an ac voltage of 12.0 v is applied to the primary transformer that has 3 times as many turns in the secondary than in the primary. what is the voltage of the secondary?

The height of the image is -6 cm.

The reflecting surface of a concave mirror is curled inward and away from the light source. Light is reflected inward to a single focus point via concave mirrors. Concave mirrors, in contrast to convex mirrors, produce a variety of images depending on the object's to the mirror.

Given that, an object placed 36 cm from a concave mirror having the focal length of 12 cm and height of image is 2.50 cm

We have to find height of the Image

Using Mirror Formula:

1/f = 1/v + 1/u

Where,

f = focal length

v =  Image distance from the mirror

u = object distance from the mirror (concave)

Substitute the known values in the above formula to find the value of 'v' i.e. from the mirror.

1/(-12) = 1/v + 1/(-36)

1/(-12) = 1/v - (1/36)

1/v = -0.055

v = -18 cm

Therefore, Image distance the from the concave mirror is -18 cm.

Now,

m = -v/u = hi/h

Substitute the values,

-(-18)/(-36) = hi/12

-0.5 = hi/12

-6 = hi

Therefore, the height of the image is -6 cm.

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Answer:

Pressure will triple   (Boyle's Law)  

Explanation:

Assuming a constant temperature:  (compressing gases usually raises the temp significantly):

P1V1 = P2V2

P1V1 / V2   = P2      

   Now change V2  to 1/3 V2:

P1V1 / (1/3 V2 ) = P2 / (1/3 )

P1V1/ (1/3 v2 ) = 3 P2                <======= THE PRESSURE WILL TRIPLE

    This is Boyle's Law

Answer:

A 2kg block is moved a long a level floor by a horizontal force of 20N if the coefficient of sliding friction is 0.4

what is the acceleration of the blove

The force result in stretching the spring 10.0 centimeters is 2.5N.

If a spring is stretched from its equilibrium position, then a force with magnitude proportional to the increase in length from the equilibrium length is pulling each end.

F = kx

where k is the proportionality constant called the spring constant or force constant.

Up to a point, the elongation of a spring is directly proportional to the force applied to it. Once you extend the spring more than 10.0 centimeters, however, it no longer follows that simple linear rule.

Let the spring constant be very low 0.04N/m

The force applied is

F = 10 cm / 0.04

F = 0.1 m  / 0.04

F = 2.5 N

Thus, the force result in stretching the spring 10cm is 2.5 N.

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Answer: 2.5 newtons

source- trust me bro

Answer:

8.4335 x 10^-²¹, 1.78204 x 10²⁶

Explanation:

p = mv

p = (5.05 x 10⁶)(1.67 x 10^-²⁷)

p = 8.4335 x 10^-²¹

p = mv

p = (5.98 x 10²⁴)(2.98 x 10)

p = 1.78204 x 10²⁶

Answer:

Approximately [tex]14\; {\rm N}[/tex].

Explanation:

By Coulomb's Law, the magnitude of the electrostatic force between two charges is proportional to the product of the magnitudes of the two charges.

For example, consider charges of magnitude [tex]q_{1}[/tex] and [tex]q_{2}[/tex] that are apart from one another by a distance of [tex]r[/tex] in between. Let [tex]k[/tex] denote Coulomb's constant. By Coulomb's Law, the magnitude of electrostatic force between the two charges would be:

[tex]\displaystyle F = \frac{k\, q_{1}\, q_{2}}{r^{2}}[/tex].

In this question, the product of the magnitude of the two charges was originally [tex]3\; {\rm \mu C} \times 7\; {\rm \mu C} = 21\; {\rm (\mu C)^{2}}[/tex]. After [tex](-1\; {\rm \mu C})[/tex] is added to each charge, product of the magnitude of the two charges would become [tex](3 - 1)\; {\rm \mu C} \times (7 - 1)\; {\rm \mu C} = 12\; {\rm (\mu C)^{2}}[/tex].

