A 950.0 mL solution of potassium permanganate was made by dissolving 45.0 g KMnO4 in 750.0 mL of water. Assume water has a density of 1.00 g/mL. (Molar Mass for H = 1 , O = 16 , K= 39 , Mn= 55 ) The mole fraction of the solute =

Answers

Answer 1

Answer:

The correct answer is 6.67×10⁻³.

Explanation:

Based on the given question, the amount of solute (KmNO4) is 45 grams. The molecular weight of KmNO4 is 158 gram per mole. The moles of solute can be determined by using the formula,  

n = mass/molecular weight  

n = 45/158 = 0.28  

The amount of solvent (water) given is 750 milliliters, and the density of water is 1 gm. per ml, 18 gram per mole is the molecular weight of water. So, the moles of solvent will be,  

n = 750/18 = 41.7  

The formula for calculating mole fraction is,  

Mole fraction = mole of solute / (mass of solute + mole of solvent)

The mole fraction of solute can be determined by putting the values in the above mentioned formula,  

Mole fraction of KmNO4 = 0.28/(0.28+41.7)

= 0.28/41.98

= 6.67 × 10⁻³ or 7 × 10⁻³.  


Related Questions

Choose the slope and Y intercept that correspond with the graph

Answers

y=3x + 4

Explanation:

Where 3 is the slope and 4 is the y-intercept

The chemical equation and thermodynamic data for the melting of tungsten are given above. Based on this information, which of the following provides the best predictions correc whether a sample of pure tungsten will melt at 3723 K?
A. The sample will not melt because T > H/s
B. The sample will not melt because T< H/s
C. The sample will mel because T>
D. The sample will mel because T

Answers

Based on the information above provided, the best predictions correct whether a sample of pure tungsten will melt at 3723 K is The sample will mel because T>

Tungsten

Tungsten is a very hard and brittle material. It properties include a very high melting point, a low vapor pressure and the highest hardness and strength of all metals. Tungsten has good corrosion resistance against most acids and alkalis.

Learn more about tungsten:

https://brainly.com/question/11014899

Why is tape attracted to my skin? Give explanation

Answers

Answer:

Since the tape has extra electrons, it has a negative charge. When you move your finger close to the tape, electrons in your skin are repelled and move away. This makes the skin on your finger tip have a slight positive charge. Since positive and negative attract, the tape moves toward your finger.

How many grams of the salt CaF2 (g) are formed when 15.7 mL of 0.612 M KF reacts with an excess of aqueous calcium bicarbonate (Ca(HCO3)2) via a metathesis reaction?

Answers

Answer:

[tex]m_{CaF_2}0.375gCaF_2[/tex]

Explanation:

Hello,

In this case, for the studied reaction:

[tex]2KF+Ca(HCO_3)_2\rightarrow CaF_2+2KHCO_3[/tex]

Thus, the first step is to compute the reacting moles of potassium fluoride by using its volume and molarity:

[tex]n_{KF}=0.0157L*0.612\frac{mol}{L} =9.61x10^{-3}molKF[/tex]

Then, we apply the 2:1 molar ratio between potassium fluoride and calcium fluoride to compute the produced moles of calcium fluoride:

[tex]n_{CaF_2}=9.61x10^{-3}molKF*\frac{1molCaF_2}{2molKF} =4.80x10^{-3}molCaF_2[/tex]

Finally, by using the molar mass of calcium fluoride (78.07 g/mol) we can compute its produced grams:

[tex]m_{CaF_2}=4.80x10^{-3}molCaF_2*\frac{78.07gCaF_2}{1molCaF_2} \\\\m_{CaF_2}0.375gCaF_2[/tex]

Best regards.

Predict the order of elution if you were to attempt to separate using column chromatography on silica gel and with a gradient eluent system starting with petroleum ether and slowly increasing MTBE % over time.

Answers

Answer:

Follows this order: B=> A => C.

Explanation:

NB: kindly check the attachment for the diagram of compounds A, B and C.

