A charged object is immersed in a 17 N/C E-field. Then the total charge on the object increases by a factor of 22 over 10 s. During this time, the electrostatic force on the object remains constant. Determine the magnitude of the E-field after the total charge has changed.

Answer:

im pretty sure it is B or D

Explanation:

Given,

Position vector, [tex]c(t)=6ti+((3t)^2)j+((t)^3)k[/tex]

We need to find the velocity vector of the given path

[tex]v=\dfrac{d(c(t))}{dt}\\\\v=\dfrac{d(6ti+((3t)^2)j+((t)^3)k)}{dt}\\\\v=\dfrac{d(6ti)}{dt}+\dfrac{d((3t)^2j}{dt}+\dfrac{d(t^3)k}{dt}\\\\v=6i+18tj+3t^2k[/tex]

Hence, this is the velocity vector of the given path.

Answer: action forc roketorce

reaction force is engine fires

Explanation:

Distance = speed × time

d = (27 m/s) (2.0 s)

d = 54 m

Answer: 12.5 km/h

Explanation: 20/1.6 = 12.5 km/h

The average velocity of an individual will be "0.08 km/min". To understand the calculation, check below.

According to the question,

Time, t = 20 minutes

Distance, d = 1.6 km

We know the formula,

→ Distance = Speed × Time,

Or,

Speed, v = [tex]\frac{Distance}{Time}[/tex]

By substituting the values,

               = [tex]\frac{1.6}{20}[/tex]

               = 0.08 km/min

Thus the avg. velocity will be "0.08 km.min" is correct.

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Answer:

57.0 m

Explanation:

Assume the time it takes for the sound to reach the top of the well is negligible.

Given:

v₀ = 0 m/s

a = 9.8 m/s²

t = 3.41 s

Find: Δy

Δy = v₀ t + ½ at²

Δy = (0 m/s) (3.41 s) + ½ (9.8 m/s²) (3.41 s)²

Δy = 57.0 m

Answer:

57 m

Explanation:

Answer:

T²= 4π²R³/GM

Explanation:

First we know that

Fg= Fc

Because centripetal force must equal gravitational force

So

GMm/R² = Mv²/R

But velocity is 2πR/T

So by substitution we have

GMm/R²= M (2πR/T)/T

We have

T²= 4π²R³/GM as period

Answer:

Explanation:

Total number of slices in the pizza = 16

Total number ate by John,

J = 7/12 * 16 = 28/3 = 9.3

Total number ate by Harold,

H = 4/23 * 16 = 2.783

Total number left over

L = 1/23 * 16 = 0.696

Total number ate by Betty

B = ?

All we have to do to get the total number eaten by Betty is to sum up that eaten by Harold and John, including the left over, then subtract it from the total pizza slices.

Betty = Total - (Harold + John + Left Over)

Betty = 16 - (9.3 + 2.783 + 0.696)

Betty = 16 - 12.779

Betty = 3.221

Therefore, Betty ate 3.221 of the total pizza as a whole

Answer:

FALSE

Explanation:

Answer:

False

Explanation:

Answer:

Approximately [tex]9.79\; \rm m \cdot s^{-2}[/tex] at the surface of the earth, given that the radius of the earth is known to be approximately [tex]6.371\times 10^{6}\; \rm m[/tex]. Assumptions: the earth is a sphere, the orbit of the moon is circular, and that the gravitational pull of the earth is the only force on the moon.

Explanation:

Convert the orbital period of the moon around the earth to seconds:

[tex]\begin{aligned}t &= (27\; \text{day} \times 24\; \text{hours} \cdot \text{day}^{-1} + 8\; \text{hour})\times 3600\; \rm \text{s}\cdot \text{hour}^{-1}\\ &= 2361600\; \text{s} \end{aligned}[/tex].

Calculate the angular velocity of the moon around the earth using the formula[tex]\displaystyle \text{angular velocity} = \frac{2\pi}{\text{orbital period}}[/tex]:

[tex]\begin{aligned}\omega = \frac{2\pi }{t} = \frac{2\pi}{2361600\; \rm s} \approx 2.66056\times 10^{-6}\; \rm s^{-1}\end{aligned}[/tex].

Let [tex]m(\text{moon})[/tex] denote the mass of the moon. Let [tex]g[/tex] denote the gravitational field strength at the surface of the earth (not at the position of the moon.) Let [tex]r[/tex] denote the radius of the earth.