Thus, the product of the magnitude of the two charges has been scaled to [tex]12\; {\rm \mu C}[/tex] from [tex]21\; {\rm \mu C}[/tex] . The magnitude of the electrostatic force between the two charges would be scaled from [tex]25\; {\rm N}[/tex] to [tex]25\; {\rm N} \times (12 / 21) \approx 14\; {\rm N}[/tex].

The time taken for the sailfish to reach the herring if it is 55.0 m away is 2.7 s.

The time taken for the star fish to travel the given distance is calculated as follows;

s = ut + ¹/₂at²

55 = 11.8t + (0.5)(6.39)t²

55 = 11.8t + 3.195t²

3.195t² + 11.8t - 55 = 0

solve the quadratic equation using formula method,

where;

a = 3.195, b = 11.8, c = -55

t = 2.7 s

Thus, the time taken for the sailfish to reach the herring if it is 55.0 m away is 2.7 s.

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The time taken for the plant to hit the ground from a distance of 7.01m and at a velocity of 8.84m/s is 1.59s.

The time taken for a motion to occur can be calculated using the following formula:

v² = u² - 2as

Where;

8.84² = 0² + 2 × a × 7.01

78.15 = 14.02a

a = 5.57m/s²

V = u + at

8.84 = 0 + 5.57t

t = 1.59s

Therefore, the time taken for the plant to hit the ground from a distance of 7.01m and at a velocity of 8.84m/s is 1.59s.

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Answer:

from my side the will be b only the mass of the planet thank you

Answer:

D

Explanation:

W=mg

g=GM/r²(G=Gravitational constant, M=mass of earth, r=Radius of earth)

>>W=m(GM/r²)

W is directly proportional to mass of earth and mass of your body

Answer:

it is double the temperature change of iron

A valve placed is before the rotameter to regulate the flow of liquid entering the extraction bed. The correct option is c.

Control valves are generally used to maintain a flow as close as possible to the desired value.

Valves positioned before the rotameter for throttling purposes. A control valve will regulates the rate of fluid flow. Control valves control typically flow rate, pressure, and temperature.

Thus, the correct option is c.

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We can obtain the velocity from the graph and plot is against time to obtain a velocity time graph.

The velocity time graph shows the change of velocity with time. Recall that velocity is the change of position with time.

As such, when we have a position time graph as shown, we can obtain the velocity from the graph and plot is against time to obtain a velocity time graph.

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Answer:

A.) It decreases

Explanation:

Generally, as you go from the top to the bottom of the periodic table (down a column), the electronegativity values of the elements decrease.

Also, as you move to the right of the periodic table (across a period), the electronegative values increase. The most electronegative elements are located on the top-right of the periodic table.

Answer:equal mass

Explanation:the mass of both is 5kg

The direction of this vector is 170° from the positive x-axis.

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Answer:

a = (V2 - V1) / t      equation  for constant acceleration

if t the independent variable is placed on the abcissa or x-axis and V the dependent variable is placed on the ordinate or y-axis then the acceleration would be the slope at the point considered.

The number of significant digits to the answer of the following problem is four.

The number of digits rounded to the approximate integer values are called the significant digits.

The following problem is

(2.49303 g) * (2.59 g) / (7.492 g) =

On solving we get

= 0.86184566204

The answer is approximated to  0.86185

Thus, the significant digits must be four.

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It is defined as the stress that results in the elongation of the material

Answer

688.32m and 277.44m

Explanation :

⠀

[tex] \large{\maltese{\textsf{\underline{To find :-}}}} [/tex]

The X and Y coordinates of the rocket relative of firing

⠀

⠀

[tex] \large{\maltese{\textsf{\underline{Given :-}}}} \\ \\ \sf velocity (v_i) = 100m{s}^{-1} \\ \sf angle ({\theta}_{1}) = 55.0{\degree} \\ \sf time (t) = 12s [/tex]

⠀

⠀

[tex] \Large{\maltese{\textsf{\underline{\underline{Step by Step Solution:-}}}}} [/tex]

⠀

⠀

The horizontal range of projectile at x.

