The volume of water from the volume of oil, which yields V_diff = 50,000 cm³ - 6.283 cm³ = 49
What is yield?Yield is a measure of the return on an investment. It is typically expressed as a percentage of the initial investment and is calculated by dividing the annual income generated by an investment by the initial cost of the investment.
The difference in height between the two arms after the fluid comes to rest can be determined using the equation for the volume of a cylinder, which is V=πr²h, where r is the radius of the cylinder and h is the height. Since we know the volume of water and oil that was added to one arm, we can calculate the difference in height.
First we need to calculate the volume of water in one arm. Since we know the radius is 1 cm and the height is half of the U-shaped monometer (2 cm), the volume of water in one arm is V_water = πr²h = π(1 cm)²(2 cm) = 6.283 cm³.
Next we need to calculate the volume of oil. Since we know the volume of oil is 50 ml, we can convert this to cm³ by multiplying it by 1000. This gives us the volume V_oil = 50 ml x 1000 = 50,000 cm³.
Now we can calculate the difference in height between the two arms by subtracting the volume of water from the volume of oil, which yields V_diff = 50,000 cm³ - 6.283 cm³ = 49
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You are driving through town at 16 m/s when suddenly a car backs out of a driveway in front of you. You apply the brakes and begin decelerating at 3.5 m/s2
Find your speed after braking half the time found in part A.
(answer for part a- t=4.6s)
The time is 5s.
In this problem, the observer is driving through town at
vi =16 m/s applies the brakes and begin decelerating with }a=−3.2 m/s²
We calculate the time for the vehicle to stop, and the speed after half the stopping time.
We use the velocity-time equation of the vehicle. When the vehicle stops, the velocity is
vf ⟹ =vi +at
T = Vf−vi
= 0−16 m/s / −3.2 m/s²
= 5.0 s
What is time?
Time is the ongoing pattern of existence and things that happen in what seems to be an unbreakable succession from the past through the present and into the future.It is a constituent quantity of many measurements that are used to compare the lengths of events or the gaps between them, to compare the sequence of occurrences, and to measure the rates at which certain quantities in the physical world or in conscious experience change.In addition to the three spatial dimensions, time is frequently considered a fourth dimension.To know more about time, click the link given below:
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In a Newton’s ring arrangement with a film observed with light of wavelength 6 x 10-5 cm,
the difference of square of diameters of successive rings are 0.125 cm2
. What will happen
to this quantity if:
i) Wavelength of light is changed to 4.5 x 10-5 cm.
ii) A liquid of refractive index 1.33 is introduced between the lens and the plate.
iii) The radius of curvature of convex surface of plano-convex lens is doubled.
Answer:
In a Newton's ring arrangement, the difference in the square of the diameters of successive rings is equal to four times the wavelength of light divided by the refractive index of the medium between the planoconvex lens and the plane glass plate.
If the wavelength of light is changed to 4.5 x 10-5 cm, then the difference in the square of the diameters of successive rings will be equal to four times 4.5 x 10-5 cm divided by the refractive index of the medium (which is assumed to be 1 if a liquid of refractive index 1.33 is not introduced).
If a liquid of refractive index 1.33 is introduced between the lens and the plate, then the difference in the square of the diameters of successive rings will be equal to four times 4.5 x 10-5 cm divided by 1.33.
If the radius of curvature of the convex surface of the plano-convex lens is doubled, then the difference in the square of the diameters of successive rings will remain the same.
A pendulum bob of mass 5 kg is displaced from the vertical until it is 0.25 m above its lowest point. Upon release, it rises to a height of 0.24 m on the other side. How much energy was lost due to friction? Assuming half the total energy loss takes place during the downward swing, with what speed does the bob pass though its lowest point?
The energy lost due to friction is 0.49 J. And the speed of the bob passing through its lowest point will be 2.19 m/s.
What is the conservation of energy?The mass is 5 kg and the heights are h₁ 0.25 m and h₂ = 0.24. And the difference in the height is given as,
h₁ - h₂ = 0.25 - 0.24
h₁ - h₂ = 0.01
The energy loss due to friction is given as,
Energy loss = mgh₁ - mgh₂
Energy loss = mg (h₁ - h₂)
Energy loss = 5 x 9.8 x 0.01
Energy loss = 0.49 J
The energy lost due to friction is 0.49 J.
