Drag the phase slider left and right to move the planet into and out of transit mode. The normalized flux (the relative amount of starlight reaching an observer on Earth) when the planet is off the side (not transiting) is 0.990 while the normalized flux when the planet is transiting is 1.000. Thus, the correct option for this question is B.
What is Normalized flux?Normalized flux may be characterized as a type of key methodology in spectral data mining. It is important for the efficiency and accuracy of the automatic processing of massive astronomical spectral data, information extraction, and sharing.
A transit occurs when a planet passes between a star and its observer. Transits within our solar system can be observed from Earth when Venus or Mercury travel. The frequency of the normalized flux when the planet is transiting is completely different from when the planet is off the side.
Therefore, the correct option for this question is B.
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Answer: 1.000,0.990 (correct)
Explanation:
(17%) Problem 2: The drawing shows a small sphere of mass m=0.26 g that carries a charge of q = 85 x 10-10 C. The sphere is attached to one end of a very thin silk string of length L = 6.25 cm. The other end of the string is attached to a large vertical conducting plate that has a charge density of o = 30 x 10-6C/m². + + + + + + L m, A 25% Part (a) Write an expression for the magnitude of the electric field due to the charge distribution on the conductive plate. E = 0 Grade Summary Deductions 0% Potential 100% €0 B 0 Y b 0 Submissions Attempts remaining: 20 (% per attempt) detailed view d h ( 789 HOME 1456 1 23 + 0 END VO BACKSPACE GEL CLEAR g k j m n P S Submit Hline Feedback I give up! Hints: for a 0% deduction. Hints remaining: 0 Feedback: 0% deduction per feedback. Date Submission History All Date times are displayed in Eastern Standard Time Red submission date times indicate late work. Time Answer Hints Feedback 24 25% Part (b) Write an expression for the horizontal component of the net force acting on the charged sphere in terms of the tension T in the string, the electric field, and the given variables. A 25% Part (c) Write an expression for the vertical component of the net force acting on the charged sphere in terms of the tension T in the string and the given variables. 425% Part (d) What is the angle in degrees that the string makes with respect to the vertical?
θ = 39.7º is the angle in degrees that the string makes with respect to the vertical using Newtons law.
In each exercise, we construct the equations at the equilibrium point using Newton's second law for the sphere. We'll assume that plate 1 is on the left for this exercise.
Y Axis
Y= -W = 0 = W
X axis
X= - F_{e2} + Tₓ = 0
Let's utilize trigonometry to determine the tension's component parts. We gauge the angle in relation to the vertical
sin θ = Tₓ / T
cos θ = T_{y} / t
Tₓ = T sin θ
T_{y} = T cos θ
Gauss's law can be used to determine the electric field of each leaf. Since a cylinder forms a Gaussian surface, the component of the field perpendicular to the cylinder's base is the one containing electric flow.
F = ∫ E. dA
The flow is towards both sides of the plate in this instance, and the scalar product is reduced to the algebraic product.
F = 2E A = q_{int} / ε₀
let's use the concept of surface charge density
σ = q_{int} / A
we substitute
2E A = σ A /ε₀
E = σ / 2ε₀
T cos θ = mg
- q σ₁ / 2ε₀ - q σ₂ /2ε₀ + T sinθ = 0
we introduce t in the second equations
- q /2 ε₀ (σ₁ + σ₂) + (mg / cos θ) sin θ = 0
mg tan θ = q /2ε₀ (σ₁ + σ₂)
θ = tan -1 (q / 2ε₀ mg (σ₁ + σ₂)
data indicates the mass of 0.26 g = 0.26 10⁻³ kg
give the charge density on plate 2, suppose ab = 10 10⁻⁶ C / m²
let's calculate
θ = tan⁻¹ (9.0 10⁻¹⁰ (30 + 10) 10⁻⁶ / (2 (6.25 10⁻¹² *0.26 10⁻³ 9.8))
θ = tan⁻¹ 8.3 10⁻¹)
θ = 39.7º
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Describe protons.
