a bicycle rider pedals towards a hill at a speed of 7.5w/s. the combined mass of the bicycle and the rider is 75.0kg the cycle and rider roll up a hill without peddling . at what height will the cycle cone to rest (use g=10N/1g)

Answer:

The absorption lines will shift to the red (become longer).

This is because of the extra distance that a wavelength λ must travel between the vibrations of the source producing the spectrum.

Note that the Doppler effect of the source is slightly different for light waves than it is for sound waves because sound waves require a medium in which to travel while light waves do not require such a medium (example air).

Last one!

Perpendicular to the wave's energy

Hope this helps!

Answer:

a?

Explanation:yes it is a

Answer:

[tex]\frac{\pi }{15}[/tex]m

Explanation:

At 10am, the minute hand and hour hand are ' 2 hours apart', since the minute hand is at 12pm and hour hand is at 10am.

Angle between the two hands = 2/12 * 360

= 60°

Arc Length = [tex]2\pi r(\frac{60}{360} )[/tex]

= [tex]2\pi (0.2)(\frac{1}{6} )\\= \frac{\pi }{15} m[/tex]

Answer:

Average acceleration = 12m/s^2

Explanation:

Acceleration is equal to the change in velocity over the change in time:

[tex]a=\frac{\Delta v}{\Delta t}[/tex]

Change in velocity is the final velocity minus the initial.

We are told the car goes from 0 to 26.8 m/s making 26.8 our final and 1 our initial. Therefore the change in velocity is 26.8-0 = 26.8m/s. ([tex]\Delta v[/tex])

And that this happens over 2.2s so this is our change in time: [tex]\Delta t[/tex]

Therefore our acceleration is: [tex]a = \frac{26.8}{2.2}[/tex]

Acceleration = 12.18 m/s^2

Rounded to 2 significant figures (2s.g. in 2.2s), the answer is 12m/s^2.

Hope this helped!

The difference in time between the sound waves being detected at the other end of the plank and the sound being heard through the air will be 0.09 sec.

A sound wave is produced when a medium begins to vibrate. When an entity vibrates, a pressure wave is formed, which causes sound.

Given data;

The speed of sound in wood,u= 3300 m/s

The speed of sound in air,v=330 m/sec

long plank of wood, L=33 m

The time period in the air was found as;

T₁ = 33 m / 330 m/sec

T₁= 0.1 sec

The time period in wood ;

T₂= 33 m / 3300 m/sec

T₂=0.01 sec

T = T₁ - T₂

T=0.1-0.01

T=0.09 sec

Hence, the difference in time between the sound waves being detected at the other end of the plank and the sound being heard through the air will be 0.09 sec.

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Answer:

Resultant horizontal force = 143 N

Explanation:

Since the a gle is 30° northwest, then it means the resultant force will be horizontal and as such;

Resultant horizontal force = 165 * cos 30

Resultant horizontal force = 142.89

Approximating to a whole number gives;

Resultant horizontal force = 143 N

The component form of the vector - u + w is determined as  -2i + 3j.

The component vector V is calculated from the summation of vector U and vector W.

v = -u + w

Given;

v = -(2i - j) + i + 2j

v = -2i + j + 2j

v = -2i + 3j

                                     y - axis        

                                        ↑  

                                        ↑  

                                        ↑ 3j

                                        ↑

x - axis  ←    ←    ←    ←    ←

                      2i

The complete question is below:

if u = 2i - j  and w = i + 2j, find the component form of ~v = -u + w~ and sketch the specified vector operations geometrically.

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Answer:

750

Explanation:

The kinetic formula is 1 over 2 *mass * velocity Square

Answer:

1.76 seconds/cycle

Explanation:

Frequency is   10 cycles / 17.6 seconds

PERIOD is  1/frequency = 17.6 seconds/10 cycles = 1.76 s/c    

          cycle is a vibration , so the unit may be  1.76 second / vibration

The motion of the inferior angle of the scapula in the superior and lateral direction is called upward rotation.

The scapula or the shoulder blade has about six different types of motion it undergoes.

The six ways of movement of the scapula are:

When the inferior angle of the scapula moves in the superior and lateral direction, the motion is called upward rotation.

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Answer:

40kg

Explanation:

w=m×

w=400n

g=10

m=?

400/10=m×10/10

m=40

Answer:

It can be either a moon or a satellite

Explanation:

a moon is a piece of space debris that orbits a planetdue to the planets gravitational force. Inherently, satellite mimics a moon but it is used for collecting data and etc

When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.

Newton's law of universal gravitation states that the force of attraction between two masses in the universe is directly proportional to the product of the masses and inversely proportional to the the square of the distance between them.

The mathematical interpretation of the above law is

Removing the proportionality sign,

Where:

From the above, When you attract every object in the universe with a force that is proportional to the mass of the objects and to the distance between them, we are obeying Newton's law of universal gravitation.

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The correct statement  for reversible reactions that reach dynamic equilibrium is option C "the rates of the forward reaction is equal to the rate of backward reactions at equilibrium."

The dynamic equilibrium is defined as a state of a particular system wherein the reversible reaction takes place and ceases modifying the ratio of reactants as well as products.

The chemical reaction is a method for creating novel chemicals with unique features.

The correct statement  for reversible reactions that reach dynamic equilibrium is option C "the rates of the forward reaction is equal to the rate of backward reactions at equilibrium."

Therefore, the correct answer will be an option (C).

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Answer:

[tex]2.5m/s^{2}[/tex]

Explanation:

Since the distance ,s = 500m

Initial velocity, u = 0m/s

Final velocity, v = 50m/s

We can one of the kinematics equations to find the acceleration.

[tex]v^{2} =u^{2} +2as\\50^{2} =0^{2} + 2a(500)\\2500 = 0 + 1000a\\1000a = 2500\\a = \frac{2500}{1000} \\= 2.5m/s^{2}[/tex]

Answer:

S=D÷T

Explanation:

50=0.5÷T

T= 100

Answer:

your answer would 50 m/s I do believe

The correct answer for the speed of the ball upon resting to it's starting point is [tex]50[/tex] m/s.

Given:

Initial speed: [tex]u = 50[/tex] m/s

To calculate the speed upon resting position, Calculate the time requires to reach starting position:

Time required to reach starting point  = 2 * (Time require to reach the maximum height)

Time required to reach the maximum height:

[tex]v = u+(-a )t[/tex]

Final velocity([tex]v[/tex]) is  [tex]0[/tex] m/s.

Negative sign indicates negative acceleration:

[tex]t= \dfrac{50}{9.8}\\\\ = 5.10[/tex]seconds

Time for start point  = [tex]2 * 5.8[/tex]

[tex]=10.6[/tex] seconds

From equation of motion:

[tex]v= u+at[/tex]

[tex]= 50 -9.8* 10.2[/tex]

[tex]= -50.2[/tex] m/s

Negative sign indicates downward direction.

Speed when ball return is  is [tex]50[/tex] m/s.

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The force of the string at the bottom is greater than the weight of the ball. The correct option is B.

When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.

A girl at a state fair swings a ball in a vertical circle at the end of a string.

When the ball is at the bottom, the force acting will be

The tension in the string , T = mass x centripetal acceleration + Force of gravity

So, T = m x ac + mg

The tension in the cable at the bottom will have centripetal force and weight forces acting on it.

Thus, the force of the string at the bottom is greater than the weight of the ball.

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According to the research, the agonic line is the line joining all places of zero variation.

It is a term that refers to the zero declination isogon, that is, it joins the points that do not have magnetic declination.

This line crosses the magnetic and geographic poles of the Earth's surface from which they are aligned and along which there is no magnetic variation.

Therefore, we can conclude that according to the research, the agonic line is the line joining all places of zero variation.

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The distance of the cliff from where you are is determined as 3,430 m.

Apply the formula for echo.

v = 2d/t

where;

2d = vt

d = vt/2

d = (343 x 20)/2

d = 3430 m

Thus, the distance of the cliff from where you are is determined as 3,430 m.

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Squeezing the clutch lever to slow down is best to be done when approaching a curve and is denoted as option C.

This is a mechanical device which used in the engagement and disengagement of transmission system in a vehicle.

Slowing down will give the driver more time to maneuver the curves so as to prevent accident. This is why it is imperative to squeeze the clutch in such road condition.

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Answer:

its Q

Explanation:

Use the table to explain how the masses of Objects 1 and 2 relate to the gravitational force between them the power of the gravitational pressure among gadgets relies upon on factors, mass and distance. the pressure of gravity the loads exert on every other.

Gravitational pressure -an appealing pressure that exists among all items with mass; an item with mass draws every other item with mass; the value of the pressure is immediately proportional to the loads of the 2 items and inversely proportional to the rectangular of the gap among the 2 items.

Since the gravitational pressure is immediately proportional to the mass of each interacting items, greater large items will entice every different with a more gravitational pressure. So because the mass of both item increases, the pressure of gravitational appeal among them additionally increases.

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The moon's orbital plane is different from that of the earth's orbit around the sun due to which lunar and solar eclipses do not occur every month.

When the moon passes in front of Earth and the sun, it creates a solar eclipse and casts a shadow across the globe.

Only during the new moon phase, when the moon travels squarely between the sun and Earth and casts shadows on its surface, can a solar eclipse occur.

Due to the moon's orbit being five degrees off-center from Earth's orbit around the Sun, lunar eclipses do not happen every month and the Moon often passes above or below the shadow.

Lunar eclipses would happen every month if there were no tilt. Eclipses of the sun and the moon happen equally often.

Hence lunar and solar eclipses aren't coming every month.

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The reason why lunar and solar eclipses do not occur every month is because; the plane of orbit of the moon around the earth is not same as that of earth around the sun.

When the Moon passes between Earth and the Sun, there's solar eclipse while when the earth passes between the Sun and the Moon, casting a shadow on the Moon, there's lunar eclipse.

Hence, because the plane of orbit of the moon around the earth is not same as that of earth around the sun, we do not have lunar and solar eclipses every month.

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Answer:

6/5  * R

Explanation:

The 3 in series sum to 3R for one branch of the parallel circuit

 the 2 in series sum to 2R  for the other side of the parallel circuit

now find the equivalent R of the parallel circuit with 3R and 2R

 here is one way

   Requiv = 1 / ( 1/(3R) + 1/(2R) ) =

                  1/ ( 5/(6R) ) =

                    6R/5  

the equiv resistance = 6/5  * R

a) 4.9 m

b) 38.3 m/s

c) 33.4 m

The three equations are,

v = u + at

v² = u² + 2as

s = ut + ½at²

According to the question,

Let hold the y-axis in the direction of gravity.

Initial velocity 0 = 0 /,

Initial height ℎ0 = 0 , and finish height ℎ = 75.0

gravitational acceleration = 9.8 /²

a) Determine the distance traveled during the first second.

By third equation of motion

[tex]S_{0} = v_{0} t +\frac{1}{2} gt^{2}[/tex]  where [tex]v_{0}[/tex] =0

then [tex]S_{0} = \frac{gt^{2}}{2} = \frac{9.8*1^{2} }{2} = 4.9 m[/tex]

b) Determine the final velocity at which the object hits the ground

let – velocity of object, when it falling to the ground

– moment falling to the ground, and obtain from condition:

ℎ = ℎ() = 75.0

[tex]v_{f} = v_{0} +gt = gt[/tex]

[tex]h (t_{f} ) = \frac{gt^{2} }{2} = 75.0 m\\t_{f} =\sqrt{\frac{2h_{f} }{g} } \\v_{f}= gt = g \sqrt{\frac{2h_{f} }{g} } =\sqrt{2hg_{f} }= =\sqrt{2*9.8*75.0} = 38.3 m/s[/tex]

c) Determine the distance traveled during the last second of motion before hitting the ground.

From the above equation we get,

[tex]\sqrt{2*75*9.8*1} - \frac{9.8*1^{2} }{2} = 38.3 -4.9 = 33.4 m[/tex]

Therefore,

a) 4.9 m is the distance traveled during the first second.

b) 38.3 m/s is the final velocity at which the object hits the ground

c) 33.4 is the distance traveled during the last second of motion before hitting the ground.

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The Oort cloud extends to the gravitational limits of the solar system would comets come from.

It is a hypothetical idea of a cloud of mostly frozen planetesimals that would orbit the Sun at distances between 2,000 and 200,000 AU.

The Oort cloud reaches the solar system's outer gravitational boundaries, where comets originate.

Hence cloud extending to the gravitational limits of the solar system will be oorto cloud.

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Answer:

The value of mass 1, m1= 6/5m

The value of mass 2, m2= 3/5m

Explanation:

case 1:

here tension and the acceleration will be:

for m1;

for m2:

adding the both equations,

2mg - 2T + 2T-mg = 2ma + ma/2

a = 2/5 g

putting the value of a into the equation 1.

mg - T = m* (2/5)g

T = 3/5 ( mg )

now

case 2:

The two identical blocks are released from the rest, the tension remains the same as the case 1.

so,

for m1:

for m2:

adding both equations we get,

2T-m2g + 2m2g - 2T = 0

m2 = m1 / 2

T = m1*g / 2

here we know that

T (case1) = T (case2)

3/5 ( mg ) = m1*g / 2

m1 = 6/5 m

hence

m2 = 3/5 m

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