Consider the following class definitions.

public class Robot

{

private int servoCount;

public int getServoCount()

{

return servoCount;

}

public void setServoCount(int in)

{

servoCount = in;

}

}

public class Android extends Robot

{

private int servoCount;

public Android(int initVal)

{

setServoCount(initVal);

}

public int getServoCount()

{

return super.getServoCount();

}

public int getLocal()

{

return servoCount;

}

public void setServoCount(int in)

{

super.setServoCount(in);

}

public void setLocal(int in)

{

servoCount = in;

}

}

The following code segment appears in a method in another class.

int x = 10;

int y = 20;

/* missing code */

Which of the following code segments can be used to replace /* missing code */ so that the value 20 will be printed?


A Android a = new Android(x);

a.setServoCount(y);

System.out.println(a.getServoCount());

B Android a = new Android(x);

a.setServoCount(y);

System.out.println(a.getLocal());

C Android a = new Android(x);

a.setLocal(y);

System.out.println(a.getServoCount());

D Android a = new Android(y);

a.setServoCount(x);

System.out.println(a.getLocal());

E Android a = new Android(y);

a.setLocal(x);

System.out.println(a.getLocal());

Answer:

The csharp program is given below.

using System;

using System.Collections.Generic;

using System.ComponentModel;

using System.Data;

using System.Drawing;

using System.Linq;

using System.Text;

using System.Threading.Tasks;

using System.Windows.Forms;

namespace WindowsFormsApplication1

{

   public partial class Form1 : Form

   {

       public Form1()

       {

           InitializeComponent();

      }

       private void button6_Click(object sender, EventArgs e)

       {

           int total = (Convert.ToInt32(textBox1.Text) +  Convert.ToInt32(textBox2.Text) + Convert.ToInt32(textBox3.Text) + Convert.ToInt32(textBox4.Text) + Convert.ToInt32(textBox5.Text));

           int dozen = total / 12;

           int eggs = total % 12;

           textBox6.Text = dozen.ToString();

           textBox7.Text = eggs.ToString();

       }

       private void button7_Click(object sender, EventArgs e)

       {

           textBox1.Text = "";

           textBox2.Text = "";

           textBox3.Text = "";

           textBox4.Text = "";

           textBox5.Text = "";

           textBox6.Text = "";

           textBox7.Text = "";

       }

        private void button8_Click(object sender, EventArgs e)

       {

           Close();

       }

    }

}

Explanation:

1. The integer variables are declared for total eggs, number of dozens and number of eggs.

2. The input of each text box is converted into integer by using the Convert.ToInt32() method on the value of that particular text box.

3. All the inputs are added and the sum is assigned to variable, total.

4. The number of dozens are obtained by dividing total by 12 and assigning the value to the variable, dozen.

5. The number of extra eggs are obtained by taking the modulus of total and 12 and the value is assigned to the variable, eggs.

6. The integer values in the variables, dozen and eggs, are converted into string using the ToString() function with that particular value.

dozen.ToString();

eggs.ToString();

7. The text boxes are assigned the respective values of dozens and number of eggs.

textBox6.Text = dozen.ToString();

textBox7.Text = eggs.ToString();

8. Two additional buttons, clear and exit, are also added.

9. The clear button erases the contents of all the text boxes. The Text property of each textbox is set to “” thereby clearing all the text fields.

10. The exit button closes the application using Close() function.

11. The program is made in visual studio and the output is attached.

Answer:

weight1 = float(input("Enter the weight of first package: "))

price1 = float(input("Enter the price of first package: "))

weight2 = float(input("Enter the weight of second package: "))

price2 = float(input("Enter the price of second package: "))

if weight1 > 0 and price1 > 0 and weight2 > 0 and price2 > 0:

   unit_cost1 = price1 / weight1

   unit_cost2 = price2 / weight2

   if unit_cost1 < unit_cost2:

       print("Package 1 has a better price.")

   else:

       print("Package 2 has a better price.")

else:

   print("All the entered values must be positive!")

Explanation:

*The code is in Python.

Ask the user to enter the weight and the price of the packages

Check if the all the values are greater than 0. If they are, calculate the unit price of the packages, divide the prices by weights. Then, compare the unit prices. The package with a smaller unit price has a better price.

