162.8 mm is spring rate.
What is Spring Rate?
The term "spring rate" describes how much force is required to compress a spring by one inch. If the spring's rate is linear, the weight applied to it has no impact on the spring's rate. For instance, a spring with a 200 lb. per inch capacity will compress by 1" when a 200 pound. load is applied to it. The spring will compress by another inch if 200 lbs. more are applied. The spring is now carrying a 400 lb weight. However, the spring's rate, which is 200 lbs. per inch, does not change.
k= 8D 3 N ad 4 G
= 8(28.5 3 )132.5 4 (81)10 3
=1.314 N/mmL 0
= kF s+L s
1.314167.9+35
=162.8 mm
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Help me with this please I need it ASAP
Scavenger can help break down or reduce organic material into smaller pieces. These smaller pieces are then eaten by decomposers.
They may be called scavengers. They assist damage down or lessen organic cloth into smaller portions. these smaller portions are then eaten through decomposers. Decomposers consume useless materials and spoil them down into chemical components.
In the event that they weren't within the ecosystem, the plant life could no longer get essential vitamins, and dead count and waste might pile up. There are sorts of decomposers, scavengers and decomposers. Scavengers are animals that locate useless animals or flora and consume them. while they consume them, they spoil them into small bits.
What is the difference among a detritivore and a scavenger? Detritivores eat organic debris that they discover, from any organisms. Scavengers consume the soft tissues of dead/decaying animals. Detritivores consume organic particles that they discover, from any organisms.
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a car is accelerated from 30 mil/h to 55 mil/h during a period of 20 s. calculate the magnitude of the force exerted on the car to accelerate.
The magnitude of the force exerted on the car to accelerate is 0.5588m N
We got some values here,
v[tex]_{0}[/tex] = 30 mil/h = 13,4112 m/s
v[tex]_{1}[/tex] = 55 mil/h = 24,5872 m/s
t = 20 s
First, we should find the acceleration of the car
a = v/t
a = v[tex]_{1}[/tex] - v[tex]_{0}[/tex] / t[tex]_{1}[/tex] - t[tex]_{0}[/tex]
a = 24.5872 - 13.4112 / 20 - 0
a = 11.176 / 20
a = 0.5588 m/s[tex]^{2}[/tex]
Now we got the amount of acceleration. We can found the force by the formula of: F = m.a but we are not given the mass value in the question. So, we can answer this question by this way
F = m.a
F = m × 0.5588 m/s[tex]^{2}[/tex]
F = 0.5588m N
What is acceleration?Acceleration (a) is the change in velocity (Δv) over the change of time (Δt), represented by the equation a = Δv/Δt. This allows you to measure how quick velocity changes in meters per second squared (m/s[tex]^{2}[/tex]. Acceleration is also a vector quantity, so it includes both magnitude and direction.
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A car braked with a constant deceleration of 18 ft/s2, producing skid marks measuring 100 ft before coming to a stop. How fast was the car traveling when the brakes were first applied?.
Answer:
[tex]60\; {\rm ft \cdot s^{-1}}[/tex].
Explanation:
Let [tex]a[/tex] denote the acceleration of this car; [tex]a = (-18)\; {\rm ft \cdot s^{-2}}[/tex]. Note that acceleration [tex]a\![/tex] measures the rate of change in velocity. Since this car is slowing down, acceleration [tex]a\!\![/tex] will be negative.
Let [tex]x[/tex] denote the displacement of the car. It is given that [tex]x = 100\; {\rm ft}[/tex] as the car braked.
Let [tex]v[/tex] denote the velocity of the car after braking. Since the car has stopped, [tex]v = 0\; {\rm ft \cdot s^{-1}}[/tex].
Let [tex]u[/tex] denote the initial velocity of the car. Apply the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex] to find the value of [tex]u\![/tex]. Rearrange this equation to obtain:
[tex]u^{2} = v^{2} - 2\, a\, x[/tex].