The velocity is given as,
KE = mgh₁ - E / 2
(1/2) x 5 x v² = 5 x 9.8 x 0.25 - 0.49 / 2
2.5v² = 12.25 - 0.245
v² = 4.802
v = 2.19 meters per second
The speed of the bob passing through its lowest point will be 2.19 m/s.
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The figure below shows a rigid 3-mass sys-
tem which can rotate about an axis perpen-
dicular to the system. The mass of each
connecting rod is negligible. Treat the masses
as particles.
The x-axis is along the horizontal direction
with the origin at the left-most mass 7 kg.
7 kg
1 kg
6 kg
5m
m.
x
*
-5m-
The masses are separated by rods of length
5 m, so that the entire length is 2 (5 m).
Determine the x-coordinate of the center of
mass for the three-mass system with respect
to the origin.
Answer in units of m. Answer in units of
The x component of the center mass is 4.64 m.
What is the x-coordinate of the center mass?The x component of the center mass is calculated by applying the following formula as shown below;
X_cm = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3),
where;
m1 is mass 1 = 7 kgx1 is the position of mass 1 = 0 mm2 is the mass 2 = 1 kgx2 is the position of mass 2 = 5 mm3 is the mass 3 = 6 kgx3 is the position of mass 3 = 10 mX_cm = (m1x1 + m2x2 + m3x3) / (m1 + m2 + m3)
X_cm = (7 x 0 + 1 x 5 + 10 x 6) / (7 + 1 + 6)
X_cm = 4.64 m
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how to solve velocity ratio
Arrange the events in the correct order to describe how the magnetic field forms around earth.
The correct order of events to describe how the magnetic field forms around the Earth is: (1). The Earth's liquid iron outer core convects due to heat flow, creating electric currents. (2). The electric currents in the outer core generate a magnetic field. (3). The magnetic field lines extend from the Earth's interior out into space, creating the magnetosphere. (4). The magnetosphere deflects charged particles from the solar wind, protecting the Earth from harmful radiation.
What is magnetic field?A region of space where the magnetic forces of a magnet or a moving electric charge can be felt is called a magnetic field. Moving electric charges, such the spinning electrons in an atom or the electrons in a wire, create magnetic fields. They can also be created by the Earth's core or permanent magnets.
The strength and direction of magnetic fields define them. A magnetic field's direction can be determined by calculating the force it would apply to a compass's north pole. The amount of force that a magnetic field would apply to a charged particle travelling through the field provides an indication of its intensity.
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A force of 50 newtons is used to do 5.0 x 102 joules of work on an object. Over what distance was this force applied?
The distance over which the force was applied would be 10 meters.
Work done problemThe work done on an object is given by the product of the force applied and the distance over which it is applied. Therefore, we can use the formula:
Work = Force x Distance
We know that the force applied is 50 newtons, and the work done is 5.0 x 10^2 joules. We can rearrange the formula to solve for distance:
Distance = Work / Force
Substituting the values we know, we get:
Distance = (5.0 x 10^2 J) / 50 N
Distance = 10 meters
Therefore, the force of 50 newtons was applied over a distance of 10 meters to do 5.0 x 10^2 joules of work on the object.
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Why is copper wire a better conductor of electricity than carbon fiber?(1 point)
Responses
Copper (Cu) has no loose electrons
The electrons in copper (Cu) are loosely bound to the nucleus.
Copper (Cu) is a metal, and only metals can conduct electricity.
Carbon (C) does not have any valence electrons
The electrons in copper (Cu) are loosely bound to the nucleus is the most accurate answer
explain about the copper ?
Copper is a chemical element with the symbol Cu and atomic number 29. It is a soft, malleable, and ductile metal with high thermal and electrical conductivity. Copper has been used by humans for thousands of years for various purposes including coinage, electrical wiring, plumbing, and industrial machinery. It is commonly found in nature as copper oxide or copper sulfide, and it can be extracted through mining and refining processes. Copper is also an essential nutrient for all living organisms and plays important roles in biological processes such as the formation of red blood cells and the maintenance of the nervous and immune systems.
