factors of production examples for a home?

Answer:

B) P1 would increase to maintain the flow rate ( correct )

C) The resistance would increase (correct )

Explanation:

flow rate = 10 liters per minute

Driving pressure (p1) = 20 cm H20

Fixed downstream pressure (p2) = 5 cm H20

The correct statements when we pinch the Lumen in the middle of the tube would be : P1 would increase to maintain the flow rate and The resistance would increase.this is because when we pinch the Lumen we reduce its diameter and the reduction of its Diameter will result to increased resistance against the flow and resistance of flow is directly proportional to pressure hence P1 would increase as well

The wrong statement would be : The flow would decrease

Answer:

Technical drawing, also known as drafting or draughting, is the act and discipline of making detailed drawings. These drawings visually communicate how something works or how it is to be made.

Answer:

The answer is "[tex]\bold{e^{-t} \sin t}[/tex]"

Explanation:

Given equation:

[tex]\to x+2x+2x=0.............(a)[/tex]

Let x= e^{mt} be a solution of the equation will be:

[tex]\to m^2+2m+2=0[/tex]

compare the value with the  [tex]am^2+bm+c=0[/tex]

[tex]\to a= 1\\\to b= -2\\\to c= 2\\[/tex]

Formula:

[tex]\bold{=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\\\\=\frac{-2 \pm \sqrt{(-2)^2-4\times 1 \times 2}}{2 \times 1}\\\\=\frac{-2 \pm \sqrt{4-8}}{2}\\\\=\frac{-2 \pm \sqrt{-4}}{2}\\\\=\frac{-2 \pm 2i}{2}\\\\[/tex]

Calculate the g.s at equation (a):

[tex]\to x = e^{-t} (c_1 \cos t+ c_2 \sin t)............(b)\\\\\to x = e^{-t} (c_2 \cos t -c_1 \sin t) - e^{-t} (c_1 \cos t + c_2\sin t) ...............(c)\\\\[/tex]

[tex]_{when} \\\\\to t= 0\\\\\to x=x_0\\\\\to x= v_0 =1 \\\\ \ then \ form \ equation \ (b) \ and \ equation \ (c)[/tex]

[tex]\to a= 0 \\ \to c_2 -c_1 =1 \\ \to c_2=1[/tex]

The value of [tex]x = e^{-t} ( 0 \times \cos t + 1 \times \sin t)[/tex]

[tex]\boxed{\bold{x = e^{-t} (\sin t)}}[/tex]

Answer:

To run. The machine one at a time

Explanation:

The interactive activities for the course will be scored by the instructor.

Interactive activities

Interactive classroom activities are defined as the activities or interactive sessions which is a two way communications or discussions where the students involved also participate in discussions and interacts with the teacher or the instructor.

For the particular course, the interactive sessions will be scored by the instructor.

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Answer:

[tex]\mathbf{stress \ \sigma = 264.6 \ Mpa}[/tex]

Explanation:

From the concept of Hooke's  Law,

[tex]E =\dfrac{ stress \ \sigma}{ strain \ \varepsilon}[/tex]

where;

[tex]strain \ \varepsilon = \dfrac{change \ in \ dimension }{original \ dimension}[/tex]

[tex]strain \ \varepsilon = \dfrac{7 \ mm }{4.75 \times 10^{3} \ mm}[/tex]

[tex]strain \ \varepsilon =0.00147368[/tex]

Recall:

[tex]E =\dfrac{ stress \ \sigma}{ strain \ \varepsilon}[/tex]

[tex]stress \ \sigma = E \times { strain \ \varepsilon}[/tex]

[tex]stress \ \sigma = 180 \times 10^{3} \ Mpa \times 0.00147[/tex]

[tex]\mathbf{stress \ \sigma = 264.6 \ Mpa}[/tex]

Thus, the stress in the pipe at the maximum allowable contraction = 264.6 Mpa

Explanation:

It gives her a sense of purpose.

Answer: the distance in advance of the curve the sign must be located to ensure that vehicles have sufficient distance to decelerate safely is 292.07 ft

Explanation:

first we calculate the distance to place sign board in advance to curve for decelerating the speed

d = 1.47Si t + [ (Si² - Sf²) / 30(0.348 ± 0.01G)

where d is the safe stopping distance, initial speed is Si (60 mi/hr ), time reaction is t (2.5s), Sf is the final speed (40 mi/hr), G is the grade (0).

so we substitute

d = (1.47 × 60 × 2.5) + [ (60² - 40²) / 30(0.348 ± 0)

= 220.5 + ( 2000/10.44)

= 220.5 + 191.57

= 412.07 ft

Now giving that a warning sign is clearly visible at a distance of 120 ft

optimum safe distance will be

d = minimum distance - sign visible distance

d = 412.07 - 120

d = 292.07 ft

therefore the distance in advance of the curve the sign must be located to ensure that vehicles have sufficient distance to decelerate safely is 292.07 ft

Answer:

The answer is "83.98, 1889.195, and 1889.195"

Explanation:

Given value:

[tex]\bold{P_{4}=2.34 \ kPa}[/tex]

In point a:

The value of [tex]h_{f4}=83.915 \ \ \frac{Kj}{kg}\\[/tex]

[tex]V_4=0.001002 \ \ \frac{Kj}{kg}\\\\U_4= 83.98 \ \ \frac{Kj}{kg}\\\\[/tex]

In point b:

calculating heat leaves formula= [tex]h_3-h_{f4}[/tex]

                                                      [tex]= 1973.11-83.915\\\\= 1889.195 \ \ \frac{KJ}{kg}[/tex]

In point c:

calculating Heat transfer rate formula[tex]=m(h_3-h_4)[/tex]

                                                              [tex]= 1(1889.195)\\\\ = 1889.19 \ \ kw.[/tex]

Answer:

The angles are missing in the question.

The angles are :

45,     30,    60,     90,    -34,     -56,      20,     -42,  -65,    -15

P=10, P=5,  P=25, P=54, P=65, P=95, P=250, P=8, P=35, P=150

Explanation:

1. P = 10,   θ = 45°  rectangular coordinates

x = r cosθ  ,   y = r sinθ

So, rectangular form is x + iy

x = P cosθ = 10 cos 45°

  = 7.07

y =P sinθ = 10 sin 45°

  = 7.07

Therefore, rectangular form

x + iy = 7.07 + i (7.07)

2. P = 5 , θ = 30°

x = 5 cos  30° = 4.33

y = 5 sin  30° = 2.5

So, (x+iy) = 4.33 + i (2.5)

3. P = 25 , θ = 60°

x = 25 cos  60° = 12.5

y = 25 sin  60° = 21.65

So, (x+iy) = 12.5 + i (21.65)

4. P = 54 , θ = 90°

x = 54 cos  90° = 0

y = 54 sin  90° = 54

So, (x+iy) = 0+ i (54)

5. P = 65 , θ = -34°

x = 65 cos  (-34°) = 53.88

y = 65 sin  (-34°) = -36.34

So, (x+iy) = 53.88 - i (36.34)

6. P = 95 , θ = -56°

x = 95 cos  (-56)° = 53.12

y = 95 sin  (-56)° = -78.75

So, (x+iy) = 53.12 - i (78.75)

7. P = 250 , θ = 20°

x = 250 cos  20° = 234.92

y = 250 sin 20° = 85.5

So, (x+iy) = 234.92 + i (85.5)

8. P = 8 , θ = (-42)°

x = 8 cos  (-42)° = 5.94

y = 8 sin  (-42)° = -5.353

So, (x+iy) = 5.94 - i (5.353)

9. P = 35 , θ = (-65)°

x = 35 cos  (-65)° = 14.79

y = 35 sin  (-65)° = -31.72

So, (x+iy) = 14.79 - i (31.72)

10. P = 150 , θ = (-15)°

x = 150 cos  (-15)° = 144.88

y = 150 sin  (-15)° = -38.82

So, (x+iy) = 144.88 - i (38.82)

Answer:

Some of the benefits are tangible for they are visible in the design and production process, while the other benefits are intangible which may not be visible directly but result in improvement in the quality of product, better control over designing and production process, reduction of stress on the designers etc.

Answer:

A.

Explanation:

Answer:

metals, composite, ceramics and polymers.

Explanation:

The four categories of engineering materials used in manufacturing are metals, composite, ceramics and polymers.

i) Metals: Metals are solids made up of atoms held by matrix of electrons. They are good conductors of heat and electricity, ductile and strong.

ii) Composite: This is a combination of two or more materials. They have high strength to weight ratio, stiff, low conductivity. E.g are wood, concrete.

iii) Ceramics: They are inorganic, non-metallic crystalline compounds with high hardness and strength as well as poor conductors of electricity and heat.

iv) Polymers: They  have low weight and are poor conductors of electricity and heat

Answer:

yes yes it is why wouldn't it be

It is true that buying shop supplies from the shop owner to work on your own car at home is an ethical practice.

The term "ethical practises" refers to deeds and conduct that uphold established moral and social norms as well as shared values.

Honesty, fairness, transparency, accountability, respect, and responsibility are the traits that define these procedures.

The precise circumstances and the relationship between the shop owner and the individual will determine if purchasing shop materials from a shop owner to work on your own car at home is an ethical practise.

The exact situation and the relationship between the shop owner and the individual will determine whether or not purchasing shop materials from a shop owner to work on your own car at home is ethical.

Before implementing such a method, it is crucial to think about the possible outcomes and any ethical issues.

Thus, the given statement can be considered as true.

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Answer: These robots study planets from space. The Cassini spacecraft is this type of robot. Cassini studies Saturn and its moons and rings. The Voyager and Pioneer spacecraft are now traveling beyond our solar system

Explanation:

Answer:

The answer is below

Explanation:

[tex]\theta_1=cos^{-1}0.28=73.74^o\ lagging\\\\S_1=125\angle 73.74^o=35\ kW+j120\ kVAR\\\\S_2=10\ kW-j40\ kVAR\\\\S_3=15\ kW[/tex]

Total power = P = 35 kW + 10 kW + 15 kW = 60 kW

Total kVAR = 120 kVAR - 40 kVAR = 80 kVAR

[tex]Total\ apparent \ power =S= S_1+S_2+S_3=(35+j120)+(10-j40)+(15)\\\\S=60\ kW+j80\ kVAR=100\angle 53.13^o\\\\Current(I)=\frac{S^*}{V^*} \frac{100000\angle -53.13^o}{1400\angle0}=71.43\angle-53.13^o\\ \\Power\ factor (PF)=cos(53.13)=0.6\ lagging\\\\The \ new\ power\ factor\ is\ to \ be\ 0.8[cos^{-1}0.8=36.87^o], hence\ since\ the\ total\ \\real\ power(P)= 60\ kW, the\ capacitor\ kVAR(Q_c)\ is:\\\\Q_c=60tan(53.13)-60tan(36.87)=80-45=35\ kVAR\\\\[/tex]

[tex]C=\frac{Q_c}{wV^2} =\frac{35000\ VAR}{2\pi*60\ Hz*1400\ V}=47.38\ \mu f[/tex]

New current (I') = [tex]\frac{S'^*}{V^*}=\frac{60000-j45000}{1400}=53.57\angle-36.87^o[/tex]

Current reduce from 71.43 A to 53.57 A

Answer:

  1.39 µmol

Explanation:

(1 gal) × (44.7 µg/L)/(121.76 g/mol)(3.785411784 L/gal) = 1.39 µmol

Answer:

The python code for the given problem is written in explanation section.

Explanation:

The code for the given situation, in Python, can be written as follows:

x = int(input("Enter a positive number for dividend: "))

y = int(input("Enter a positive number for divisor: "))

quotient = x//y

remainder = x%y

print("The Quotient of the given calculation is:",quotient)

print("The Remainder of the given calculation is:",remainder)

Answer:

hmm i would try calling him. ask your mom or other adults where he is!

Explanation:

hope you get help soon!

Answer:

if he actually said that about the money, then do it. If its dirty money then get away. drug cartels or corrupt people will torture you just to get back at him, regardless if he even knows or if you did anything to them. If you are female, then yeah you really should run. its like the tv shows, but except, they dont have to keep it within movie standards.

Explanation:

Answer:

the answer is A

Explanation:

Answer:

A

Explanation:

Answer:

A ) CPI : M1 = 2.4 , M2 = 2.65

B ) MIPS : M1 = 1083, M2 = 1056

C ) The machine that has a better performance based on MIPS is M1 and this is  by 27 million number of instructions per sec

Explanation:

A) The CPI for each machine

CPI = ( Total number of execution cycles ) / ( instruction counter executed )

For Machine 1 ( M1 )

we have to make some assumptions : number of instructions = 10

number of times A was executed = 4 , Number of times B was executed = 2.5 , number of times C was executed = 2.5, Number of times D was executed = 1. and this was based on the frequency given above

hence CPI for M1 =[ ( 1 * 4 ) + ( 3 * 2.5 ) + ( 3 * 2.5 ) + ( 5 * 1 ) ] / 10

       CPI  for M1 = 2.4

For Machine 2 ( M2 )

we have to make some assumptions : number of instructions = 10

number of times A was executed = 4 , Number of times B was executed = 2.  number of times C was executed = 1.5, Number of times D was executed = 2.5 times. and this was based on the frequency given above

Hence CPI  for M1 = [ ( 2 * 4 ) + ( 2 * 2 ) + ( 3 * 1.5 ) + ( 4 * 2.5 ) ] / 10

            CPI for M2 = 2.65

B ) Calculate the native MIPS  ratings for M1 and M2

MIPS = ( instruction counts ) / ( Execution time * 10^6 )

For M1

Assumptions : number of instructions executed = 10

                        each clock cycle = 0.3846 * 10^-9.      frequency = 2.6 Ghz

first we calculate the total execution time which is equal to :

= [ ( 1 * 4 ) + ( 3 * 2.5 ) + ( 3 * 2.5 ) + ( 5 * 1 ) ] * 0.3846 * 10 ^-9

= 9.2304 * 10 ^-9 secs

therefore the MIPS for M1

= 10 / ( 9.2304 * 10^-9 ) * 10^6  = 1083

For M2

Assumptions : number of instructions executed = 10

                        each clock cycle = 0.3846 * 10^-9.      frequency = 2.8 Ghz

first we calculate the total execution time which is equal to :

= [ (2*4) + (2*2) + (3 * 1.5 ) + ( 4 * 2.5 ) ] * 0.3846 * 10^-9 = 9.4631 * 10^-9 secs

therefor the MIPS for M2

= 10 / ( 9.4631*10^-9) * 10^6 = 1056

C ) The machine that has a better performance based on MIPS is M1 and this is by 27 million number of instructions per sec

Answer:

  5 rpm

Explanation:

Each turn of the driver gear moves 10 teeth past the point of engagement with the driven gear. That is half of the 20 teeth on the driven gear, so it makes 1/2 turn for each turn of the driver.

In 1 minute, the driver makes 10 turns, so the driven gear makes 5 turns. Its speed is 5 rpm.

Answer: C. Biotechnology system

Explanation:

Answer:

LCDs consume less power than CRTs

Explanation:

The sentence that best compares LCDs with CRTs is that "LCDs consume less power than CRTs".

Recently, in many homes and offices, cathode ray tube (CRT) monitors are being replaced by liquid crystal display (LCD) monitors. There are some benefits that LCD panels offer over CRT monitors. Some of them are:

LCD monitors don't usually take up much space. They take less space than CRT monitors. Also, LCDs consume less power than CRT monitors. Which means that CRTs consume more power than LCDs. LCD monitors gives a much brighter image than CRT monitors .

Answer:

k = 0.1118 per min

Explanation:

Assume;

Initial number of bacteria = N0

Number of bacteria IN 'T' time = Nt

So,

[tex]Nt=N0e^{-kt}\\\\in\ 6.2 min\\\\\\frac{N0}{2}= N0e^{-k(6.2)}\\\\ln\frac{1}{2} = -k[6.2][/tex]

k = 0.1118 per min

Answer:

3150 L/min

Explanation:

The volume of the room is the product of the height of the room and its area. It is given as:

Volume (V) = height (h) × Area (A)

V = h × A

Height = 2.7 m, Area = 200 m². Hence:

V = h × A = 2.7 × 200 = 540 m³

The flow capacity ([tex]\dot {V}[/tex]) is given by

[tex]\dot {V}=ACH*Volume\ of\ room[/tex]

ACH = air changes per hour = 0.35

[tex]\dot {V}=ACH*Volume\ of\ room\\\\\dot {V}=0.35*540\\\\\dot {V}=189\ m^3/h[/tex]

But 1 m³ = 1000 L, 1 hr = 60 min

[tex]\dot{V}=189\ m^3/h=\frac{189\ m^3*\frac{1000\ L}{1\ m^3} }{1\ h*\frac{60\ min}{1\ h} } =3150\ L/min\\\\\dot{V}=3150 \ L/min[/tex]

Answer:

Centimeters

Explanation:

Answer:

[tex]v = 250[1 - {e^{-6000t}}][/tex] mV

Explanation:

The voltage across a capacitor at a time t, is given by:

[tex]v(t) = \frac{1}{C} \int\limits^{t}_{t_0} {i(t)} \, dt + v(t_0)[/tex]                 ----------------(i)

Where;

v(t) = voltage at time t

[tex]t_{0}[/tex] = initial time

C = capacitance of the capacitor

i(t) = current through the capacitor at time t

v(t₀) = voltage at initial time.

From the question:

C = 2μF = 2 x 10⁻⁶F

i(t) = 3[tex]e^{-6000t}[/tex] mA

t₀ = 0

v(t₀ = 0) = 0

Substitute these values into equation (i) as follows;

[tex]v = \frac{1}{2*10^{-6}} \int\limits^{t}_{0} {3e^{-6000t}} \, dt + v(0)[/tex]    

[tex]v = \frac{1}{2*10^{-6}} \int\limits^{t}_{0} {3e^{-6000t}} \, dt + 0[/tex]

[tex]v = \frac{1}{2*10^{-6}} \int\limits^{t}_{0} {3e^{-6000t}} \, dt[/tex]            

[tex]v = \frac{3}{2*10^{-6}} \int\limits^{t}_{0} {e^{-6000t}} \, dt[/tex]             [Solve the integral]

[tex]v = \frac{3}{2*10^{-6}*(-6000)} {e^{-6000t}}|_0^t[/tex]

[tex]v = \frac{-3000}{12} {e^{-6000t}}|_0^t[/tex]

[tex]v = -250 {e^{-6000t}}|_0^t[/tex]

[tex]v = -250 {e^{-6000t}} - [-250 {e^{-6000(0)}][/tex]

[tex]v = -250 {e^{-6000t}} - [-250][/tex]

[tex]v = -250 {e^{-6000t}} + 250[/tex]

[tex]v = 250 -250 {e^{-6000t}}[/tex]

[tex]v = 250[1 - {e^{-6000t}}][/tex]

Therefore, the voltage across the capacitor is [tex]v = 250[1 - {e^{-6000t}}][/tex] mV

Answer:

A,C and E

Explanation:

It should be understood that a function generator can be explained as a piece of electronic test equipment or software which is used in generating different types of electrical waveforms over a wide range of frequencies. It should be noted that some of the examples of waveforms produced by the function generator are the sine wave, square wave, triangular wave and sawtooth shapes.

Therefore, the reason why of picking the options as highlighted above.