[tex]\displaystyle u = \sqrt{v^{2} - 2\, a\, x}[/tex].
Substitute in [tex]v = 0\; {\rm ft \cdot s^{-1}}[/tex], [tex]a = 18\; {\rm ft \cdot s^{-2}}[/tex], and [tex]x = 100\; {\rm ft}[/tex] to find the value of [tex]u[/tex]:
[tex]\begin{aligned} u &= \sqrt{v^{2} - 2\, a\, x} \\ &= \left(\sqrt{0^{2} - 2 \times 18 \times 100}\right)\; {\rm ft \cdot s^{-1}} \\ &= 60\; {\rm ft \cdot s^{-1}}\end{aligned}[/tex].
In other words, this car was travelling at [tex]60\; {\rm ft \cdot s^{-1}}[/tex] before braking.
when a separate branch-circuit is run to a wall mounted oven, or to a counter-mounted cooking unit, the branch circuit size is based on of the nameplate rating of the appliance.
When a separate branch-circuit is run to a wall mounted oven, or to a counter-mounted cooking unit, the branch circuit size is based on of the nameplate rating of the appliance.
The ratings are shown in watts on the appliance nameplate. The circuit must be sized to provide the required number of amperes to operate the appliance at its nameplate rating.
One ampere is defined as the current that flows through a conductor when a potential difference of one volt is applied across it. The ampere is thus equivalent to the coulomb, the SI unit of charge. The ampere was originally defined as one tenth of the unit of electric current in the centimetre–gram–second system of units.
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Two objects, A and B, are pushed across the floor. Object A is pushed across a longer distance. Which statement best describes what must be true for Object B to have a greater value of work? The distance traveled by Object A is higher. The distance traveled by Object B is lower. Equal forces are applied to Objects A and B. A greater force applied to Object B.
It is clear that, what would make object B to have a greater work is that a greater force applied to Object B.
What is the work done?We know that in physics, it is common to understand that work is done when the force that has been applied is said to move a distance in the direction of the force.
Now we have see that when force is applied to an object, we expect that the position of the object would change as a result of the fact that work has been done on the object as we can see. Thus by applying a greater force on B it does a greater work.
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A 2.0 kg block is released from rest at the top of a rough plane inclined at 37° to the horizontal, as shown
below. The block slides down the incline with an acceleration of 4.0 m/s. What is the approximate magnitude
of the force of friction on the block as it slides down the incline?
Approximate magnitude of the force of friction on the block as it slides down the incline is calculated as 4N.
What is force of friction?
Force of friction is the force resisting the relative motion of solid surfaces, fluid layers and material elements sliding against each other. There are many types of friction like static friction, sliding friction, rolling friction, and fluid friction. Static friction is the strongest which is followed by sliding friction and rolling friction is the weakest. Fluid friction takes place in fluids which are liquids or gases.
Given mass is 2 kg and
acceleration is 4.0 m/s
m *g *sin 37° - F = m*a
F= m *g *sin 37° - m*a
=( 2* 9.81 * sin 37°- 2 *4)
=3.8 N
approximately equal to 4N
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The mass
of a tennis ball is 60g. If it strikes a wall
with a velocity of 20m/s, and comes back in opposite
The direction with a
velocity of 16 m/s.
Calculate the change
in momentum of the ball.
Change in momentum is 2.16 kg m/s
What is Change in momentum ?
The change in momentum is equal to the product of the change in mass and velocity. The mass is constant and does not change. It is the change in velocity that causes the change in momentum. The change in momentum is denoted by the symbol Δp.
The change in momentum (Δp) is defined as the change in the mass times the velocity of an object. A force is required to change the momentum of an object. This applied force can increase or decrease momentum or even change the orientation of an object
Δp =m * [ v ( final ) - v( initial ) ] = 60/1000 [ 16 - ( - 20) ]
= 2.16kg m/s
Change in momentum is 2.16 kg m/s
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The mass of 12c is 12. 000 amu. Multiply the mass of 12c by its abundance. Report the number to 5 significant digits.
