0.3)^{4} = 0.0081[/tex]

[tex]P(X = 1) = C_{4,1}.(0.7)^{1}.(0.3)^{3} = 0.0756[/tex]

Then

[tex]P(X < 2) = P(X = 0) + P(X = 1) = 0.0081 + 0.0756 = 0.0837[/tex]

0.0837 = 8.37% probability that more than half of the firms he applied do not make him any offer.

(d) What assumptions do you need to make to find the probabilities? To increase the chance of securing more job offers, the student decides to apply to as many companies as possible, he sent out 60 applications to all different accounting firms.

Each job must be independent of other jobs. Additionaly, if [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the normal approximation to the binomial distribution can be used.

(e) What is the probability of him securing more than 3 offers?

Between 4 and n, since n is 4, 4 offers, so:

[tex]P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}[/tex]

[tex]P(X = 4) = C_{4,4}.(0.7)^{4}.(0.3)^{0} = 0.2401[/tex]

0.2401 = 24.01% probability of him securing more than 3 offers.

Answer:

A. $15

B. $25

C. 84 peaches

Answer:

a)3dozenx$5=$15

b)60=5 dozen 5x$5=$25

c)35/5=7,7 dozen, 7 x 12= 84

Step-by-step explanation:

Answer:

-3/5

Step-by-step explanation:

3/ -5 is also equal to -3/5  or - (3/5)

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

The imaginary value is plotted on the vertical axis in the same way that the y-coordinate would be for an ordered pair (x, y). Similarly, the real value is plotted on the horizontal axis.

__

I find it helpful to think of the complex number a+bi as equivalent to the ordered pair (x, y) = (a, b) when it comes to graphing.

Answer:

With an ageing population, dietary approaches to promote health and independence later in life are needed. In part, this can be achieved by maintaining muscle mass and strength as people age. New evidence suggests that current dietary recommendations for protein intake may be insufficient to achieve this goal and that individuals might benefit by increasing their intake and frequency of consumption of high-quality protein. However, the environmental effects of increasing animal-protein production are a concern, and alternative, more sustainable protein sources should be considered. Protein is known to be more satiating than other macronutrients, and it is unclear whether diets high in plant proteins affect the appetite of older adults as they should be recommended for individuals at risk of malnutrition. The review considers the protein needs of an ageing population (>40 years old), sustainable protein sources, appetite-related implications of diets high in plant proteins, and related areas for future research.

Answer:

When variables are the same, multiplying them together compresses them into a single factor (variable). ... When multiplying variables, you multiply the coefficients and variables as usual. If the bases are the same, you can multiply the bases by merely adding their exponents.

Step-by-step explanation:

Let the numbers are x and y

According to the question

⇒x+y=1000.....eq1⇒x 2 −y 2

=256000∵x 2 −y 2

=(x+y)(x−y)

⇒1000∗(x−y)=256000

⇒x−y=256.....eq2

Adding eq1 and eq2

⇒2x=1256⇒x=628

Put the value of x in eq1

⇒628+y=1000⇒y=372

The numbers are 628 and 372

Hi I'm From PHILIPPINES

I'm here to help USA users like you

Answer:

-78

Step-by-step explanation:

Zinc group :

Mean, x1 = 3328

σ1 = 640

Sample size, n1 = 28

Placebo group :

Mean, x2 = 3406

σ2 = 851

Sample size, n2 = 31

The point estimate for the true difference between the population means is obtained as :

Mean difference between population :

x1 - x2 = 3328 - 3406 = - 78

Answer:

To find critical points, take the first derivative and set it equal to zero:

f(x) = -2x^2 + 4x + 5

f'(x) = -4x + 4

-4x+4 = 0

-4x = -4

x = 1

Critical point at x = 1

Alternatively, if you mean zeros, or where the x intersects, you can use the quadratic equation.

Answer:

10

Step-by-step explanation:

10

Answer:

24

Step-by-step explanation:

The topic here is COMBINATORICS.

The parent topic is PERMUTATIONS & COMBINATORICS.

Permutation deals with arrangement in a definite order while, as stated in the question here, definite order in not needed in Combinatorics.

Now, the multiplication rule of counting, also known as the rule of product, talks about the multiplication of the figures that represent the different ways of doing something.

For example, in this question, the robot needs to attach 4 wires to a circuit board. If you know how Physics or Electricity works, you'll that truly this is a combination matter and not permutation.

Putting/Connecting the 4 wires together (in a square shaped circuit for instance), the arrangement RGBY is different from RGYB or RBGY.

So there will be more ways to connect or combine these wires, than if we were to follow a definite rule like: "Red and Green must always stay together".

So using the multiplication rule of counting to determine 4 choices for the Red wire, 3 choices for the Green wire, 2 choices for the Blue wire, and 1 choice for the yellow wire, we have:

R4 x G3 x B2 x Y1  =  4 x 3 x 2 x 1  =  4!  =  24

The term "4!" means "Four Factorial".

Answer:

Part A:

the first step is to work out the brackets by multiplying the coefficients outside the brackets by everything in the brackets.