Elution is a very important concept in chromatography separation techniques. It deals with the use of eluent in the removal of an adsobate from an adsorbent. The principle behind Elution is just about how polar the solvent is.

So, in this question Compound B will go with the Elution first because of its polarity. Compound B has lesser polarity as compared to Compounds A and B.

Compound A will then elutes second because of its polarity too as resonance increases its polarity.

Last, compound C elutes because it has the highest polarity which is caused by electronegative atoms.

Determine if the following salt is neutral, acidic or basic. If acidic or basic, write the appropriate equilibrium equation for the acid or base that exists when the salt is dissolved in aqueous solution. If neutral, write only NR. LiNO₃

Answers

Answer:

It is neutral (NR)

Explanation:

Salts are formed when the ionizable hydrogens in an acid is replaced by metallic or ammonium ions from bases. The reaction is known as a neutralization reaction.

The nature of a salt formed from this reaction depends on the nature of the reacting acid and base.

If the reaction is between a strong acid and strong base, the salt produced is a neutral salt.

If the reaction occurs between a strong acid and a weak base, the salt produced is acidic.

If the reaction occurs between a strong base and a weak acid, the salt produced is a basic salt.

Considering the salt above, LiNO3.

On hydrolysis, addition of water, the following products are obtained:

LiNO3 + H2O ----> LiOH + HNO3

The products obtained, LiOH and HNO3 are a strong base and a strong acid respectively. Therefore, the salt, LiNO3, is a neutral salt.

The salt, LiNO₃ is a neutral, NR salt as it's a salt formed from the reaction of a strong acid and a strong base.

In neutralisation reactions, acids and bases react to form salt and water.

However, the salt formed may be acidic, basic or neutral. This is dependent on the type of acid and base which form the salt.

A strong acid and a strong base react to yield a neutral salt like, LiNO₃.

The equilibrium equation when LiNO₃ is dissolved in aqeous solution is;

LiNO₃ + H2O ==>. LiOH + HNO₃

Evidently, LiOH and HNO₃ are an example strong base and acid respectively.

Read more:

https://brainly.com/question/2254059

Two samples of the same rainwater are tested using two indicators at an environrnental lab. The first indicator, Methyl Orange, reveals a distinct yellow color when added to the sample. The second indicator, Litmus, turns red when placed in contact with the water sample.

Required:
a. Identify a possible pH value for the rainwater.
b. Explain, in terms of hydronium ions and hydroxide ion concentrations, the pH value of the rainwater.

Answers

Answer:

A. The pH value of rainwater is acidic about 4.4

B. The molar concentrations of the Hydronium ions are more than that of the hydroxide ions. That is why the rainwater is acidic with a pH of less than 7

Explanation:

A. Methyl orange is an acid indicator that is used to detect acidic solutions which have pH values that fall within the range of about 4.4 to 7.  The distinct yellow colour change that was shown by the methyl orange as it was added to the water shows that the pH value is acidic, with a value above 4.4. (it has to be like this before methyl orange changes to  yellow colour)

B. The Hydronium ( H30+) ion concentrations and the hydroxide (OH-) ion concentrations are used to measure the pH values of substances.

We can tell that the Hydronium ( H30+) ion concentrations are more than the hydroxide (OH-) ion concentrations in the sample of rainwater tested. This can be detected from the colour change that both the methyl orange and the litmus paper gave. The indicators showed that the rainwater solution was indeed acidic. Hence, the pH value will be less than 7, but greater than 4.4.

Dry chemical hand warmers utilize the oxidation of iron to form iron oxide according to the following reaction: 4Fe(s)+3O2(g)→2Fe2O3(s) Standard thermodynamic quantities for selected substances at 25 ∘C Reactant or product ΔH∘f(kJ/mol) Fe(s) 0.0 O2(g) 0.0 Fe2O3(s) −824.2 Calculate ΔH∘rxn for this reaction.

Answers

Answer:

-1648.4 kJ/mol

Explanation:

Based on Hess's law:

ΔHr = ∑n×ΔH°f(products) - ∑n×ΔH°f(reactants)

In the reaction:

4Fe(s) + 3O₂(g) → 2Fe₂O₃(s)

ΔHr = 2 ΔH°f {Fe₂O₃} - (4ΔH°f {Fe(s)} + 3ΔH°f{O₂(g)}

As:

ΔH°f {Fe₂O₃} = -824.2kJ/mol

ΔH°f {Fe(s)} = 0.0kJ/mol

ΔH°f{O₂(g)} = 0.0kJ/mol.

Thus,

ΔHr = 2 ₓ -824.2kJ/mol =

-1648.4 kJ/mol

Answer:

-1648.4 kJ

Explanation:

The product has the only nonzero heat of formation, so it is the only value needed to calculate the enthalpy of this reaction. Normally, you would want to express the enthalpy of a reaction with respect to one mole of a chemical species, whether it is a reactant or product. However, since the balanced chemical equation contains only coefficients greater than 1, you should consider how the enthalpy relates to one mole of each substance according to the coefficients. In other words,  − 1648.4  kJ  of heat is released when 4  mol  of  Fe  reacts with 3  mol  of  O2  to produce 2  mol  of  Fe2O3 .

Which compound would you expect to be least soluble in water? Explain.
a. CCl4
b. CH3Cl
c. NH3
d. KF

Answers

Answer:  a.CCl4 aka carbon tetrachloride

Explanation:

ionic compounds and polar molecules can be dissolved in water which is a polar solvent.

choice d (KF) is a salt (an ionic compound) and can be dissolved in water /(K+ and F- ions would be formed in water).

choice c (NH3 or ammonia) is a very polar molecule and thus can be dissolved in water(Hydrogen bonding).

choice b (CH3Cl) is slightly polar because the atoms surrounding the central carbon atom are different(3 H atoms and 1 chlorine atom) and can be dissolved in water(Dipole-dipole interaction).

choice a is nonpolar and cannot be dissolved in water.

what type of bonds do compounds formed from non metal consist of?​

Answers

Compounds formed from non-metals consist of molecules. The atoms in a molecule are joined together by covalent bonds. These bonds form when atoms share pairs of electrons.

The boiling point of ethanol is 78.40°C. A student conducts an
experiment and finds a boiling point of 75.70°C. How far off
from the accepted value was the student's result?
Error = °C

Answers

Answer:

2.7 °C

Explanation:

78.4-75.7=2.7

The student's result is 2.7° C less than the expected result.

We have a student conducting an experiment to find the boiling point of ethanol.

We have to determine how far off from the accepted value is the student's result.

What is Measurement error ?

Measurement Error (also called Observational Error) is the difference between a measured quantity and its true value.

According to the question, we have -

True value of the boiling point of ethanol [T] = 78.40°C.

Measured value of the boiling point of ethanol [M] = 75.70°C.

The Error (E) in the measurement will be -

E = T - M

E = 78.40° - 75.70° = 2.7° C

Hence, the student's result is 2.7° C less than the expected result.

To solve more questions on Errors in measurements, visit the link below-

https://brainly.com/question/16199575

#SPJ2

A 25.0 mL solution of quinine was titrated with 1.00 M hydrochloric acid, HCl. It was found that the solution contained 0.125 moles of quinine. What was the pH of the solution after 50.00 mL of the HCl solution were added

Answers

Answer:

pH = 9.08

Explanation:

Quinine, C₂₀H₂₄O₂N₂, Q, is a weak base that, in water, has as equilibrium:

Q + H₂O ⇄ QH⁺ + OH⁻

Where pKb is 5.10

Using H-H equation for weak bases:

pOH = pKb + log₁₀ [QH⁺] / [Q]

The reaction of quinine with HCl is:

Q + HCl → QH⁺ + Cl⁻

Initial moles of quinine are 0.125 moles and moles added of HCl are:

0.05000L × (1.00mol / L) = 0.05000moles.