In the scientific community determined precise value of Mu to make C12 weigh 12 Mu that indicates that one C12 atom weighs 12/NA grams. because NA = 6.0223 X 10²³.
By definition, an atom of C-12 has a mass of 12 Atomic Mass units.
One C12 atom weighs 12/(6 x 10²³) grams, or approximately 2 x 10⁻²³gm.Mass spectrometry can precisely determine the mass of any non-radioactive atom.Experimental work revealed that the mass of a carbon atom is 1.99264650724 x 10⁻²³By multiplying an amu by 12, it is simple to duplicate this value. As one amu is defined as having one-twelfth the mass of an atom of carbon ,in essence, it is (10/6)*(12) * 10^(-23).To learn Mass spectrometry -
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Problem 4: In a multiple-slit interference experiment, 15 narrow slits are equally spaced 0.25 mm apart and illuminated with light of wavelength 570 nm. The interference pattern is projected on a screen 2.4 m away. 25% Part (a) What is the angular position, in degrees, of the third principal maximum? A=0.391 ✓ Correct! 25% Part (b) What is the angular position, in degrees, of the fourth principal maximum? 0 = 0.522 ✓ Correct! 25% Part (c) If y is the position along the screen measured from the center of the pattern, then what is the distance, Ay between the third and fourth principal maxima on the screen? Recall that the screen is located 2.4 m from the barrier with the slits. Ay=0.00548 ✓ Correct! * 25% Part (d) In an N-slit interference pattern, there are N - 2 secondary maxima and N - 1 dark minima between each pair of sequential principal maxima. The dark minima are equally spaced between the centers of the pair of principal maxima. Calculate the width, 8y, of the third principal maximum. dy= 0.000000712 Deductions 1% Potential Grade Summary mi 99%
Given- 15 narrow slits, d=0.25 mm, λ=570 nm, D=2.4m
Angular position (interference)- formulae β=Dλ/d
after solving we get Angular position = 0.391
b) angular position, in degrees, of the fourth principal maximum = 0.522
c) If y is the position along the screen measured from the center of the pattern, then the distance, Ay between the third and fourth principal maxima on the screen = 0.00548m
d) In an N-slit interference pattern, there are N - 2 secondary maxima and N - 1 dark minima between each pair of sequential principal maxima. The dark minima are equally spaced between the centers of the pair of principal maxima. The width is = dy = 0.000000712 m
The vector total of the amplitudes of the individual waves is equal to the consequent amplitude at a location where two or more waves of the same sort are incident, according to the principle of superposition of waves. When the crests of two waves of the same frequency collide at the same spot, constructive interference happens.
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An apple is placed on a kitchen counter How could the movement of the particles in the apple be decreased
OA. Put it in the sunlight.
OB.
Put it in the microwave.
OC. Put it in the refrigerator.
OD.
Eat it for dinner
Reset
Submit
Answer: The correct option would be (Put it in the refrigerator)
Explanation: Have a good day :)
Answer:
C
Explanation:
Decreasing its temp decreases particle movement
An egg is dropped from a treehouse and takes 1.51.51, point, 5 seconds to reach the ground. We can ignore air resistance.
What is the egg's displacement?
An egg is dropped from a treehouse and takes 5 seconds to reach the ground. Air resistance can be ignored. The displacement of the egg will be 122.5m.
This question is from the branch of physics called kinematics. We use equations of motion to find out the unknown quantity from the given data. Let us use the equation of motion, s=ut+1/2*a*t²
where, s is the displacement of the egg in metres
u is the initial velocity of the egg in m/s
a is the acceleration in m/s²
t is the time in seconds
As we know that, the egg is in a freefall condition, its initial velocity is zero and acceleration is nothing but acceleration due to gravity here as it is under the action of gravity.
s=1/2*g*t²
s=1/2*9.8*5*5
s=122.5m
So, the displacement of the egg is 122.5m.
