The friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 × 10^8 respectively. Also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 × 10^8 respectively.
How to determine the friction factorUsing the formula
μ = viscosity = 0. 06 Pas
d = diameter = 120mm = 0. 12m
V = velocity = 1m/s and 3m/s
ρ = density = 0.9
a. Velocity = 1m/s
friction factor = 0. 52 × [tex]\frac{0. 06}{0. 12* 1* 0. 9}[/tex]
friction factor = 0. 52 × [tex]\frac{0. 06}{0. 108}[/tex]
friction factor = 0. 52 × 0. 55
friction factor [tex]= 0. 289[/tex]
b. When V = 3mls
Friction factor = 0. 52 × [tex]\frac{0. 06}{0. 12 * 3* 0. 9}[/tex]
Friction factor = 0. 52 × [tex]\frac{0. 06}{0. 324}[/tex]
Friction factor = 0. 52 × 0. 185
Friction factor [tex]= 0.096[/tex]
Loss When V = 1m/s
Head loss/ length = friction factor × 1/ 2g × velocity^2/ diameter
Head loss = 0. 289 × [tex]\frac{1}{2*6. 6743 * 10^-11}[/tex] × [tex]\frac{1^2}{0. 120}[/tex] × [tex]\frac{1}{100}[/tex]
Head loss = 1. 80 × 10^8
Head loss When V = 3m/s
Head loss = [tex]0. 096[/tex] × [tex]\frac{1}{1. 334 *10^-10}[/tex] × [tex]\frac{3^2}{0. 120}[/tex] × [tex]\frac{1}{100}[/tex]
Head loss = 5. 3× 10^8
Thus, the friction factor and head loss when velocity is 1m/s is 0.289 and 1.80 ×10^8 respectively also, the friction factor and head loss when velocity is 3m/s is 0.096 and 5.3 ×10^8 respectively.
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what type of forces that created at shaping machine
Answer:
a magnetic force
Explanation:
What is the magnitude of the gravitational force of attraction to Jupiter exerts on IO
The gravity force between Jupiter and Io will be 6.343 × 10²² N.
What is Newton's law of gravitation?
Newton's law of gravity states that each particle having mass in the universe attracts each other particle with a force known as the gravitational force.
Given data;
Mass of Jupiter,[tex]\rm m_j = 1.9 \times 10^{27} \ kg[/tex]
Mass of moon of Jupiter,[tex]\rm m_{i_0}= 8.9 \times 10^{22} \ kg[/tex]]
The gravitational constant is,[tex]\rm G = 6.67 \times 10^{-11 } \ m^3 kg^{-1} s^{-2}[/tex]
Distance between Jupiter and Io, R = 421,700 km = 4,217,00,000 m
The gravitational force is proportional to the product of the masses of the two bodies and inversely proportional to the square of their distance.
The gravitational force is found as;
[tex]\rm F = G \frac{ m_J m_{I_0}}{R^2} \\\\\ F = (6.67\times 10^{-11}) \frac{( (1.9\times 10^{27})\times (8.9\times 10^{22} )} { (421700000)^2}\\\\ F_g = 6.343 \times 10^{22} \ N[/tex]
Hence, the gravity force between Jupiter and Io will be 6.343 × 10²² N.
The complete question is
"Jupiter has a mass of 1.9 × 1027 kg, and its moon Io has a mass of 8.9 × 1022 kg. Their centers are separated by a distance of 421,700 km what is the force of gravity acting on Io? "
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(the problem setup and question are below)
The gauge pressure at bottom of vaccine solution will be 16 kPa
Positive pressure is another name for gauge pressure. When a system's internal pressure exceeds that of its surroundings, it is said to be under positive pressure. Any leak that develops in the positively pressured system will therefore escape into the outside world. In contrast, a negative pressure chamber draws air into it.