If all the entered values are not greater than 0, print a warning message

Answer: Provided in the explanation section

Explanation:

C++ Code

#include<iostream>

#include<fstream>

#include<string>

using namespace std;

// read plain text from file

void readPlaneText(char *file,char *txt,int &size){

  ifstream inp;

  inp.open(file);

  // index initialize to 0 for first character

  int index=0;

  char ch;

  if(!inp.fail()){

      // read each character from file  

      while(!inp.eof()){

          inp.get(ch);

          txt[index++]=ch;

      }

  }

  // size of message

  size=index-1;

}

// read key

int **readKey(char *file,int **key,int &size){

  ifstream ink;

  //

  ink.open(file);

      if(!ink.fail()){

          // read first line as size

      ink>>size;

      // create 2 d arry

      key=new int*[size];

      for(int i=0;i<size;i++){

          key[i]=new int[size];

      }

      // read data in 2d matrix

      for(int i=0;i<size;i++){

          for(int j=0;j<size;j++){

              ink>>key[i][j];

          }  

      }

  }

  return key;

}

// print message

void printText(string txt,char *msg,int size){

  cout<<txt<<":\n\n";

  for(int i=0;i<size;i++){

      cout<<msg[i];

  }

}

// print key

void printKey(int **key,int size){

  cout<<"\n\nKey matrix:\n\n";

  for(int i=0;i<size;i++){

      for(int j=0;j<size;j++){

          cout<<key[i][j]<<" ";

      }  

      cout<<endl;

  }

}

void encrypt(char *txt,int size,int **key,int kSize,char *ctxt){

  int *data=new int[kSize];

  for(int i=0;i<size;i=i+kSize){  

  // read key size concecutive data

      for(int a=0;a<kSize;a++){

          data[a]=txt[i+a]-'a';

      }

      // cipher operation

      for(int a=0;a<kSize;a++){

          int total=0;

          for(int b=0;b<kSize;b++){

              total+=key[a][b]*data[b];

          }  

          total=total%26;

          ctxt[i+a]=(char)('a'+total);

      }      

  }

}

int main(int argc,char **argv){

  char text[10000];

  char ctext[10000];

  int **key;

  int keySize;

  int size;

  // input

  key=readKey(argv[1],key,keySize);

  readPlaneText(argv[2],text,size);

  encrypt(text,size,key,keySize,ctext);

  // output

  printKey(key,keySize);

  cout<<endl<<endl;

  printText("Plaintext",text,size);

  cout<<endl<<endl;

  printText("Ciphertext",ctext,size);

  return 0;

}

cheers i hope this helped !!!

Answer:

This program is written using python

It uses less comments (See explanation section for more explanation)

Also, see attachments for proper view of the source code

Program starts here

#Prompt user for price of package 1

price1 = int(input("Enter Price 1: "))

while(price1 <= 0):

     price1 = int(input("Enter Price 1: "))

#Prompt user for weight of package 1

weight1 = int(input("Enter Weight 1: "))

while(weight1 <= 0):

     weight1 = int(input("Enter Weight 1: "))

#Calculate Unit of Package 1

unit1 = float(price1/weight1)

print("Unit cost of Package 1: "+str(unit1))

#Prompt user for price of package 2

price2 = int(input("Enter Price 2: "))

while(price2 <= 0):

     price2 = int(input("Enter Price 2: "))

#Prompt user for weight of package 2

weight2 = int(input("Enter Weight 2: "))

while(weight2 <= 0):

     weight2 = int(input("Enter Weight 2: "))

#Calculate Unit of Package 2

unit2 = float(price2/weight2)

print("Unit cost of Package 2: "+str(unit2))

#Compare units

if unit1 > unit2:

     print("Package 1 has a better price")

elif unit1 == unit2:

     print("Both Packages have the same price")

else:

     print("Package 2 has a better price")

Explanation:

price1 = int(input("Enter Price 1: ")) -> This line prompts the user for price of package 1

The following while statement is executed until user inputs a value greater than 1 for price

while(price1 <= 0):

     price1 = int(input("Enter Price 1: "))

weight1 = int(input("Enter Weight 1: ")) -> This line prompts the user for weight of package 1

The following while statement is executed until user inputs a value greater than 1 for weight

while(weight1 <= 0):

     weight1 = int(input("Enter Weight 1: "))

unit1 = float(price1/weight1) -> This line calculates the unit cost (per weight) of package 1

print("Unit cost of Package 1: "+str(unit1)) -> The unit cost of package 1 is printed using this print statement

price2 = int(input("Enter Price 2: ")) -> This line prompts the user for price of package 2

