Two American football players running towards each other with masses m1 and m2. Let m1 = 70 kg and m2 = 100 kg, respectively. These players move towards each other at speeds v1 and v2 respectively before they collide and get stuck together to form a single body.
According to the law of conservation of momentum, the momentum before the collision is equal to the momentum after the collision. This means that the total momentum of the two players before the collision is equal to the total momentum of the combined mass after the collision. Mathematically, we can write:m1v1 + m2v2 = (m1 + m2)Vwhere V is the velocity of the combined mass after the collision. Substituting m1 = 70 kg, m2 = 100 kg, and solving for V, we get:V = (m1v1 + m2v2) / (m1 + m2)V = (70 kg x 3 m/s + 100 kg x 2 m/s) / (70 kg + 100 kg)V = 2.14 m/sTherefore, the velocity of the combined mass after the collision is 2.14 m/s.For such more question on velocity
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If the density of the object varies linearly with x-that is, ρ=αx , where α is a positive constant-calculate the x-coordinate of the rod's center of mass. Express your answer in terms of some or all of the variables ρ , M , L , and A .
The x-coordinate of the center of mass of the object if the density of the object varies linearly with x-that is, ρ=αx is X = 2L/3
What is center of mass?The center of mass of an object is the position at which the mass of the object appears to be concentrated.
If the density of an object varies linearly with x-that is, ρ=αx , where α is a positive constant. Calculate the x-coordinate of the rod's center of mass. Express your answer in terms of some or all of the variables ρ , M , L , and A .
We proceed as follows
The x-coordinate of the center of mass is given by
X = ∫xdM/∫dM where
x = coordinate of differential element dM,dM = ρdx where ρ = density of object = αx and dx = differential length elementSo, substituting these into the equation, we have
X = ∫xdM/∫dM
X = ∫xρdx/∫ρdx
X = ∫x(αx)dx/∫αxdx
X = ∫αx²dx/∫αxdx
X = α∫x²dx/α∫xdx
X = ∫x²dx/∫xdx
We integrate x from x = 0 to x = L. So, we have
X = ∫x²dx/∫xdx
X = x²⁺¹/(2 + 1)/x¹⁺¹/(1 + 1)
X = [x³/3]₀ˣ/[x²/2]₀ˣ
X = [L³/3 - 0³/3]/[L²/2 - 0²/3]
X = [L³/3 - 0³/3]/[L²/2 - 0²/3]
X = [L³/3 - 0]/[L²/2 - 0]
X = L³/3/L²/2
X = 2L/3
So,the x-coordinate is X = 2L/3
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What's Kinetic energy Give definition
Answer:
Kinetic energy is the energy of motion, observable as the movement of an object or subatomic particle. Every moving object and particle have kinetic energy. A person walking, a soaring baseball, a crumb falling from a table and a charged particle in an electric field are all examples of kinetic energy at work
An areosynchronous
satellite orbits
Mars (mass = 6.42 x 1023 kg) once
every Martian day, 88640 s. At what
radius does it orbit?
[?] x 10
Coefficient (green)
[?]
m
Exponent (yellow)
Enter
E
The satellite orbits Mars at a radius of approximately 2.043 x 10⁷ meters
How to solve for the time that the satellite orbits Mars= [(T²GM)/(4π²)]¹/³)
Substituting the given values:
r = [(88640²)(6.67430 x 10⁻¹¹)(6.42 x 10²³) / (4π²)]¹/³
Calculating this expression, we find:
r = 2.043 x 10⁷ meters
Therefore, the satellite orbits Mars at a radius of approximately 2.043 x 10⁷ meters
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During the earthquake, what we need to do to be safe,write steps.
(i) When you are in the classroom.
(ii) When you are out of danger
During an earthquake, it is important to take appropriate steps to ensure safety
Steps you can follow in two different scenarios(i) When you are in the classroom
Drop, Cover, and Hold On: Quickly drop to the ground, take cover under a sturdy desk or table, and hold on to it to protect yourself from falling objects and potential structural collapse.
Protect Your Head: If possible, use your arms to cover your head and neck to provide additional protection.
Stay Indoors: Remain inside the classroom until the shaking stops and it is safe to exit. Be prepared for aftershocks, which are smaller tremors that may occur after the main earthquake.
(ii) When you are out of danger:
Evacuate to Open Space: If you are no longer in immediate danger, move quickly to an open space away from buildings, trees, streetlights, and utility wires that may pose a risk of falling or collapsing.
Watch for Falling Debris: Be aware of your surroundings and watch out for any hazards such as falling debris, broken glass, or damaged infrastructure.
Stay Clear of Buildings: Avoid entering damaged buildings or structures as they may be unstable. Keep a safe distance until authorities confirm it is safe to enter.
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Can someone pls help?
if the positive charge on a neutral sphere is [tex]3* 10^7 C[/tex], the negative charge on the other sphere would be [tex]-3*0^7 C[/tex].
How do we calculate?We take the neutral sphere as Sphere A and the other sphere as Sphere B.
Since Sphere A is initially neutral, it has no net charge. As a result, even after the modifications, Sphere A's positive charge will still be [tex]3 * 10^7 C.[/tex]
The Sphere B changes:
The separation between the spheres doubles, doubling the separation between Spheres A and B as well.
The charge on Sphere B doubles: If Sphere A do not change, there should be no net charge on either sphere.
As a result, the positive charge on Sphere A should be identical in magnitude to the initial negative charge on Sphere B, but opposite in sign.
In conclusion, Sphere B would have a negative charge of[tex]-3 *10^7 C.[/tex]
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What's light (raduation) energy. Give simple definition
Answer:
an energy that travels in the form of electromagnetic waves.
A toy train is going around a circular track of radius 1.2 m. The train takes 9 seconds to complete one lap of the circular track.
Calculate the speed of the train
The circumference of a circle is given by 2πr, where r is the radius of the circle. Therefore, the circumference of the circular track is:
C = 2π(1.2 m) = 2.4π m
The train completes one lap of the track in 9 seconds, so its speed is given by:
speed = distance / time
where distance is the circumference of the track and time is 9 seconds. Substituting the values, we get:
speed = 2.4π m / 9 s ≈ 0.84 m/s
Therefore, the speed of the toy train is approximately 0.84 m/s.