The orbital radius of the moon would thus be [tex]60.1\, r[/tex]. Note that in the gravitational field due to a single spherical mass, the field strength is inversely proportional to the square of distance from the center of that mass.

The gravitational field at the surface of the earth is [tex]g[/tex]. Therefore,  at the position of the moon ([tex]60.1[/tex] times further away from the center of the earth compared to the earth surface,) the gravitational field strength would be:

[tex]\displaystyle \left( \frac{r^2}{(60.1\, r)^2} \right)\, g = \frac{g}{60.1^2}[/tex],

Hence, the gravitational pull of the earth on the moon would be [tex]\displaystyle \frac{m(\text{moon})\, g}{60.1^2}[/tex].

Assume that the gravitational pull of the earth is the only force on the moon. That gravitational pull would then be the equal (in size) to the net force on the moon. That is:

[tex]\displaystyle \text{Net force on the moon} = \frac{m(\text{moon})\, g}{60.1^2}[/tex].

On the other hand, the rotation (assumed to be perfectly circular) of the moon would give the net force on the moon in terms of:

[tex]\displaystyle \text{Net force on the moon} = m(\text{moon})\, \omega^2\, (60.1\, r)[/tex].

Combine the two expressions for the net force on the moon to obtain an equation for [tex]g[/tex]:

[tex]\displaystyle \frac{m(\text{moon})\, g}{60.1^2} = m(\text{moon})\, \omega^2\, (60.1\, r)[/tex].

Simplify and solve for [tex]g[/tex]:

[tex]\displaystyle g = 60.1^3 \, \omega^2\, r[/tex].

The angular velocity of this rotation, [tex]\omega[/tex], has already been found to be approximately [tex]2.66056\times 10^{-6}\; \rm s^{-1}[/tex]. Look up the radius of the earth: [tex]r = 6.371\times 10^{6}\; \rm m[/tex]. Evaluate this expression for [tex]g[/tex]:

[tex]\begin{aligned}g &= 60.1^3 \, \omega^2\, r \\ &\approx 60.1^3 \times \left( 2.66056\times 10^{-6}\; \rm s^{-1}\right) \times 6.371\times 10^{6}\;\rm m \\ &\approx 9.79\; \rm m \cdot s^{-1}\end{aligned}[/tex].

Answer:

-The amount of electric force depends on the amount of charge

-Adding more charge to either balloon caused a greater repulsive force.

-If the one balloon has more electric charge, that causes a greater electric force on both balloons, causing them to deflect equally.

Explanation:

According to Coulomb's law of electrostatic force between two charged masses, the force of attraction is proportional to the product of the charges on the masses. This means that the more the charge on the masses, the more the electric force on them. And adding more charge to either balloon will only cause the balloons to repel each other with a greater amount of force.

The electric force between two charged masses is of the same magnitude both ways, regardless of the individual charges on the masses. This justifies the fact that If one balloon has more electric charge, it will cause a greater electric force to be exerted between both balloons, causing them to deflect equally.

Answer:

48.9°, 29°

Explanation:

We kno that snell's law States that

( sin i / sin r ) = ( n 2 / n 1 )

And here

i = 90 - α

r = 90

n 2 = n a = 1.00029

n 1 = n = 1.52

So

( sin ( 90 - α ) / sin 90 ) = (1.00029 / 1.52 )

= 0.658

sin ( 90 - α ) = 0.658

90 - α = sin -1 ( 0.658 )

= 41.15

α = 90 - 41.15

= 48.9°

( b ) to find angle when prism immerssed in water

Using snell's law again

( sin i / sin r ) = ( n 2 / n 1 )

here i = 90 - α

r = 90

n 2 = n w = 1.33

n 1 = n = 1.52

So

( sin ( 90 - α ) / sin 90 ) = (1.33 / 1.52 )

= 0.875

sin ( 90 - α ) = 0.875

90 - α = sin -1 ( 0.875 )

= 61

α = 90 - 61

= 29°

Answer:

the answer is 2000Nm

Explanation:

wprk done = force × distance moved

w.d = 200N × 10m

w.d = 2000Nm

mark me as brainliest plyyzzz

Answer:

The  value is   [tex]F_t =  76024 \  N[/tex]  

Explanation:

From the question we are told that

  The  flow rate is  [tex]v_1 =  5 \  m/s[/tex]

   The  entrance diameter is  [tex]d =  0.7 \  m[/tex]

  The  exit diameter is evaluated as [tex]d_e  =  0.6  *  0.7 =  0.42  \  m[/tex]