Part B:

5(3x-4)=-2(6x-9)

15x-20=-12x+18

Part C:

15x-20=-12x+18

15x+12x=18+20

27x/27=38/27

x=1.407

I hope this helps

Answer:93/2 or 46.5 mph

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

Answer:

X = 64

Step-by-step explanation:

All of the angles are right angles (because of the square at one of the angles shown above). This means each angle equals 90 degrees. If X + 26 = 90, then X = 64 because 90 - 26 = 64. I hope this helps!

Answer: X = 64

Step-by-step explanation:

Answer:

A. 22

B. 8

C. 23 + 24

D. 22 + 23 + 24

E. 8 + 8 + 10

F. 104 - (sum of all the given numbers) = 3

Answer:

10.97%

Step-by-step explanation:

There are 52 cards.

13 of them, are hearts.

Then

52 - 13 = 39 cards are not hearts.

4 cards are drawn, we want to find the percent chance that the fourth card is a heart card, but no before.

So the first card can't be a heart card.

because the deck is well-shuffled, all the cards have the same probability of being drawn.

Then the probability of not getting a heart card, is equal to the quotient between the number of non-heart cards (39) and the total number of cards (52), then the probability is:

p₁ = 39/52

The second card also can't be a heart card, the probability is calculated in the same way than above, but now there are 38 non-heart cards and a total of 51 cards (because one card was already drawn) then the probability here is:

p₂ = 38/51

For the third card the reasoning is similar to the two above cases, here the probability is:

p₃ = 37/50

The fourth card should be a hearts card, the probability is computed in the same way than above, as the quotient between the number of heart cards in the deck (13) and the total number of cards in the deck (now there are 49 cards)

then the probability is:

p₄ = 13/49

The joint probability (the probability of these 4 events happening together) is equal to the product between the individual probabilities:

P = p₁*p₂*p₃*p₄

P = (39/52)*(38/51)*(37/50)*(13/49) = 0.1097

The percent chance is the above number times 100%

Percent =  0.1097*100% = 10.97%

The fraction of the remaining cars in the lot that are preowned is 7/15

In order to determine the fraction of the remaining cars in the lot that are preowned, we have to first determine the total number of new cars and preowned cars before the sale occurred.

Total number of preowned cars before the sales = (ratio of preowned cars / total ratio) x total number of cars

ratio of preowned cars = 5

total ratio = 6 + 5 = 11

total number of cars = 66

(5/11) x 66 = 30 cars

Total number of new cars before the sale = (ratio of new cars / total ratio) x total number of cars

ratio of new cars = 6

total ratio = 6 + 5 = 11

total number of cars = 66

(6/11) x 66 = 36 cars

Total number of new cars after the sale = total number of new cars before the sale - number of new cars sold

36 - 4 = 32

Total number of preowned cars after the sale = total number of preowned cars before the sale - number of preowned cars sold

30 - 2 = 28

The fraction of the remaining cars on the lot that are preowned = number of preowned cars after the sale / total number of cars on the lot after the sale

total number of cars on the lot after the sale = 28 + 32 = 60

28/60

to convert to the simplest term, divide the numerator and the denominator by 4

7/15

To learn more about fractions, please check : https://brainly.com/question/15898494?referrer=searchResults

Answer:

There would be [tex]120[/tex] of them.

Step-by-step explanation:

There are [tex]6[/tex] distinct letters in the word "[tex]\verb!theory![/tex]".

Hence, there would [tex]6[/tex] possible choices for the first letter that was selected.

Since the chosen card won't be placed back in the pool, there would be only [tex](6 - 1) = 5[/tex] possible choices for the second letter.

Likewise, there would be [tex](6 - 2) = 4[/tex] choices for the third letter.

[tex]6 \times 5 \times 4 = 120[/tex]. In other words, there are [tex]120[/tex] possible ways to draw three cards out of [tex]6[/tex] one after another.

Since the question states that the order of the cards matters, it won't be necessary to eliminate repetitions such as "[tex]\verb!the![/tex]" and "[tex]\verb!het![/tex]" from the number of combinations.

Answer:

A

Step-by-step explanation:

v=πr2h

r=(3)²* 5

45π unit³

Answer:

x = 2[tex]\sqrt{5}[/tex]

Step-by-step explanation:

Pytago:

[tex]2^2 + 4^2 = x^2\\x = \sqrt{2^2 + 4^2} \\x = 2\sqrt{5}[/tex]

Answer:

4.47

Step-by-step explanation:

x²= 2² + 4²

x² = 4 + 16

x²= 20

x = √20

x= 4.47

Answer:

35

Step-by-step explanation:

The pattern is adding powers of 2.

4+1=5 (exception)

5+2=7

7+4=11

11+8=19

19+16=35

Answer:

35

Step-by-step explanation:

4 + 1 = 5

5 + (1 × 2) = 5 +2 =7

7 + (2×2) = 7 + 4 = 11

11 +(4×2) = 11 + 8 = 19

19 + (8×2) = 19 + 16 = 35

Answer:

Ask in English then I can help u

Answer:

6

Step-by-step explanation:

Answer:

Step-by-step explanation:

x = 0, 1/5

Answer: oranges 1.2 Kg and apples 0.75 Kg.

Step-by-step explanation:

Oranges (4)(1.5)/5

Apples (3)(2)/8

Answer:

Exact Form: -4⊥√15

Decimal Form:

0.12701665

7.87298334

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