That means after the addition of 50.00mL of the HCl solution, moles of Q and QH⁺ are:

Q = 0.125mol - 0.050mol = 0.075 moles

QH⁺ = 0.050 moles

Replacing in H-H equation:

pOH = 5.10 + log₁₀ [0.050] / [0.075]

pOH = 4.92

As pH = 14 - pOJ

pH = 9.08

Compare the conjugate bases of these three acids. Acid 1: hypochlorous acid , HClO Acid 2: phosphoric acid , H3PO4 Acid 3: hydrogen sulfide , HS- What is the formula for the weakest conjugate base ?

Answers

Answer:

The weakest conjugate is HClO-.

Explanation:

As a general rule, the stronger the Bronsted-Lowry acid, the weaker its conjugate base, and vice versa.  

Acid 1: HClO is a strong acid, hence its conjugate base would be weak

Acid 2: H3PO4 is a weak acid, hence its conjugate base would be strong

Acid 3: hydrogen sulphide is also a moderately weak acid with a moderately strong conjugate base.

In order of increasing strengths:

HClO < H2S < H3PO4

If the Moon rises at 7 P.M. on a particular day, then approximately what time will it rise six days later?

Answers

Answer:

below

Explanation:

28th 10;24 am

If the Moon rises at 7 P.M. on a particular day, then approximately what time will it rise six days later at 12A.M.

How much time changes between Moon rises from one day to the next?

This movement is from the Moon's orbit, which takes 27 days, 7 hours and 43 minutes to go full circle. It causes the Moon to move 12–13 degrees east every day. This shift means Earth has to rotate a little longer to bring the Moon into view, which is why moonrise is about 50 minutes later each day.

So knowing that moonrise is about 50 minutes later each day, we have:

[tex]7+50 minutes = 7:50\\8:40\\9:30\\10:20\\11:10\\12:00 A.M[/tex]

See more about moon at brainly.com/question/13538936

#SPJ2

Hot coffee in a mug cools over time and the mug warms up. Which describes the energy in this system? The average kinetic energy of the particles in the mug decreases. The average kinetic energy of the particles in the coffee increases. Thermal energy from the mug is transferred to the coffee. Thermal energy from the coffee is transferred to the mug.

Answers

Answer:

d

Explanation:

Answer:

D

Explanation:

Edge 2021

One of the radioactive isotopes used in chemical and medical research is sulfur-35, which has a half-life of 87 days. How long would it take for 0.25 g to remain of a 1.00 g sample of sulfur-35

Answers

Answer:

Time taken = 174 days

Explanation:

Half life is the time take for a subsrtance taken to decay to half of it's origial or initial concentration.

In this probel, the haf life is 87 days, this means that after evry 87 days, the concentration or mass of sulfur-35 decreases by half.

If the starting mass is 1.00g, then we have;

1.00g --> 0.5g (First Half life)

0.5g --> 0.25g (Second half life)

This means that sulphur-335 would undergo two half lives for 0.25g to remain.

Total time taken = Number of half lives  * Half life

Time taken = 2 * 87

Time taken = 174 days


Which best explains how heat plays a role in the movement of materials within Earth's interior?

Answers

Answer:

Hot material near the core is less dense and rises, when it cools, it becomes more dense and sinks.

Explanation:

This best explains how heat plays a role in the movement of materials within Earth's interior because it's how convection works. Convection is the circular motion that happens when warmer air or liquid which has faster moving molecules, making it less dense rises, while the cooler air or liquid drops down. Convection currents within the earth move layers of magma, and convection in the ocean creates currents.

Earth’s interior is like a closed chamber, hot material near Earth's surface is more denser and sinks, and when it cools, it becomes less dense and Rises.

What is Convection?

Convection is the process of heat transfer by the bulk movement of molecules within fluids such as gases and liquids. The heat transfer take place from solid to no solid material. like air and water.

As we take example of home. In home heat take nearer the roof and cold air will be nearer to the flour. It is because of hot is less denser then the cold air. Hot air will become less denser and move towords upside. Cold air become denser move towards down.

Similarly, on earth. Nearer to earth hot materials are more dense and sinks. When it cools, it become less dense and rises.

To find more about Heat flow, refer the link below:

brainly.com/question/15394654

#SPJ2

What must happen for an ionic bond to be created between two elements?

Answers

Answer:

they must be heated

Explanation:

Round off the following measurement to three significant digits: 29.950g

Answers

Answer:

30.0 g.

Explanation:

Hello,

In this case, for us to round the given number off to three significant figures, we firstly realize it has initially five significant figures. Thus, cutting at the third digit, which is the second nine, we will have 29.9 g, nonetheless, as a five is after such nine, we should round the nine to ten, so the result is 30.0 g.

Best regards.

Arrange the measurements from least to greatest

Answers

Answer: 1.8 micrograms, 1.8 milligrams, 1.8 grams, 1.8 kilograms

Explanation:

2 FONS
How does the electric force between two charged particles change if the
distance between them is increased by a factor of 22
A. It increases by a factor of 4.
B. It increases by a factor of 2.
C. It decreases by a factor of 4
O
D. It decreases by a factor of 2.
SUB

Answers

Answer:

C. It decreases by a factor of 4

Explanation:

F1 = kq1*q2/r²

F2 = kq1*q2/(2r)² = kq1*q2/(4r²) = kq1*q2/(r²*4)  = F1/4

WILL GIVE BRAINLIEST!!!!! will give brainliest!!!! ******According to the reaction in question I above, how many grams of solid copper will theoretically be

produced when 14.4 g of aluminum are reacted with 14.4 g of copper (II) sulfate? Which reactant is the

limiting reactant? Show your work. Be sure to include units!

Answers

Answer:

5.73 g Cu

Explanation:

M(CuSO4) = 159.6 g/mol

M(Al) = 27.0 g/mol

M(Cu) = 63.5 g/mol

14.4 g Al * 1 mol/27.0 g = 0.5333 mol Al

14.4 g CuSO4 * 1 mol/159.6 g = 0.0902 mol CuSO4

                                2 Al         +     3CuSO4 ------->  3Cu + Al2(SO4)3

from reaction           2 mol               3 mol

given                     (0.5333 mol )x       0.0902 mol

needed                   0.0601 mol

x= 2*0.0902/3 = 0.0601 mol   Al

Al is excess, CuSO4 is a limiting reactant.

                               2 Al         +     3CuSO4 ------->  3Cu + Al2(SO4)3

from reaction                               3 mol                  3 mol

given                                            0.0902 mol         x mol

x = 0.0902 mol Cu

0.0902 mol Cu * 1 mol/63.5 g Cu = 5.73 g Cu

Propane (C3H8) is widely used in liquid form as a fuel for barbecue grills and camp stoves. For 67.7 g of propane, determine the following.(a) Calculate the moles of compound.mol(b) Calculate the grams of carbon.g

Answers

Answer:

A. 1.54 mole.

B. 55.39g of carbon

Explanation:

A. Determination of the number of mole in 67.7g of C3H8.

Mass of C3H8 = 67.7g

Molar mass of C3H8 = (3x12) + (8x1) = 44g/mol

Number of mole of C3H8 =..?

Number of mole = Mass/Molar Mass

Number of mole of C3H8 = 67.7/44

Number of mole of C3H8 = 1.54 mole

B. Determination of the mass of carbon in the compound.

This is illustrated below:

The mass of C in compound can be obtained as follow:

=> 3C/C3H8 x 67. 7

=> 3x12 / 44 x 67.7

=> 36/44 x 67.7

=> 55.39g

Therefore, 55.39g of carbon is present in the compound.

Suppose that a wave has a period of 0.03 seconds what is its frequency be sure to show the steps for your work

Answers

Answer:

f = 33.34 Hz

Explanation:

A wave has a period of 0.03 seconds. It is required to find the frequency of a wave. The relation between time period and frequency is inverse. The time period of a wave is given by :

T = 1/f, f = frequency of wave

[tex]f=\dfrac{1}{T}\\\\f=\dfrac{1}{0.03}\\\\f=33.34\ Hz[/tex]

So, the frequency of the wave is 33.34 Hz.

At 25.0 °C the Henry's Law constant for sulfur hexafluoride (SP) gas in water is 2.4x 10 M/atm Calculate the mass in grams of SFo, gas that can be dissolved in S25. ml. of water at 25.0 C and a SF, partial pressure of 1.90 atm Be sure your answer has the correct number of significant digits.

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

The mass is [tex]m = 0.0349 \ g[/tex]

Explanation:

From the question we are told that

   The Henry's Law constant is  [tex]k = 2.4 *10^{10} M/atm[/tex]

   The volume of water is [tex]V = 525 \ ml = 0.525 \ L[/tex]

   The partial pressure is  [tex]P = 1.90 \ atm[/tex]

   The temperature is [tex]T = 25 ^oC[/tex]

Henry's  law is mathematically represented as

       [tex]C = P * k[/tex]

Where C is  the concentration of sulfur hexafluoride(SP)

substituting value

        [tex]C = 1.90 * 2.4*10^{-4}[/tex]

        [tex]C = 4.56*10^{-4} \ M[/tex]

The number of moles of  SP is mathematically represented as

        [tex]n = C * V[/tex]

substituting value

       [tex]n = 0.525 * 4.56*10^{-4}[/tex]

       [tex]n = 2.39 *10^{-4} \ moles[/tex]

The mass of SP that dissolved is

          [tex]m = n * Z[/tex]

Where Z is the molar mass of SP which has a constant value of

           [tex]Z = 146 g/mole[/tex]

So

         [tex]m = 2.394*10^{-4} * 146[/tex]

         [tex]m = 0.0349 \ g[/tex]

What mass of carbon dioxide is produced from the complete combustion of 7.30×10−3 g of methane?

Answers

We know that the reaction goes to completion, so all the methane will be reacted. To find the mass of carbon dioxide used, we can use the number of moles from the above equation, and the molecular weight of CO2 (= 44.009 g/mol). The mass of CO2 produced is 3.29*10^-3g.

If a solution containing 23.81 g of lead(II) acetate is allowed to react completely with a solution containing 7.410 g of sodium sulfate, how many grams of solid precipitate will be formed g

Answers

Answer:

The correct answer is 15.80 grams.

Explanation:

The reaction taking place in the given question,  

Pb(CH₃COO)₂ + Na₂SO₄ ⇒ PbSO₄ + 2NaCH₃COO

The number of moles can be calculated by using the formula,  

n = weight / molecular mass

Based on the given question, the weight of lead (II) acetate is 23.81 grams and the weight of sodium sulfate is 7.410 grams.  

The number of moles of Pb(CH₃COO)₂ is,  

n = 23.81 g / 325.29 g/mol = 0.0732 moles

The number of moles of Na₂SO₄ is,  

n = 7.410 g / 142.04 g/mol = 0.0521 moles

As one mole of lead (II) acetate needs one mole of sodium sulfate. Therefore, 0.0732 moles of lead (II) acetate needs 0.0732 moles of sodium sulfate.  

However, as sodium sulfate is less, that is, 0.0521, therefore, Na₂SO₄ is a limiting reactant.  

One mole of sodium sulfate produces one mole of PbSO₄. So, 0.0521 moles of Na₂SO₄ produces 0.0521 moles of PbSO₄.  

Now the mass of PbSO₄ is,  

mass = moles × molecular mass

mass = 0.0521 × 303.26 g/mol

mass = 15.80 grams.  

The solubility of N2 in water at a particular temperature and at a N2 pressure of 1 atm is 6.8 × 10–4 mol L–1. Calculate the concentration of dissolved N2 in water under normal atmospheric conditions where the partial pressure of N2 is 0.78 atm.

Answers

Answer:

The correct answer is 5.30 * 10^-4 mol per L.

Explanation:

Based on Henry's law, in a solution solubility of the gas is directly proportional to the pressure, that is, C is directly proportional to P. Here P is the pressure and C is the concentration of the dissolved gases.  

Therefore, it can be written as,  

C2/C1 = P2/P1

Here, C1 is 6.8 * 10^-4 mol/L, P1 is 1 atm and P2 is 0.78 atm, then the value of C2 obtained by putting the values in the equation,  

C2/(6.8*10^-4) = 0.78/1

C2 = 0.78 * 6.8*10^-4

C2 = 5.30 * 10^-4 mol per L.  

Hence, the concentration of dissolved nitrogen at 0.78 atm is 5.30*10^-4 mol/L.  

Glycine, C2H5O2N, is important for biological energy. The combustion reaction of glycine is given by the equation 4C2H5O2N(s) + 9O2(g) → 8CO2(g) + 10H2O(l) + 2N2(g) ΔH°rxn = –3857 kJ/mol Given that ΔH°f[CO2(g)] = –393.5 kJ/mol and ΔH°f[H2O(l)] = –285.8 kJ/mol, calculate the enthalpy of formation of glycine.

Answers

Answer:

ΔH°f C₂H₅O₂N(s)  = -537.2kJ

Explanation:

Based on the reaction:

4 C₂H₅O₂N(s) + 9O₂(g) → 8CO₂(g) + 10H₂O(l) + 2N₂(g)

ΔHrxn = ΔH°f products - ΔH°f reactants.

As:

ΔH°fO₂(g) = 0

ΔH°fCO₂(g) = -393.5kJ/mol

ΔH°fH₂O(l) = -285.8kJ/mol

ΔH°fN₂(g) = 0

The ΔHrxn is:

ΔHrxn = (8×-393.5kJ/mol + 10×-285.8kJ/mol) - (4×ΔH°fC₂H₅O₂N(s)) = -3857kJ/mol

-6006kJ/mol - (4×ΔH°fC₂H₅O₂N(s)) = -3857kJ/mol

-4×ΔH°fC₂H₅O₂N(s) = 2149kJ/mol

ΔH°fC₂H₅O₂N(s) = 2149kJ/mol / -4

ΔH°f C₂H₅O₂N(s)  = -537.2kJ
Other Questions
Can anyone explain to me what I did wrong here? Thanks! Kansas Enterprises purchased equipment for $76,000 on January 1, 2021. The equipment is expected to have a ten-year service life, with a residual value of $7,200 at the end of ten years. Using the straight-line method, depreciation expense for 2021 would be: there are between 24 and 40 students in a class the ratio of boys to girls is 4:7 how many students are there in class "There is within me (and with sadness I have watched it in others) a knot of cruelty borne by a stream of love, much as our blood sometimes bears the seed of our destruction, and at times I was mean to Doodle". What is the narrator trying to convey by putting "and with sadness I have watched it in others" in parenthesis?A.The narrator is admitting that he can recognize "cruelty" because he was "mean" himselfB. The narrator is erasing some of his own guilt by stating that others possess "cruelty" tooC. The narrator is indicating that he feels victimized by "cruelty." D.The narrator is hoping that no one will remember his "cruelty" toward Doodle Requirements 1. Record each transaction in the journal using the following account titles: Cash; Accounts Receivable; Office Supplies; Prepaid Insurance; Land; Furniture; Accounts Payable; Utilities Payable; Unearned Revenue; Common Stock; Dividends; Service Revenue; Salaries Expense; Rent Expense; and Utilities Expense. Explanations are not required. 2. T-accounts have been opened for each of the accounts. Post the journal entries to the T-accounts, using transaction dates as ledger accounts. Label the balance of each account Bal posting references in the ledger accounts.3. Prepare the trial balance of Beth Stewart, Designer, as of November 30, 2018.Nov.1 Received $41,000 cash and issued common stock to Stewart Nov. 1 4 Purchased office supplies, $1,200, and furniture, $2,300, on account. 6 Performed services for a law firm and received $2,100 cash. 7 Paid $27,000 cash to acquire land to be used in operations. 10 Performed services for a hotel and received its promise to pay the $800 within one week. 14 November 4 on account Paid for the furniture purchased 14 on. 15 Paid assistant's semimonthly salary, $1,470. 17 Received cash on account, $500. 20 Prepared a design for a school on account, $680. 25 Received $1,900 cash for design services to be performed in December. 28 Received $3,100 cash for consulting with Plummer & Gordon. 29 Paid $840 cash for a 12-month insurance policy starting on December 1. 30 Paid assistant's semimonthly salary, $1,470. 30 Paid monthly rent expense, $650. 30 Received a bill for utilities, $650. The bill will be paid next month 30 Paid cash dividends of $2,800. Post the journal entries to the T-accounts, using transaction dates as posting references in the ledger accounts. Label the balance of each account Bal.We will post to the accounts one transaction at a time. Begin by posting the events from the 1st.July1: Yangcontributed $64,000 cash to the business in exchange for Common Stock.Date Accounts Debit CreditJul.1 Cash 68,000 Commom Stock 68,000 calculate the volume of marble if its diameter is 10mm In terms of what it shows about America, being American, and America's core values, with which work did you identify the most? Why? Cite specific examples from the texts and your personal feelings or experiences to illustrate the points in your response. (That is, which work contained characters, events, or themes that you recognized and understood because of your own experiences as an American? Why do you think this work spoke to you as it did?) Find x in the following right triangle. In which areas do you think peoples rights and liberties are at risk of government intrusion? some help plz??? what is the simplified form??? (-2)(-6x)(7) Match the following.binary fissioncolonymultiple fissionasexual reproduction in which a single cell divides into two1. with no exchange of genetic material, reproduction methodof bacteriaasexual reproduction involving the growth of a new individualfrom part of an older organism, uneven distribution of2.cytoplasm that results in one cell receiving most of the cellcontentsa group of organisms attached to one another after3.undergoing asexual reproduction from a common parentthe part of the cell division that causes the separation of the4.cytoplasma phenomenon in which organisms break into two or more5.parts and then each part grows into a new individualthe process involving the division of the nucleus of a body6.cellasexual reproduction in which a single cell undergoes many7 mitotic divisions in the nucleus and a number of daughtercells are produced all at oncebuddingcytokinesismitosisfragmentation New lithographic equipment, acquired at a cost of $800,000 at the beginning of a fiscal year, has an estimated useful life of five years and an estimated residual value of $90,000. The manager requested information regarding the effect of alternative methods on the amount of depreciation expense each year. On the basis of the data presented to the manager, the double-declining-balance method was selected. In the first week of the fifth year, the equipment was sold for $135,000. Required: 1. Determine the annual depreciation expense for each of the estimated five years of use, the accumulated depreciation at the end of each year, and the book value of the equipment at the end of each year by the following methods: a. Straight-line method Year Depreciation Expense Accumulated Depreciation, End of Year Book Value, End of Year 1 $ $ $ 2 $ $ $ 3 $ $ $ 4 $ $ $ 5 $ $ $ b. Double-declining-balance method Year Depreciation Expense Accumulated Depreciation, End of Year Book Value, End of Year 1 $ $ $ 2 $ $ $ 3 $ $ $ 4 $ $ $ 5 $ $ $ Hide 2. Journalize the entry to record the sale, assuming double-declining balance method is used. If an amount box does not require an entry, leave it blank. 3. Journalize the entry to record the sale, assuming that the equipment was sold for $88,750 instead of $135,000. If an amount box does not require an entry, leave it blank. Would somebody help with this? Which American Indian groups formed an alliance with the French as the French and Indian War began? Which of the following is a correct interpretation of the expression -4 + 134+13minus, 4, plus, 13? What would be Athena point of view in the Arachne story Which equation can be used to solve for x in the following diagram? Michael and his dog raced down the ________________to escape the fire. a. designated c. wreckage b. firepole d. stairwell Which expression is equivalent to log Subscript 8 Baseline 4 a (StartFraction b minus 4 Over c Superscript 4 Baseline EndFraction)? Joan draws a bar chart to show the temperatures at middayon March 1st in five cities.Joan has made four mistakesin her diagram