   The entrance gauge pressure is  [tex]P_g =  350 \  kPa =  350*10^{3} \  Pa[/tex]

    The  droped gauge  pressure is  [tex]P_d =  50 \  kPa =  50*10^{3} \  Pa[/tex]

 The presure at the exist is evaluated as  [tex]P_e =(350  -    50 ) \  kPa =  300*10^{3} \  Pa[/tex]

Generally the entrance cross-sectional area is mathematically represented as

     [tex]A =  \pi \frac{d^2}{4}[/tex]

     [tex]A = 3.142 \frac{0.7^2}{4}[/tex]

      [tex]A =0.385 \ m^2[/tex]

Generally the exit  cross-sectional area is mathematically represented as

        [tex]A_e =  \pi \frac{d_e^2}{4}[/tex]

     [tex]A_e = 3.142 \frac{0.42^2}{4}[/tex]

      [tex]A_e =0.139\ m^2[/tex]

Generally from the continuity equation

    [tex]v_1 * A  =  v_2 * A_e[/tex]

=>  [tex]v_2  =  \frac{v_1 * A}{A_e}[/tex]

=>  [tex]v_2  =  \frac{5 * 0.385}{0.139}[/tex]

=>  [tex]v_2  =  13.8 m/s [/tex]

Generally the net force in horizontal axis is equivalent to the net momentum change in the horizontal direction

So

     [tex]P_g *  A +  F_t - P_e *  A_e  =  P_d [ A_e * v_2^2 -  A* v_1^2][/tex]

Here  [tex]F_t[/tex] is the horizontal thrust on the fitting

So  

        [tex]350*10^{3} * 0.385  +  F_t -0.385  *  0.139  =  50*10^{3} [ 0.385* 13.8^2 -  0.385* 5^2][/tex]

Answer:

You are putting more force on the ball no the racket so the racket wouldnt swing back but if you hit a racket on the ground it will swing backits just the way the force reaction works

Explanation:

^^^^^^^^^^^^^^^

The racket wouldn't swing back because you were applying more power to the ball than to the racket, so the racquet swings backward when the ball hits it.

Any action that aims to maintain, modify, or deform a body's motion is considered a force in mechanics. Isaac Newton's three laws of motion, which are outlined in his Principia Mathematica, are frequently used to illustrate the concept of force (1687).

According to Newton's third law, whenever one body applies force to another, the second body also applies an equal amount of force to the first body. The action-reaction concept explains why a force tends to cause a body to deform, or change shape, whether it moves the body.

The racket wouldn't swing back because you were applying more power to the ball than to the racket, but it would if you struck the racket on the ground; that's how the force reaction operates.

Therefore, the racquet swings backward when the ball hits it.

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Answer:

Subliminal simulation

Explanation:

When an individual registers sensory input without being aware of the process consciously, Subliminal simulation occurs.

Subliminal stimulation defined as sensory stimulation which is below a person's threshold for perception.

It can't be seen by the bare eye or consciously heard. An example is visual stimuli which is flashed so quickly on a screen that a person can't process it. So, they are unaware they have seen anything.

Subliminal stimuli helps facilitate conscious processing of related information, changes the current mood, boost our motivation. It can even change a person's political attitudes and voting intentions.

When an individual registers sensory input without being aware of the process consciously, Subliminal simulation occurs.

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Answer:

Mirage is an optical illusion due to the refraction of light as it travels through different layers of air at different temperature.

Explanation:

On a clear hot afternoon, the sun heats up the ground, and the ground heats up the air immediately above it. The result is that the air directly above the ground is hotter than the air above it, leaving the air layers with different refractive indies. Since refractive index decreases with increase in temperature, the air immediately above the ground bends the light that travels through it from the sky, directly into our eyes. The image seen is perceived to be reflected from the ground, but in an actual sense is a direct image of the sky, giving one the impression of seeing a pool of water on the ground.

Answer:

-Suzy flies up into the sky because of the upward force on the jetpack.

-Newton's third law of motion can be ascribed to this.

Explanation:

We know that in momentum, Force is described as the rate of change of momentum. Thus, for us to understand the forces, we will need to establish how the momentum of the water changes.

Suppose the mass flow rate of the water is denoted as M kg/sec and the upward velocity is denoted as v_u.

