Text 1 is a program that demonstrates how to use the Timer and Timer Task classes to schedule a task to execute at fixed intervals.
In the given program, the task's run method outputs the current date and time. You can detect a timer overrun exception by wrapping the schedule At Fixed Rate method call in a try-catch block that catches the Timer Runtime If the timer queue overruns, the schedule At Fixed Rate method throws a Timer Runtime Exception, which indicates that the task's next scheduled execution was delayed and the task might now be running continuously to catch up.
Timer overrun exception A timer overrun exception is thrown when the timer queue overruns and a timer task cannot be run because too many tasks are scheduled. The timer queue will only execute tasks scheduled within the next 100 milliseconds.
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problem 07.071 - determine the maximum shearing stress for the given general state of stress. skip to question consider the given state of stress. take x = 38 mpa and y = 18 mpa.
The maximum shearing stress for the given general state of stress, considering the given state of stress, taking x = 38 MPa and y = 18 MPa is 20 MPa.
The maximum shearing stress for the given general state of stress, considering the given state of stress, taking x = 38 MPa and y = 18 MPa is 20 MPa.
The general state of stress is given as:σx = 38 MPa, σy = 18 MPa, τxy = -12 MPa
The normal and shear stresses on an inclined plane with respect to x-axis is given by the following equation:
σn = (σx + σy)/2 + [(σx - σy)/2]cos2θ + τxy sin2θσs = [(σx - σy)/2]sin2θ + τxy cos2θ
where, σn = normal stress,σs = shear stress,θ = angle made by the plane with the x-axis
In this case, we need to find the maximum shear stress, which occurs when θ is such that the second term in σs expression is maximum.
To obtain maximum value of σs, we equate the derivative of the second term with respect to θ to zero.
τxy cos2θ - [(σx - σy)/2]sin2θ = 0τxy cos2θ = [(σx - σy)/2]sin2θtan2θ = 2τxy/(σx - σy)
Substituting the given values, we have:tan2θ = 2(-12)/20 = -1.2
The maximum value of tan2θ is -1. So, we have:tan2θ = -1 = tan(-45°)2θ = -45°θ = -22.5°
The maximum shear stress is obtained by substituting the obtained value of θ in the expression for σs.
σs = [(σx - σy)/2]sin2θ + τxy cos2θ= [(38 - 18)/2]sin(-45°) - 12 cos(-45°)= 20 MPa
Hence, the maximum shearing stress for the given general state of stress, considering the given state of stress, taking x = 38 MPa and y = 18 MPa is 20 MPa.
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a support desk technician is dealing with an angry customer. which two approaches should the technician take in dealing with the customer? (choose two.)
When dealing with an angry customer, a support desk technician should take the following two approaches:
How to deal with an angry customerActive Listening: The technician should actively listen to the customer's concerns without interruption. This means allowing the customer to express their frustration fully and empathetically understanding their perspective.
Calm and Respectful Tone: The technician should maintain a calm and respectful tone throughout the interaction. By speaking politely and professionally, the technician can help de-escalate the situation and create a more positive environment for resolving the customer's issue.
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