The following while statement is executed until user inputs a value greater than 1 for price

while(price2 <= 0):

     price2 = int(input("Enter Price 2: "))

weight2 = int(input("Enter Weight 2: ")) -> This line prompts the user for weight of package 2

The following while statement is executed until user inputs a value greater than 1 for weight

while(weight2 <= 0):

     weight2 = int(input("Enter Weight 2: "))

unit2 = float(price2/weight) -> This line calculates the unit cost (per weight) of package 2

print("Unit cost of Package 2: "+str(unit2)) -> The unit cost of package 2 is printed using this print statement

The following if statements compares and prints which package has a better unit cost

if unit1 > unit2:

     print("Package 1 has a better price")

elif unit1 == unit2:

     print("Both Packages have the same price")

else:

     print("Package 2 has a better price")

Camera and Mic

These 2 things are the most likely things to get you in trouble. Unless you have a 100% protected device, and honestly even if you do, cover up the camera and close your mic. This will definitely save you later.

Answer:

I think that they should ban ads for all four products.  These products, e-cigarettes, abortion clinics, ice cream, and sugared soft drinks, are all discreet adult products that should not be advertised because of their health hazards.  Since the "large online company provides a widely used search engine, social network, and/or news service, which are mainly patronized by younger people, such ads that promote products injurious to individual health should be banned.  Those who really need or want these products know where they could get them.  Therefore, the products should not be made easily accessible to all people.  Nor, should ads promote their patronage among the general population.

Explanation:

Advertisements create lasting and powerful images which glamourize some products, thereby causing the general population, especially children, to want to consume them without any discrimination of their health implications.  If online banning is then contemplated, there should not be any distinguishing among the four products: e-cigarettes, abortion clinics, ice cream, and sugared soft drinks.

Answer:

Engineering and Science

Explanation:

Answer:

import java.util.*;

public class Grade {

   public static void main(String[] args) {

       Scanner input = new Scanner(System.in);

       double[] grades =  new double[4];

       for (int i=0; i<4; i++){

           System.out.print("Enter a grade: ");

           grades[i] = input.nextDouble();

       }

       double lowest = grades[0];

       double highest = grades[0];

       double total = 0;

       for (int i=0; i<4; i++){

           System.out.println("Grade " + (i+1) + " is: "  + grades[i]);

           if(grades[i] >= highest)

               highest = grades[i];

           if(grades[i] <= lowest)

               lowest = grades[i];

           total += grades[i];

       }

       double average = total/4;

       System.out.println("The highest grade is: " + highest);

       System.out.println("The lowest grade is: " + lowest);

       System.out.println("The average is: " + average);

  }

}

Explanation:

Ask the user for the grades and put them in the grades array using a for loop

Create another for loop. Inside the loop, print the grades. Find highest and lowest grades in the grades array using if-structure. Also, add each grade to the total.

When the loop is done, calculate the average, divide the total by 4.

Print the highest grade, lowest grade and average.

Answer:

Here is the function unzip:

def unzip(lst):

   result= zip(*lst)

   return list(result)

The complete program in Python is given below:

def unzip(lst):

   result= zip(*lst)

   return list(result)

lst =[(1, "one"), (2, "two"), (3, "three")]

tup= unzip(lst)

print(tup)

Explanation:

Here zip() function is used in the unzip function. The return type of zip() function is a zip object. This means the function returns the iterator of tuples. This function can be used as its own inverse by using the * operator.

If you do not want to use zip() function then the above program can also be implemented as following which uses a for loop for elements in the given list (lst). This can make a pair of lists (2 tuple) instead of list of tuples:

def unzip(lst):

   output = ([ a for a,b in lst ], [ b for a,b in lst ])

   return output

lst =[(1, "one"), (2, "two"), (3, "three")]  

tup= unzip(lst)  

print(tup)

The programs along with their output are attached.

Answer:

In dynamic scoping the current block is searched by the compiler and then all calling functions consecutively e.g. if a function a() calls a separately defined function b() then b() does have access to the local variables of a(). The visible variables with the name of the function in which it was defined are given below.

