An SEO account manager is concerned website developers are using too many keywords per web page. The SEO account manager would like to carry out a hypothesis test and test the claim that a web page has, on average, more than 10 keywords. Why is this hypothesis test right-tailed?
Select the correct answer below:
This is a right-tailed test because a direction is not specified.
This is a right-tailed test because a direction is specified. The population parameter is greater than the specified value.
This is a right-tailed test because a direction is specified. The population parameter is less than the specified value.
More information is needed.

Yes, it is true that if A is a 3×3 matrix and the equation Ax = [1, 0, 0] has a

unique solution, then A is invertible.

To see why, suppose that A is not invertible.

Then there exists a non-zero vector v such that Av = 0.

Multiplying both sides of the equation Ax = [1, 0, 0] by v, we get Av = 0,

which means that the equation has no solution or infinitely many solutions,

contradicting the assumption that it has a unique solution.

Therefore, if the equation Ax = [1, 0, 0] has a unique solution, then A must

be invertible.

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The digit 4 in 8.4 has a value of 0.4, which is indeed 1/10 the value of the digit 4 in 7.4.

The digit 4 in the number 7.4 has a value of 4 tenths or 0.4. To find a number where the value of the digit 4 is 1/10 of this value, we need to find a number that has a digit 4 in the tenths place and a digit in the ones place that is 10 times greater than 7.

Let's consider the number 8.4. In this number, the digit 4 is in the tenths place and the digit 8 is in the ones place. The value of the digit 4 in this number is 4 tenths or 0.4, which is 1/10 the value of the digit 4 in 7.4.

To check, we can calculate the value of the digit 4 in 8.4 as follows:

4/10 + 8 = 8.4

Therefore, the answer is 8.4.

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a. A tea bag is considered small if it weighs less than 2.626 grams.

b. The probability that it weighs at least 2.25 grams is 17.07%.

The probability of an event occurring is defined by probability. There are many instances in real life where we may need to make predictions about how something will turn out. The outcome of an event may be known to us or unknown to us. When this happens, we say that there is a chance that the event will happen or not.

(a) Let X be the weight of a tea bag. Then X ~ N(3.5, 0.53²). We want to find the value of w such that P(X < w) = 0.052. Using the standard normal distribution, we have:

(P(X < w) - P(X < 3.5)) / 0.53 = z

where z is the 0.052 quantile of the standard normal distribution. Using a standard normal table or calculator, we find that z ≈ -1.645. Substituting the values and solving for w, we get:

(w - 3.5) / 0.53 = -1.645

w - 3.5 = -0.874

w ≈ 2.626

Therefore, a tea bag is considered small if it weighs less than 2.626 grams.

(b) We want to find P(X ≥ 2.25 | X < 2.626), which is the conditional probability that a selected tea bag weighs at least 2.25 grams given that it is small. Using the properties of the normal distribution, we have:

P(X ≥ 2.25 | X < 2.626) = P((X - 3.5) / 0.53 ≥ (2.25 - 3.5) / 0.53 | (X - 3.5) / 0.53 < (2.626 - 3.5) / 0.53)

= P(Z ≥ -2.358 | Z < -1.566)

where Z is a standard normal random variable. Using a standard normal table or calculator, we find that:

P(Z ≥ -2.358) ≈ 0.990

P(Z < -1.566) ≈ 0.058

Therefore, P(X ≥ 2.25 | X < 2.626) ≈ 0.990 / 0.058 ≈ 17.07%.

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If gender and handedness were independent, it would mean that the proportion of left-handed individuals would be the same for both men and women, and that knowing someone's gender would not provide any information about their handedness.

Gender and handedness are associated because women are more likely to be left-handed than men. D

The fact that women are about six times as likely to be left-handed as men suggests that there is a relationship between gender and handedness, and that knowing someone's gender can provide some predictive power for their handedness.

To conclude that gender and handedness are associated.

The proportion of left-handed people would be the same for both men and women if gender and handedness were independent, and knowing someone's gender would not reveal anything about their handedness.