The electrons in copper (Cu) are loosely bound to the nucleus is the most accurate answer. This is because in metals like copper, the outermost electrons of atoms are not tightly bound to their respective nuclei, and can therefore move easily through the material, allowing for efficient conduction of electricity. On the other hand, in non-metal substances like carbon fiber, the electrons are more tightly bound to their respective nuclei, making it less efficient in conducting electricity.
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Answer:
(Question) Why is copper wire a better conductor of electricity than carbon fiber?
(Answer) The electrons in copper (Cu) are loosely bound to the nucleus
(Question) Which of the following best describes a direct current?
(Answer) An electrical current that flows in one direction
(Question) Which of the following substances would allow an electric current to flow through it easily?
(Answer) aluminum (Al)
(Question) Which of the following statements about electrical charges is true?
(Answer) Opposite charges attract one another
(Question) Which of the following statements best describes the relationship between atoms and conductivity?
(Answer) Atoms with a nearly empty valence shell make good conductors
Explanation:
i just finished the quick check
Landing with a speed of 71.4 m/s and traveling due south, a jet comes to rest in 939 m
Assuming the jet slows with constant acceleration, find the magnitude of its acceleration.
(part a)
Assuming the jet slows with constant acceleration, find the direction of its acceleration.
(part b)
The acceleration is 2.7 m/s^2.
What is the acceleration?Acceleration is a measure of the rate at which an object changes its velocity. It is defined as the change in velocity per unit time and has units of meters per second squared (m/s^2). Acceleration can be positive (when an object is speeding up), negative (when it is slowing down), or zero (when its velocity is constant).
We can get the acceleration;
v^2 = u^2 - 2as
v = final velocity
u = initial velocity
a = acceleration
s = distance
Thus we have that;
v = 0 m/s thus;
u^2 = 2as
a = u^2/2s
a = (71.4)^2/2 * 939
a = 5097.96/1878
a = 2.7 m/s^2
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A startled deer runs 520 m at 20.0° north of east for half a minute, then turns and runs 380 m at 55.0° north of west for 15.0 seconds and stops. What is the average velocity of the deer during this time?
Answerbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
Explanation:
A startled deer runs 520 m at 20.0° north of east for half a minute, then turns and runs 380 m at 55.0° north of west for 15.0 seconds and stops. Therefore, 60m/s is the average velocity of the deer during this time.
What is average velocity?Motion may be defined using physical quantity concepts such as speed, velocity, duration, displacement, as well as acceleration. Sir Isaac Newton provided the correct explanation of motion.
All of these quantities are explained in terms of a single quantity, time. In this section, we will look at average velocity, its mathematical representation, and its graphical depiction.
average velocity = 520 m+ 380 m / 15=60m/s
Therefore, 60m/s is the average velocity of the deer during this time.
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A 0.0272 kg arrow is fired with a velocity of 87.3 m/s from a 0.0245 kg bow. Determine the equivalent impulse value imparted on the arrow. (hint: you can also use newton's third law of motion)* A.2.37 Ns B.3.11 Ns C.113.5 Ns D.214.2 Ns
Answer:
Explanation:
C. 113.5 Ns
The following table shows the distance from the sun of some unknown planets of equal mass.
Distance from Sun
Planet Distance from Sun
W 1.5 AU
X 0.723 AU
Which of the following best explains which planet revolves at a faster speed?
Planet X, because the sun pulls it with a greater force
Planet W, because the sun pulls it with a greater force
Planet W, because the gravitational force is weakened by distance
Planet X, because the gravitational force is strengthened by distance
(D was wrong, I'm taking the test again)
The correct answer is : Planet X, because the sun pulls it with a greater force
The speed at which a planet revolves around the sun is determined by its distance from the sun and the gravitational force between the planet and the sun. The closer a planet is to the sun, the stronger the gravitational force, and the faster it will orbit. Therefore, Planet X, which is closer to the sun than Planet W, will revolve around the sun at a faster speed, assuming that both planets have equal masses. Thus, the correct answer is "Planet X, because the gravitational force is strengthened by distance." The farther a planet is from the sun, the weaker the gravitational force, but this would result in a slower orbital speed, not a faster one.To know more about planets visit:
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Answer: A A A !!!!