Location:
Charge:
Mass:
The protons location is nucleus of an atom, the Mass is 1 amu and the charge is positive.
What is protons?
Protons are subatomic particles with a positive electrical charge. They are found in the nucleus of atoms and are responsible for most of the atom’s mass. Protons are one of the three main subatomic particles, along with neutrons and electrons.
Location: Proton is located in the nucleus of an atom. The nucleus is the small, dense, positively charged center of an atom. The protons, along with the neutrons, make up the nucleus of the atom.
Mass: The mass of a proton is approximately 1.007276467 u (unified atomic mass units). It is slightly heavier than a neutron, which has a mass of approximately 1 u.
Charge: A proton has a positive charge of +1 elementary charge (e). This charge is what gives the proton its repelling force to other positively charged particles and its attractive force to negatively charged particles.
Hence, a proton is a positively charged subatomic particle with a mass of 1 amu, located in the nucleus of an atom.
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Answer:
Location:
✔ nucleus
Charge:
✔ positive
Mass:
✔ one amu
Explanation:
An 8.7 hour trip is made at an average speed of 73.0 km/hr. If the first third of the trip (chronologically) was driven at 96.5 km/hr, what was the average speed for the rest of the journey?
The average speed for rest of the journey = (632.1 - 281.55) / 5.8 km/hr = 88.4 km/hr.
What is average speed?Average speed is a measure of the rate of change of a certain distance traveled over a period of time. It is usually calculated by dividing the total distance traveled over time, usually in hours, minutes, or seconds. Average speed is a measure of the average rate of motion, not necessarily the actual speed at any given moment.
Let the total distance covered be D. Time taken for first third of the journey = 8.7/3 hrs = 2.9 hrs
Distance covered in first third of the journey = 2.9 * 96.5 km/hr = 281.55 km
Therefore, distance covered in rest of the journey = D - 281.55 km
Time taken for rest of the journey = 8.7 - 2.9 hrs = 5.8 hrs
Average speed for rest of the journey = (D - 281.55) / 5.8 km/hr
Substituting the value of D = 8.7 hrs * 73 km/hr = 632.1 km
Therefore, average speed for rest of the journey = (632.1 - 281.55) / 5.8 km/hr = 88.4 km/hr
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What is the smallest possible value of the principal quantum number n for an s electron?
Answer:
The smallest possible value of the principal quantum number (n) for an electron in an atom is n = 1. This is referred to as the first energy level or the "1s" orbital, and it corresponds to the lowest energy state of an electron in an atom.
Explanation:
In general, the value of n determines the size and energy of the electron orbital. The larger the value of n, the larger the size of the orbital and the higher the energy of the electron. The smallest possible value of n is therefore always 1, and it corresponds to the electron being in its lowest energy state.
A proton moving along the lines of force of a uniform electric
field, the intensity of which is 10 kV/m, increased its speed from 106 m/s
up to 1.1∙ 106 m/s. Find: 1) potential difference between points, 2)
acceleration of a proton, 3) path of a proton during acceleration, 4) work
electric field. The charge of a proton is 1.6 ∙ 10−19 K; the mass of a proton
1.67 ∙ 10−27 kg.
A glider of length 12.4 cm moves on an air track with
constant acceleration (Fig P2.31). A time interval of 0.628 s
elapses between the moment when its front end passes a
fixed point A along the track and the moment when its
back end passes this point. Next, a time interval of 1.39 s
elapses between the moment when the back end of the
glider passes the point A and the moment when the front
end of the glider passes a second point B farther down the
track. After that, an additional 0.431 s elapses until the
back end of the glider passes point B. (a) Find the average
speed of the glider as it passes point A. (b) Find the acceleration
of the glider. (c) Explain how you can compute the
acceleration without knowing
the distance between points A
and B.
[tex]19.7cm/s and 4.70 cm/s^2[/tex] are the average speed and acceleration of the glider.
(a) As the glider's front end crosses point A, start a timer at t=0. The instantaneous speed at t=0.314s, halfway through the time interval, is [tex]12.4cm/(0.628s)=19.7cm/s[/tex], which equals the glider's average speed for the interval between t=0 and t=0.628s.
