You bake a batch of muffins. You freeze 6 muffins and share the rest equally among yourself and 2 friends. Write an
expression that can be used to determine the number of muffins, m, each friend gets.

Answer: I’m pretty sure its A on e2020

Step-by-step explanation:

It is an obligation to pay, but the spender has some control over the amount.

Option A is the correct answer.

We have,

The reason that a data usage bill for a smartphone is an essential (variable) expense is that it is an obligation to pay.

In other words, the phone service is necessary for the phone to function properly, and therefore, the bill must be paid.

However, the spender has some control over its amount by managing their data usage, such as turning off data for certain apps or using Wi-Fi instead of cellular data.

This means that while the bill cannot be eliminated entirely, the spender can take steps to reduce the amount owed.

Statement b is incorrect because while the bill cannot be eliminated entirely, it can be reduced by managing data usage.

Statement c is incorrect because the amount of the bill is not expected to be the same every month, as it will depend on how much data is used. Statement d is incorrect because while bills for services rendered may be a priority, they do not necessarily have a higher priority than other types of essential expenses, such as food or housing.

Thus,

It is an obligation to pay, but the spender has some control over the amount.

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Answer:

3. The tree increased in height each month until the time period between month 9 and month 11.

The statement that can be supported by the information in the table is that the tree increased in height each month until the time period between month 9 and month 11.

It should be noted that a table simply means a list of numbers to that depicts a particular information.

In this case, the statement that can be supported by the information in the table is that the tree increased in height each month until the time period between month 9 and month 11.

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[tex]\tt Step-by-step~exlpanation:[/tex]

To find out the answer, we would have to try and divide all the numbers.

[tex]\tt \frac{34,776}{2}= 17,388\\ YES[/tex]

[tex]\tt \frac{34,776}{3}= 11,592\\YES[/tex]

[tex]\tt \frac{34,776}{9}=3,864\\ YES[/tex]

[tex]\tt \frac{34,776}{6}= 5,796\\YES[/tex]

[tex]\large\boxed{\tt Our~final~answer:~ALL ~(2,3,9,6)}[/tex]

Answer:

1. [tex]\frac{10}{21}[/tex]

2. [tex]\frac{405}{49} = 8\frac{13}{49}[/tex]

Step-by-step explanation:

first one:

[tex]p^{2} q[/tex] = [tex](\frac{1}{3})^{2}[/tex] × [tex]4\frac{2}{7}[/tex] = [tex]\frac{1}{9}[/tex] × [tex]\frac{30}{7}[/tex] = [tex]\frac{1}{3}[/tex] × [tex]\frac{10}{7}[/tex] = [tex]\frac{10}{21}[/tex]

second one:

[tex]t^{2}[/tex]/[tex]s[/tex] = [tex](1\frac{2}{7})^{2}[/tex] / [tex]\frac{1}{5}[/tex] = [tex](\frac{9}{7})^{2}[/tex] × [tex]5[/tex] = [tex]\frac{81}{49}[/tex] × [tex]5[/tex] = [tex]\frac{405}{49}[/tex] = [tex]8\frac{13}{49}[/tex]

Given :

Ellen sells wedges of cheese at the local farmers' market. To make the wedges, she cuts a big 5-pound block of cheese into 16 pieces.

To Find :

How much does each wedge of cheese weigh.

Solution :

Let , weight of each wedge of cheese is x.

16 pieces of wedge of cheese weight 5 pounds .

So,

[tex]16x=5\\\\x=\dfrac{5}{16}\\\\x=0.3125\ pounds[/tex]

Therefore, weigh of cheese is 0.3125 pounds.

Hence, this is the required solution.

Answer:

y= 1 /4 x − 3 /4

Step-by-step explanation:

y=mx+b

Answer:

1/10

Step-by-step explanation:

Answer:

1/100

Step-by-step explanation:

it would be 1/10 if the decimal was 1 space to the right.

Answer:

c

Step-by-step explanation:

Answer:

1 over 36

Step-by-step explanation:

Answer:

1 over 36 or A

Step-by-step explanation:

Trust me bro;)

Answer:

n = -5

Step-by-step explanation:

-2(-7n-8)=-39+3n

Distribute

14n +16 = -39 +3n

Subtract 3n from each side

14n -3n +16 = -39 +3n -3n

11n +16 = -39

Subtract 16 from each side

11n +16 -16 = -39 -16

11n = -55

divide by 11

11n /11 = -55/11

n = -5

Answer:

This is simple,

Step-by-step explanation:

If the bus costs 200$ and the fair charges 4$ per students that means you have to do this:

300$ budget - 200 of the bus = 100$ left

and if $4 per student:

100 divided by 4 = 25

she can take 25 students

Hope this helps!