Explanation: just did the test, got it right thx thx!!!
What is the magnitude of velocity of a 900 kg horse that has a momentum of 8000 kgm/s
A.8.9 m/s
B.0.11 m/s
C.8900 m/s
D.7100 m/s
The magnitude of the velocity of the horse will be 8.89 m/s.
Given, the mass of the horse is 900 kg and the momentum of the horse is 8000 Kgm/s.
To calculate, the velocity of the horse from the given values.
Momentum of any body is defined as the product of the mass of the body and the velocity of that body. Momentum(p) = Mass(m) × Velocity(v)
Keeping the provided values in the formula, momentum = mass × velocity to calculate the velocity of the horse
8000 Kgm/s = 900Kg × velocity
velocity = 8000/900 m/s = 8.89 m/s
So, the velocity of the horse is 8.89 m/s.
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HELPPPP
i need this done quickly
Answer:
F(Net) = F(a) + F(g) + F(f) + FN.
If the electric potential at point a is +30. 0 v , what is the electric potential at point b ?.
Answer:
Explanation:Electric potential of a point charge is V=kQ/r V = k Q / r . Electric potential is a scalar, and electric field is a vector. Addition of voltages as numbers gives the voltage due to a combination of point charges, whereas addition of individual fields as vectors gives the total electric field.
In your own words, what is distance? Provide your own
example to illustrate your point
Answer:
the expanse or amount of space between two things, points, lines, anything in science or math.
DISTANCE...
Explanation:
aInfinite Sheets of Charge | 1|2 In both cases shown below, the colored lines represent positive (blue) and negative (red) charged planes. The magnitudes of the charge per unit area on each plane is the same. Case A Case B 1) In which case is the magnitude of the electric field at point P bigger? Case A Case B They are the same Submit (Survey Question) 2) Explain your reasoning Submit
Because the charge densities per unit area on every plane are equal. Hence, the strength of the electric field around point P is the same in situations A and B.
Explain the electric filed due to infinite line of charge?Gauss' law can be used to determine the electric field of such an infinite line charge with such a uniform linear charge density.
The electric field is of equal strength at each point of a cylinder and thus is pointed outward when a Gaussian surface with radius r is modeled as a cylinder.
We discovered that electric field is radially oriented away as from line charge and that its strength decreases in inverse proportion to its distance.
The colored lines in the two instances below denote the positive (blue) and negative (red) charged planes, respectively.Because the charge densities per unit area on every plane are equal.Hence, the strength of the electric field around point P is the same in situations A and B.
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6528 8891
A 0.25 kg ball with a velocity of 63 m/s strikes a 1.25kg ball at rest. After the collision, th
balls bounce off each other, and the 1.25 kg ball is moving with a velocity of 9m/s. Whc
is the velocity (in m/s) of the 0.25 kg ball?
Round your answer to the nearest whole number but leave units out of your answer.
Answer:
Answer is in the attached photo.
Explanation:
SolutionThe solution is in the attached photo, do take note the formula for linear collision:
m₁v₁i + m₂v₂i = m₁v₁f + m₂v₂f
where 'i' is the initial state and 'f' is the final state.
A simple circuit contains a 10 V battery connected with wires to a small bulb. If the power dissipated by the bulb is 0.5 W, what is the resistance of the bulb?
Group of answer choices
200 ohms
100 ohms
5 ohms
20 ohms
The resistance (slope of a curve) is about 490 so when bulb is lit. According to this model, the resistance was inversely proportional to temperature for materials (such this tungsten filament).200 ohms
LED lights have how many ohms?The datasheet for such LED will include this information as well as the forward dc voltage. LEDs typically demand 10 to 20mA. For instance, a 9V battery powered ultra-bright blue LED has a forwards voltage or 3.2V and a typical current is 20mA. Thus, the resistor must be 290 ohms and as close to that value as is feasible.