Now, since water is lying stationary at the sea, the initial momentum of the water will be zero. If every second the boat pumps upwards with mass flow rate M at velocity vu, the momentum per second would be;

Δp = F_water = Mv_u

Now, from Newton's third law the boat/pump would experience a downwards force with the formula:

F_boat = −Mv_u

Furthermore at the jetpack, the water does a reverse turn in direction and is now again directed back down at a different velocity v_d. Therefore the final momentum per second is Mv_d and therefore change in momentum is now;

Δp = M(v_d - v_u)

The velocity v_d will be negative since the boat/pump would experience a downwards force. Thus, the force on the water will be downwards and F_water ≤ 0 .

We will finally use Newton's third law to conclude that the upward force on the jetpack will be;

F_jetpack = M(v_u - v_d)

Thus upward force is what makes Suzy to fly up in the sky.

Answer:

a) Magnitude = 1.03 m/s², Direction: south

b) [tex]V_{f} = 8.16 m/s [/tex]

Explanation:

a) The magnitude and direction of the acceleration can be calculated using the following equation:

[tex] V_{f} = V_{0} + at [/tex]     (1)

Where:

[tex]V_{f}[/tex]: is the final speed = 9.40 m/s  

[tex]V_{0}[/tex]: is the initial speed = 13.0 m/s

t: is the time = 3.50 s

Solving equation (1) for a, we have:

[tex] a = \frac{V_{f} - V_{0}}{t} = \frac{9.40 m/s - 13.0 m/s}{3.50 s} = -1.03 m/s^{2} [/tex]

Hence, the magnitude of the acceleration is 1.03 m/s² and the direction of the bird's acceleration is the opposite of the initial velocity direction, which means that the bird is decelerating.  

b) The final velocity of the bird can be found using the same equation 1:

[tex] V_{f} = V_{0} + at [/tex]

[tex] V_{f} = 13.0 m/s + (-1.03 m/s^{2})*(3.50 s + 1.20 s) = 8.16 m/s [/tex]

Therefore, the bird’s velocity after an additional 1.20 s has elapsed is 8.16 m/s.

I hope it helps you!

Answer:

We know that the atomic number of sodium is 11. This tells us that sodium has 11 protons and because it is neutral it has 11 electrons. The mass number of an element tells us the number of protons AND neutrons in an atom (the two particles that have a measurable mass)

Answer:

The answer is

Explanation:

The speed of an object given it's kinetic energy and mass can be found by using the formula

[tex]v = \sqrt{ \frac{2KE}{m} } [/tex]

where

KE is the kinetic energy

m is the mass

v is the speed

From the question

KE = 31,500 J

m = 7000 kg

The speed is

[tex]v = \sqrt{ \frac{2(31500)}{7000} } \\ = \sqrt{ \frac{63000}{7000} } \\ = \sqrt{ \frac{63}{7} } \\ = \sqrt{9} \: \: \: \\ = 3 \: \: \: \: \: \: \: [/tex]

We have the final answer as

Hope this helps you

Answer:

360000

Explanation:

Answer:

360000 milliseconds

Explanation:

I have this remembered dont worry homie i got chu

Answer:

The car does not hit the deer.

Explanation:

In order to find out, whether the car stops before hitting the dear or not, we will use 3rd equation of motion.

2as = Vf² - Vi²

where,

s = distance covered by car before stopping = ?

a = deceleration of car = - 4.2 m/s²

Vf = Final Velocity of the Car = 0 m/s (Since, the car finally stops)

Vi = Initial Velocity of the Car = 25 m/s

Therefore,

2(- 4.2 m/s²)s = (0 m/s)² - (25 m/s)²

s = (- 625 m²/s²)/(-8.4 m/s²)

s = 74.4 m

So, the car stops in 74.4 m, while the deer is at a distance of 75 m.

Hence, the car does not hit the deer.

Using third equation of kinematics

[tex]\boxed{\sf v^2-u^2=2as}[/tex]

[tex]\\ \sf\longmapsto (0)^2-(25)^2=2(-4.2)s[/tex]

[tex]\\ \sf\longmapsto -625=-8.4s[/tex]

[tex]\\ \sf\longmapsto 8.4s=625[/tex]

[tex]\\ \sf\longmapsto s=\dfrac{625}{8.4}[/tex]

[tex]\\ \sf\longmapsto s=74.4m[/tex]

Answer:

36 m/s

Explanation:

Given:

v₀ = 50 m/s

a = -3.5 m/s²

t = 4 s

Find: v

v = at + v₀

v = (-3.5 m/s²) (4 s) + 50 m/s

v = 36 m/s