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three blocks are stacked on top of one another.The top block has a mass of 4.6kg,the middle one has a mass of 1.2kg, and the bottom one has a mass of 3.7kg.Identify the calculate any normal force between the object
The normal force between the objects is achieved by adding up. They are 36.26 N and 48.02 N respectively.
What is Force ?A force can simply be defined as a pull or push. The normal force is a reactive force on the weight of an object.
Given that three blocks are stacked on top of one another. The top block has a mass of 4.6kg, the middle one has a mass of 1.2kg, and the bottom one has a mass of 3.7kg.
The weight of each block will be;
First block = 4.6 × 9.8 = 45.08 N
Middle block = 1.2 × 9.8 = 11.76 N
Bottom block = 3.7 × 9.8 = 36.26 N
The normal force between the bottom and the middle objects will be 36.26 N
The normal force between the middle and the first objects will be 36.26 + 11.76 = 48.02 N
The normal force on the first object will be 36.26 + 11.76 + 45.08 = 93.1 N
Therefore, the normal force between the objects are 36.26 N and 48.02 N respectively
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Isabel pushes a shuffleboard disk, accelarating it to a 6,5 m/s before releasing it as indicated in Figure 13(picture). If the coefficient of kinetic friction between the disk and concrete court is 0.31, how far does the disk travel before it comes to a stop? Will Isabel's shot stop in the 10 point section of the board?
When Isabel pushes a shuffleboard disk, accelarating it to a 6,5 m/s before releasing it, the shot will stop in the 10 point section of the board.
What is the meaning of speed?The average speed is calculated by dividing the total distance traveled by the total time it took to travel that distance. Speed is the rate at which something moves at any given time. Average speed is the average rate of speed over the course of a journey. .
Velocity is the directional speed of a moving object as an indication of its rate of change in position as observed from a specific frame of reference and measured by a specific time standard.
Since Isabel pushes a shuffleboard disk, accelarating it to a 6,5 m/s before releasing and the coefficient of kinetic friction between the disk and concrete court is 0.31, this will be illustrated thus:
The initial speed of disk = 6.5 m/s
deceleration of disk = 0.31*9.8=3.038 m/s²
Let the distance travelled by disk before coming to stop s
s=6.52/(2*3.038)
s =6.95 m
Therefore, it's within the 10 point range.
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Between ball b and ball c, ball ____________ has less potential energy because_________________________.
b: b; its mass is smaller
Between ball B and ball C, ball B has LESS potential energy because its mass is smaller.
A potential energy, stored energy that depends upon the relative position of various parts of a system. A spring has more potential energy when it is compressed or stretched.
Potential energy is given by formula.
Since, P.E is directly proportional to mass. Thus, the ball having smaller mass will have the less P.E.
Thus, option b is correct.
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Sketch or describe the FBD from for finding the static friction of the experiment. You can upload a picture or describe where all the vectors/forces point.
If describing, you can use phrases like: The weight is straight up The force is straight down The tension goes up the wooden block The force goes down the wooden block (Or anything else that would describe the FBD.)
Frictional force μk = T - ma / mg
As block is moving with acceleration 'a', so we will we equilibrium equation.
T - f = ma
T - μk N = ma
μk = T - ma/N
μk = T - ma / mg
where T = tension in rope
m = mass of block of wood
g = acceleration due to gravity
The net force acting on an object is equal to the rate at which its momentum varies over time, according to Newton's second law in its original version. This law suggests that an object's acceleration is directly related to its mass if it has a constant mass.
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The form of energy that includes visible light, x rays, and microwaves and that exhibits wavelike behavior as it travels through space is called.
Electromagnetic radiation is a form of energy that exhibits wavelike behaviour as it travels through space.
Examples of EMR include ultraviolet light, infrared light, microwaves, and radio waves.