Explanation:

a. main calls fun1; fun1 calls fun2; fun2 calls fun3

Solution:

b. main calls fun1; fun1 calls fun3

Solution:

c. main calls fun2; fun2 calls fun3; fun3 calls fun1

Solution:

Here variables c, d and e of fun2 are not visible .

d. main calls fun1; fun1 calls fun3; fun3 calls fun2

Solution:

Answer:

Explanation:

The objective here is to determine if the programmer can simply increase the upperbound to 80,000.

Of course Yes, The programmer can simply increase the delay by doubling the upperbound by 80000. The representation can be illustrated as:

( int : i = 0;  i <  40,000; i ++ )

{

  // delay code

}

Which can be modified as:

( int : i = 0;  i <  80,000; i ++ )

{

  // delay code

}

b)  If the code contains a delay loop and we noticed that no delay is being created at run-time. What should we suspect during debugging?

Assuming there is no delay being created at the run-time,

The code is illustrated as:

For ( int : i = 0 ; i < 0 ; i ++ )

{

  // delay code which wont

  //execute since code delay is zero

}

we ought to check whether the loop is being satisfied or not.  At the Initial value of loop variable, is there any break or exit statement is being executed in between loop. Thus, the  aforementioned delay loop wont be executed since the loop wont be executed for any value of i.

Answer:

B - The user is no longer able to log on to the network

Explanation:

Answer:

one-sided looking

Explanation:

Larry purposely looks away

Philosophy, I beleive. He tought Sikander liturature and eloquence, but his most famous teachings were of philosophy.

Aristotle taught the world science. He was considered the best scientists of his time.

Answer:

Explanation:

public class Team {

   private String teamName;

   private int teamWins;

   private int teamLosses;

   public String getTeamName() {

       return teamName;

   }

   public void setTeamName(String teamName) {

       this.teamName = teamName;

   }

   public int getTeamWins() {

       return teamWins;

   }

   public void setTeamWins(int teamWins) {

       this.teamWins = teamWins;

   }

   public int getTeamLosses() {

       return teamLosses;

   }

   public void setTeamLosses(int teamLosses) {

       this.teamLosses = teamLosses;

   }

   public double getWinPercentage() {

       return teamWins / (double) (teamWins + teamLosses);

   }

}

Following are the Java program to define the Team class and calculate its  value:

class Team //defining the class Team

{

   private String teamName;//defining String variable

   private int teamWins, teamLosses;//defining integer variable

   //defining the set method to set value the input value

   public void setTeamName(String teamName)//defining setTeamName method that takes one String parameter

   {

       this.teamName = teamName;//using this keyword that sets value in teamName

   }

   public void setTeamWins(int teamWins) //defining setTeamWins method that takes one integer parameter

   {

       this.teamWins = teamWins;//using this keyword that sets value in teamWins

   }

   public void setTeamLosses(int teamLosses)//defining setTeamLosses method that takes one integer parameter

   {

       this.teamLosses = teamLosses;//using this keyword that sets value in teamLosses

   }

   //defining the get method that returns the input value

   public String getTeamName() //defining getTeamName method

   {

       return teamName;//return teamName value

   }

   public int getTeamWins()  //defining getTeamWins method

   {

       return teamWins;//return teamWins value

   }

   public int getTeamLosses() //defining getTeamLosses method

   {

       return teamLosses;//return teamLosses value

   }

   public double getWinPercentage()//defining getWinPercentage method

   {              

       return ((teamWins * 1.0) / (teamWins + teamLosses));//using the return keyword that returns percentage value

   }      

}

Please find the complete code in the attached file and its output file in the attached file.

Class definition:

Find out more about the Class here:

brainly.com/question/17001900

Answer:

C. Resource Pool share value.

Explanation:

The vSphere is a term used to describe the VMware’s virtualization cloud platform. The vSphere comprises of the following, vCenter Server, ESXi, Virtual Machine File System (VMFS) and vCenter Client.

If a vSphere Administrator receive complaints that a database Virtual Machine (VM) is experiencing performance issues and the Virtual Machine (VM) is a member of the high priority resource pool and the cluster has not experienced contention.

In order to address immediate performance concerns, the vSphere Administrator should check the Resource Pool share value.

VMware resource pool refers to the aggregated central processing unit and memory allocated to a Virtual Machine (VM) for flexible management of the resources.

Also, the vSphere Administrator should install VMware tools to check which processes are having high CPU usage by using vimtop, as well as checking if vCenter Server is swapping.