Given that women are more likely to be left-handed than males, gender and handedness go hand in hand.

Given that women are almost six times more likely to be left-handed than males, there may be a correlation between gender and handedness, and one's gender may be able to predict someone's handedness.

to draw the conclusion that handedness and gender are related.

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The numerator and denominator is D. 3 and 116.

In fractions, the numerator and denominator are the two constituent parts. They comprise fractions, in other words. A fraction's top digit is always referred to as the numerator. It displays the quantity of our parts. A fraction's numerator—the lowest digit—is referred to as the denominator. It displays the overall number of pieces that something can be broken down into.

For an ANOVA procedure with k groups (in this case, k=4), the degrees of freedom for the numerator and denominator of the F-statistic are given by:

- Numerator degrees of freedom: k-1

- Denominator degrees of freedom: n-k, where n is the total sample size (in this case, n=4*30=120)

Therefore, for the given ANOVA procedure with four samples of 30 observations each, the numerator and denominator degrees of freedom for the critical value of F are:

- Numerator degrees of freedom: 4-1 = 3

- Denominator degrees of freedom: 120-4 = 116

So the answer is D. 3 and 116.

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The original price of the luxury car was $73,000.

The equation is in the form of y = mx + b.

The y represents the value of the car

The x represents the number of years since its purchase

The m represents the depreciation rate per year

The b represents the original value of the car.

From this, we see that the depreciation rate per year is -2,500. To find the original value of the car, we set x = 0 and solve for y:

y = -2,500(0) + 73,000

y = 73,000.

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The area of window is 14.56 sq ft. The contractor should pay $101.92 to replace the window.

a) To find the area of the window, we need to use the formula for the area of a trapezoid, which is:

Area = (1/2) * (sum of parallel sides) * (height)

In this case, the sum of the parallel sides is 4 + 5 = 9 feet, and we know that one of the other sides is 3 feet. To find the height, we need to use the Pythagorean theorem:

[tex](Height)^{2}[/tex] = [tex](5-4.5)^{2}[/tex] +[tex]3^{2}[/tex]

[tex](Height)^{2}[/tex] = 0.25 + 9

[tex](Height)^{2}[/tex] = 9.25

Height ≈ 3.04 feet

So the area of the trapezoidal window is:

Area = (1/2) * (4 + 5) * 3.04

Area ≈ 14.56 square feet

b) To find the cost of replacing the window, we need to multiply the area of the window by the cost per square foot of the glass. In this case, the cost is $7 per square foot. So the cost of replacing the window is:

Cost = Area * Cost per square foot

Cost = 14.56 * 7

Cost ≈ $101.92

Therefore, the contractor should expect to pay about $101.92 to replace the window with glass that costs $7 per square foot.

Correct Question :

A contractor is replacing a trapezoidal window on the front of a house with measurements as length of parallel side be 4ft and 5 ft and the length of one of the two other side is 3 ft.

a) find the area of the window. ft

b) if the glass for the window costs $7 per square foot, about how much should the contractor expect to pay to replace the window?

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The trend in the boiling points of the molecules shown is primarily determined by their intermolecular forces. As the intermolecular forces between molecules increase, so does the boiling point.
Based on the information given, we need to identify statements that explain the trend in boiling points of molecules with similar or identical molecular weight. When considering boiling point trends, key factors to take into account are molecular size, polarity, and intermolecular forces.

In conclusion, Molecules with stronger intermolecular forces, such as hydrogen bonding or dipole-dipole interactions, typically have higher boiling points. Additionally, molecules with larger surface areas or more polar bonds may exhibit higher boiling points due to increased interactions between the molecules.

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The degree of the polynomial P(x) is 2.

Let the degree of the polynomials P(x) and Q(x) be 'm' and 'n' respectively.

deg {P(x)} = m

deg {Q(x)} = n

So deg {P(x²)} = 2m

and deg {Q³(x)} = 3n

Given that the degree of polynomial {P(x²).Q³(x)} is 12.

So, 2m*3n = 12

6mn = 12

mn = 12/6

mn = 2

n = 2/m ..................... (i)

Again, deg {P³(x)} = 3m

deg (Q(x)) = n

Now given that, deg[P³(x)/Q(x)] = 7

So, 3m/n = 7

3m = 7n

3m = 7*(2/m) [Using the equation (i)]

3m² = 14

m² = 14/3

m = 2 (approximating to nearest whole number)

Hence, the degree of the polynomial p(x) is 2.

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Based on the given information, we can assume that the survey has a 95% confidence level, which means that the margin of error can be calculated using the formula:

Margin of Error = (maximum difference in percentage points / 2)

The maximum difference in percentage points between the two candidates is 53% - 47% = 6%. Dividing this by 2 gives us a margin of error of 3%. Therefore, we can say that the results of the phone survey indicate that between 44% and 56% of voters may choose candidate a over candidate b (with a margin of error of +/- 3%).

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If a force of 18 lb is required to hold a spring stretched 2 inches, the work done in stretching the spring from its natural length to 4 inches beyond is 72 lb*in.

To find the work done in stretching the spring from its natural length to 4 inches beyond, we need to first find the spring constant k.

Using Hooke's law, we know that F = kx, where F is the force applied, x is the displacement from the natural length, and k is the spring constant.

So, when the spring is stretched 2 inches beyond its natural length, we have:

18 lb = k * 2 in

Solving for k:

k = 9 lb/in

Now, to find the work done in stretching the spring from its natural length to 4 inches beyond, we use the equation for work:

W = (1/2)kx²

Where x is the displacement from the natural length, which in this case is 4 - 0 = 4 inches.

W = (1/2) * 9 lb/in * (4 in)²

W = 72 lb*in

So, the work done in stretching the spring from its natural length to 4 inches beyond is 72 lb*in.

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The dimensions of the rectangular sticker with perimeter of 20 centimeters and area of 21 square centimeters are either 3 cm by 7 cm or 7 cm by 3 cm.

To find the dimensions of the rectangular sticker, we need to use the given information about its perimeter and area. Let's start by using the formula for perimeter of a rectangle:

Perimeter = 2(length + width)

We know that the perimeter of the sticker is 20 centimeters, so we can write:

20 = 2(length + width)

Simplifying this equation, we get:

length + width = 10

Now let's use the formula for area of a rectangle:

Area = length x width

We know that the area of the sticker is 21 square centimeters, so we can write:

21 = length x width

We now have two equations with two variables (length and width). We can use substitution to solve for one of the variables. Let's solve for width in terms of length using the perimeter equation:

width = 10 - length

Now we can substitute this expression for width into the area equation:

21 = length x (10 - length)

Expanding the right side, we get:

21 = 10 length - length^2

Rearranging and simplifying, we get a quadratic equation:

length^2 - 10 length + 21 = 0

We can solve this quadratic equation using factoring or the quadratic formula. Factoring gives us:

(length - 3)(length - 7) = 0

So the possible values for length are 3 and 7. If we plug these values into the width equation, we get:

width = 10 - length

For length = 3, width = 7
For length = 7, width = 3

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Answer:

B. no, the survey represented both groups in the population of students

Step-by-step explanation:

It says, "surveyed all students"

If the equation of the line that contains diagonal MT is y = -2x + 3, the equation of the line that contains diagonal AH is y = -2x + 3.

In a rhombus, the diagonals intersect at a 90-degree angle and bisect each other. Therefore, if the point of intersection of the diagonals is known, we can find the equations of the diagonals by using the midpoint formula and the slope formula.

To find the equation of the diagonal that contains point A, we first need to find the coordinates of point A. Since the diagonals bisect each other, point A is the midpoint of diagonal MT. We can use the midpoint formula to find the coordinates of point A:

x = (x₁ + x₂)/2 and y = (y₁ + y₂)/2

x = (4 + x₂)/2 and y = (-5 + y₂)/2

Multiplying both sides by 2, we have:

2x = 4 + x₂ and 2y = -5 + y₂

Simplifying, we have:

x₂ = 2x - 4 and y₂ = 2y + 5

Now, we can use the slope formula to find the slope of the diagonal AH. Since diagonal MT has a slope of -2, we know that the product of the slopes of the diagonals of a rhombus is -1. Therefore, the slope of diagonal AH is:

m = 1/2 = -1/m'

where m' is the slope of the line that contains diagonal AH.

Solving for m', we have:

m' = -2

Now we have the slope and a point on the diagonal AH (point A). We can use the point-slope form of the equation of a line to find the equation of diagonal AH:

y - (-5) = -2(x - 4)

y + 5 = -2x + 8

y = -2x + 3

In conclusion, we can find the equation of the diagonal that contains point A in a rhombus by using the midpoint formula and the slope formula. Since the diagonals of a rhombus bisect each other and are perpendicular, we can use this information to find the equation of the second diagonal once we know the equation of the first diagonal.

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kelly  clark has different books to arrange on a shelf: 4 blue, 3 green, and 2 red  The books can be arranged on a shelf in 9!/(4!3!2!) = 1260 ways

(a) The books can be arranged on a shelf in 9!/(4!3!2!) = 1260 ways.

(b) If books of the same color are to be grouped together, we can treat each group as a single "super book." Then, there are 3! = 6 ways to arrange the three "super books" on the shelf. Within each group, the books can be arranged in the same number of ways as in part (a), so the total number of arrangements is 6 x 4!/(2!) = 144.

(c) There are 4 ways to choose a blue book, 3 ways to choose a green book, and 2 ways to choose a red book, for a total of 4 x 3 x 2 = 24 ways.

(d) There are 4 ways to choose a first book, 3 ways to choose a second book (since one color has already been chosen), and 2 ways to choose a third book (since two colors have already been chosen), for a total of 4 x 3 x 2 = 24 ways.

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Answer: We can simplify the left side of the equation as follows:

7×10^0 - 3×10^-1 = (7/1)×10^0 - (3/10)×10^0 = (7-0.3)×10^0 = 6.7×10^0

Substituting this into the given equation, we get:

6.7×10^0 = k×10^0

Dividing both sides by 10^0, we get:

k = 6.7

Therefore, the value of k that satisfies the given equation is 6.7.

Answer:

x - matinee tickets

y - evening tickets

x≥0

y≥0

5x+8y≤40

the probability of choosing exactly 5 red marbles when 12 marbles are chosen at random is approximately 0.028.

This is a hypergeometric probability problem .

The total number of ways to choose 12 marbles from 27 is:

${{27}\choose{12}} = \frac{27!}{12!15!} = 10,!626,!766$

The number of ways to choose 5 red marbles and 7 blue marbles is:

$ {{15}\choose{5}}\cdot{{12}\choose{7}} = \frac{15!}{5!10!}\cdot\frac{12!}{7!5!} = 300,!450$

So the probability of choosing exactly 5 red marbles is:

$P(\text{5 red}) = \frac{300,!450}{10,!626,!766} \approx 0.028$

what is probability?

Probability is the measure of the likelihood or chance of an event occurring. It is a quantitative measure that ranges from 0 to 1, where 0 indicates an impossible event and 1 indicates a certain event.

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The value of the integral is -3ln(8)/8 + 21/8.

The summing of discrete data is indicated by the integration. To determine the functions that will characterise the area, displacement, and volume that result from a combination of small data that cannot be measured separately, integrals are calculated.

We can evaluate the integral using integration by parts:

Let u = ln(x) and dv = 3/x² dx. Then, du = 1/x dx and v = -3/x.

Using the formula for integration by parts, we have:

∫3ln(x)/x² dx = u*v - ∫v*du

= ln(x)*(-3/x) - ∫(-3/x)*1/x dx

= -3ln(x)/x + 3∫1/x² dx

= -3ln(x)/x - 3/x + C

where C is the constant of integration.

Now, we can evaluate the definite integral from 1 to 8:

∫1⁸ 3ln(x)/x² dx

= [-3ln(x)/x - 3/x]_1⁸

= [-3ln(8)/8 - 3/8] - [-3ln(1)/1 - 3/1]

= -3ln(8)/8 - 3/8 + 3

= -3ln(8)/8 + 21/8

Therefore, the value of the integral is -3ln(8)/8 + 21/8.

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Answer:

Step-by-step explanation:

Let's start by finding out how much soup was initially in the pot. We know that Erin, Shelby, and all 8 of their children ate some soup, but we don't know how much.

If we add up the amounts left in the bowls, we can find out how much soup they didn't eat:

3 kids left 3/4 cup each = 3 * 3/4 = 9/4 cups

2 kids left 1/4 cup each = 2 * 1/4 = 1/2 cup

3 kids left 1/2 cup each = 3 * 1/2 = 3/2 cups

Adding these amounts together:

9/4 + 1/2 + 3/2 = 5 cups

So they left 5 cups of soup in their bowls.

If we assume that each person had one serving of soup (even though some left some in their bowls), and that each serving was the same size, then the amount of soup they didn't eat is equal to the amount of soup that was left in the pot.

So, the amount of soup left over is 5 cups.

Answer:

2 specials are made possible

Step-by-step explanation:

2 of each category

Answer:

The answer is 6

Step-by-step explanation:

The answer is the total number of drinks,sandwiches and desserts

T(s)=2+2+2=6

Answer:

9000

Step-by-step explanation:

There are a total of 9000 integers between 1000 and 9999 but every second number is even

The pattern that occurs d⁹⁵/dx⁹⁵ sin(x)  is -cos(x)

To find the derivative of d^95/dx^95 sin(x), we can use the fact that the derivative of sin(x) is cos(x) and that the derivative of cos(x) is -sin(x). Therefore, the pattern for the derivatives of sin(x) is:

d/dx sin(x) = cos(x)

d²/dx² sin(x) = -sin(x)

d³/dx³ sin(x) = -cos(x)

d⁴/dx⁴ sin(x) = sin(x)

d⁵/dx⁵ sin(x) = cos(x)

d⁶/dx⁶ sin(x) = -sin(x)

d⁷/dx⁷ sin(x) = -cos(x)

d⁸/dx⁸ sin(x) = sin(x)

We can see that this pattern repeats every 4 derivatives. Therefore, we can simplify the expression d^95/dx^95 sin(x) by dividing 95 by 4 and finding the remainder:

95 ÷ 4 = 23 remainder 3

This tells us that the 95th derivative of sin(x) will be the same as the third derivative of sin(x), which is:

d⁹⁵/dx⁹⁵ sin(x) = d³/dx³ sin(x)

= -cos(x)

Therefore,  the pattern that occurs d⁹⁵/dx⁹⁵ sin(x) is -cos(x).

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Answer:

do the opposite

Step-by-step explanation:

multiply 8 times 4(instead of dividing)

x= 32

The test statistic value is -2.03.

What is the mean and standard deviation?

In statistics, the measurement of variability known as the standard deviation (SD) is frequently utilised. It displays the degree of variance from the mean (average). While a high SD shows that the data are dispersed throughout a wide range of values, a low SD suggests that the data points tend to be close to the mean.

We can use a one-sample t-test to test whether the mean endurance time of the tires is significantly different from the claimed value of 40000 km. The test statistic is given by:

[tex]t = (x - \mu) / (s / \sqrt{(n)})[/tex]

where x is the sample mean (39750 km), μ is the claimed mean (40000 km), s is the sample standard deviation (387 km), and n is the sample size (25).

Substituting the values, we get:

[tex]t = (39750 - 40000) / (387 / \sqrt{25})[/tex]

t = -250 / (387/5)

t = -2.03

Therefore, the test statistic value is -2.03.

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To compare the mean math anxiety levels for participants in treatment condition A to the mean math anxiety levels for participants in treatment condition B, a two-sample t-test would be appropriate. This test is used to compare the means of two independent groups and assumes normally distributed populations with equal variances.

To compare the mean math anxiety levels for participants in treatment condition A to the mean math anxiety levels for participants in treatment condition B, a two-sample t-test would be an appropriate statistical test.

This test is used to determine if there is a significant difference between the means of two independent groups. Since the participants were randomly assigned to each treatment condition, the groups can be considered independent.

The two-sample t-test compares the means of the two groups while taking into account the variance of each group.

It assumes that the populations being sampled from are normally distributed and have equal variances. If these assumptions are not met, other statistical tests such as non-parametric tests may be more appropriate.

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Answer:

84

Step-by-step explanation:

A= Bh

Base is 12

Height is 7

= 84

Answer:

84

Step-by-step explanation:

To find the smallest possible value of n, we need to consider the cost of each candy option. We know that each piece of candy costs a whole number of cents,

which means that the cost of 12 pieces of red candy, 14 pieces of green candy, and 15 pieces of blue candy must be multiples of 12, 14, and 15 cents, respectively. Let's consider the cost of 12 pieces of red candy. Since the cost must be a multiple of 12 cents, the total cost of 12 pieces of red candy must be 12x cents, where x is some whole number.

Similarly, the total cost of 14 pieces of green candy must be 14y cents, and the total cost of 15 pieces of blue candy must be 15z cents, where y and z are whole numbers. Now let's consider the cost of n pieces of purple candy. We know that each piece costs 20 cents, so the total cost of n pieces of purple candy is 20n cents.

We also know that Casper has exactly enough money to buy any of these options. This means that the total cost of the candy he chooses must be less than or equal to the amount of money he has. Let M be the amount of money Casper has. Then we have: 12x + 14y + 15z ≤ M, 20n ≤ M.

We want to find the smallest possible value of n, so we should start by finding the largest possible value of x, y, and z that still satisfies the inequality above. To do this, we can use the fact that the greatest common divisor of 12, 14, and 15 is 1. This means that any number that is a multiple of 12, 14, and 15 must be a multiple of their least common multiple, which is 12 x 14 x 15 = 2520.

So we can write: 12x + 14y + 15z = k(2520), where k is some whole number. This equation tells us that the cost of any combination of red, green, and blue candy that Casper chooses must be a multiple of 2520 cents. Now we can substitute this equation into the first inequality above: k(2520) ≤ M.

Dividing both sides by 2520, we get: k ≤ M/2520
So the largest possible value of k that still satisfies the inequality is ⌊M/2520⌋, where ⌊⌋ denotes the floor function. Now we can use this to find the smallest possible value of n. We know that the total cost of n pieces of purple candy must be less than or equal to M,

so we can write: 20n ≤ M - k(2520), Substituting the largest possible value of k that we found above, we get: 20n ≤ M - ⌊M/2520⌋(2520), To find the smallest possible value of n, we want to maximize the right-hand side of this inequality. This happens when the floor function evaluates to its smallest possible value,

which is ⌊M/2520⌋ - 1. So we can write: 20n ≤ M - (⌊M/2520⌋ - 1)(2520), Simplifying, we get: 20n ≤ M - 2520⌊M/2520⌋ + 2520, 20n ≤ M - 2520(⌊M/2520⌋ - 1), Since n is a whole number, the smallest possible value of n that satisfies this inequality is: n = ⌊(M - 2520(⌊M/2520⌋ - 1))/20⌋ + 1.

This formula gives us the smallest possible value of n that allows Casper to buy a whole number of purple candies with the money he has.

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we can expect a typical shopper to visit the store about 6 times in a 30-day period, on average.

What is the average?

This is the arithmetic mean and is calculated by adding a group of numbers and then dividing by the count of those numbers. For example, the average of 2, 3, 3, 5, 7, and 10 is 30 divided by 6, which is 5.

If we assume that a typical shopper makes an average of 36 trips to the store over a 180-day period, we can use the Poisson distribution to calculate the expected number of trips in a 30-day period.

The Poisson distribution describes the probability of a certain number of events occurring in a fixed interval of time or space, given the average rate at which they occur. In this case, we can use the Poisson distribution to model the number of trips a typical shopper makes to the store in a 30-day period, given the average rate of 36 trips over 180 days.

The formula for the Poisson distribution is:

[tex]P(X = k) = (\lambda^k * e^{(-\lambda)}) / k![/tex]

where:

X is the number of events (in this case, trips to the store)

λ is the average rate of events per interval (in this case, 36 trips over 180 days)

k is the number of events we want to calculate the probability for

To find the expected number of trips in a 30-day period, we can set λ equal to the average rate of trips per day (i.e., 36 trips / 180 days = 0.2 trips per day), and k equal to the number of days in a 30-day period (i.e., 30 days).

So, the expected number of trips a typical shopper makes to the store in a 30-day period is:

λ = 0.2 trips per day * 30 days = 6 trips

Therefore, we can expect a typical shopper to visit the store about 6 times in a 30-day period, on average.

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The a survey of 1,150 people for choose their favorite laundry detergent from brands. If percent value of people who choose brand A is 3, then the number of people who chose A as their favorite brand are 30 , 35 , 40.

We have a survey results of total 1150 people. That is sample size = 1150

The survey is based on their favorite laundry detergent from brands A, B, and C. The percent of people who chose A as their favorite brand = x %

If x = 3, we have to determine the number of people who chose A as their favorite brand. So, we use percentage formula, for each option and see for which number of people percent is equals to 3. Now, percent formula is [tex] \frac{value}{total \: value}×100%.[/tex]

a) [tex] (\frac{20}{1150 }) 100 \% = 1.73 \%[/tex] ≈ 2%

b) [tex] (\frac{25}{1150 }) 100 \% = 2.17 \%[/tex] ≈ 2%

c) [tex] (\frac{30}{1150 }) 100 \% = 2.60\%[/tex] ≈ 3 %

d) [tex] (\frac{35}{1150 }) 100 \% = 3.04\%[/tex]≈ 3 %

e)[tex] (\frac{40}{1150 }) 100\% = 3.48 \%[/tex] ≈ 3%

f)[tex] (\frac{45}{1150 }) 100 \% = 3.91 \%[/tex]≈ 4%

g)[tex] (\frac{50}{1150 }) 100 \% =4.35 \%[/tex] ≈ 4%

Hence, all such numbers are 30 , 35 , 40.

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Complete question:

A survey asked 1,150 people to choose their favorite laundry detergent from brands A, B, and C. Of the people surveyed, x percent chose A as their favorite brand. If x is rounded to the nearest integer, the result is 3. Which of the following could be the number of people who chose A as their favorite brand? Indicate all such numbers.

a)20

b) 25

c)30

d) 35

e) 40

f) 45

g) 50

If x percent of people chose A as their favorite brand, then the number of people who chose A can be found by multiplying x percent by the total number of people surveyed:

number of people who chose A = (x/100) * 1150

Since x is rounded to the nearest integer and equals 3, we have:

number of people who chose A = (3/100) * 1150 = 34.5, which is closest to 35.

If x percent chose brand A as their favorite and x is rounded to the nearest integer, it means that x lies between x-0.5 and x+0.5. In other words, x-0.5 <= actual percentage of people who chose A <= x+0.5.

From the given information, we know that x rounded to the nearest integer is 3. Therefore, we have:

2.5 <= x <= 3.5

Since x represents the percentage of people who chose brand A, we can find the number of people who chose A as their favorite by multiplying x with the total number of people surveyed (1150). Therefore, the number of people who chose brand A lies between:

2.5% of 1150 <= number of people who chose A <= 3.5% of 1150

28.75 <= number of people who chose A <= 40.25

Since the number of people who chose A must be a whole number, the only possible value for the number of people who chose is 29.

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