In terms of science, electromagnetic radiation (EMR) is made up of electromagnetic (EM) field waves that travel over space while carrying radiant electromagnetic energy. It consists of X-rays, gamma rays, microwaves, infrared, visible light, ultraviolet, and radio waves. These waves are all a component of the electromagnetic spectrum.
Electromagnetic waves, which are synchronized oscillations of the electric and magnetic fields, are the traditional form of electromagnetic radiation. Due to the periodic alteration of the electric or magnetic field, electromagnetic radiation or waves are produced. Different wavelengths of the electromagnetic spectrum are created depending on the way this periodic change takes place and the power generated. Electromagnetic waves move at the speed of light, typically abbreviated as c, in a vacuum.
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a machinist bores a hole 2.000 cm in diameter in a brass plate at a temperature of 20 c. what is the diameter of the hole when the temperature of the plate is increased to 200c? assume the expansion coefficient remains constant.
Let d2 be the hole's diameter. Therefore, the coefficient d2 = d1 (1 + alpha dt) remains constant.
Diameter and circumference are what?Since a circle's center must be the longest distance between any two points on the circle, the diameter is essentially twice as large as the radius. The distance around a circle or the duration of a circuit along a circle can be used to define its circumference.
What does a diameter mean in plain English?The distance that runs through the center of a circle through one point on its surface to another is known as the diameter of the circle.
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Calculate the force that is needed to propel a rocket into space if the rocket weighs 10,000 kg and the escape velocity for Earth's gravity is 11 km/s. (Hint: use the formula F = ma).
Mass:
Initial velocity:
Final velocity:
Time: 10 minutes
Force:
The correct answer is 183300 Newton amount of force is needed to propel a rocket.
What connection exists between force and mass of acceleration?
Mass times acceleration, or F=m x a, equals force. This means that in order to move an object at the same speed as an object with smaller mass, a stronger force is required. Newton's Second Law of Motion is this.
Force = Mass x acceleration
Initial velocity = 11 Km/s
Acceleration = Velocity / time = 11000 / 600 = 110/ 6 = 18.33 m/s^2
Force = 10000 x 18.33 = 183300 N
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Increasing following distance to __________when encountering other motorists who follow too closely is an example of appropriate implementation of the ipde defensive driving strategy for the maintenance of an appropriate safety cushion.
Increasing following distance to Four-seconds when encountering other motorists who follow too closely is an example of appropriate implementation of the IPDE defensive driving strategy for the maintenance of an appropriate Safety Cushion.
Continuous scanning is essential to manage the nine to fifteen space driving zones while maintaining the necessary safety cushion while using the IPDE defensive driving approach. As a result, drivers need to be able to recognise the objects and hazards in their line of sight and their direction of movement.
They ought to anticipate potential conflict hotspots. They should decide what driving behaviours are suitable and safe to use, when, and where. In order to ensure that confrontations are avoided, action must be taken.
Identify, Predict, Decide, and Execute is the acronym for IPDE. Off-road driving should also employ this tactic. Determine any items or situations that could be problematic for you while driving. Make an educated guess as to what might happen when you come across the thing or condition.
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a body is projected from the ground at an angle theta to the horizontal with a velocity of 30m/s. it reached a maximum height of 11.25m. calculate: the value of theta
The value of theta for the maximum height is 30°.
Calculation:-
Since the angle from the horizontal is Cosθ, therefore the angle from the vertical is sinθ.
Hmax = U² sin²θ/2g
11.25 = 30² sin²θ/2g
sin²θ = (11.25 × 2 × 10)/900
⇒ sin²θ = 0.25
⇒ sin θ = 0.5
⇒ sin θ = 1/2 = 30°
The horizontal pace of a projectile is regular (in no way converting in value), and there's a vertical acceleration because of gravity; its cost is 9.8 m/s/s, down, The vertical speed of a projectile changes via nine.8 m/s every second, The horizontal motion of a projectile is impartial of its vertical movement.
Projectile motion is a form of motion experienced with the aid of an object or particle that is projected in a gravitational field, such as from Earth's floor, and movements alongside a curved route below the action of gravity best.
Projectile motion is the movement of an object thrown (projected) into the air. After the initial force that launches the item, it most effectively reports the pressure of gravity. The object is known as a projectile, and its route is called its trajectory.
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what is the charge on the smaller of the two charges in coulombs? (note: if you calculate your answer using your result from part (a), make sure you didn't round it substantially.)
The Charge on smaller of the two charges is 1.747 × 10⁻⁷ C .
When two charges come together, an attractive force occurs for opposite charges and a repulsive force for similar charges. Coulomb's law can be used to calculate the electrostatic force between two charges if the distance between them is known.
Coulomb's Law defines the following equation for this: F.E = Kₑq₁ q₂/r²
Where,
F.E --> electrostatic force in Newton
Kₑ---> Coulomb constant
q₁---> charge of the larger charge in coulombs
q₂---> charge of the smaller charge in coulombs
r ---> distance between the objects in meters
we have given that ,
charge on larger charge(q₁) = 9.56 × 10⁻⁶C
Coulomb constant (Kₑ) = 8.988×109 Nm²C⁻²
distance between two charges = 0.45 m
repulsive force between charges = 0.015 N
putting all the values in above formula we get, 0.015 = (8.988×10⁹ Nm²C⁻² × q₂ × 9.56×10⁻⁶ C)/(0.45)²
=> q₂ = 1.747 × 10⁻⁷ Coulomb
Hence, the charge on smaller charger is 1.747× 10⁻⁷C
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Complete Question :
Two point charges totaling 9.5 uC exert repulsive force of 0.015 N on one another when separated by 0.45 m Randomized Variables.
Part (a) the charge on the larger of the two charges in coulombs = 9.56 * 10-6
Part (b) What is the charge on the smaller of the two charges in coulombs? (Note: If you calculate your answrer using YOur result from part (a). make sure you didn round it substantially.
Match the symbols used in electric circuit diagrams to their functions.
3F
00
a device that converts electric
energy into sound energy
a device that glows when it
receives current
a device that provides energy
to a circuit
a device that starts or stops
the flow of current
4
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what should the magnitude of the force f be if the mass m is to have an upward acceleration of magnitude a?
Product of mass and acceleration is the magnitude of force.
A push or pull of an object is called force. Product of mass and acceleration is the magnitude of force. The S.I. unit of force is m/s². Unit can be represented by newton symbol is N.
F = m × a
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an air-conditioning system requires a 20m long section of 15cm diameter duct work to be laid underwater. determine the upward force the water will exert on the duct.
The upward force the water will exert on the duct is 3.463kN.
Here we have to find the buoyancy force:
Buoyancy force:
The buoyant force is the upward force exerted on an object wholly or partly immersed in a fluid. This upward force is also called Upthrust. Due to the buoyant force, a body submerged partially or fully in a fluid appears to lose its weight, i.e. appears to be lighter.
Formula to calculate buoyancy forces:
B = ρgV
ρ= fluid density
g = acceleration due to gravity
V = fluid volume
V = πr²L
So;
B = ρgπr²L
Given data:
g = 9.8 m/s²
r = 15 cm = 0.15m
L = 20m
ρ = 1000
B = 1000× 9.8 × 22/7 ( 0.15/2)² × 20
= 3.465kN
Therefore the upward force is 3.465kN.
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What is the shape of the projectiles loaded for shotshells?.
Small spherical projectiles are few shapes of the projectiles loaded for shotshells.
A projectile is any object that once projected or dropped continues in motion by its own inertia and is influenced only by the downward force of gravity.
Projectile is a body projected by external force and continuing in motion by its own inertia and the velocity is constant horizontally.
Modern ammunition varies depending on the type of firearm. Rifles and handguns use a cartridge containing a single projectile (bullet). Shotguns use a shot shell containing either a single slug or a large number of small projectiles (shot or pellets). However, the basic components of cartridges and shot shells are similar. The projectile is one of them.
This projectile is similar to many. Single shot firearm is different from a repeating firearm because of the fact that the single shot firearm is in need to be reloaded each time that the single shot firearm is being used whereas the repeating firearm has extra cartilages by which it doesn't necessarily in need to be reloaded each time it has been fired.
Therefore, the shape of projectiles loaded for shot shells are small spherical projectile.
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How fast does a 1000 kg car have to move to have a momentum of 50,000 kg-m/sec?
A block of ice with a mass of 10 kg is resting on a frozen pond. How much
force will it take to accelerate the ice at 0.25 m.s^-2
Answer:
See below
Explanation:
Answer 3 and 6 with F = ma to find the 'a' or F
4 and 5 are also F = ma with a = 9.81 m/s^2
A flat, circular loop of radius r = 1 m is at rest in a uniform magnetic field of magnitude b. The plane of the loop is parallel to the page and the magnetic field is directed perpendicular to and out of the page, as indicated by the blue dots. If the magnitude of the magnetic field decreases from 8 t to 2 t in 2 s, what is the rate of change in the magnetic flux through the circular loop?.
The rate of change in the magnetic flux for the induced emf in a loop is 9.42 volts.
Magnetic flux is the number of lines of force that penetrate a plane surface perpendicularly. Meanwhile, the induced emf is the emergence of an emf on the ends of the coil caused by a change in the magnetic flux enclosed by the coil.
ε = (dΦ/dt)
With:
ε = induced emf (volts)
ΔΦ = change in magnetic flux (Wb)
Δt = time interval for changing magnetic flux (s)
On a known matter
The radius of the circular loop: r = 1 m
Time: t = 2 s
Initial magnetic field: Bi = 2T
Final magnetic field: Bf = 8T
The expression for the induced emf in a loop is:
ε = (dΦ/DT) → Φ = magnetic flux
ε = [tex]\frac{d(BA cos 0)}{dt}[/tex] → θ = 90°
ε = [tex]A\frac{d(B)}{dt}[/tex]
ε = [tex]A \frac{Bf -Bi}{t}[/tex]
ε = π(1)² x (8-2/2)
ε = 22/7 x 3
ε = 9.42 volts
So, the induced emf in the loop is 9.42 volts.
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what is the electromagnetic frequency for the following variables? 3 t, 0.25 m, 3 m/s group of answer choices 6.75 v 2.25 v 20.25 v 0.75 v
Electromagnetic waves occur at frequencies between 104 and 1024 Hz and have wavelengths between 10-16 and 104 meters.
All types of electromagnetic waves have in common that their velocity in vacuum is 3.00 × 108 m/s. Radio waves form the long wavelength, low frequency end of the electromagnetic spectrum. The sections of the EM spectrum are named, in order of increasing energy,
gamma rays, X-rays, ultraviolet, visible light, infrared, and radio waves. Microwaves (used in microwave ovens) are a subsection of the radio segment of the EM spectrum. Electromagnetic waves are transverse waves. The wavenumber is k = 2π/λ, where λ is the wavelength of the wave. The wave frequency f is f = ω/2π, where ω is the angular frequency.
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What are 10 types of malware?.
Malware can come in many different forms, but the most prevalent ones are viruses, keyloggers, worms, trojan horses, ransomware/crypto-malware, logic bombs, bots/botnets, adware & spyware, and rootkits.
How widespread is malware?Currently, there are more than 1 billion malware programmes available. Ransomware assaults affect four businesses per minute. Of all computer malware, trojans make up 58%.
Adware is malware that targets computer users and delivers intrusive advertisements. By claiming compensation from the companies whose ads are served by the malware, the malware's creator can profit. According to Check Point Research, adware is still the most prevalent kind of mobile malware.
Safeguarded Remote Desktop Protocol (RDP) and other risky services. Data backups should be done offline. Inform and educate end users about phishing and social engineering.
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