⠀

[tex] \sf \large{x = v_{xi}} \times t \\ \\ \sf \large{x = v_i \times \cos {\theta}_{i} \times t} [/tex]

⠀

⠀

[tex] \large\textsf{\underline{Now substituting the required values}} [/tex]

⠀

⠀

[tex] \sf x = 300 \times \cos 55{\degree} \times 12 \\ \\ \sf x = 100 \times 0.5756 \times 12 \\ \\ {\underline{\boxed{\bold{ x = 688.32m}}}} [/tex]

⠀

⠀

The vertical position of projectile at y.

⠀

⠀

[tex]\sf \large y = v_{yi} \times t - (\frac{1}{2} \times g \times {t}^{2}) \\ \\ \sf \large y = v_i \times \cos \theta \times t - \frac{1}{2} g {t}^{2} [/tex]

⠀

⠀

[tex]\textsf{ \large {\underline{Now substituting the required values}} } [/tex]

⠀

⠀

[tex] \sf y = 100 \times \cos55{ \degree} \times 12 - \frac{1}{2} \times 9.80 \times {12}^{2} \\ \\ \sf y = 100 \times 0.8192 \times 12 - 0.5 \times 9.8 \times 144 \\ \\ \sf y = 983.04 - 705.6 \\ \\ \underline{ \boxed{ \bold{y = 277.44m}}} [/tex]

⠀

⠀

⠀

Answer:

Multiple so you can test multiple hypothesis at once

Explanation:

because

Answer:

To test the hypothesis, we need to make an observation or perform an experiment associated with the prediction. For instance, in this case, we would plug the toaster into a different outlet and see if it toasts.

inspired by answer up there

sorry i couldn't add details because think its bad

Hypothesis testing is a formal procedure for investigating our ideas about the world using statistics. It is most often used by scientists to test specific predictions, called hypotheses, that arise from theories.

(a) From the first sentence, particularly goes with condition.

(b) From the second sentence, everybody goes with is.

(c) From the third sentence, forecasts goes with enable.

In subject- verb agreement, if a subject is singular, its verb must also be singular and if a subject is plural, its verb must also be plural.

From the first sentence, the correct subject-verb agreement is;

The release of energised particles from the sun , coupled with particularly helpful overnight condition, are predicted to make the "Northern Lights" visible much further south than normal.

From the second sentence, the correct subject-verb agreement is;

'Everybody is talking about it. It's a once-in-a-decade opportunity that people really shouldn't miss.'

From the third sentence, the correct subject-verb agreement is;

'The forecasts given out by the weather office enable us to know when the skies will be clear.

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The speed of a 16cm wave with a period of 8 seconds is 2cm/s

Using the formula;

Speed = distance ÷ time

Distance = 16cm

time = 8 seconds

Substitute into the formula

Speed = 16 ÷ 8

Speed = 2 cm/s

Therefore, the speed of a 16cm wave with a period of 8 seconds is 2cm/s

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Answer:

u=speed, w=wavelenght, f=frequency

It's known that u=w*f =>  f=u/w

                                       u=20m/s     ==>  f=20/0,5  => f=40 Hz

                                       w=0,50m

Explanation:

Whenever a wave is brought on by a cool summer breeze across the field. The grass tilts in the wind's direction before reverting to its original posture. Option A is correct.

Air pressure variations within our atmosphere result in the wind, which is the movement of air.

Areas with a low pressure are approached by air in high pressure. The air flows more quickly when there is a bigger pressure differential. Most rapid winds.

The wind is the movement of air produced by changes in air pressure in our atmosphere.

High-pressure air goes toward low-pressure locations. The bigger the pressure differential, the faster the air moves.

Hence, option A is correct.

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Statement B  is true about the energy level of gas, Gases have more energy than liquids and solids.

A gas is a sample of matter that adopts the shape of the container in which it is housed and develops a uniform density inside the container.