Answer:

1. The solution to question 1 is as follows;

srand(seedVal);

cout<<rand()%10<<endl;

cout<<rand()%10<<endl;

2. The solution to question 2 is as follows

cout<<100+rand()%50 <<endl;

cout<<100+rand()%50 <<endl;

Explanation:

The general syntax to generate random number between interval is

Random Number = Lower Limit + rand() % (Upper Limit - Lower Limit + 1)

In 1;

The solution starts by calling srand(seedVal);

The next two statements is explained as follows

To print two random integers between intervals of 0 and 9 using rand()"

Here, the lower limit = 0

the upper limit =  9

By substituting these values in the formula above; the random number will be generated as thus;

Random Number = 0 + rand() % (9 - 0 + 1)

Random Number = 0 + rand() % (10)

Random Number = rand() % (10)

So, the instruction to generate the two random variables is rand() % (10)

2.

Similar to 1 above

To print two random integers between intervals of 100 and 149 using rand()"

Here, the lower limit = 100

upper limit = 149

By substituting these values in the formula above; the random number will be generated as thus;

Random Number = 100 + rand() % (149 - 100 + 1)

Random Number = 100 + rand() % (50)

So, the instruction to generate the two random variables is 100 + rand() % (50)

Answer:

total = 0

count = 0

while(True):

   grade = float(input("Enter a grade: "))

   if grade < 0:

       break

   else:

       total += grade

       count += 1

average = total/count

print("The average is: " + str(average))

Explanation:

*The code is in Python.

Initialize the total and count as 0

Create a while loop that iterates until a specific condition is met inside the loop

Inside the loop, ask the user to enter a grade. If the grade is smaller than 0, stop the loop. Otherwise, add the grade to the total and increment the count by 1.

When the loop is done, calculate the average, divide the total by count, and print it

Answer:

Explanation:

The objective of this question is to  compute a program  that involve using  a  C++ code for  designing and implementing  a Bank Account Management Simulator with integrated file storage for saving details to secondary storage.

When writing this code I notice the words are more than 5000 maximum number of characters the text editor can contain, so i created a word document for it. The attached file  to the word document can be found below.

Answer:

import java.util.Scanner;

public class ShippingCharge

{

   static double wt_2=1.50;

   static double wt_6=3;

   static double wt_10=4;

   static double wt_more=4.75;

   static double charge;

   static double weight;

public static void main(String[] args) {

    Scanner sc = new Scanner(System.in);

   do

   {

 System.out.print("Enter the weight of the package: ");

 weight = sc.nextDouble();

 if(weight<=0)

     System.out.println("Invalid input value!");

}while(weight<=0);

 if(weight<=2)

    charge=wt_2;

else if(weight<=6 && weight>2)

    charge=wt_6;

else if(weight<=10 && weight>6)

    charge=wt_10;

else

    charge=wt_more;

System.out.println("Shipping charges for the entered weight are $"+charge);

}

}

OUTPUT

Enter the weight of the package: 0

Invalid input value!

Enter the weight of the package: 4

Shipping charges for the entered weight are $3.0

Explanation:

1. The variables to hold all the shipping charges are declared as double and initialized.

   static double wt_2=1.50;

   static double wt_6=3;

   static double wt_10=4;

   static double wt_more=4.75;

2. The variable to hold the user input is declared as double.

   static double charge;

   static double weight;

3. The variable to hold the final shipping charge is also declared as double.  

4. Inside main(), an object of Scanner class is created. This is not declared static since declared inside a static method, main().

Scanner sc = new Scanner(System.in);

5. Inside do-while loop, user input is taken until a valid value is entered.

6. Outside the loop, the final shipping charge is computed using multiple if-else statements.

7. The final shipping charge is then displayed to the user.

8. All the code is written inside class since java is a purely object-oriented language.

9. The object of the class is not created since only a single class is involved.

10. The class having the main() method is declared public.  

11. The program is saved with the same name as that of the class having the main() method.

12. The program will be saved as ShippingCharge.java.

13. All the variables are declared as static since they are declared outside main(), at the class level.

Answer:

Replace /* Your solution goes here */  with the following lines of code

for(i = 0;i<SCORES_SIZE-1;i++)

{

bonusScores[i]+=bonusScores[i+1];

}

Explanation:

The above iteration starts from the index element (element at 0) and stops at the second to the last element (last - 1).

Using an iterative variable, i

It adds the current element (element at i) with the next element; element at i + 1.