Are batteries highly resistant?Due to their relatively high resistance, alkaline, carbon-zinc, and the majority of primary batteries can only be used in low-current devices like flashlights, remotes, portable entertainment systems, and kitchen clocks. The resistance gets worse when these batteries run out of power.
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A spring with a spring constant of 2 N/m is stretched by Laura until extended by 0. 5 m. How much elastic potential energy is stored by the spring?
The spring stores 0.5 joules of elastic potential energy when stretched by 0.5 meters.
What is Potential Energy?
It is a form of energy that is stored in an object and has the potential to do work. The amount of potential energy depends on the position, shape, and orientation of the object. The most common types of potential energy are gravitational potential energy, elastic potential energy, and chemical potential energy.
The elastic potential energy stored by a spring is given by the formula:
Elastic potential energy = 1/2 * spring constant * (extension)^2
where the spring constant is measured in Newtons per meter (N/m), and the extension is measured in meters (m).
Given that the spring constant is 2 N/m and the extension is 0.5 m, we can plug these values into the formula:
Elastic potential energy = 1/2 * 2 N/m * (0.5 m)^2
= 0.5 J
Therefore, the spring stores 0.5 joules of elastic potential energy when stretched by 0.5 meters.
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Which object has the greatest momentum?* A. A sports car driving on the highway.
B. A baseball thrown by a professional pitcher.
C.An 18-wheeler tractor trailer at rest.
D. An average mass person walking.
Answer: B
Explanation: The best answer is B. A baseball thrown by a professional pitcher. Momentum is the product of an object's mass and its velocity. Since the baseball has the greatest velocity of all the objects listed, it has the greatest momentum.
Four capacitors are of the same capacity. If three of them are connected in
parallel and the remaining one is connected in series with this combination, the
resultant capacity is 16.5 μF. Find the capacity of each capacito
Answer:
bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb
Explanation:
What is/are the energy transformation(s) that take place when using a wind turbine to generate usable energy?.
The energy transformation that takes place when using a wind turbine to generate usable energy is mechanical-to-electrical.
This is done by converting the kinetic energy of the wind into mechanical energy, which then turns a generator to produce electrical energy. Then, residences and businesses can be powered by this electrical energy. Wind drives the rotor blades of contemporary wind turbines, which transform kinetic energy into rotational energy. Kinetic energy is a particular kind of power that can be present in a moving object or particle. An object can perform work, which involves the transfer of energy, by applying a net force. The effect is that the object accelerates and acquires kinetic energy. Aerodynamic force is used by the rotor blades of a wind turbine, which function similarly to an aeroplane wing or a helicopter rotor blade, to transform wind energy into electricity. The air pressure drops on one side of the blade as the wind passes across it.
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complete question: What is/are the energy transformation(s) that take place when using a wind turbine to generate usable energy?
A) friction- electrical
B) kinetic - mechanical - electrical
C) friction - mechanical - electrical
D) mechanical - friction - electrical
After a workplace incident requiring first aid, why is it beneficial to review the first aid response? (select 3 correct answers).
After a workplace incident requiring first aid, is it beneficial to review the first aid response because:
1) The WHS Act and Regulations make it a legal duty.
2) That the initial responder/s were properly trained for the occurrence.
3) Verify the efficacy of the workplace's first aid strategy and risk management procedure.
A review of first aid occurrences may be required by the workplace health and safety (WHS) act and regulations to confirm that correct procedures and protocols were followed and to identify any areas for improvement.
Confirming that the first aider/s had the requisite training for the event is critical to ensuring that the appropriate steps were taken during the incident and that the first aider/s were equipped with the knowledge and abilities to respond correctly.
After an event, review the first aid response to confirm the success of the workplace's first aid strategy and risk management approach. This can aid in identifying areas for development and preparing the workplace for similar situations in the future. The study may involve assessing the availability and accessibility of first aid equipment and supplies, as well as first aid personnel response time.
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Newton's universal law of gravitation states that response area objects attract each other with a force response area proportional to the product of their masses and response area proportional to the square of the distance between their centers. When considering objects on the surface of the earth, the force is directly proportional to the product of the mass of the object and the response area due to response area at the earth's surface. Since the earth is response area than any object under consideration, the object is drawn response area the earth.