Given As seen in the illustration, a syringe is held vertically. The container carries a 3 cm tall column of vaccine solution and has an open inner diameter of 1 cm. The needle contains a 2 cm column of vaccine solution and has an open inner diameter of 0.5 mm. At the needle's open end, the solution is exposed to the air. The vaccination solution has a density of 1200 kg/m3.
We have to find the gauge pressure at bottom of vaccine solution
Since the 5N force is applied to vaccine solution the pressure exerted will be much more
Hence the gauge pressure at bottom of vaccine solution will be 16 kPa
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Calculate the frequency of the wave shown below.
Frequency = Speed/Wavelength (λ)
Select one:
a. 4 hertz
b. 3 hertz
c. 2 hertz
d. 1 hertz
[tex] \color{skyblue}{ \underline{ \frak { \: option \: ( \: c \: ) = 2 \: hertz ✓}}}[/tex]
[tex] \: \: [/tex]
Given :
Wavelength ( λ ) = 2 m[tex] \: \: [/tex]
Speed = 4 m/s[tex] \: \: [/tex]
We, have to find frequency :
[tex] \: [/tex]
[tex] \large \tt \: Frequency = \frac{Speed}{Wavelength ( \: λ \: )} [/tex][tex] \: \: [/tex]
[tex]\large \tt \: Frequency = \frac{4}{2} [/tex][tex] \: \: [/tex]
[tex]\large \tt \: Frequency = \cancel \frac{4}{2} [/tex][tex] \: \: [/tex]
[tex] \pink{ \boxed{\large \tt \: Frequency =2 \: Hertz ✓}}[/tex][tex] \: \: [/tex]
Hope Helps!
the primary coil of a transformer has 480 turns, and the secondary has 112 turns. when an ac voltage of 28.0 v is applied to the primary, what is the output voltage in the secondary?
The voltage of the secondary will be 36 V.From the given conditions primary transformer has 3 times as many turns in the secondary coil.
What is induced voltage?Electromagnetic induction is what causes the induced voltage. Electromagnetic induction is the process of generating emf (induced voltage) by subjecting a conductor to a magnetic field.
Given data;
No turns in the primary coil,[tex]\rm N_p = 480 turns[/tex]
No turns in the secondary coil,[tex]\rm N_s = 112 turns[/tex]
The voltage of the primary coil,[tex]\rm V_p = 28 v[/tex]
The voltage of the secondary coil,[tex]\rm V_s = ?[/tex]
For a transformer,
[tex]\rm \frac{V_p}{V_s}= \frac{N_p}{N_s} \\\\ \rm \frac{28}{V_s}= \frac{480}{112} \\\\ V_s = 6.53 \ v[/tex]
Hence the voltage of the secondary will be 36 V.
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Answer: 6.53
Explanation: I had the same question and here's what I got:
Values:
Vp (Primary Voltage) = 28.0
Ns (Secondary Number of Turns) = 112
Np (Primary Number of Turns) = 480
Vs = Vp Ns/Np
= (28)(112)/(480)
Vs = 6.53 (FINAL ANSWER)
Question 2 of 25
What is the term for a pair of forces described by Newton's third law?
A.
Normal-friction pair
B.
Action-reaction pair
C.
Kinetic-static pair
D.
Inertia-movement pair
The term for a pair of forces described by Newton's third law is action-reaction pair. Details about Newton's law can be found below.
What does Newton's third law state?Newton's third law of motion states that for every action, there is an equal and opposite reaction.
This law proposed that when an object 1 acts on object 2 with a force of a particular magnitude, object 2 also acts on object 1 with an opposite force of same magnitude.
Therefore, it can be said that the term for a pair of forces described by Newton's third law is action-reaction pair.
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A mass of 2.0 kg of water is heated. The temperature increase of the water is 80 degrees Celsius. The specific heat capacity of water is 4200 J / kg degrees Celsius. Calculate the change in thermal energy when the water is heated. Use the equation. change in the thermal energy = mass x specific heat capacity x temperature change
Answer:
672 000 J or 672 kJ
Explanation:
change in the thermal energy = mass x specific heat capacity x temperature change
= 2 kg * 4200J/kg-C *80 C =672000 J
Question 4 of 20
If the distance between two objects is doubled, what happens to the
gravitational force between them?