The full code becomes

#include<iostream>

using namespace std;

int main(void) {

const int SCORES_SIZE = 4;

int bonusScores[SCORES_SIZE];

int i = 0;

bonusScores[0] = 10;

bonusScores[1] = 20;

bonusScores[2] = 30;

bonusScores[3] = 40;

for(i = 0;i<SCORES_SIZE-1;i++)

{

bonusScores[i]+=bonusScores[i+1];

}

/* Your solution goes here */

for (i = 0; i < SCORES_SIZE; ++i) {

printf("%d ", bonusScores[i]);

}

printf("\n");

return 0;

}

See attachment for .cpp file

Answer:int main() {

const int SCORES_SIZE = 4;

int bonusScores[SCORES_SIZE];

int i;

for (i = 0; i < SCORES_SIZE; ++i) {

cin >> bonusScores[i];

}

for (i = 0; i < SCORES_SIZE-1; ++i){

bonusScores[i] += bonusScores[i+1];

}

for (i = 0; i < SCORES_SIZE; ++i) {

cout << bonusScores[i] << " ";

}

cout << endl;

return 0;

}

Explanation: SCORES_SIZE -1 will prevent the for loop from going past the last value in the array. bonusScores[i] += will add the value of bonusScores[i+1] to the original bonusScores[i].

for example, i = 1; 1 < SCORES_SIZE - 1 ; bonusScores[1] += bonusScores[1+1} becomes{ bonusScores[1] + bonusScores{2];

Answer:

Given:

Passwords are selected from 4 characters.

Character combinations are 26 lower case alphabetic characters.

Passwords attempts by adversary is at rate of 1 second.

To find:

Expected time to discover the correct password

Explanation:

Solution:

4 character combinations of 26 alphabetic characters at the rate of one attempt at every 1 second = 26 * 4 = 104

So 104 seconds is the time to discover the correct password. However this is the worst case scenario when adversary has to go through every possible combination. An average time or expected time to discover the correct password is:

13 * 4 = 52

You can also write it as 104 / 2 = 52 to discover the correct password. This is when at least half of the password attempts seem to be correct.

Answer:

change bullets to numbers

Explanation:

100%

Answer:

Many-to-one (multiple inputs, single output)

Explanation:

Solution

In the case of a recurrent neural network that listens to a audio speech sample, and classifies it according to whose voice it is, the RNN will listen to the audio and will give result by doing classification.

There will be a single output, for the classified or say identified person.

The RNN will take a stream of input as the input is a audio speech sample.

Therefore, there will be multiple inputs to the RNN and a single output, making the best fit Architecture to be of type Many-to-one(multiple inputs, single output).

Answer:

The programming language is not stater; However, I'll answer this question using C++.

This program does not use comments (See explanation)

See Attachment for program file

Program starts here

#include <iostream>

using namespace std;

int main()

{

string response;

cout<<"What kind of swallow?\n";

cin>>response;

for(int i =0; i<response.length();i++)

{

 response[i]=toupper(response[i]);

}

   if(response == "AFRICAN")

   {

    cout<<"Yes, it could grip it by the husk.";

}

else if(response == "EUROPEAN")

   {

    cout<<"A five-ounce bird could not carry a one-pound coconut.";

}

else

{

 cout<<"You really are not fit to be a king.";

}

   return 0;

}

Explanation:

string response; -> A string variable to hold user input is declared

cout<<"What kind of swallow?\n"; -> prompts user for input

cin>>response; -> user input is stored here

The following iteration converts user input to uppercase; so that the program will work for inputs like African, AFRICAN, AFriCAN, etc.

for(int i =0; i<response.length();i++)

{

 response[i]=toupper(response[i]);

}

The following if statement prints "Yes, it could grip it by the husk." if user input is AFRICAN

   if(response == "AFRICAN")

   {

    cout<<"Yes, it could grip it by the husk.";

}

Otherwise, if user input is EUROPEAN, it prints; "A five-ounce bird could not carry a one-pound coconut."

else if(response == "EUROPEAN")

   {

    cout<<"A five-ounce bird could not carry a one-pound coconut.";

}

Lastly; for every inputs different from AFRICAN and EUROPEAN, the program displays "You really are not fit to be a king."

else

{

 cout<<"You really are not fit to be a king.";

}

Answer:

Web pages with personal or biographic information are called. a. Social Networking sites. c.

Explanation:

Answer:

Please follow the code indentation for the python program.

Explanation: