Calculate the frequency of the wave shown below.
Frequency = Speed/Wavelength (λ)

Select one:
a. 4 hertz
b. 3 hertz
c. 2 hertz
d. 1 hertz

Answer:

a (2m)

Explanation:

according to wavelenght = speed / frequency,

the wavelength is 2 m

This planet's mass must be four times that of Earth in order for the gravitational pull at its surface to be comparable to Earth's.

Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.

The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.

The planet's mass is directly related to its mass at the surface and inversely proportional to the square of its radius;

When mass increases and distance reduces, gravity rises. Gravity also lowers when the distance between two points grows and the mass decreases.

The astronomers discovered a planet twice the size of Earth that resembles Earth.

This planet's mass must be four times that of Earth in order for the gravitational pull at its surface to be comparable to Earth's.

Hence the masses of this planet will be 4 times that of Earth.

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Answer:

50km/h

Explanation:

average = (a + b) / 2

average = (60 + 40) / 2

average = 50

Answer:

Approximately [tex]9.39 \; {\rm m\cdot s^{-1}}[/tex] after the sphere has travelled a distance of [tex]5\; {\rm m}[/tex].

Approximately [tex]16.3\; {\rm m\cdot s^{-1}}[/tex] right before touching the ground (a distance of [tex]15\; {\rm m}[/tex].)

Assumption: [tex]g = 9.81\; {\rm N\cdot kg^{-1}}[/tex].

Explanation:

Weight of the sphere: [tex]m\, g = 9.81\; {\rm N \cdot kg^{-1}} \times 10\; {\rm kg} = 98.1\; {\rm N}[/tex], downwards.

Drag on the sphere: [tex]10.0\; {\rm N}[/tex] upwards.

Net force on the sphere: [tex]98.1\; {\rm N} - 10\; {\rm N} = 88.1\; {\rm N}[/tex] downwards.

Acceleration of the sphere: [tex]a = F_\text{net} / m = 88.1\; {\rm N} / (10\; {\rm kg}) = 8.81\; {\rm m\cdot s^{-2}}[/tex].

Apply the SUVAT equation [tex]v^{2} - u^{2} = 2\, a\, x[/tex], where [tex]v[/tex] is the final velocity, [tex]u[/tex] is the initial velocity ([tex]0[/tex] in this case, as the sphere was released from rest,) and [tex]x[/tex] is the distance (displacement) that the sphere has travelled so far.

Rearrange this equation to obtain an expression for [tex]v[/tex]:

[tex]\displaystyle v = \sqrt{2\, a\, x + u^{2}}[/tex].

For example, after the ball travelled a distance of [tex]5.00\; {\rm m}[/tex], [tex]x = 5.00 \; {\rm m}[/tex]:

[tex]\begin{aligned} v &= \sqrt{2\, a\, x + u^{2}} \\ &= \sqrt{2 \times 8.81\; {\rm m\cdot s^{-2}} \times 5.0\; {\rm m} + 0} \\ &\approx 9.39\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

Similarly, [tex]x = 15.0\; {\rm m}[/tex] right before landing, such that:

[tex]\begin{aligned} v &= \sqrt{2\, a\, x + u^{2}} \\ &= \sqrt{2 \times 8.81\; {\rm m\cdot s^{-2}} \times 15.0\; {\rm m} + 0} \\ &\approx 16.3\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

The allowable ampacity of a No. 12 copper wire with type THHN insulation installed in a raceway with 35 wires is approximately 12 amperes. This is best represented by option D.

According to the National Electrical Code Table (NEC), a derating factor must be applied for any raceway with more than three current-carrying conductors (in our case, copper wires). In a raceway with 31-40 current-carrying conductors, the derating factor is 50%. Because the ampacity of a No. 12 copper wire usually is 25 amperes (A), we can multiply this by our derating factor to find that:

25 • 0.50 = 12.5

The exact allowable ampacity of this copper wire is 12.5 amperes; however, we can round down to find that the closest answer is 12 A.

Hence, option D represents the best answer.

Answer:

  D)  12 A

Explanation:

You want to know the allowable ampacity of AWG 12 type THHN copper wire in a raceway with 35 wires.

Table 310.15(B)(16) of the 2017 National Electrical Code gives the nominal rating of AWG 12 type THHN copper wire as 30 A when installed in an environment with a temperature of 30 °C or less.

Table 310.15(B)(3)(a) gives the adjustment factor when there are more than three conductors in a raceway or cable. For 31–40 conductors, the ampacity must be derated to 40% of its nominal value.

In a raceway with 35 wires, the allowable ampacity of THHN AWG 12 wire is ...

  (30 A)(0.40) = 12 A

__

Additional comment

For environmental temperatures above 30 °C, Table 310.15(B)(2)(a) gives additional derating factors. The adjustment factor for temperatures up to 50 °C (122 °F) is 0.82, which would bring the allowable ampacity down to about 9.8 A.

Explanation:

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⠀

(a) The segment A shows acceleration as velocity increases with the increase in time.

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⠀

⠀

(b) The segment C shows the object is slowing down as the time increases in segment C, the velocity decreases and afterwards it comes to rest.

⠀

⠀

⠀

(c) The velocity is segment B is 40m/s. And in the diagram there is no change in velocity.

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⠀

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(d) The acceleration of segment B is zero. As there in no change in curve and it is moving with uniform velocity.

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⠀

⠀

[tex] \: [/tex]

Answer:

1 A and C

2 C

3 40m/s

4 zero

Explanation:

Bianca is helping the theatre director at her school with lighting, sound, and set design for a school play. She will be choosing the materials that will be used on stage and on the walls of the theatre the materilas neee to be changes is The only lights available are white, purple, and yellow.

A proper echo is a single mirrored image of the sound source. The phrase echo derives from the Greek ἠχώ (ēchō), itself from ἦχος (ēchos), "sound". Echo withinside the Greek peoples tale is a mountain nymph whose cappotential to talk changed into cursed, leaving her capin a position handiest to copy the ultimate phrases spoken to her.

Bianca draws a detailed illustration of her plan to show the theatre director. She labels it with the materials she plans to use the  only lights available are white, purple, and yellow should be removed as to avoid the light refraction.

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Answer:

1. 92, 138, 92

2. 7, 7, 7

3. 17, 18, 17

4. 29, 34, 29

Explanation:

the number on the bottom is always going to be the atomic number, or the number of protons.

the number on the top is going to be the atomic mass number, which is the sum of the number of protons and neutrons.

there is always going to be the same number of electrons as protons, because that was the overall charge of each atom is 0.

for example, for the first one:

there are 92 protons

there are 230 - 92 = 138 neutrons

there are 92 electrons

Answer:

a force of acts on a body of mass 50 kg for 10 sec when the first of acting on the body the body covers 80 and in the next 10 second

Answer:

a = 0.4 ms⁻²

Explanation:

• First calculate the resultant force on the body:

If we consider upwards to be the positive direction and downwards to be the negative direction, then the resultant force will be:

F = +100 + (-80)

  = +20 N

The resultant force is positive, so it will act upwards.

• Next calculate the acceleration:
F = ma

a = F/m

a = 20/ 50

a = 0.4 ms⁻²

As the force is acting upwards, the acceleration will also be upwards.

The final common speed of the two carts will be 69.3 m/sec.The momentum conservation principle is applied.

According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.

Unit conversion:

1 metric tons = 1000 kg

Given data;

m₁= 11.6 metric ton =11600 kg

m₂ = 23.2 metric ton =  23200 kg

Let v represent the combined velocity of the two carts once they are connected, and let u represent the starting velocity of cart 1 when it reaches the bottom.

Considering energy conservation;

[tex]\rm m_1 g h = \frac{1}{2} m_1 \times u^2 \\\\ u^2 = 2gh\\\\ u^2 = 2 \times 9.8 \times 10.6 \\\\ u = 207.972 \ m/s[/tex]

From the conservation of momentum principle;

[tex]\rm m_1 \times u = (m_1 + m_2) v\\\\ 11600 \times 207.972 = (11600 + 23200) \times v \\\\ v = 69.3 \ m/s[/tex]

Hence, the final common speed of the two carts will be 69.3 m/sec.

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Speed can be defined as the change in distance with respect to time.

The speed is the change in distance with the time and velocity is the change in displacement with the time. Speed is a scalar quantity having magnitude only and Velocity is a vector quantity having magnitude as well as direction.

If the velocity of the object is changing, it shows that the object is accelerating.

Inertia is a resistance of an object to resist a change in its state of motion or of rest. If a ball is rolled, it will continue rolling unless friction or something else stops it by force.

Some common forces are gravitational forces, electric forces, magnetic forces, nuclear forces, etc. Gravitational forces act between the earth and the object, it is an attraction force. Similarly, there is an electric force, which acts between the two charges, it can be attractive or repulsive.

The forces that are opposite in direction and equal in size, are known as balanced forces. This can be explained as forces acting horizontal, and the forces are balanced, so the left-sided forces and right-sided forces must be equal.

Power can be defined as the measure of the amount of work that can be done in a given amount of time. Power is work done per unit time.

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The atomic bomb explosion, depends on the energy released, W, the elapsed time, t, and the air density which altogether lead to the vaporisation of the contents within the mushroom cloud created.

An atomic bomb is type of nuclear weapon that releases a vast amount of energy upon explosion in the form of fission reaction.

During an explosion of atomic bomb, a cloud of mushroom fire is formed which vaporises anything found within it. The extent of destruction depends on:

Therefore, the atomic bomb explosion, depends on the energy released, W, the elapsed time, t, and the air density which altogether lead to the vaporisation of the contents within the mushroom cloud created.

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The boat’s resultant velocity with respect to North is determined as 17 m/s.

The boat’s resultant velocity with respect to North is calculated as follows;

R² = Va² + Vb²

where;

R = √(Va² + Vb²)

R = √(15² + 8²)

R = 17 m/s

Thus, the boat’s resultant velocity with respect to North is determined as 17 m/s.

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Answer:

a

Explanation:

Answer:

B

Explanation:

Charles Darwin's theory of natural selection states that features that offer survival or reproductive advantage are more likely to be handed down to subsequent generations.

A trait is a distinctive pattern of behavior or conscious motivation that may be evaluated by peers or oneself.

Traits that provide a survival or reproductive advantage are more likely to be passed on to future generations is Charles Darwin’s theory of natural selection state traits.

Hence option D is correct.

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Answer: option d

Explanation:

The acceleration of this sled can be calculated by doing: option A, B, E and F.

The acceleration of this sled can be calculated by using Newton's Second law of motion. Mathematically, the acceleration of an object is given by this formula:

Net force = Mass × acceleration

Deductively, the acceleration of this sled can be calculated by doing the following:

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Complete Question:

A sled is moving down a steep hill. The mass of the sled is 50 kg and the net force acting on it is 20 n. What must be done to find the acceleration of the sled? check all that apply.

A. The force of gravity must be broken into its parallel and perpendicular components.

B. Acceleration can be found by dividing the net force by mass.

C. Acceleration can be found by multiplying the net force by mass.

D. The magnitude of the force components must be multiplied by gravity.

E. Trigonometry can be used to solve for the magnitude of the force components.

F. Net force must be found before acceleration can be found.

Answer:

To find the acceleration, you do 20N/50kg = 0.4 m/s^2

Explanation:

example: a = F/m = 10/2 = 5 m/s2

Answer:

588J

Explanation:

Work done = Fd

=wh=mgh

=6×9.8×10

=558J

The magnitude of the net force that the atmosphere applies to the roof when the outside pressure drops suddenly is  1.9 x 10⁵ N.

The pressure is the amount of force applied per unit area.

Pressure p = Force/Area

Given is a house has a roof (colored gray) with the dimensions shown in the drawing. The outside pressure drops suddenly by 13.2 mm of mercury, before the pressure in the attic can adjust.

The pressure difference ΔP = 13.2 mm of Hg

The length of the roof l = 14.5m

the breadth of the roof h = 4.21m

The force exerted by pressure is

Force, F = P x A

         = (13.2 mm of Hg) [(133 N/m²) /1 mm of Hg ](14.5 x 4.21)

         = 107,170.6 N

Then the net vertical force

    Fnet = 2F cos30

    Fnet = 2 ( 107,170.6) cos30

    Fnet = 185625 N

    Fnet =1.9 x 10⁵ N

The direction of the force is downwards, since the horizontal components of the forces cancel each other.

Hence,  magnitude of the net force is 1.9 x 10⁵ N

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The bomb strike the ground relative to the point at 1km . B

Using the equation

h = 1/2 gt^2

500 = 1/2 * 10* t^2

500 = 5t^2

t = √500/5

t = √100

t = 10seconds

To find the distance,

Distance = velocity * time

Distance = 100 ÷ 10

Distance = 1000m = 1km

Therefore, the bomb strike the ground relative to the point at 1km . B

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The cost to use all lamps is $62.

           power=energy/time

          (60+ 100+150)=energy/2.5

          energy=775 joule

cost for 1 hour=$0.08

                      = 775 * 0.08

                     = $62

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Answer:

6.2 cents

Explanation:

(60+100+150/1000)*2.5*8=6.2 cents

The output voltage of a transformer is 40V.

An output voltage is the voltage released by a device, such as a voltage regulator or a generator.

The formula to calculate Output voltage of transformer is:

[tex]\frac{V_{s} }{V_{p} } = \frac{N_{s} }{N_{p} }[/tex]

here,  [tex]V_{s}[/tex] is the secondary voltage, [tex]V_{p}[/tex] is the primary voltage, [tex]N_{s}[/tex] is the number of secondary windings and [tex]N_{p}[/tex] is the number of primary windings.

According to the question.

[tex]N_{p}[/tex] =1200 , [tex]N_{s}[/tex]=200 , [tex]V_{p}[/tex]=240V  ,[tex]V_{s}[/tex]= ?

By using the formula of Output voltage,

[tex]{V_{s} } = \frac{V_{p}N_{s} }{N_{p} }[/tex]

=[tex]\frac{240*200}{1200}[/tex]

[tex]=40V[/tex]

Therefore, 40V is the output voltage of a transformer.

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Answer:I would say that it would be about 2/3rds as fast as the moon and i have seen a similar question but it asked different info about it. I also believe that the basketball would have a lower weight due to it being in space. I feel bad saying this but i know that i got some info off this website when working with this and i hope it helps.

Explanation:

Note- I am new to Brainly so sorry if this isn't as helpful as you expected this to be.

The Total assets based on the given table is $88,800.

An asset refers to a resource owned by an individual or company which has tangible value and whose value is expected to rise in the future.

The Total assets based on the table = Cash + Supplies + Prepaid rent + Equipment

Total assets = 13,100 + 6,000 + 3,800 + 65,900

Total assets = $88,800

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Ocean bulges on Earth would be bigger if the Moon had twice as much mass and yet orbited the planet at the same distance. Option B is correct.

The fluid and moveable ocean water are drawn towards the moon by the gravitational attraction between the moon and the Earth.

The ocean nearest to the moon experiences a bulge as a result, and as the Earth rotates, the affected seas' locations shift.

The Moon's bulges in the oceans would be larger if it had twice the mass and orbited Earth at the same distance.

Hence option B is corect.

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Answer:

See below

Explanation:

The work done equals the increase in Potential Energy

PE = mgh

    = 150 * 9.81 * 1 = 1471.5 j

3 sets of 10 is 30 times this = 44145 j

The amount of work done by a football player in the weight room when he squats 150 kg will be equal to 1471.5 J.

Potential energy is a form of stored energy that is dependent on the relationship among different components. When a spring is compressed or stretched, its potential energy increases. If a steel ball is raised above the floor as opposed to falling to the ground, it has more potential energy. It is capable of carrying out additional work when raised.

Potential energy is a feature of systems rather than of particular bodies or particles; for instance, the system created up of Earth and the elevated ball has more energy stored as they become further apart.

Potential energy develops in systems components whose configurations, or spatial arrangement, determine the amount of the forces they apply to one another.

As per the instructions given in the question,

Work performed is equivalent to Potential Energy Increase,

PE = mgh

= 150 × 9.81 × 1

PE = 1471.5 J

Also,

3 sets of 10 are 30 times this = 44145 J

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The magnitude of the maximum force that the tow rope can apply to the skier without causing her to move will be 81.03 N,

It is a type of opposition force acting on the surface of the body that tries to oppose the motion of the body. its unit is Newton (N).

It is defined as the product of the coefficient of friction and normal reaction.

On resolving the given force and acceleration. Mathematically aion in the different components and balancing the equation gets. Components in the x-direction.

The normal force is balanced by weight;

N = mg

The magnitude of the maximum force that the tow rope can apply to the skier without causing her to move is;

F = μN

F= μmg

F=0.14 ×  59 kg × 9.81 m/s²

F = 81.03 N

Hence, the magnitude of the maximum force will be 81.03 N,

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Compared with the car, the truck will travel four times as far.

The initial velocity of car and truck, u = 0

The acceleration of both the truck and car = a

The length of time for the acceleration = t

Let the time the truck accelerated be 2t

The distance traveled by car is calculated as;

s = ut + ¹/₂at²

s₁ = 0(t) + ¹/₂at²

s₁ = ¹/₂at²

The distance traveled by truck

s = ut + ¹/₂at²

s₂ = 0(2t) + ¹/₂a (2t)²

s₂ =  ¹/₂a x 4t²

s₂ = 4 (¹/₂at²)

s₂ = 4(s₁)

We can conclude that the Truck distance is four times the car distance.

Therefore, Compared with the car, the truck will travel four times as far.

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(a) The average velocity of the particle in the time interval t₁=2sec and t₂=3sec is 10 m/s.

(b) The velocity and acceleration at any time t is v =  (2ati + bj) m/s and a = 2ai m/s²

(c)  The average acceleration in the time interval given in part (a)​ is 4 m/s².

x = at²i + btj

x = 2t²i + tj

Δv = Δx/Δt

x(2) = 2(2)²i + 2j

x(2) = 8i + 2j

|x(2)| = √(8² + 2²) = 8.246

x(3) =  2(3)²i + 3j

x(3) = 18i + 3j

|x(3)| = √(18² + 3²) = 18.248

Δv = (18.248 - 8.246)/(3 - 2)

Δv =  10 m/s

x = at²i + btj

v = dx/dt

v =  (2ati + bj) m/s

a = dv/dt

a = 2ai m/s²

a = 2ai m/s²

a = 2(2)(1)

a = 4 m/s²

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