Bone Injuries
Practices/Activities on How To
Avoid the Injuries
Fracture
Dislocation
Sprain​

Answers

Answer 1

Answer:

1.=fracture.... Balance: Consider balance training and physical therapy if your body feels off. Use a cane or walker if you need to.

2.=dislocation.... Wearing protective gear during contact sports.

3.=sprain...Take precautions to prevent falls, such as holding handrails on stairways, avoiding slippery surfaces, and keeping your floors uncluttered.

Answer 2

The practices/activities which should be done to avoid the following injuries

include

Fracture- Balance training should be done by individuals as it helps to strengthen the muscles and relieve some of the load the bones are being subjected to in ensuring proper support for the body.

Dislocation- Precautions such as wearing of protective gears and proper lightning should be done to prevent individuals from falling and getting bones dislocated. The protective equipment also help to reduce the effect of force on joints which may cause dislocation.

Sprain- Activities which involve stretching the muscles of the body should be frequently done to prevent such type of injuries.

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Related Questions

Draw a Lewis structure for H3O+ . Include all hydrogen atoms and show all unshared electrons and the formal charges, if any. Assume that bonding follows the octet rule.

Answers

Answer:

In this Lewis equation it can be seen how oxygen and hydrogen have a dative union, that is, there is a proton that is temporarily "borrowed"

Explanation:

This molecule is the same as water but with one more hydrogen, that is why the general charge of the molecule is positive

Explain why the quantitative value for the lattice enthalpy of calcium bromide is larger than the value for the lattice enthalpy of potassium bromide.

Answers

Answer:

Explanation:

We define lattice energy as "the change in internal energy that accompanies the formation of one mole of the solid from its constituent gas phase ions." (Housecroeft and Sharpe, 2012).

Also, lattice energy depends on the size of the ions. In this case, the anion is the same so we consider the relative sizes of the cations. The smaller the size of the cation, the greater the quantitative value of the lattice energy.

Since Ca^2+ is smaller than K^+, the quantitative value for the lattice enthalpy of calcium bromide is larger than the value for the lattice enthalpy of potassium bromide.

During a flood, a mountain stream is carrying clay, silt, sand, and pebbles. The streambed and particle sizes are shown below. Which sediments will most likely be deposited first when the stream slows down?

A. Pebbles
B. Sand
C. Silt
D. Clay

Answers

The clay because it has the smallest particles size.

Answer:

Pebbles

Explanation:

The faster a stream flows, the larger the particles it can carry. When the current slows down the largest particles will be deposited first, which in this case are the pebbles. If the stream continues to slow down the sand will be deposited next, followed by the silt and clay. (Clay is only deposited when the water is nearly still.)

Which group of elements satisfies the octet rule?
Alkali metals
Alkaline earth metals
halogens
Noble gases

Answers

Answer:

the anser is c

Explanation:

Does anyone know the answer please?

Answers

Answer:Cs2O + H2O —> 2CsOH [2Cs+ + 2OH-]

Explanation: Cs is the most electropositive element, with electron structure [Xe] 6s1.

When NH3(aq) is added to Cu2 (aq), a precipitate initially forms. Its formula is:


a. Cu(NH)3

b. Cu(NO3)2

c. Cu(OH)2

d. Cu(NH3)22

e. CuO

Answers

It’s B the cu looses its 2 and passes it to the NH3 that needs a bracket to separate them. The NH3 doesn’t loose its 3 because it’s already a compound!
Hope this helps!

When NH₃(aq) is added to Cu₂(aq), a precipitate initially forms. Its formula is Cu(NH₃)². The correct option is d.

What is a chemical formula?

A chemical formula is a representation of chemical elements and chemical compounds. The chemical letters are used to write the chemical formula. The charges if present is written by charges symbols like plus, minus.

The chemical reaction is

NH₃(aq) + Cu₂(aq) = Cu(NH₃)²

This is called a chemical reaction, which contains reactant on the left side and products on the right side. The precipitate that is formed is copper ammonia whole twice.

Precipitation is the solid crystals' substance that is come out at the surface of the liquid. It is collected in solid form, and it is called a precipitate.

Thus, the correct option is d. Cu(NH₃)².

To learn more about chemical formulas, refer to the link:

https://brainly.com/question/15138610

#SPJ2

A triangle has vertices with coordinates (2,0), (3, -1) and (-2,-5). If the triangle is dilated by a scale factor of 3 with the origin as the center of dilation, what are the coordinates of the vertices of the image?

a
(5,3), (6,2), (1,-2)
b
(6,0), (9,-3), (-6,-15)
c
(2/3,0), (1,-1/3), (-2/3,-5/3)
d
(-1,-3), (0,-4), (-5,-8)

Answers

The right answer is a but not sure tho
Tanong mo sa mama mo HAHAHAH

Explain the differences among "s," "p," "d", and "f," electron orbitals

Answers

Answer:

Explanation:

The Electronic Configuration of the elements is the arrangement of all electrons of an element in energy levels and sub-levels (orbitals).  

There are 7 energy levels, numbered from 1 to 7, and in which electrons are distributed, logically in order according to their energy level. Electrons with less energy will be spinning at level 1. Each level is divided into sub-levels. These sub-levels into which each level is divided can be up to 4. These 4 sub-levels are called: s, p, d, f. In the sub-level s there can only be a maximum of 2 electrons, in p there can be a maximum of 6 electrons, in the sub-level d 10 electrons and finally in the sub-level f there can be a maximum of 14 electrons.

In other words, the difference between the sub-levels consists of the number of electrons that it can hold at each level. In each sublevel there are a certain number of orbitals [1 orbital describes the rotation of a maximum of two electrons around the nucleus] that can contain a maximum of 2 electrons each. In this way, the maximum number of electrons that each sublevel admits is: 2 in the s; 6 in the p (2 electrons x 3 orbitals); 10 in the d (2 electrons x 5 orbitals); 14 in the f (2 electrons x 7 orbitals).

what is the mass of 1 mole of NaCl and 1 mole of Nitrogen​

Answers

Answer:

1 mole of sodium chloride( NaCl)

=58.4g/mol

1 mole of nitrogen

=14.0g/mol

Part of the electromagnetic spectrum is visible light. Which color is at the opposite end from red on the visible spectrum?
green
infrared
violet
yellow

Answers

Pretty sure it’s violet

Answer:

c voilet

Explanation:

How many electrons can the n = 4 shell hold?

Answers

Answer: I think its 32 I'm not sure

Explanation:

I’m pretty sure is 34 or it’s either 24

What is the mass of 9 atom(s) of Oxygen in grams?

Answers

Answer:

2 × 10⁻²² g

Explanation:

Step 1: Given data

Atoms of oxygen: 9 atoms

Step 2: Calculate the moles corresponding to 9 atoms of O

We will use Avogadro's number: there are 6.02 × 10²³ atoms of O in 1 mole of atoms of O.

9 atom × 1 mol/6.02 × 10²³ atom = 1 × 10⁻²³ mol

Step 3: Calculate the mass corresponding to 1 × 10⁻²³ moles of O

The molar mass of O is 16.00 g/mol.

1 × 10⁻²³ mol × 16.00 g/mol = 2 × 10⁻²² g

How would you make 5mls of a solution that is 2.0% lactose and 0.1M SPG buffer from separate stock solutions that are 6% lactose and 1M SPG in concentration

Answers

Answer:

Check the explanation section.

Explanation:

The following steps should be followed orderly.

STEP ONE:

Use the dilution equation in the calculation of the volume for the stock solution. That is, C1 × V1 = C2 × V2.

Where C1 and C2 are the concentration of the stock solution and the diluted solution.

STEP TWO:

Put 6% of lactose and make sure to dilute it in order to make 2.0% lactose

and put it in Beaker A. Also, make sure to dilute the 1M to 0.1M SPG buffer in Beaker B.

STEP TWO:

Now, from beaker A containing 2% lactose, measure and remove 5.0 mL from it. Also, measure and remove 5.0 mL from beaker B containing 0.1M SPG.

So, in STEP TWO above we won't know how much water we need to use for dilution, thus, there is the need to make use of STEP ONE.

Therefore, from STEP ONE ABOVE, we have the dilution equation given as;

C1 × V1 = C2 × V2.

Hence, 6 × V1 = 2 × 5. Therefore, the volume needed from the stock solution, V1 = (2 × 5)/ 6 = 1.6 mL.

STEP THREE:

Now measure out 1.6 mL from the stock solution, that is 6% lactose and add it to 5mL of the diluted solution of 2% in beaker A into another container, say beaker C and add H2O to form SOLUTION X.

STEP FOUR:

Using the dilution equation again, Determine the the volume that is needed from 1M SPG.

C1 × V1 = C2 × V2.

V1 = ( 0.1 × 5)/ 1 = 0.5mL.

STEP FIVE:

measure 0.5mL out from the 1M SPG and 5 mL out of 0.1M SPG buffer and add water to it to form SOLUTION Y.

STEP SIX:

Now, mix solution X and solution Y together and take the required 5ml

A single gold atom has a mass of 197.0 amu. How many gold atoms are in a cube of gold that is 10.0 mm on each side (about the size of a sugar cube) if the density of gold is 19.3 g/cm3

Answers

Answer:

5.90x10²² atoms of gold are present in the cube

Explanation:

First, we must find the volume of the cube in cm³. With density we can find the mass of the gold and the moles using its molar mass. As 1 mol = 6.022x10²³ atoms we can find the number of atoms:

Volume in cm³:

(10.0mm)³ = 1000mm³

1mm³ = 0.001cm³

1000mm³ * (0.001cm³ / 1mm³) = 1cm³

Mass gold:

1cm³ * (19.3g/cm³) = 19.3g Gold

Moles Gold:

19.3g * (1mol / 197.0g) = 0.0980 moles Gold

Atoms gold:

0.0980 moles Gold * (6.022x10²³ atoms / mol) =

5.90x10²² atoms of gold are present in the cube

The following data were collected for the reaction between hydrogen and nitric oxide at 700°C: 2H2(g) + 2NO(g) -+ 2H20(g) + N2(g) Experiment [H2]/M [NO]/M Initial rate/M. s-1 1 0.010 0.025 2.4 X 10-6 2 0.0050 0.025 1.2 X 10-6 3 0.010 0.0125 0.60 X 10-6 (a) What is the rate law for the reaction? (b) Calculate the rate constant for the reaction. (c) Suggest a plausible reaction mechanism that is consistent with the rate

Answers

Answer:

Explanation:

Given that:

2H₂(g) + 2NO(g) → 2H₂O(g) + N₂(g)

Experiment      [H₂] (M)       [NO]   (M)      Initial Rate  (M/s)

1                        0.010          0.025          2.4 × 10⁻⁶

2                       0.0050       0.025          1.2  × 10⁻⁶

3                       0.010          0.0125         0.60 × 10⁻⁶

The general formula for rate law is:

[tex]rate = k[H_2]_x [NO]_y[/tex]

From (1) and (2), it is obvious that the concentration of NO looks constant unlike that of H₂ which has decreased by 1/2. Similarly, the initial rate also reduced by 1/2. Hence, the initial rate is proportional to the concentration of H₂. So, x = 1

Also;

From (1) and (3), it is obvious that the concentration of H₂ looks constant unlike that of NO which has decreased by 1/2. Similarly, the initial rate also reduced by 1/4. Hence, the initial rate is proportional to the concentration of NO. So, y = 2

The overall rate law is: [tex]rate = k[H_2][NO]_2[/tex]

[tex]Order \ of \ reaction = 1 + 2 = 3[/tex]

(b)

From (1)

The rate constant is:

[tex]rate = k[H_2][NO]_2[/tex]

[tex]k = \dfrac{rate}{ [H_2] [NO]^2}[/tex]

[tex]k = \dfrac{2.4 \times 10^{-6} \ M/s}{(0.010 \ M)(0.025 \ M)^2 }[/tex]

k = 0.38 / M².s

(c)

From the rate law, it is pertinent to understand that the slow step in the reaction includes one molecule of H₂ and two molecules of NO, where O atoms serve as an intermediary.

SO;

H₂ + 2NO → N₂ + H₂O + O        slow step

O + H₂  →   H₂O                         fast step

                                               

                                                  2H₂ + 2NO → 2H₂O + N₂

An ________ molecular ion peak usually indicates the presence of an odd number of nitrogen atoms in the molecule.

Answers

Answer:

odd

Explanation:

By applying the Nitrogen rule; A molecular ion with odd mass numbers will contain an odd number of a nitrogen atom, however, a molecular ion with an even mass number will contain either an even number of a nitrogen atom or no nitrogen.

So from the given information, the missing word is odd .

A chemist has 2.0 mol of methanol (CH3OH). The molar mass of methanol is 32.0 g/mol. What is the mass, in grams, of the sample? 16 30 32 64

Answers

Answer:

[tex]\boxed {\boxed {\sf D. \ 64 \ grams }}[/tex]

Explanation:

Given the moles, we are asked to find the mass of a sample.

We know that the molar mass of methanol is 32.0 grams per mole. We can use this number as a fraction or ratio.

[tex]\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}[/tex]

Multiply by the given number of moles, which is 2.0

[tex]2.0 \ mol \ CH_3OH *\frac{32 \ g \ CH_3OH}{1 \ mol \ CH_3OH}[/tex]

The moles of methanol will cancel each other out.

[tex]2.0 \ *\frac{32 \ g \ CH_3OH}{1 }[/tex]

The denominator of 1 can be ignored.

[tex]2.0 * 32 \ g\ CH_3OH[/tex]

Multiply.

[tex]64 \ g \ CH_3OH[/tex]

There are 64 grams of methanol in the sample.

The answer is 64 grams, or:

D. 64

what is periodic table​

Answers

it has all the chemical elements organized by atomic #, from the element w the lowest atomic # , hydrogen, the element w the highest atomic # & by oganesson

Which part of the body is least involved in striking a volleyball?

back
hand
core
legs

The only part used in hitting a volleyball is your hand. T/F?
True
False

.
______ is important in volleyball because it is important that you are able to change direction.
speed
strength
coordination
agility

________ is important in volleyball because in order to strike the ball, you must first see the ball
body coordination
clothing coordination
hand eye coordination

Answers

Answer:

1. your back

2. false

3. agility

4. hand eye coordination

Explanation:

hope this helps <3

how does the percentage by mass of the solute describe the concentration of an aqueous solution os potassium sulfate

Answers

Answer:

Explanation:

In an aqueous solution of potassium sulfate (K₂SO₄), the solute is K₂SO₄ and the solvent is water. The percentage by mass describes the grams of solute there are dissolved per 100 grams of solution. It can be calculated as:

mass percentage = (mass of solute/total mass of solution) x 100%

For example, in an aqueous solution which is 2% by mass of K₂SO₄, there are 2 grams of K₂SO₄ per 100 g of solution.

What is the difference between oxygen and water?

Answers

Answer:

Oxygen is a pure element. Water, however, is a compound molecule containing oxygen. Water also contains hydrogen, In an H2O molecule, the two hydrogen molecules and the oxygen molecules are chemically bonded together.

Answer:

Water is 1% oxygen and it is a compound

While oxygen is a Pure element that means it forms with only oxygen molecules

Explanation:

how do you find the guide statements are they easy or difficult to complete?​

Answers

Answer:

difficult

Explanation:

Does a reaction occur when aqueous solutions of chromium(III) sulfate and calcium nitrate are combined

Answers

Answer: [tex]Cr_2(SO_4)_3(aq)+3Ca(NO_3)_2(aq)\rightarrow 2Cr(NO_3)_3(aq)+3CaSO_4(aq)[/tex]

Explanation:

A double displacement reaction is one in which exchange of ions take place. The salts which are soluble in water are designated by symbol (aq) and those which are insoluble in water and remain in solid form are represented by (s) after their chemical formulas.  

The balanced chemical equation when when aqueous solutions of chromium(III) sulfate and calcium nitrate are combined is:

[tex]Cr_2(SO_4)_3(aq)+3Ca(NO_3)_2(aq)\rightarrow 2Cr(NO_3)_3(aq)+3CaSO_4(aq)[/tex]

Which of these elements has physical and chemical properties most similar to Sulfur (S)?
A)Selenium (Se)
B) Phosphorus (P)
C) Argon (Ar)
D) Chlorine (Cl)

Answers

A) Selenium - is apart of Sulfur family

is anyone blonde hair?????​

Answers

no why

anser;

explinaton;

Mercury, also known as quicksilver, is a metallic element and a liquid at room temperature. Calculate mercury's density if a sample of mercury is found to have a mass of 685.0685.0 g and a volume of 51.3951.39 mL. density: g/mL

Answers

Answer:

13.33g/mL is mercury's density

Explanation:

The density of a substance is defined as the ratio between the mass of the substance and the space that occupy. We can express the density of mercury in g/mL:

Grams mercury: 685.0g

Volume = 51.39mL

That means the density of the mercury is:

685.0g / 51.39mL

13.33g/mL is mercury's density

A chemist determines by measurements that moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrogen gas that participates.

Answers

Answer:

0.56 g

Explanation:

A chemist determines by measurements that 0.020 moles of nitrogen gas participate in a chemical reaction. Calculate the mass of nitrogen gas that participates.

Step 1: Given data

Moles of nitrogen gas (n): 0.020 mol

Step 2: Calculate the molar mass (M) of nitrogen gas

Molecular nitrogen is a gas formed by diatomic molecules, whose chemical formula is N₂. Its molar mass is:

M(N₂) = 2 × M(N) = 2 × 14.01 g/mol = 28.02 g/mol

Step 3: Calculate the mass (m) corresponding to 0 0.020 moles of nitrogen gas

We will use the following expression.

m = n × M

m = 0.020 mol × 28.02 g/mol

m = 0.56 g

2.015×107km Express your answer as an integer.

Answers

Answer: 216km

Explanation:

An integer simply refers to a whole number. We should note that fractions and decimals are not integers. Therefore, expressing 2.015×107km as an integer will be:

= 2.015 × 107

= 215.605

= 216

yall ever just wanna then ‍?

Answers

Answer:

ummmmm huh?

Explanation:

.......im confused on the question

Propane burns in oxygen to produce carbon dioxide and water. How many grams of oxygen gas are required
to burn 10.0 grams of propane?

Answers

Answer:

[tex]m_{O_2}=36.3gO_2[/tex]

Explanation:

Hello!

In this case, since the reaction between propane and oxygen is:

[tex]C_3H_8+5O_2\rightarrow 3CO_2+4H_2O[/tex]

Given the 1:5 mole ratio between propane and oxygen, and their molar masses (44.09 g/mol and 32.00 g/mol respectively), we can follow up the shown below stoichiometric setup to compute the required mass of oxygen for the reaction:

[tex]m_{O_2}=10.0gC_3H_8*\frac{1molC_3H_8}{44.09gC_3H_8}*\frac{5molO_2}{1molC_3H_8} *\frac{32.00gO_2}{1molO_2} \\\\m_{O_2}=36.3gO_2[/tex]

Best regards!

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