(b) The instantaneous speed at the point [tex]t=(2.02+2.45)/2=2.23s[/tex]. is equal to [tex]12.4cm/(0.431s)=28.8cm/s[/tex], which is the average speed of the glider for the time span between [tex]0.628+1.39=2.02s[/tex] and [tex]0.628+1.39+0.431=2.45s[/tex].
Now that we are aware of the velocities at two points, we can calculate the acceleration using the formula [tex][(28.8-19.7)cm/s]/[(2.23-0.314)s]=4.70cm/s2[/tex].
(c) The average velocity over a predetermined period of time is determined using the glider's length rather than the distance between points A and B.
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The cart is given an initial push up the ramp. After this push, as the car moves up the ramp, the direction of the acceleration of the cart is_________the ramp. After ther turns around, and begins moving down the ramp, the direction of the acceleration of the cart is__________ eaches its highest point, the ramp. At the highest point the cart reaches on the ramp, when the cart momentarily comes to rest, the magnitude of the acceleration of the cart is_________O down, down, zeroO up, down, nonzeroO down, down, nonzeroO up, down, zero
The correct answers to the blanks are 1. UP ,2. UP and 3. ZERO
When the cart is initially given a push up the ramp, the direction of the acceleration of the cart is up the ramp. This is because the net force acting on the cart is directed up the ramp, in the same direction as the component of the gravitational force that is parallel to the ramp. As a result, the cart accelerates up the ramp in the same direction as the net force.
When the cart turns around and begins moving down the ramp, the direction of the acceleration of the cart is still up the ramp. This is because the component of the gravitational force that is parallel to the ramp is still directed down the ramp, but the net force acting on the cart is directed up the ramp due to the normal force exerted by the ramp on the cart. As a result, the cart accelerates down the ramp in the opposite direction to the net force, which is up the ramp.
At the highest point that the cart reaches on the ramp, when the cart momentarily comes to rest, the magnitude of the acceleration of the cart is zero. This is because at this point, the cart is at the highest point on the ramp and has stopped moving. As a result, the velocity of the cart is zero, and therefore the acceleration of the cart is also zero.
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TRUE OR FALSE: Increasing the time of impact during a collision increases the force experienced by the object. * True False
Answer:
False
Explanation:
I'm pretty sure increasing the time of impact actually decreases the force because it is being spread out.
If two bowling balls were to collide head on stick to one another, with some loss in kinetic energy, the collision would be considered a(n) ___________ collision.*
A. Cushy
B.Perfectly Inelastic
C.Reversable
D.Elastic
Answer: D
Explanation:An inelastic collision is one in which objects stick together after impact, and kinetic energy is not conserved. This lack of conservation means that the forces between colliding objects may convert kinetic energy to other forms of energy, such as potential energy or thermal energy.
You use a ruler marked with 1 mm increments to measure the lengths of the height h of a block and find h = 121 mm. According to the half least count rule, what is the uncertainty in your measurement of the height?
The uncertainty in height is, 0.5 mm.
The "half least count rule" states that the uncertainty in a measurement is equal to half of the smallest division on the measuring instrument. In this case, the ruler is marked in 1 mm increments, so the smallest division is 1 mm.
Using the half least count rule, the uncertainty in the measurement of the height is,
uncertainty = 1/2 * 1 mm = 0.5 mm
Therefore, the uncertainty in the measurement of the height is 0.5 mm. We can express the result as,
h = 121 ± 0.5 mm
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what is the difference in mechanical energy from point A to point C below?
Answer:
their speed maybe cause of the ups and downs
A car moving with an initial velocity of 25 m/s north has a constant acceleration of 5.5 m/s2 south. After 10 seconds its velocity will be
Answer:
80 m/s
Explanation:
v = v₀ + at
v = 25 m/s + (5.5 m/s²)(10 s) = 80 m/s
Blackbody Temperature 5800 K B GR Graph Values Labels Intensity 100 Sirius A o Spectral Power Density (MW/m/um) Sun Light Bulb 0 Earth Wavelength (m) 1 n = 1000 mm This simulation shows the amount of power opaque objects at different temperatures will emit at different electromagnetic wavelengths. Such spectra are known as blackbody spectra and it is the feature of the light emitted by any object due to its temperature. Stars, famously, produce blackbody spectra that affect the colors that they appear. The simulation starts with simulating the Sun's spectrum. Explore the simulation and search through the different options to determine the wavelength of light in micrometers where the Sun's blackbody spectrum peaks: micrometers Express this value in nanometers: nanometers What kind of electromagnetic radiation is this? infrared visible ultraviolet What is the solar intensity (the amount of power per unit area emitted by the Sun 10
The wavelength of light in micrometers where the Sun's blackbody spectrum peaks is approximately 0.5 micrometers or 500 nanometers.
The simulation provided allows the user to explore blackbody spectra emitted by opaque objects at different temperatures. Such spectra are the characteristic feature of light emitted by any object due to its temperature. The simulation begins by showing the blackbody spectrum of the Sun. By exploring the different options, the user can determine the wavelength of light in micrometers where the Sun's blackbody spectrum peaks, which turns out to be around 0.5 micrometers or 500 nanometers. This is within the visible spectrum of electromagnetic radiation, which is why we can see the Sun as a yellowish-white color. Additionally, the simulation provides information about solar intensity, which is the amount of power per unit area emitted by the Sun.
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A child is riding on a merry go round. As the speed of the merry go round is doubled, the magnitude of the centripetal force acting on the childa. Remains the sameb. Is quadrupledc. Is doubledd. Is halved
A youngster is on a merry-go-round. The centripetal force acting on the toddler is quadrupled as the merry-go-speed round's is doubled. So, option B is correct.
What is centripetal force?
Centripetal force is a term used to describe a force that moves a body along a curved path. The centripetal force is always applied in the general direction of the path's instantaneous center of curvature and against the motion of the subject. According to Isaac Newton, it is "a force by which bodies are dragged or forced, or in any other way gravitate, towards a point as to a center." Gravity is the centripetal force that generates astronomical orbits, according to Newtonian mechanics theory.
As, the formula of Centripetal force,
[tex]F=\frac{mv^2}{r}[/tex],
We can see that, F is directly proportional to [tex]v^{2}[/tex], When the speed of the merry-go-round is doubled, the centripetal force acting on the child is multiplied by four.
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Learning Goal:
To understand the role of the internal resistance of various devices and the use of the ammeter and the voltmeter.
Consider the circuit shown.(Figure 1) All wires are considered ideal; that is, they have zero resistance. We will assume for now that all other elements of the circuit are ideal, too: The value of resistance R is a constant, the internal resistances of the battery (r) and the ammeter (RA) are zero, and the internal resistance of the voltmeter (RV) is infinitely large.
The internal resistance of devices like batteries, ammeters, and voltmeters can affect the overall current and voltage in a circuit.
To accurately measure these values, it's important to take into account the internal resistance of these devices and to use them correctly in the circuit. It's important to note that the internal resistance of devices can affect the overall performance of a circuit.
For example, the internal resistance of a battery can affect the voltage available to the circuit and the internal resistance of a speaker can affect its efficiency. Therefore, it's important to take into account the internal resistance of devices when designing and analyzing circuits.
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A skier with a mass of 55 kg is skiing down a snowy slope that has an incline of 30°.
Find the coefficient of kinetic friction for the skier if friction is known to be 25 N.
The coefficient of kinetic friction for the skier, if friction is known to be 25 N, is calculated to be 0.463.
What is Kinetic friction?Kinetic friction may be characterized as a type of force that considerably resists the relative movement of the surfaces once they're in motion. It is just the opposite of static friction.
According to the question,
The total weight of a skier = mass of a skier × gravity = 55 × 9.8
The angle at which it inclines = 30° i.e. θ = 30°.
Normal force, N = mgcosθ
The friction force, F = kinetic friction (N)
25 N = Kf (55 × 9.8 × 30)
Kf = 0.463.
Therefore, the coefficient of kinetic friction for the skier, if friction is known to be 25 N, is calculated to be 0.463.
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Lab: Newton's Laws of Motion
Newton's law of motion
Three newton's law of motion:-
1. An object will not change its motion unless a force acts on it.
2. The force of an object is equal to its mass time its acceleration.
3. When two objects interact , they apply forces to each other of equal magnitude and opposite direction.
Newton's law of motion are three basic laws of classical mechanics that describes the relationship between the motion of an object and the forces acting on it.
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Which of these is an example of acceleration?
Answer:
a bus triveling north at 25m/s
Electric Field Direction only OO Voltage Values Grid 00V a +1 nc -1 nc Sensors Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 m away from the positive charge (1 m is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength. Consider the locations to the right, left, above, and below the positive charge, all 1 m away. For these four locations, the magnitude of the electric field is. greatest to the right of the charge. greatest below the charge. greatest above the charge. greatest to the left of the charge. O O O the same. Submit Request Answer
Considering the locations to the right, left, above, and below the positive charge, all 1 mm away. For these four locations, the magnitude of the electric field is the same.
The area, space, or field around it is an electric field of an isolated charge. There are mainly two types of electric fields i.e., static and dynamic. Moving charges produced dynamic electric fields whereas static electric fields are produced by stationary charges.
Direction and magnitude do not change over time for static electric fields. The direction can be positive or negative which is determined by the charge of the source.
The electric field formula is the electric field magnitude at a certain point from the charge Q, and it hangs on two factors- the distance r from the point to the origin Q and the amount of charge at the origin Q.
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The correct question is:
Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/mV/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 mm away from the positive charge (1 mm is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength.
Consider the locations to the right, left, above, and below the positive charge, all 1 mm away. For these four locations, the magnitude of the electric field is________________.
The diagram below shows three cubes of the same material and density. If the cubes all start out at 80°C, which cube will cool the most slowly?
Answer:
the cube that will slowly cool is 2
The cube 2 will cool the most slowly.
What is meant by cooling ?The removal of heat from a system is known as cooling, and it usually leads to a decrease in temperature or a change in phase.
Here,
Three cubes of same material and density are given in the diagram. They all are said to be cooling starting from 80°C.
The three cubes have different volumes.
We know that, as the volume of the cube increases, the surface area of the cube decreases accordingly. That means, the volume of a cube is inversely proportional to its surface area.
V ∝ 1/A
According to the principle of cooling, the rate of cooling is directly proportional to the surface area. That means, the rate of cooling is higher for objects with higher surface area and slower for those with lower surface area.
So, the cube 2 is having the lowest volume among the three cubes and thus the highest surface area.
Therefore, it will take more time to cool down.
Hence,
The cube 2 will cool the most slowly.
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a) calculate the magnitude of the force parallel to surface 1 b) calculate the magnitude of the force parallel to surface 2
A force can make a body at rest to move. The magnitude of force parallel to surface 1 is 5.04 N and the magnitude of the force parallel to surface 2 is 4.02 N.
What is Force?The force can be defined as the quantity which is expressed as the product of mass (m) and acceleration (a). It is known as the push or pull on an object which produces acceleration in the body on which it acts.
The equation which is used to calculate the force is given as:
F = ma
a) F₁ = m₁ g sin40
= 0.800 kg × 9.81 m/s² × 0.64
= 5.04 N
b) F₂ = m₂ g sin55
= 0.500 kg × 9.81 m/s² × 0.82
= 4.02 N
Thus the magnitude of the force parallel to surface 1 is 5.04 N and the magnitude of the force parallel to surface 2 is 4.02 N.
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Would the field representation of a positive or negative charge be a better
representation for the gravitational field around one mass? Why?
Field representation of a positive or of a positive or negative charge cannot be a representation for the gravitational field around one mass. It height from the ground must be determined.
What is gravitational force?The gravitational force is a kind of force by which an object attracts other objects into its center of a mass. Earth attracts every objects in its surface in to the ground and that is why we are all standing on the ground.
Gravitational force between two objects depends on their mass and distance between them. The field representation of the charge does not represent a gravitational field but it can show an electric field between them.
The height of the mass from the surface have to be determined to represent the gravitational field. The gravitational field is not at all depending on the charge of the object.
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1. A car moves at 10m/s
a. Net Force on the car is zero
b. Force of friction is equal to the forward force applied by the engine
c. Both a and b are correct
d. a is correct but b is wrong
Answer:
d. a is correct but b is wrong.
Explanation:
A car that is moving at a constant speed of 10m/s is experiencing a net force of zero, meaning that the sum of all forces acting on the car is equal to zero. This means that the forward force applied by the engine is equal in magnitude but opposite in direction to the force of friction acting on the car.
The force of friction acts to slow down the car, but it does not equal the forward force applied by the engine. Instead, it is determined by factors such as the weight of the car, the road surface, and the tire traction. If the forward force applied by the engine is greater than the force of friction, the car will accelerate. Conversely, if the force of friction is greater than the forward force applied by the engine, the car will decelerate.
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A 3.0 kg object swings back and forth as a simple pendulum with a small amplitude. The potential energy U of the object as a function of distance x from its equilibrium position is shown above. This particular object has a total energy E of 0.4 J.
b) What is the farthest the object moves along the x-axis in the positive direction? Explain your reasoning.
c) Determine the object’s kinetic energy when its displacement is -8 cm.
d) What is the object’s speed at x = 0?
10cm is the farthest the object moves along the x-axis in the positive direction .0.15J is the object’s kinetic energy when its displacement is -8 cm. 0.316m/s is the object’s speed at x = 0.
Define kinetic energy.
Kinetic energy, which may be seen in the movement of an item or subatomic particle, is the energy of motion. Kinetic energy is present in every particle and moving object. Examples of kinetic energy in action include a person walking, a baseball soaring through the air, a piece of food falling from a table, and a charged particle in an electric field.
Given,
Total energy is 0.4J
m is 3kg
The farthest the object moves along the x-axis in the positive direction would be as potential energy is 0.4J. So from given diagram, displacement will be 10cm
If displacement is -8cm , P.E from diagram will be 0.25J
According to energy conservation formula ,
ME ⇒ U+KE
KE ⇒ ME-U ⇒ 0.4-0.25 ⇒ 0.15J
At x ⇒ 0,
KE ⇒ 1/2 mv^2
0.15 ⇒ 0.5*3*v^2
v ⇒ 0.316m/s
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Without having the help of the moving pad, you and a friend have to move the very heavy
entertainment center. The kinetic friction opposing the motion is equal to 1600 N and your
maximum applied force is 1000N. How much force does your friend need to apply to make the
entertainment center move at a constant velocity?
The force needed by my friend to make the entertainment center move at a constant velocity is 600 N
How to find force application?To find the force application in a specific situation, one needs to consider the forces that are acting on an object and the net force (the vector sum of all forces acting on an object) which determines the motion of the object.
In order to make the entertainment center move at a constant velocity, the sum of the applied forces must equal the force of kinetic friction. If the maximum applied force you can provide is 1000 N, then your friend needs to apply a force of 1600 N - 1000 N = 600 N.
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In which collision(s) is momentum conserved?
A.Elastic
B.Inelastic
C.Perfectly inelastic
Momentum is conserved in both elastic and perfectly inelastic collisions.
In an elastic collision, the total momentum of the colliding objects is conserved before and after the collision. This means that the sum of the momentum of the objects before the collision is equal to the sum of the momentum of the objects after the collision.
In a perfectly inelastic collision, the two objects stick together after the collision, forming a single object with new momentum. In this case, the total momentum of the system is also conserved.
However, in an inelastic collision, momentum is not conserved, as some of the momenta are transformed into other forms of energy, such as heat or sound. This means that the total momentum of the objects before the collision is not equal to the total momentum of the objects after the collision.
Answer:
Explanation:
A
A 1500 kg car traveling east at 20 m/s collides with a moving 2500 kg truck moving 30 m/s west.. After they collide, the two interlock and move together. What was the final velocity of the truck? (Hint-momentum is a vector and direction matters, use + or - values as appropriate)*
A. 11.25 m/s west
B. 11.25 m/s east
C. 32.6 m/s east
D. 32.6 m/s west
The final velocity of the truck after collision, given that the car and the truck interlock and move together is 11.25 m/s west (Option A)
How do I determine the final velocity of the truck?The final velocity of the truck after the collision can be obtained as illustrated below:
Mass of car (m₁) = 1500 KgInitial velocity of car (u₁) = 20 m/sMass of truck (m₂) = 2500 KgInitial velocity of truck (u₂) = 11 m/sEast = Positvie directionWest = Negative directionFinal velocity (v) = ?Momentum before = momentum after
m₁u₁ + m₂u₂ = v(m₁ + m₂)
(1500 × 20) - (2500 × 30) = v(1500 + 2500)
30000 - 75000 = v × 4000
-45000 = v × 4000
Divide both sides by 4000
v = -45000 / 4000
v = -11.25 m/s
Recall => West is negative
v = 11.25 m/s west
Thus, the final velocity is 11.25 m/s west (Option A)
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A moving object has
kinetic energy
velocity.
speed.
all of these
It has all of these. everything has kinetic energy, it is moving so it will have both speed and velocity as well.
Simulate a blackbody spectrum of temperature 1700 Kelvin. Determine the peak wavelength in 3.22 nanometers of an object of that temperature nanometers What is the emissive intensity of the object
a) The peak wavelength in 3.22 nanometers of an object is 345 nanometre, b) the emissive intensity of the object is 2.82 * 10⁸ W/m².
The relationship between the temperature,T and the peak wavelength, [tex]\lambda[/tex] emitted by a black body is given by wien's displacement law:
[tex]\lambda[/tex] = b / T
Where, b is a constant and it's value is 2.898 * 10-3 m-K
Given: T = 8400 K
So, [tex]\lambda[/tex] = (2.898 * 10-3 )/8400
\lambda = 3.45 * 10-7
\lambda = 345 nm
Hence, the peak wavelength of the object at this temperature is 345 nanometre.
The amount of power emitted per unit area, P is given by Stefan Boltzmann law:
P =[tex]\sigma[/tex]T⁴
Where,
Absolute temperature, T = 8400 K
Stefan Boltzmann constant, [tex]\sigma[/tex] = 5.67 * 10-8 W/m²K⁴
So, P = 5.67 * 10-8 * (8400)⁴
P = 2.82 * 10⁸ W/m²
Hence, the power emitted per unit area is 2.82 * 10⁸ W/m².
Learn more about Emissive intensity and wavelength:
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A 5.0 kilogram initially at rest is accelerated by a force of 25 newtons such that it attains 5.0 x 102 joules of kinetic energy
Therefore, the distance over which the force acts is 20 meters.
explain about kinetic energy ?The initial kinetic energy of the object is zero since it is at rest. The work done on the object by the applied force is equal to the change in its kinetic energy:
[tex]W = ΔK[/tex]
where W is the work done and [tex]ΔK[/tex] is the change in kinetic energy.
The work done by the force can be found using:
[tex]W = Fd[/tex]
where F is the force applied and d is the distance over which the force acts.
Since the object starts from rest, we can use the equation for the work-energy principle:
[tex]W = Kf - Ki[/tex]
where Kf is the final kinetic energy and Ki is the initial kinetic energy.
Setting these two expressions for W equal to each other, we have:
[tex]Kf - Ki = Fd[/tex]
Substituting the given values, we have:
[tex]Kf - 0 = (25 N) dKf = 25d[/tex]
But we also know that the final kinetic energy is[tex]5.0 x 10^2 J[/tex], so:
[tex]5.0 x 10^2 J = 25d[/tex]
d = 20 meter
Therefore, the distance over which the force acts is 20 meters.
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