A. It decreases to 1/2 its original magnitude.
B. It increases to 2 times its original magnitude.
C. It increases to 4 times its original magnitude.
D. It decreases to 1/4 its original magnitude.
Answer:
D
Explanation:
F = G m1 m2 / r^2 now double r
F = G m1m1/ (2r)^2
F = 1/4 G m1m2/r^2 <===== this is 1/4 of the original
R S ( M ) = 2 G M c 2 , where G is the gravitational constant and c is the speed of light. It is okay if you do not follow the details of the equation; the basic point is that if you put an amount of mass M or larger in a sphere of radius smaller than RS(M)
What equation is this
The provided question's answer is "Schwarzschild radius".
The conversion factor between mass and energy is the speed of light squared.
GM/r stands for gravitational potential energy, also known as energy per unit mass.
GM/rc² then has "mass per unit mass" units. In other words, as mass/mass splits out in a dimensional analysis, "dimensionless per unit."
The derivation yields a formula for time or space coordinate ratios requiring sqrt(1 - 2GM/rc²). This number becomes 0 when r=2GM/c2, or the formula becomes infinite if in the denominator. However, there is no justification for using c² as a conversion factor there. Consider the initial expression sqrt(1 - 2GM/rc²).
Assume that m is used as the test particle's mass instead of 1. Then you have sqrt(m - 2GMm/rc² and mass units. This expression denotes that the rest energy of the test mass m you introduced into the gravitational field is "gone" at that radius.
The 2 would be absent if the gravitational field were Newtonian. However, at the event horizon, Einstein gravity is slightly stronger than Newton gravity, resulting in the factor 2 in qualitative terms.
So, the given equation is of Schwarzschild radius.
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Which of the following is not a use of nuclear chemistry in industry?
thickness gauges
tracers
leak detectors
stimulate plant growth
Stimulating plant growth is not a use of nuclear chemistry in industry. Thus, the correct option is D.
What is Nuclear Chemistry?Nuclear chemistry may be defined as the sub-branch of chemistry that involves the investigation of physical and chemical characteristics of elements that are affected by transformations in the configuration of the atomic nucleus.
Thickness gauges measure the thickness, density, and fill levels and are utilized in manufacturing to make sure that an entire product or a set of products are of identical thickness.
Tracers are utilized in tracing the actual composition of radioactive decay through the chemical compounds. While the leak detectors monitor the actual and constant flow of water through a given system precisely.
Therefore, the correct option for this question is D.
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Answer:
it is d
Explanation:
Which sentence describes an object that has kinetic energy?
Answer:
Kinetic energy is referred to the energy associated with movement and or motion, thus the only object that is moving would be A boat sailing across the ocean.
Explanation:
A 200-gram liquid sample of Alcohol Y is prepared at -6°C. The sample is then added to 400 g of water at 20°C in a sealed styrofoam container. When thermal equilibrium is reached, the temperature of the alcohol-water solution is 12°C. What is the specific heat capacity of the alcohol? Assume the sealed container is an isolated system. The specific heat capacity of water is 4.19 kJ/kg · °C. 3.14 kJ/kg \xe2\x88\x99 °C 4.14 kJ/kg \xe2\x88\x99 °C 3.72 kJ/kg \xe2\x88\x99 °C 4.88 kJ/kg \xe2\x88\x99 °C
The specific heat capacity of the alcohol will be 3.72 kJ/kg°C.
What is the specific heat capacity?The amount of heat required to increase a substance's temperature by one degree Celsius is known as its "specific heat capacity."
Similarly, heat capacity is the relationship between the amount of energy delivered to a substance and the increase in temperature that results.
Given data;
Mass of liquid sample of Alcohol m₁ = 200-gram
The temperature of alcohol, T₁ = -6°C.
Mass of liquid sample of water m₂ = 400-gram
The temperature of the water, T₂= 20°C.
The specific heat capacity of the alcohol, S₁=?
The specific heat capacity of water is, S₂=4.19 kJ/kg.°C
As we know that;
[tex]\rm Q_{gain}= Q{loss} \\\\ Q_{alcohol} =Q_{water} \\\\\ m_1s_1\triangle T_1 = m_2S_2 \triangle S_2 \\\\ 200 \times 10^{-3} \times S_1 [ (12-(-6) ] = 40 \times 10^{-3} \times 4.19 \times 10^{-3} \times (20-12)\\\\S_1 = 2 \times 4.19 \times 10^3 \times \frac {8}{18} \\\\ S_1 = 3.72 \ kJ /kg ^0 C[/tex]
Hence the specific heat capacity of the alcohol will be 3.72 kJ/kg°C.
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Which picture shows the wave with the smallest wavelength?
Select one:
a. A
b. B
c. C
d. D
Answer:
b. B
Explanation:
Picture B has the smallest peaks among all which henceforth makes the wavelength i.e. distance between two adjacent crests or troughs, small.
Answer:b
Explanation:Wavelength can be calculated using the following formula: wavelength = wave velocity/frequency. Wavelength usually is expressed in units of meters. The symbol for wavelength is the Greek lambda λ, so λ = v/f.
Identify the law, write the equation and calculate the answer to the problem below.
An incident light ray strikes water at an angle of 45 degrees. The index of refraction of air is 1.0003, and the index of refraction of water is 1.33. What is the angle of refraction rounded to the nearest whole number?
Find refractive index first
[tex]\\ \rm\Rrightarrow \mu=\dfrac{c}{v}[/tex]
[tex]\\ \rm\Rrightarrow \mu=\dfrac{1.0003}{1.33}[/tex]
[tex]\\ \rm\Rrightarrow \mu =0.75[/tex]
Now
[tex]\\ \rm\Rrightarrow \dfrac{sini}{sinr}=\mu[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{sin45}{sinr}=0.75[/tex]
[tex]\\ \rm\Rrightarrow \dfrac{sin45}{0.75}=sinr[/tex]
[tex]\\ \rm\Rrightarrow sinr=0.94[/tex]
[tex]\\ \rm\Rrightarrow r=sin^{-1}(0.94)[/tex]
[tex]\\ \rm\Rrightarrow r=70^{\circ}[/tex]
Your heart pumps about 70 mL of blood per beat and beats an average of 80 Times per minute how many gallons of blood does your heart pump every hour
Answer:
88.761
Explanation:
What is the acceleration of the object?
m/s²
Answer:
-2.5m/s^2
Explanation:
10-40/12-0=-2.5
a 1kg ball is bening pushed by the rod to move in horizontal groved smooth slot if it startes from angle teta = zero degree . determaine the force the rod exertes on the ball at teta is =15 dgree if ai this instant the rod moves at angular speed of teta = 1 rad per sec end with angular acceleration theta = 2 rad persec and square the ball is only in contact with the outer side of the slot
The force the rod exerts on the ball at the given angle is determined as 3.94 N.
Force exerted on the rod by the ball
The force exerted is calculated as follows;
F = ma
F = mv²/r
F = mω²r
where;
m is mass of the ballω is angular speed of the ballr is radius of the pathr = 2cosθ
Angular speed when the ball moves 15 degreesωf² = ωi² + 2αθ
where;
θ is angular displacement in radians, 15⁰ = 15 x π/180 radωf² = (1)² + 2(2)(15 x π/180)
ωf² = 2.04
ωf = √2.04
ωf = 1.428 rad/s
F = mω²(2cosθ)
F = (1)(1.428)²(2 x cos15)
F = 3.94 N
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A mass of (200 of hot water at (75, 0 degrees * C) is mixed with cold water of mass M at (5, 0 degrees * C) The final temperature of the mixture is (25, 0 degrees * C) What is the mass of the cold water (M)
Q in = Q out
mcΔt in = mcΔt out (c = equal)
mΔt in = mΔt out
200 x (75-25) = M x (25-5)
M = 500 g
∆T for hot water
75-2550°C∆T for cold water
25-520°CBoth are equal according law of conservation of energy
[tex]\\ \rm\Rrightarrow m_1c\delta T_0=m_2c\delta [/tex]
[tex]\\ \rm\Rrightarrow 200(50)=m_2(20)[/tex]
[tex]\\ \rm\Rrightarrow 10000=m_2(20)[/tex]
[tex]\\ \rm\Rrightarrow m_2=500g=0.5kg[/tex]
A skier (m=55.0 kg) starts sliding down from the top of a ski jump with negligible friction and takes off horizontally.
H = 1.15x10^1 m, h= 6.50 m, and D = 11.4 m.
Find her total kinetic energy as she reaches the ground.
The total kinetic energy of the woman when she reaches the ground is 6,198.5 J.
Total kinetic energy of the woman at the ground levelThe total kinetic energy of the woman when she reaches the ground is calculated from the principle of conservation of energy.
P.E(top) = K.E(bottom)
P.E(top) = mgh
P.E(top) = 55 x 9.8 x 11.5
P.E(top) = 6,198.5 J
Thus, the total kinetic energy of the woman when she reaches the ground is 6,198.5 J.
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You drive 8.50 km in a straight line in a direction 30° East of North.
(a) Find the distances you would have to drive straight East and then straight North to arrive at the same point. (This is equivalent to finding the components of the displacement along the East and North directions.)
km East
km North
(b) Show that you still arrive at the same point if the East and North legs are reversed in order.
(a.1) The component of displacement along the East is 7.36 km.
(a.2) The component of displacement along the North is 4.25 km.
(b) When the East and North legs are reversed in order, you will still travel 8.5 km.
Component of displacement along the East
dx = d cosθ
dx = 8.5 km x cos(30)
dx = 7.36 km
Component of displacement along the Northdy = d sinθ
dy = 8.5 km x sin(30)
dy = 4.25 km
When East and North legs are reversed;dx = 4.25 km
dy = 7.36 km
Resultant displacement;
R = √(dx² + dy²)
R = √(4.25² + 7.36²)
R = 8.5 km
Thus, when the East and North legs are reversed in order, you will still travel 8.5 km.
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At a given temperature, lighter gas molecules:
A) have an average speed less than heavier gas molecules.
B) have an average speed greater than heavier gas molecules.
C) ll move more slowly than heavier gas molecules.
At a given temperature, lighter gas molecules, have an average speed greater than heavier gas molecules.
What is temperature?Temperature is the measure of degree of hotness or coldness of a body. It is also the measure of average kinetic energy of a body.
As temperature increases, the average kinetic energy of a body increases.
K.E = ¹/₂mv²
v² = 2K.E/m
v = √( 2K.E/m)
where;
m is massv is velocityK.E is kinetic energyFrom the equation above, at a constant temperature, the speed of a gas molecule will decrease with increase in the mass of the molecules and vice versa.
Thus, at a given temperature, lighter gas molecules, have an average speed greater than heavier gas molecules.
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A 63.3 kg wood board is resting on very smooth ice in the middle of a frozen lake. A 35.7 kg boy stands at one end of the board. He walks from one end of the board to the other end with a velocity of 1.47 m/s relative to the ice in the positive direction. What is the velocity of the board relative to the ice?
The velocity of the board relative to the ice is zero, since both are at rest.
What is relative velocity?Relative velocity is the velocity of an object in relation to another reference object or point.
When two objects are travelling or moving with the same velocity in the same direction, the relative velocity one relative to the other is zero.
Also, when two objects are at rest, the relative velocity one relative to the other is zero.
Therefore, the velocity of the board relative to the ice is zero, since both are at rest.
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A contestant in a winter games event pushes a 54.0 kg block of ice across a frozen lake as shown in Figure 4.29(a). The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03.
a) Calculate the minimum force F he must exert to get the block moving.
N
(b) What is its acceleration once it starts to move, if that force is maintained?
m/s2
Answer:
54.0 x0.1=5.4 x0.03=0.162
kinetic force
If a contestant in a winter games event pushes a 54.0 kg block of ice across a frozen lake. The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03, then the minimum force F he must exert to get the block moving would be 5.2974 Nwrons.
What is friction?
Friction is a type of force that resists or prevents the relative motion of two physical objects when their surfaces come in contact.
As given in the problem, If a contestant in a winter games event pushes a 54.0 kg block of ice across a frozen lake. The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03,
The force required to get the block moving = μMg
= 0.01×54×9.81
= 5.2974 Newtons
Thus, the minimum force required to move the block would be 5.2974 Newtons.
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Any Acellus folk figure out the answer to this one??? I CANNOT for the life of me.
What is the angular velocity of the minute hand of a clock?
[?] rad/s
Hint: It travels clockwise and takes 60 minutes to make one revolution.
(not 1.25, 1.7, 1800, 30, 60, 0.1047)
Answer:
-0.10472[tex]\frac{rad}{s}[/tex]
Explanation:
Remember that any clockwise rotation is considered negative, and any counterclockwise rotation is considered positive.
The formula for period is:
[tex]T = \dfrac{2\pi}{\omega}[/tex]
Solve for [tex]\omega\\[/tex] and you get:
[tex]\omega=\dfrac{2\pi}{T}[/tex]
The period is 60 seconds so make that division and you're left with -0.10472[tex]\frac{rad}{s}[/tex] or -0.10[tex]\frac{rad}{s}[/tex] if significant figures apply (negative because the rotation is clockwise).
the road from city A to city B is described by a car with Vm 40 km / h. When the car turns (from B to A) the average speed is 60 km / h. Find the average round trip speed.
Answer:
Let distance between two cities is x km . So total distance travelled bus x+x=2x km and time taken was=(x/40)+(x/60)=(3x+2x)/120=5x/120=x/24 hrs . So avg speed is 2x/(x/24)=48 km per hr.
or
dt1=60km1h
dt2=30km1h
2dt1+t2=r¯
d=60t1
d=30t2
60t1=30t2
2t1=t2
2dt1+(2t1)=r¯
2(60t1)t1+2t1=r¯
2(60t1)=r¯(t1+2t1)
120=r¯+2r¯
r¯=1203
r¯=40km/h
A solenoid with 465 turns has a length of 8.00 cm and a cross-sectional area of 3.10 ✕ 10−9 m2. Find the solenoid's inductance and the average emf around the solenoid if the current changes from +3.50 A to −3.50 A in 7.83 ✕ 10−3 s
The solenoid's inductance and the average emf around the solenoid if the current changes from +3.50 A to −3.50 A in 7.83 ✕ 10−3 s will be 1.01 ×10⁻⁸ H and 9.02 × 10⁻² V.
What is a solenoid?A coil of wire that carries an electric current is a solenoid. A solenoid is an electromagnet formed by a helical coil of wire.
Which generates a magnetic field when an electric current is passed through the coil.
A solenoid is a form of coil that produces a magnetic field when the electric current is passed through it. A solenoid is created when a conductive wire is used to make a loop.
Given data;
Turns ,N = 465
Length,L= 8.00 cm
Cross-sectional area,A = 3.10 ✕ 10−9 m2.
Solenoid's inductance, L=?
The average emf around the solenoid, E=?
Time of flow,t= 7.83 ✕ 10−3 s
Current changes from +3.50 A to −3.50 A
The inductance of the solenoid is found as;
[tex]\rm L = \frac{\mu_0 AN^2}{L} \\\\ \rm L = \frac{4 \times \pi \times 10^{-7}\times 3.0 \times 10^{-9} \times (465)^2 }{8.00 \times 10^{-2}} \\\\ L= 1.01 \times 10^{-8} \ H[/tex]
The average emf around the solenoid is found as;
[tex]\rm e = L \frac{I_2-I_1}{t} \\\\ \rm e = 1.01 \times 10^{-8} \times \frac{3.50-(-3.50)}{7.83 \times 10^{-3}} \\\\ e =9.02 \times 10^{-12} \ V[/tex]
Hence, the solenoid's inductance will be 1.01× 10⁻⁸ H.
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a generator produces a maximum emf of 240 v when rotating at 3.7 rad/s in a magnetic field of 0.200 t. if the coil has 822 loops what is the area of each loop?
Answer:
I actually did that but I fprgot
Answer: 0.0387
Explanation: I had the same problem and here's what I got:
Values:
ε (Voltage) = 240
ω (Angular velocity) = 37.7
B (Magnitude) = 0.200
N (Number of loops) = 822
ε = NABω (Rearrange to get A)
A = ε/WBN
= (240)/(37.7)(0.200)(822)
A = 0.0387 (FINAL ANSWER)
A 17-kg sled is being pulled along the horizontal snow-covered ground by a horizontal force of 31 N. Starting from rest, the sled attains a speed of 2.3 m/s in 9.2 m. Find the coefficient of kinetic friction between the runners of the sled and the snow.
What is the number and units?
The sled accelerates with magnitude [tex]a[/tex] such that
[tex]\left(2.3\dfrac{\rm m}{\rm s}\right)^2 = 2a(9.2\,\mathrm m) \implies a = 0.2875\dfrac{\rm m}{\mathrm s^2}[/tex]
By Newton's second law, the net force in the plane of motion (parallel to the ground) is
[tex]31\,\mathrm N - F_{\rm friction} = (17 \,\mathrm{kg}) \left(0.2875 \dfrac{\rm m}{\mathrm s^2}\right)[/tex]
so that the force of friction exerts a magnitude of
[tex]F_{\rm friction} = 26.1125 \,\mathrm N[/tex]
Perpendicular to the ground, the sled is in equilibrium, so Newton's second law says
[tex]F_{\rm normal} - (17\,\mathrm{kg})g = 0 \implies F_{\rm normal} = 166.6 \,\mathrm N[/tex]
The magnitude of friction is proportional to the magnitude of the normal force by a factor of [tex]\mu_k[/tex], the coefficient of kinetic friction. It follows that
[tex]F_{\rm friction} = \mu_k F_{\rm normal} \implies \mu_k = \dfrac{26.1125\,\rm N}{166.6\,\rm N} \approx \boxed{0.16}[/tex]
(and the coefficient is dimensionless).
The action force is the ballon pushing the air out. What is the magnitude of the reaction force of the air pushing the ballon
The magnitude of the reaction force of the air pushing the balloon would be equal and opposite.
How is the reaction force equal and opposite?A push or a pull that an object experiences as a result of interacting with another item is known as a reaction force.
Newton's third law is officially expressed as follows: There is an equal and opposite reaction to every action. The implication of the statement is that there are always two forces acting on the two interacting objects. The force acting on the first object is equal in size to the force acting on the second. The force acting on the first object is acting in the opposite direction to the force acting on the second object. Force pairs—equal and opposing action-reaction force pairs—always exist in pairs.
Knowing that everything has an equal and opposite reaction according to Newton's second law. The preasured air that a balloon had to push out into the free air acts as the reaction force.
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A block of mass 4 kg is attached to a spring of force constant (k) 1000 N/m, and undergoes simple harmonic motion. What is the period of the motion?
a. 0.1 s
b. 0.4 s
с. 0.2 s
d. 0.3 s
Answer:
0.4
Explanation:
ω = km
ω = 1000 x 4
ω = 4000 divide this by 10000 and you get 0.4s
