Answer: 9.81 times 3s= 29.43m/s
so 29.43 m/s times 3= 88.29m
Explanation:
How long does it take for a car to change its velocity from 10 m/s to 25 m/s if the acceleration is 5 m/s^2?
Answer:five times five is twenty five divded by 10 is 2.5 seconds of acceleration
does it take more force to slow something down than to speed it up.
If an object must be slowed quickly, the force applied to it must be greater than that required for gradual slowing. For example, the greater the force applied to a bicycle's brakes, the faster it will slow or stop.
What is force?A force is an influence in physics that can change the motion of an object. A force can cause a mass object to change its velocity, or accelerate.
Intuitively, force can be described as a push or a pull. A force is a vector quantity because it has both magnitude and direction.
Force is defined as the tendency of a body to modify or change its state as a result of an external cause. When applied force, the body can also change shape, size, and direction.
The same force that was used to accelerate something can be used to slow it down. It will stop faster if more force is applied.
Thus, it can be concluded that it take more force to slow something down than to speed it up.
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Mr. Rudman drives his race car for 4 hrs at 150
miles/hr. How far will he travel?
A 0.144-kg baseball is moving toward home plate with a speed of 43 m/s when
it is bunted. The bat exerts an average force of 6,500-N on the ball for 0.00135.
The pitcher throws in the positive x direction. (The Force will act in the -
direction).
10 m/s^2 is an example of which vocabulary word?
Answer:
Acceleration.
Explanation:
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
[tex]Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}[/tex]
[tex]a = \frac{v - u}{t}[/tex]
Where,
a is acceleration measured in [tex]ms^{-2}[/tex]
v and u is final and initial velocity respectively, measured in [tex]ms^{-1}[/tex]
t is time measured in seconds.
The S.I unit for measuring acceleration is meters per seconds square (m/s²).
Hence, 10 m/s^2 is an example of acceleration.
heyy i don't understand this question may u help me pls?
Answer:
What question?
Explanation:
How much pressure is being exerted by blood cells that are applying 375N of force over 25.5m2 of your body’s blood vessels?
PLS HELP MEEE
Answer:
Pressure = 14.71N/m²
Explanation:
Given the following data;
Force = 375N
Area = 25.5m²
To find the pressure;
Pressure = force/area
Pressure = 375/25.5
Pressure = 14.71N/m²
Therefore, the amount of pressure that is being exerted by blood cells is 14.71 Newton per meter square.
A 25 kg object is at rest. Calculate the momentum of the object.
Answer:
there is no momentum
Explanation:
if an object is at rest there is no momentum to build, no speed, no acceleration it does not move unless force is acted upon it.
PLZ Help!! Answer the Question Below:
Answer:
18.78 m/s.
Explanation:
From the question given above, the following data were obtained:
Mass (m) = 50 kg
Initial velocity (u) = 0 m/s
Height (h) of cliff = 18 m
Acceleration due to gravity (g) = 9.8 m/s²
Final velocity (v) =?
The velocity with which the diver reach the water can be obtained as follow:
v² = u² + 2gh
v² = 0² + (2 × 9.8 × 18
v² = 0 + 352.8
v² = 352.8
Take the square root of both side
v = √352.8
v = 18.78 m/s
Thus, the diver will reach the water with a velocity of 18.78 m/s.
- An object in equilibrium has three forces exerted on it. A 33-N force act at 90° from the x-axis and a 44-N force act at 60°. What are the magnitude and direction of the third force
Answer:
The magnitude of third force is 74.4 N and direction of third force is 72.8 degrees South.
Explanation:
Let F1, F2 and F3 are three forces exerted on an object.
[tex]\theta_1=90^{\circ}[/tex]
[tex]\theta_2=60^{\circ}[/tex]
[tex]|F_1|=33 N[/tex]
[tex]|F_2|=44 N[/tex]
We have to find the direction and magnitude of third force i.e F3.
[tex]F_{1x}=33cos(90^{\circ})=0 N[/tex]
[tex]F_{1y}=33sin(90^{\circ})=33 N[/tex]
[tex]F_{2x}=44cos(60^{\circ})=22 N[/tex]
[tex]F_{2y}=44 sin(60^{\circ})=22\sqrt{3}=38.11 N[/tex]
Now,
x-component of resultant
[tex]R_x=F_{1x}+F_{2x}=0+22=22 N[/tex]
y-component of resultant
[tex]R_y=F_{1y}+F_{2y}=33+38.11=71.11 N[/tex]
[tex]|R|=\sqrt{R^2_x+R^2_y}[/tex]
[tex]|R|=\sqrt{(22)^2+(71.11)^2}=74.4 N[/tex]
[tex]\theta=tan^{-1}(\frac{R_y}{R_x})[/tex]
[tex]\theta=tan^{-1}(\frac{71.11}{22})=72.8^{\circ}[/tex] South
Hence, the magnitude of third force is 74.4 N and direction of third force is 72.8 degrees South.
The magnitude and direction of the third force is;
F3 = 74.44 N
θ3 = 72.81° in the south direction
We are given;
F1 = 33 N
F2 = 44 N
θ1 = 90°
θ2 = 60°
Let the third force be F3 which will serve as the resultant
Let's first find the x and y component of the forces.
F1x = F1 cos θ1
F1x = 33 × cos 90
F1x = 0 N
F1y = F1 sin θ1
F1y = 33 × sin 90
F1y = 33 N
F2x = F2 cos θ2
F2x = 44 × cos 60
F2x = 22 N
F2y = F2 sin θ2
F2y = 44 × sin 60
F2y = 38.11 N
Thus, the resultant of the x component is;
F3x = F1x + F2x
F3x = 0 + 22
F3x = 22 N
The resultant of the y component is;
F3y = F1y + F2y
F3y = 33 + 38.11
F3y = 71.11 N
Thus, magnitude of resultant of the F3 force is;
F3 = √((F3x)² + (F3y)²)
F3 = √(22² + 71.11²)
F3 = 74.44 N
The direction of the resultant of F3 is;
θ3 = tan^(-1) F3y/F3x
θ3 = tan^(-1) 71.11/22
θ3 = 72.81° in the south direction
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The energy of a given wave in the electromagnetic spectrum is 2.64 × 10-21 joules, and the value of Planck's constant is 6.6 × 10-34 joule·seconds. What is the value of the frequency of the wave?
Answer:
the answer is b
wjejehebe ehshw es
A ball with a mass of 0.8 kg is thrown straight upward, flies up to its maximum height, and
then falls back down. If the ball reaches a maximum height of 10.7 meters, how fast was the
ball thrown initially? Round your answer to the tenths place.
Answer:
v = 14.5 m/s
Explanation:
The Principle Of Conservation Of Mechanical Energy
In the absence of friction, the total mechanical energy is conserved. That means that
Em=U+K is constant, being U the potential energy and K the kinetic energy
U=mgh
[tex]\displaystyle K=\frac{mv^2}{2}[/tex]
The ball with a mass of m=0.8 kg is thrown straight upward from the zero height reference (h=0) and with some speed (v). The potential energy is zero, but the kinetic speed is given by the equation above.
When the ball reaches its maximum height of h=10.7 m, the speed is zero and all the initial kinetic energy was transformed into potential energy, thus:
[tex]\displaystyle \frac{mv^2}{2}=mgh[/tex]
Simplifying by m:
[tex]\displaystyle \frac{v^2}{2}=gh[/tex]
Solving for v:
[tex]\displaystyle v=\sqrt{2gh}[/tex]
Substituting:
[tex]\displaystyle v=\sqrt{2*9.8*10.7}[/tex]
Calculating:
v = 14.5 m/s
