A stone is propelled vertically off the ground. After it is released, which of the following are true? It’s total mechanical energy increases It’s total energy is proportional to its distance off the ground It’s kinetic energy decreases It’s gravitational energy increases

In every scenario, the automobile is accelerating. The automobile is accelerating in the scenarios below.

gaining speed means moving more quickly. The vehicle accelerated gradually. The rate of change has quickened recently. To move through the grades more quickly than is customary.

Due to this, a shift in speed could be either a shift in how quickly something is going or a shift in the way it is moving. When an object accelerates, it alters its direction, speed, or both.

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In fresh water the block will float at Height of 2.5cm above water.

In salt water the block will float at Height of 2.72cm above water.

Density is defined as the mass per unit volume. It is an intensive property, which is mathematically defined as mass divided by volume:

ρ = m/V

In words, the density (ρ) of a substance is the total mass (m) of that substance divided by the total volume (V) occupied by that substance. The standard SI unit is kilograms per cubic meter (kg/m3). The Standard English unit is pounds mass per cubic foot (lbm/ft3). The density (ρ) of a substance is the reciprocal of its specific volume (ν).

ρ = m/V = 1/ρ

In fresh water (density of Ig/cc.), the block will float with [tex]$10-(10 \times 0.75)=2.5 \mathrm{~cm}$[/tex]. above water.

The salt water one is tougher.

Block density is [tex]$750 \frac{kg}{m^3}$[/tex], which equates to [tex]$0.75 \mathrm{~g} / \mathrm{cc}$[/tex].

Block volume [tex]$=\left(10^3\right)=1,000$[/tex]

Its mass is. [tex]$(1,000 \times 0.75)=750$[/tex] grams

It will displace its own mass of water when it floats.

The volume of water displaced. [tex]$=(750 / 1.030)=728.16 \mathrm{cc}$[/tex]

The block area [tex]$=(10 \times 10)=100 \mathrm{~cm}^2$[/tex].

Height out of water [tex]$=10 \mathrm{~cm}-(728.16 / 100)=2.72 \mathrm{~cm}$[/tex]

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Explanation:

As we draw the ray diagram, the image seems to fall between the f and c. It was real, inverted and magnified image.

Here it is given that the focal length is 20 cm.

So the curvature of the mirror will be 2f = 2 ×20 = 40 cm.

The light bulb is 60 cm away from the concave mirror. So the object is beyond C. As per theory, if an object is beyond c, the image will fall between c and f, and it will be a real, diminished and inverted image. The ray diagram we draw also give the same result.

Lets look into calculations.

The distance between object, the image and focal length is related by the equation,

   1/f = 1/v +1/u

     v is the distance of image from mirror

      u is the distance of the object from the mirror.

So , 1/v = 1/f - 1/u

            = 1/20 - 1/60

           = 60-20 / 1200 = 1/30

So v = 30 cm.

This proves the diagram we draw is correct.

So the image will be formed 30 cm away from the mirror and it will be real, inverted, diminished image.

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The near point of the eye is the shortest distance Anna can hold the coin and still have it appear in focus.

The closest distance at which an object can be placed in front of the eye and still be in focus is the near point of the eye, also referred to as the closest point of distinct vision. To change the eye's focal length and enable it to focus on objects at different distances, changes are made to the pupil's size and the lens of the eye.

The near point for a typical eye is approximately 25 cm.

Use the lens equation,

1/f = 1/d₀ + 1/di

We know that f = 12 D and di = 1.7 cm

Therefore,

1/f = 1/d₀ + 1/di

1/12D = 1/d₀ + 1/(1.7cm)

d₀ = 1/(1/12D - 1/(1.7cm))

d₀ = -1.98cm

The unit will be in cm.

The closest distance at which an object can be positioned in front of the eye and still be in focus is at the near point of the eye. The near point of a typical eye is approximately 25 cm.

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The near point of the eye is the closest distance at which Anna can hold the coin and still have it seem in focus. She can make out the picture of the coin at 1.98 cm.

The closest distance at which an object may be placed in front of the eye and still be in focus is the near point of the eye, sometimes referred to as the nearest point of distinct vision. The pupil size and the eye's lens can be altered to change the eye's focal length and enable it to focus on objects at different distances.

The near point of a typical eye is roughly 25 cm distant.

Use the lens equation,

1/f = 1/d₀ + 1/di

We are aware that di = 1.7 cm and f = 12 D.

Therefore,

1/f = 1/d₀ + 1/di

1/12D = 1/d₀ + 1/(1.7cm)

d₀ = 1/(1/12D - 1/(1.7cm))

d₀ = -1.98cm

Centimeters will be used to measure it.

The closest point at which an object may be positioned in front of the eye and still be in focus is the near point of the eye. The near point of a typical eye is roughly 25 cm distant.

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The general rules for combining equilibrium constants (Kc) when performing equilibrium calculations include:

KC values (also known as partition coefficients) are a measure of the relative solubility of a compound in two different solvents. They are used in biochemistry and pharmacology to determine the solubility of a drug in water and in lipids (fats). KC values can provide insight into the absorption and distribution of a drug in the body, and can also help predict the effectiveness of a drug.

1. Multiply the Kc values together if the reaction is being reversed.

2. Divide the Kc values if the reaction is being advanced.

3. If the reaction involves more than two Kc values, use the appropriate algebraic equations to combine the values.

4. Always remember to keep track of the total number of moles of reactants and products involved in the equilibrium calculation.

5. When combining Kc values, be sure to include the necessary exponents from the balanced equation.

6. When combining Kc values, always maintain the same units for consistency.

7. When combining Kc values, the temperature must remain constant for the entire calculation.

8. Finally, always check your work to make sure the correct Kc value was calculated.

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The general rules for combining equilibrium constants (Kc) when two or more kc values are described below.

Kc values (also known as partition coefficients) are a measure of the relative solubility of a compound in two different solvents. They are used in biochemistry and pharmacology to determine the solubility of a drug in water and in lipids (fats). Kc values can provide insight into the absorption and distribution of a drug in the body, and can also help predict the effectiveness of a drug.

1. Multiply the Kc values together if the reaction is being reversed.

2. Divide the Kc values if the reaction is being advanced.

3. If the reaction involves more than two Kc values, use the appropriate algebraic equations to combine the values.

4. Always remember to keep track of the total number of moles of reactants and products involved in the equilibrium calculation.

5. When combining Kc values, be sure to include the necessary exponents from the balanced equation.

6. When combining Kc values, always maintain the same units for consistency.

7. When combining Kc values, the temperature must remain constant for the entire calculation.

8. Finally, always check your work to make sure the correct Kc value was calculated.

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The tracking device sends data to a computer during the game and one advantage of the data being sent during the game is to ensure that adequate statistics and summary of the game is available.

This is referred to as a set of instructions that a computer needs to carry out its tasks is known as a program while data on the other hand is a set of raw facts and figures.

The tracking device sends data to a computer during the game which makes the statistics and summary available for the game accurate and adequate.

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Part A) The distance from the top of the block to the water if the water is fresh is 3 cm.

Part B) The distance from the top of the block to the sea water if the water is fresh is 3.31cm.

We refer to an object or substance's volume (or how much space it occupies) in terms of its density (its mass).

(a) The density of fresh water is ρwater = 1000 kg/m³

ΣF = 0

ΣF = - (ρwood)g(Vwood) + (ρwater)g(vwood)

- (ρwood)g(Vwood) + (ρwater)g(vwood) = 0

(vwood)/(Vwood) = (ρwood)/(ρwater)

(690×h)/(10×10×10) = (690)/(1000)

h = 6.9 cm

The block's top is above the water, and it is 10 - 6.9 = 3 cm

(b) The density of seawater is ρsea = 1030 kg/m³

(vwood)/(Vwood) = (ρwood)/(ρsea)

(690 × h')/(10 ×10 × 10) = (690)/(1030)

h' = 6.69 cm

The distance from the top of the block to the water is

10 - 6.69 = 3.31cm.

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The temperature change that occurred when the 1 m long brass experience an increase in length of 5.757 mm is 303 °C

Coefficient of linear expansion is given by the following formula:

α = ΔL / L₁(ΔT)

Where

With the above formula, we can obtain the temperature change as illustrated below:

α = ΔL / L₁(ΔT)

0.000019 = 5.757 / (1000 × ΔT)

Cross multiply

0.000019 × 1000 × ΔT = 5.757

0.019 × ΔT = 5.757

Divide both sides by 0.019

ΔT = 5.757 / 0.019

ΔT = 303 °C

Thus, we can conclude that the temperature change is 303 °C

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Radio waves are transverse waves that disturb electromagnetic fields.

Electromagnetic field, a feature of space brought on by the movement of an electric charge. Only an electric field will be generated by a stationary charge in the surrounding area. A magnetic field is also created if the charge is in motion.

A changing magnetic field can also create an electric field. An electromagnetic field is created by the mutual interaction of electric and magnetic fields. This field is thought to exist independently of any charges or currents (a stream of moving charges) to which it may be related. It is possible to think of this electromagnetic field in some situations as an electromagnetic energy-transporting wave.

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The impulse delivered to the roof is  -0.115 Ns and the magnitude of the force of the impact is -31.17 kN.

a. Impulse is defined as the product of the force acting on an object and the time over which the force is applied. In this case, the impulse delivered to the roof is the product of the force acting on the raindrop and the time it takes for the raindrop to come to a stop after hitting the roof. Since we don't know the time of impact, we can use the impulse-momentum theorem which states that the impulse of a force acting on an object is equal to the change in momentum of the object.

The impulse delivered to the roof is given by J = Δp = pf - pi

The initial momentum of the raindrop is given by pi = m * vi = 0.014g * 8.1 m/s = 0.115 Ns

Since the final velocity of the raindrop is zero (it comes to rest), the final momentum is zero. Therefore, the impulse delivered to the roof is J = pf - pi = 0 Ns - 0.115 Ns = -0.115 Ns

b. To find the force of the impact we can use the equation: F = J/t

where F is the force of the impact, J is the impulse delivered to the roof, and t is the time it takes for the raindrop to come to a stop after hitting the roof.

We have that t = 0.37 ms = 0.00037 s

So F = J/t = -0.115 Ns / 0.00037 s = -31167.57 N or -31.17 kN

Here, the negative sign of the force tells us that the force is opposite to the direction of motion, which means that the force is acting to stop the motion of the raindrop.

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Answer:

v=66.6km/hr

V=66.6km/hr due east

Explanation:

[tex]v= \frac{s}{t} [/tex]

given

s=200km

t=3hr

required

v=?

solution

v=s/t

v=200km/3hr

v=66.6km/hr

Maximum speed can it go around a curve having a radius of 78.0 m

The speed of an object, also known as v in kinematics, is a scalar quantity that depends on how much its position changes over time or how much it changes per unit of time. Velocity and speed are the  two distinct concepts.

The International System of Units (SI) uses the metre per second as the unit of both speed (a scalar quantity) and velocity (a vector quantity with direction and magnitude), with one metre per second being the speed of a body traveling one meter in one second.

The truck receives the necessary centripetal acceleration from friction between the tires and the flat road in order to safely and skid-free navigate the bend.

[tex]a_{c,max} =\frac{v^{2}_{max} }{r} \rightarrow( 1)[/tex]

inserting the given values we get

[tex]a_{c,max} =\frac{(36)^{2}_{} }{150}[/tex]

[tex]a_{c,max} =[/tex]8.64m[tex]s^{-2}[/tex]

For a changed in the radius of curve of 78.0m , the maximum speed can it go

[tex]v_{new,max} =\sqrt(a_{c,max} \times R_{new} )[/tex]

[tex]v_{new,max} =\sqrt(8.64\times 78 )[/tex]

[tex]v_{new,max} =\\[/tex]25.95m/s

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Of the forces present in the external environment, which is considered to be significantly uncontrollable are political forces, competition force. In physics, nuclear energy is uncontrollable.

The economy, politics, competitors, customers, and even the weather are all uncontrollable factors. the energies which are mentioned in the above part are the forces that are involuntary and voluntary both and can be controlled or cannot be controlled by our own means. we cannot tend to change it. the nuclear energy whereas is the energy that generally cannot be controlled and we have to make controls to take a control over it. this is involuntary and generally cannot be controlled. by this primary information, we can firmly conclude that of the forces present in the external environment, which is considered to be significantly uncontrollable are political forces, competition force. In physics, nuclear energy is uncontrollable.

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The provided statement states that a photon including a potential of 30 eV has a wavelength of 41.36 nm and is an ultraviolet photon.

The SI unit representing wavelength is the metre, which is frequently abbreviated as m. Time is also measured in different amounts or percentages of meters. Notably, proportional ratios of 10 are used when wavelengths constitute a key component. A negative exponential is used to describe shorter wavelengths. Here are some examples of wavelengths: Yellow Sunshine is a good illustration. All light source has a frequency spectrum between 400 and 700 nanometers (nm). Yellow light has a wavelength of around 570 nanometers.

[tex]$\lambda=\frac{\left(6.626 * 10^{-34}\right)\left(3 * 10^8\right)}{(30) *\left(1.602 * 10^{-19}\right)}$[/tex]

λ = 4.136 * 10⁻⁸ m

λ = 41.36 x 10⁻⁹ m

λ = 41.36 nm → ultraviolet

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At the front of the eye, most of the focusing is performed by the cornea, a transparent membrane that bends light inward. The ideal selection is A. The cornea, which is transparent and forms the front of the eye.

Shields the iris and pupil. The anterior chamber, etc. Around two thirds of the optical power of the eye is refracted by the cornea, anterior chamber, and lens. Light, often known as visible light, is electromagnetic radiation that can be seen by humans. The wavelengths of visible light are commonly thought to range from 400 to 700 nanometers (nm), or from 750 to 420 terahertz. In physics, a force is an effect that has the ability to change how an object moves.

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The initial momentum of the bullet is 3.2 kg m/s.

The principle of conservation of linear momentum states that in an isolated system, the total momentum of the system is always conserved.

Based on the law of conservation of linear momentum, the sum of the initial momentum of an object is always equal to the sum of the final momentum of the object.

Pi = Pf

Pi = mv

where;

The initial momentum of the bullet is calculated as follows;

Pi = ( 400 m/s ) x ( 0.008 kg )

Pi = 3.2 kg m/s.

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According to the given question ,-53x10^10 electrons were transferred during this process

The negatively charged particles called as electrons revolve about the outside of the nucleus. For scientists, it might be hard to monitor them due to the way quickly they spin. The tiniest atoms in an atom, you can put 2000 of them in a proton, they are drawn to the positive ions of the protons.

Charge that the balloon has collected, q = 85 nC

e determines an electron's charge.

e = -1.6x10^-19 C

The amount of total value to the charge of one particle yields the number of electrons.

Suppose there are n electrons.

e = 85x10^-9/-1.6x10^-19 

= -53x10^10

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The electric motor takes 7,5 seconds to lift the 50 N. It is important to note that Power is a rate and energy is a scalar quantity.

To estimate the power required by a motor over a certain period of time, you would need to know the load that the motor will be driving (such as the weight of the object being moved, the resistance of the system, etc.) and the operating conditions (such as the speed at which the motor will be running, the duration of the operation, etc.).

Power = Force x velocity

From the text we know that the value of power is 1000 W. The value of force is 50 N and the distance is 150 m.

So, we get:

1000 = 50 N x velocity

Velocity = 20 m/s

To know how long a power rating of 1000 W can take the motor to lift a 50 N, we can use the formula:

s = v x t

Because we want to know the time, so the it will be

t = s/v

t = 150/20

t = 7,5 second

Or we can calculate it by this formula:

Power = work / time

Power = Force x distance/time

time = Force x distance / Power

time = 50 N x 150 m / 1000

time = 7,5 second

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The 70-kg skater acquires a speed of -0.125 m/s relative to the ice, meaning that it moves in the opposite direction of the 55-kg skater.

The distance traveled in a unit of time is called speed. It refers to a thing's rate of movement. The scalar quantity known as speed is the velocity vector's magnitude. It has no clear direction.

In this case, the two skaters and the ice are considered as a closed system since no external force is acting on them. Therefore, the total momentum before and after the skaters push off against one another must be the same.

We can use this principle to find the speed of the 70-kg skater relative to the ice. Let's call the speed of the 55-kg skater v1 and the speed of the 70-kg skater v².

We can use the formula for momentum p = m*v,

where m is the mass and v is the velocity.

The total momentum before the skaters push off is 0 (since they are at rest) and the total momentum after the skaters push off is:

p = (55 kg) * (0.175 m/s) + (70 kg) * v²

Since the total momentum is conserved, we can set the initial momentum to be equal to the final momentum:

0 = (55 kg) * (0.175 m/s) + (70 kg) * v²

Solving for v2, we get:

v2 = -(55 kg * 0.175 m/s) / 70 kg = -0.125 m/s.

The 70-kg skater acquires a speed of -0.125 m/s relative to the ice, meaning that it moves in the opposite direction of the 55-kg skater.

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The correct answer is Option 3: her moment of inertia increases and her angular speed increases. When the lady extends her arms out, her moment of inertia increases because she is now further away from the axis of rotation and the mass of her arms is now contributing to her moment of inertia. Since her moment of inertia increases, her angular speed must also increase in order to conserve angular momentum.

An earth satellite moves in a circular orbit at a speed of 4000 m/s, its orbital period is 648.84 hours.

Every particle in the universe is said to attract every other particle with a force along a line connecting them, according to Newton's universal law of gravitation. The force is inversely proportional to the square of the distance between them and directly proportional to the product of their masses.

F= G[tex]\frac{m1m2}{R^{2} }[/tex]

where F is Gravitational Force, G is Gravitational Constant (6.67×[tex]10^{-11}[/tex]Nm²/kg²), m is mass of the object and R is the distance between objects(m).

Given:

speed of the satellite is v=4000m/s.

mass of the earth=M=6×[tex]10^{24}[/tex] kg.

∑F=ma

G[tex]\frac{Mm}{R^{2} }[/tex]=m[tex]\frac{v^{2} }{R}[/tex]

G[tex]\frac{M}{R^{2} }[/tex] = [tex]\frac{v^{2} }{R}[/tex]

G[tex]\frac{M}{R\\}[/tex] = [tex]v^{2}[/tex]

R=G[tex]\frac{M}{v^{2} }[/tex]

2πR= 2πG[tex]\frac{M}{v^{2} }[/tex]

2πR/v= (2πG[tex]\frac{M}{v^{2} }[/tex]) /v

T= 2πG[tex]\frac{M}{v^{3} }[/tex]

T= 2π×6.67×[tex]10^{-11}[/tex]×[tex]\frac{6*10^{24} }{4000}[/tex]

T= 648.48 hours.

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"The work done in accelerating an object along a frictionless horizontal surface is equal to the change in the object's kinetic energy."

The amount of internal and mechanical energy that objects possess fluctuates as a result of work. When work is done on a system or an object, energy is contributed to it. When a system or item accomplishes work, some of its energy is transferred to something else.

Work involves the transfer of energy from the agent to the object, which modifies the object's motion.

The energy of motion is known as kinetic energy, and it can be observed in the motion of objects or subatomic particles. Kinetic energy can be found in all particles and moving objects. Examples of kinetic energy in action include a person walking, a baseball soaring through the air, a piece of food falling from a table, and a charged particle in an electric field.

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Jordan's car has more momentum because it weighs more.

Jordan's car accelerates faster due to its weight. Momentum is the result of a particle's mass and velocity. As a vector quantity, momentum has both magnitude and direction. Newton's second law, which may be expressed in its most general form as F = d p/dt, asserts that the force acting on a particle controls the rate of change of its momentum, p.

The second equation of motion of Isaac Newton states that the force applied to a particle is equal to the time rate of change of momentum. Since momentum depends on both the speed and the direction of the body's motion, it is expressed as "mass velocity." Since mass is a scalar and velocity is a vector, momentum is a vector quantity.

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The magnitude e of the electric field be if the charge is to hit the target on the screen is E = mv₀²yh/0.5qL².

Charge's speed in the x direction is equal to v₀.

The charge's time to reach the screen at a distance L, t = L/v₀

F = qE = ma, which is the force on the charge

When the two equations are equalized, force ma = qE/m and charge a = qE/m

The charge's initial velocity in the y-direction is o, and the vertical distance it covers is given by the equations

y = 0.5 (qE/m) (L/v₀)

y = 0.5qL²E/mv² and y = 0.5at².

If the target on the screen is the charge's intended target, y = yh

yh = 0.5qL²E/mv²

Making E the formula's subject, the following is the size of the electric field:

E = mv₀²yh/0.5qL².

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ghaegh agkl;agp oahjbkv w]ifskbv-ia]gaeglksrtbbthae atyaeyy

Plugging in the values given in the problem, we get: 1.69 * 10^-3 N.

Electric force is the force that exists between two objects that have an electric charge. It is one of the four fundamental interactions of nature, alongside gravitational force, the weak nuclear force, and the strong nuclear force.

The magnitude of the electric force that one particle exerts on the other can be calculated using the equation F = k * (q1 * q2)/r^2, where k is the Coulomb's Constant (k = 8.99 * 10^9 Nm^2/C^2), q1 and q2 are the charges of the two particles, and r is the distance between them.
Plugging in the values given in the problem, we get:
F = (8.99 * 10^9 Nm^2/C^2) * (8.08 nC * 4.02 nC)/(1.62 m)^2
F = 1.69 * 10^-3 N

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If the distance of the satellite from the surface of the moon varies from 357 km to 710 km, the equation of the ellipse is:

x²/(1669)² + y²/(1316)² = 1.

In mathematics, an ellipse is a planar curve with two focal points, where the total of the two distances from any point on the curve to the focal points is a constant.

Length of semi-major axis = (959 km + 710 km) = 1669 km.

Length of semi-minor axis = (959 km + 357 km) = 1316 km.

Hence, the equation of the ellipse is:

x²/(1669)² + y²/(1316)² = 1.

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Answer:

To find the number of antinodes in the standing wave pattern, we need to find the wavelength of the fifth harmonic. The fifth harmonic has a frequency of 5 times the fundamental frequency, and the fundamental frequency is equal to the speed of sound divided by the length of the pipe. Thus, the wavelength of the fifth harmonic is the speed of sound divided by 5 times the fundamental frequency, which is equal to 340 m/s / (5 * (340 m/s / 1.5 m)) = 0.3 m.

Since the length of the pipe is 1.5 m, and the wavelength is 0.3 m, there will be 1.5 m / 0.3 m = 5 full wavelengths in the pipe. Since there is an antinode at both ends of the pipe, there will be a total of 5 + 2 = 7 antinodes in the standing wave pattern. Therefore, the correct answer is (C) 7.

The  height of the cliff is 43.6 m.

The height of the cliff is calculated by applying the following kinematic equation as shown below.

h = vt + ¹/₂gt²

where;

The  height of the cliff is calculated as follows;

h = ( 12 m/s x 2 s )   +   ¹/₂ ( 9.8 m/s² ) x ( 2.0 s )²

h = 43.6 m

Thus, the height of the cliff is a function of the initial velocity, time of motion and acceleration due to gravity.

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Car A and car B of equal mass travel up a hill. Car A moves up the hill at a constant speed that is twice the constant speed of car B. Compared to the power developed by car B, the power developed by car A is four times as great.

The power developed by a vehicle is the product of its mass and acceleration. Car A has the same mass as car B but is traveling at twice the speed. Therefore, if the speed of Car A is double the speed of Car B, then the acceleration of Car A must be double that of Car B. This means that the power developed by Car A must be four times the power developed by Car B.

This is because the power is equal to the mass multiplied by the acceleration, so if the acceleration is double, then the power must also be double. The power of a vehicle also depends on the amount of friction, or resistance, it encounters. Since Car A and Car B have the same mass, any difference in the power developed by each car is solely due to the difference in their speeds. Therefore, the power developed by Car A is four times that of Car B.

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