Liquid molecules are more energetic than solid molecules. Further heating will cause the molecules to move so quickly that they won't stick together at all. The gas molecules have the highest energy content.

Gases have more energy than liquids and solids.

Hence statement B  is true about the energy level of gas.

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The flux of [tex]\vec E = -x\,\vec\imath + y\,\vec\jmath[/tex] is given by the surface integral

[tex]\displaystyle \iint_S \vec E \cdot d\vec\sigma[/tex]

where [tex]S[/tex] is the given square region, which we can parameterize by

[tex]\vec s(x, z) = x\,\vec\imath + z\,\vec k[/tex]

with [tex]0\le x\le 1[/tex] and [tex]0\le z\le 1[/tex]. The area element is

[tex]d\vec\sigma = \vec n \, dx\,dz[/tex]

where [tex]\vec n[/tex] is the normal vector to [tex]S[/tex]. Depending on the orientation of [tex]S[/tex], this vector could be

[tex]\vec n = \dfrac{\partial\vec s}{\partial x} \times \dfrac{\partial\vec s}{\partial z} = -\vec\jmath[/tex]

or [tex]-\vec n = \vec \jmath[/tex]; either way, the integral reduces to

[tex]\displaystyle \iint_S \vec E \cdot d\,\vec\sigma = \int_0^1 \int_0^1 (-x\,\vec\imath + z\,\vec k) \cdot (\pm\vec\jmath) \, dx\,dz = \boxed{0}[/tex]

The minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]

If an object is lifted, work is done against gravitational force. The object gains energy.

Given are space stations Alpha and Beta located on the line between the planets. Both space stations are at rest with respect to the planets. Alpha is at distance d 4 from planet 1 and Beta is at distance d 3 from planet 2. A projectile of mass m is fired from station Alpha, with its velocity v pointing directly at planet 2.

The range of the projectile is given by R =  v²sin2θ / g

g = gravitational acceleration of Earth

If g = g(p) for planet , range  R =  v²sin2θ / g(p)..................(1)

The gravitational force of attraction = weight force

Gm² /d² = m g(p)

g(p) = Gm/d².........................(2)

For R = d/3, from equation (1), we have

d/3 =  v²sin2θ / g(p)

Plug the expression for g(p) , we get

v = √ [Gm/3dsin2θ ]

For velocity to be minimum, sin2θ =1

So, the minimum velocity will be

v = √ [Gm/3d]

Thus, the minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]

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(a) The time for a particle of water leaving the orifice to reach point B is 0.63 s.

(b) The horizontal distance x where it hits from surface is 3.94 m.

The time of the water to reach the surface is calculated as follows;

h = ¹/₂gt²

2h = gt²

t² = 2h/g

t = √(2h/g)

where;

t = √( (2 x 2)/(9.8) )

t = 0.63 s

The horizontal distance is calculated as follows;

X = vt

where;

X = (√2gh)t

X = (√2 x 9.8 x 2) x 0.63

X = 3.94 m

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Sentences A and D describe examples of energy transformation.Heat is produced when a car's tires rub against the pavement and as electricity passes across power wires, they become hotter.

According to the law of conservation of energy, the energy of an isolated system stays unchanged throughout time.it is said to be conserved.

Energy cannot be created nor destroyed and can be transferred from one form to the other form.

The complete question is

"When energy is moved from one component of a system to another, some of the energy is lost and cannot be used as planned.

Which two statements provide examples?

A. Friction between a car's tires and the road produces heat.

B. Sunlight strikes a solar panel, generating electricity.

c. Stereo speakers emit a sound when powered by electrical energy,

D. Wind moves a turbine, generating electricity.

I E. Power lines heat up as electricity flows through them."

Some of the energy wasted during the movement of energy from one section of a system to another is heat is produced by friction between a car's tires and the road and as electricity passes via power lines, they heat up.

Hence, sentences A and D describe examples of energy transformation.

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