Newton's Law of Universal Gravitation says that every particle in the cosmos attracts every other particle with a force directly equal to the product of their masses and inversely proportional to the square of their distance.
To detect the gravitational force of attraction between any two objects, at least one of them on Earth must have an exceptionally massive mass. We cannot detect such forces because no object on Earth has an enormously big mass.
Newton's universal law of gravitation states that all objects attract each other with a force (i) away from directly proportional to the product of their masses and (ii) gravity proportional to the square of the distance between their centers. When considering objects on the surface of the Earth, the force is (iii) directly proportional to the product of the mass of the object and the (iv) acceleration due to (v) smaller at the Earth's surface. Since the Earth is (vi) larger than any object under consideration, the object is drawn (vii) towards the Earth.
The two items in a room do not move towards one other since the gravitational force of attraction between them is extremely minimal due to their modest masses. According to the universal law of gravity, every object exerts a gravitational force on every other thing. The gravitational force is directly proportional to the product of masses and inversely proportional to the square of their distances, according to the universal law of gravitation.
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Complete Question:
Fill in the blanks with the appropriate option:
Newton's universal law of gravitation states that all objects attract each other with a force (i) _____ proportional to the product of their masses and (ii) ____ proportional to the square of the distance between their centers. When considering objects on the surface of the Earth, the force is (iii) _____ proportional to the product of the mass of the object and the (iv) ____ due to (v) _____ at the Earth's surface. Since the Earth is (vi) ____ than any object under consideration, the object is drawn (vii) ______ the Earth.
Options:
acceleration, away from directly, directly, gravity, inversely, larger, smaller, some, toward.
A 1500 kg car traveling east at 20 m/s collides with a moving 2500 kg truck moving 30 m/s west.. After they collide, the two interlock and move together. What was the final velocity of the truck? (Hint-momentum is a vector and direction matters, use + or - values as appropriate)* A. 11.25 m/s west B. 11.25 m/s east C. 32.6 m/s east D. 32.6 m/s west
Answer:cccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccccc
Explanation:
For a given star size, which planet type is easier to detect using the transit method?
OSmaller planets
O Larger planets
O The relative size of the planet does not matter.
Answer: Smaller planets are easier to detect using the transit method.
Explanation:
The transit method is a technique for detecting exoplanets, or planets outside our solar system, by observing the periodic dimming of a star as a planet passes in front of it (transits). The size of the planet affects the amount of light that is blocked, and therefore the magnitude of the dimming.
Smaller planets block less light than larger planets, making it more difficult to detect the transit. However, smaller planets are more numerous, and their transits are more frequent and easier to observe. Additionally, smaller planets are more likely to be located in the habitable zone of their star, where conditions may be suitable for life.
Therefore, smaller planets are easier to detect using the transit method, as they cause a smaller but more frequent dimming of the star, making them easier to detect with current technology. The relative size of the planet does matter in the transit method, as smaller planets are easier to detect.
Answer:
larger planets (correct)
Explanation:
State any five (5) clinical uses of heat enery .
The therapeutic effects of heat include increasing the extensibility of collagen tissues; decreasing joint stiffness; reducing pain; relieving muscle spasms; reducing inflammation, edema, and aids in the post acute phase of healing; and increasing blood flow.
What is the role of heat energy in the body?In the process of ATP production by cells throughout the body, approximately 60 percent of the energy produced is in the form of heat used to maintain body temperature. Thermoregulation is an example of negative feedback.
Why is heat used as a treatment during health care?
Heat treatments should be used for chronic conditions to help relax and loosen tissues, and to stimulate blood flow to the area. Heat is a great treatment option for chronic conditions caused from old injuries or even arthritis. Heat can be applied before participating in activities to help limber up.
So we can conclude that heat is one of the most important form of energy for our daily life.
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The speed of light in vacuum is 3* 10^8. If the refractive index of a transparent liquid is 4/3, then what is the speed of light in the liquid?
The speed of light in vacuum is 3 × 10⁸ m/s. If the refractive index of a transparent liquid is 4/3, then the speed of light in water will be 2.25 × 10⁸ m/s.
What is Refractive index?Refractive Index is a value calculated from the ratio of the speed of light in a vacuum to the speed of light in the second medium of greater density. The refractive index variable is most commonly symbolized by the letter n or n'.
R.I. of water = Speed of light in vacuum / speed of light in water
n' = 4/3
Speed of light in vacuum = 3 × 10⁸
n' = Speed of light in vacuum / speed of light in water
Speed of light in water = Speed of light in vacuum/ n'
Speed of light in water = 3 × 10⁸/ 4/3
Speed of light in water = 2.25 × 10⁸
Therefore, the speed of light in water medium will be 2.25 × 10⁸ m/s.
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(a) A charge of -275e is uniformly distributed along a circular arc of radius 3.85 cm, which subtends an angle of 37°. What is the linear charge density along the arc?
1 C/m
(b) A charge of -275e is uniformly distributed over one face of a circular disk of radius 1.85 cm. What is the surface charge density over that face?
2 C/m2
(c) A charge of -275e is uniformly distributed over the surface of a sphere of radius 1.85 cm. What is the surface charge density over that surface?
3 C/m2
(d) A charge of -275e is uniformly spread through the volume of a sphere of radius 1.85 cm. What is the volume charge density in that sphere?
4 C/m3
Uniform distribution of charge a) [tex]-1.752 * 10^(-17) C/m[/tex] b) [tex]-4.038 * 10^(-16) C/m^2[/tex] c) [tex]-6.346 * 10^(-16) C/m^2[/tex] d) [tex]-4.580 * 10^(-13) C/m^3[/tex]
(a) To find the linear charge density along the arc, we divide total charge (-275e) by arc length. Arc length is product of radius (3.85 cm) by the angle (in radians) arc subtends. Convert angle to radians:
[tex]37 degree = (37/360) * 2\pi radians = 0.6435 radians[/tex]
The length of the arc is then:
length = radius x angle = (3.85 cm) x (0.6435) ≈ 2.477 cm
The linear charge density is then:
linear charge density = charge in total / length magnitude = (-275e) / (2.477 cm)
e: elementary charge.
Using charge value:
linear charge density = [tex]-1.752 * 10^(-17) C/m[/tex]
Therefore, linear charge density along the arc is [tex]-1.752 * 10^(-17) C/m.[/tex]
(b) To find the surface charge density over the face of the circular disk, we need to divide the total charge (-275e) by area of disk. Area of face of disk is [tex]\pi[/tex] times radius squared
area =[tex]\pi * (1.85 cm)^2 = 10.78 cm^2[/tex]
The surface charge density is then:
surface charge density = total value of charge / area magnitude = [tex](-275e) / (10.78 cm^2)[/tex]
e: elementary charge.
Using charge value:
surface charge density = [tex]-4.038 * 10^(-16) C/m^2[/tex]
Surface charge density over the face of the circular disk is [tex]-4.038 * 10^(-16) C/m^2[/tex].
(c) To get surface charge density over sphere surface, we divide total charge (-275e) by sphere surface area:
surface area = [tex]4\pi * (radius)^2[/tex]
The surface charge density:
surface charge density = total charge / surface area =[tex](-275e) / [4\pi * (1.85 cm)^2][/tex]
where e is the elementary charge.
Use charge value:
surface charge density ≈ [tex]-6.346 * 10^(-16) C/m^2[/tex]
Surface charge density over sphere is[tex]-6.346 * 10^(-16) C/m^2.[/tex]
(d) To get volume charge density in the sphere, we divide the total charge (-275e) by the volume of the sphere.
volume = [tex](4/3)\pi * (radius)^3[/tex]
The volume charge density is then:
volume charge density = total charge / volume = [tex](-275e) / [(4/3)\pi * (1.85 cm)^3][/tex]
e: elementary charge
Using value of the elementary charge:
volume charge density = [tex]-4.580 * 10^(-13) C/m^3[/tex]
Therefore, the volume charge density in the sphere is [tex]-4.580 * 10^(-13) C/m^3[/tex]
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