Answer:

b

Step-by-step explanation:

give other person brainliest

The mistake lies in step -(66/5)/(22/5) → -(66/5)(22/5) where he didn't take the reciprocal of the divisor while dividing the two fractions.

The step would have been like this:

-(66/5)/(22/5) = -(66/5)(5/22) = -(3).

A fraction is a portion of a whole or, more broadly, any number of equal pieces.

It is written in the form p/q, read as "p by q", where p is called the numerator and q is called the denominator, and the fraction p/q represents p number of equal parts from q number of equal parts.

Fractions are of two types:

Fractions are divided by multiplying the dividend by the reciprocal of the divisor

Suppose we are asked to divide a fraction a/b by x/y.

This is written as (a/b) ÷ (x/y) or (a/b)/(x/y), and calculated as:

(a/b)*(y/x).

In the question, we are informed that last night, the temperature fell from 0°F to Negative 13 and one-fifth °F in 4 and two-fifths hours. Alan calculated the average temperature change per hour.

He followed the following steps:

-(13 1/5)/(4 2/5)

= -(66/5)/(22/5)

= -(66/5)(22/5)

= -(1452/25).

The mistake lies in step -(66/5)/(22/5) → -(66/5)(22/5) where he didn't take the reciprocal of the divisor while dividing the two fractions.

The step would have been like this:

-(66/5)/(22/5) = -(66/5)(5/22) = -(3).

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Step-by-step explanation:

it is 3 one

Answer:

9x-5

Step-by-step explanation:

(4x - 6) + (5x + 1)

Add like terms

4x+5x=9x

-6+1=-5

Combine

9x-5

Hope this helps! Plz award Brainliest : )

It is saying that irrational numbers like pie can be broken down into approximate irrational numbers and plotted onto points.

Example [tex]\sqrt{1.6}[/tex] approximate value is 1.264911

That number can be plotted in place of [tex]\sqrt{1.6}[/tex]

Answer:.583

Step-by-step explanation:

Answer:

d = 40w x 2

Step-by-step explanation:

Answer:

4

Step-by-step explanation:

The constant is the number without a variable, usually being added or subtracted from the variable but not multiplied or divided by it.

Step-by-step explanation:

1.8(2/7x)15

1.8×15(2/7x)

27(2/7x)

54/7x

Answer:

2 x 10 to the -6th power is .000002.

Answer:

[tex]\frac{1}{20^} ^6[/tex]

Step-by-step explanation:

Depends what you mean

if you mean 2x10^-6 it would be different than (2x10)^-6 but I'll solve for the latter.

[tex](2*10)^-6 = (20)^-6\\20^-6 = \frac{1}{20^6}[/tex]

1/20^6 would just be

[tex]\frac{1}{64000000}[/tex]

Answer:

Cube root of 8/27 is 2/3

[tex] \sqrt{ \frac{8}{27} } [/tex]

[tex] = \sqrt{ (\frac{2}{3} {)}^{2} } [/tex]

[tex] = \frac{2}{3} [/tex]

Answer:

B-2

Step-by-step explanation:

It is B, because On the first month, Armando has 12 and Daniel has 8, now on the 2nd month Armando has 9 because he gives away 3 each month and Daniel now has 9 because he adds one each month, so all in all, they have the same exact number of pencils on the 2nd month

After 5 months is when Armando and Daniel had the same number of pencils.

The proof for this is simple. Let's say that A + B + C = π. From here on we require several trigonometric identities that must be applied.

[tex]\cos \left(A\right)+\cos \left(B\right)+\cos \left(C\right) \\= 2 * cos((A + B) / 2) * cos((A - B) / 2) + \cos C \\= 2 * cos((\pi /2) - (C/2)) * cos((A - B) / 2) +\cos C \\= 2 * sin(C/2) * cos((A - B) / 2) + (1 - 2 * sin^2 (C/2)) \\= 1 + 2 sin (C/2) * cos((A - B) / 2) - sin (C/2) \\= 1 + 2 sin (C/2) * cos((A - B) / 2) - sin((\pi /2) - (A + B)/2 ))\\= 1 + 2 sin (C/2) * cos((A - B) / 2) - cos((A + B)/ 2)\\= 1 + 2 sin (C/2) * 2 sin (A/2) * sin(B/2) \\= 1 + 4 sin(A/2) sin(B/2) sin(C/2)[/tex]

Hope that helps!

Answer:  see proof below

Step-by-step explanation:

Given: A + B + C = π                     → A + B = π -  C

                                                     → C = π - (A + B)

Use Sum to Product Identity:  cos A + cos B = 2 cos [(A + B)/2] · cos [(A - B)/2]

Use Product to Sum Identity:  2 sin A · sin B = cos [(A + B)/2] - cos [(A - B)/2]

Use the Double Angle Identity:   cos 2A = 1 - 2 sin² A

Use the Cofunction Identity: cos (π/2 - A) = sin A

Proof LHS → RHS:

LHS:                       cos A + cos B + cos C

                           = (cos A + cos B) + cos C

[tex]\text{Sum to Product:}\qquad 2\cos \bigg(\dfrac{A+B}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+\cos C[/tex]

[tex]\text{Given:}\qquad 2\cos \bigg(\dfrac{\pi -C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+\cos C\\\\\\.\qquad \qquad =2\cos \bigg(\dfrac{\pi}{2} -\dfrac{C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+\cos C[/tex]

[tex]\text{Cofunction:}\qquad 2\sin \bigg(\dfrac{C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+\cos C[/tex]

[tex]\text{Double Angle:}\qquad 2\sin \bigg(\dfrac{C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+\cos\bigg(2\cdot \dfrac{C}{2}\bigg)\\\\\\.\qquad \qquad \qquad =2\sin \bigg(\dfrac{C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)+1-2\sin^2 \bigg(\dfrac{C}{2}\bigg)\\\\\\.\qquad \qquad \qquad =1+2\sin \bigg(\dfrac{C}{2}\bigg)\cdot \cos \bigg(\dfrac{A-B}{2}\bigg)-2\sin^2\bigg(\dfrac{C}{2}\bigg)[/tex]

[tex]\text{Factor:}\qquad 1+2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[\cos \bigg(\dfrac{A-B}{2}\bigg)-\sin\bigg(\dfrac{C}{2}\bigg)\bigg][/tex]

[tex]\text{Given:}\qquad 1+2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[\cos \bigg(\dfrac{A-B}{2}\bigg)-\sin\bigg(\dfrac{\pi-(A+B)}{2}\bigg)\bigg]\\\\\\.\qquad \qquad 1+2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[\cos \bigg(\dfrac{A-B}{2}\bigg)-\sin\bigg(\dfrac{\pi}{2}-\dfrac{A+B}{2}\bigg)\bigg][/tex]

[tex]\text{Cofunction:}\qquad 1+2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[\cos \bigg(\dfrac{A-B}{2}\bigg)-\cos\bigg(\dfrac{A+B}{2}\bigg)\bigg][/tex]

[tex]\text{Product to Sum:}\qquad 1+2\sin \bigg(\dfrac{C}{2}\bigg)\bigg[2\sin \bigg(\dfrac{A}{2}\bigg)\cdot \sin\bigg(\dfrac{B}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad \qquad =1+4\sin \bigg(\dfrac{C}{2}\bigg)\bigg[\sin \bigg(\dfrac{A}{2}\bigg)\cdot \sin\bigg(\dfrac{B}{2}\bigg)\bigg]\\\\\\.\qquad \qquad \qquad \qquad =1+4\sin \bigg(\dfrac{A}{2}\bigg)\sin \bigg(\dfrac{B}{2}\bigg) \sin\bigg(\dfrac{C}{2}\bigg)[/tex]

[tex]\text{LHS = RHS:}\ 1+4\sin \bigg(\dfrac{A}{2}\bigg)\sin \bigg(\dfrac{B}{2}\bigg) \sin\bigg(\dfrac{C}{2}\bigg)=1+4\sin \bigg(\dfrac{A}{2}\bigg)\sin \bigg(\dfrac{B}{2}\bigg) \sin\bigg(\dfrac{C}{2}\bigg)\quad \checkmark[/tex]

Answer:

6

Step-by-step explanation:

6x2.5=15

yeßssssssss I do math easy pressure

Answer:

When dividing numbers with the same base, you subtract the exponents.

Step-by-step explanation:

For example, 8^5/8^3 = 8^2 or 64

Answer:

12

Step-by-step explanation:

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