find the sum or difference of 4/5 - (-3 4/5)

Answers

Answer 1

Answer:

4 3/5

Step-by-step explanation:

4/5 - (-3 4/5)

Subtracting a negative is like adding

4/5 + 3 4/5

3 8/5

3 5/5 + 3/5

3+1+3/5

4 3/5


Related Questions

7 days 8 hours 20 minutes
- 4 days 10 hours 30 minutes
2 days 21 hours
50 minutes
3 days 2 hours
10 minutes
7 days 8 hours
20 minutes
J 11 days 8 hours
50 minutes
K none of these

Answers

Answer:

A

Step-by-step explanation:

         1                                          2                                       3  

days hours minutes       days   hours   minutes     days    hours  minutes  

  7        8         20             6       24+8       20              6        31        60+20

  4       10         30

 -

_______________

         4

days     hours    minutes

  6           31           80

  4            10          30

-

____________________

  2             21          50

___________________

What constant acceleration is required to increase the speed of a car from 30 miyh to 50 miyh in 5 seconds?

Answers

Answer:

The acceleration is 1.8 m/s^2.

Step-by-step explanation:

initial velocity, u = 30 mph = 13.4 m/s

Final velocity, v = 50 mph = 22.4 m/s

time, t = 5 s

Let the acceleration is a.

Use first equation of motion

v = u + at

22.4 = 13.4 + 5 a

a = 1.8 m/s^2

A telescope contains both a parabolic mirror and a hyperbolic mirror. They share focus ​, which is 46feet above the vertex of the parabola. The​ hyperbola's second focus is 6 ft above the​ parabola's vertex. The vertex of the hyperbolic mirror is 3 ft below . Find the equation of the hyperbola if the center is at the origin of a coordinate system and the foci are on the​ y-axis. Complete the equation.

Answers

the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.

The hyperbola focus F1 is 46 feet above the vertex of the parabola and the hyperbola focus F2 is 6 ft above the parabola's vertex. Then the distance F1F2 is 46-6=40 ft.

In terms of hyperbola, F1F2=2c, c=20.

The vertex of the hyperba is 2 ft below focus F1, then in terms of hyperbola c-a=2 and a=c-2=18 ft.

Use formula c^2=a^2+b^2c

2

=a

2

+b

2

to find b:

\begin{gathered} (20)^2=(18)^2+b^2,\\ b^2=400-324=76 \end{gathered}

(20)

2

=(18)

2

+b

2

,

b

2

=400−324=76

.

The branches of hyperbola go in y-direction, so the equation of hyperbola is

\dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1

b

2

y

2

a

2

x

2

=1 .

Substitute a and b:

\dfrac{y^2}{76}- \dfrac{x^2}{324}=1

76

y

2

324

x

2

=1 .

Can anyone help with this math equation please?

Answers

I might be wrong but the first one would be 60 and then the next blank would be 38 correct me if I’m wrong

what function represents exponential decay?

Answers

Answer:

There are two types of exponential functions: exponential growth and exponential decay. In the function f (x) = bx when b > 1, the function represents exponential growth. In the function f (x) = bx when 0 < b < 1, the function represents exponential decay.

Step-by-step explanation:

The method of tree-ring dating gave the following years A.D. for an archaeological excavation site. Assume that the population of x values has an approximately normal distribution.

1,2851,1871,2221,1941,2681,3161,2751,3171,275

Required:
a. Use a calculator with mean and standard deviation keys to find the sample mean year x and sample standard deviations.
b. Find a 90% confidence interval for the mean of all tree-ring dates from this archaeological site. (Round your answers to the nearest whole number.)

Answers

Answer:

a) The sample mean is 1260 and the standard deviation is 48.

b) The 90% confidence interval for the mean of all tree-ring dates from this archaeological site is (1230, 1290).

Step-by-step explanation:

Question a:

Mean is the sum of all values divided by the number of values. So

[tex]\overline{x} = \frac{1285 + 1187 + 1222 + 1194 + 1268 + 1316 + 1275 + 1317 + 1275}{9} = 1260[/tex]

Standard deviation is the square root of the sum of the differences squared between each value and the mean, divided by the one less than the sample size. So

[tex]s = \sqrt{\frac{(1285-1260)^2 + (1187-1260)^2 + (1222-1260)^2 + (1194-1260)^2 + (1268-1260)^2 + ...}{8}} = 48[/tex]

The sample mean is 1260 and the standard deviation is 48.

Question b:

We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So

df = 9 - 1 = 8

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 8 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.9}{2} = 0.95[/tex]. So we have T = 1.8595

The margin of error is:

[tex]M = T\frac{s}{\sqrt{n}} = 1.8595\frac{48}{\sqrt{9}} = 30[/tex]

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1260 - 30 = 1230

The upper end of the interval is the sample mean added to M. So it is 1260 + 30 = 1290

The 90% confidence interval for the mean of all tree-ring dates from this archaeological site is (1230, 1290).

A poll of 2,060 randomly selected adults showed that 89% of them own cell phones. The technology display below results from a test of the claim that 91% of adults own cell phones. Use the normal distribution as an approximation to the binomial distribution, and assume a 0.01 significance level to complete parts (a) through (e).
Test of p=0.91 vs p≠0.91
Sample X N Sample p 95% CI Z-Value p-Value
1 1833
2,060 0.889806 ( 0.872035 , 0.907577 ) ~ 3.20 0.001
a. Is the test two-tailed, left-tailed, or right-tailed?∙
Left-tailed test∙
Two-tailed test∙
Right tailed test
b. What is the test statistic?
The test statistic is _____ (Round to two decimal places as needed.)
c. What is the P-value?
The P-value is _____ (Round to three decimal places as needed.)
d. What is the null hypothesis and what do you conclude about it?
Identify the null hypothesis.
A. H0:p<0.91∙
B. H0:p≠0.91∙
C. H0:p>0.91∙
D. H0:p=0.91.

Answers

Answer:

Two tailed test

Test statistic = 3.20

Pvalue = 0.001

H1 : p ≠ 0.91

Step-by-step explanation:

Given :

Test of p=0.91 vs p≠0.91

The use if not equal to ≠ sign in the null means we have a tow tailed test, which means a difference exists in the proportion which could be lesser or greater than the stated population proportion.

The test statistic :

This is the Z value from the table given = 3.20

The Pvalue = 0.001

Since Pvalue < α ;Reject H0

how do i establish this identity?

Answers

RHS

[tex]\\ \sf\longmapsto \frac{2 \tan( \theta) }{ \sin(2 \theta) } \\ \\ \sf\longmapsto \frac{ \frac{2 \sin( \theta) }{2 \cos( \theta) } }{ \sin(2 \theta) } \\ \\ \sf\longmapsto \frac{1}{ \cos {}^{2} ( \theta) } \\ \\ \sf\longmapsto {sec}^{2} \theta[/tex]

A population is equally divided into three class of drivers. The number of accidents per individual driver is Poisson for all drivers. For a driver of Class I, the expected number of accidents is uniformly distributed over [0.2, 1.0]. For a driver of Class II, the expected number of accidents is uniformly distributed over [0.4, 2.0]. For a driver of Class III, the expected number of accidents is uniformly distributed over [0.6, 3.0]. For driver randomly selected from this population, determine the probability of zero accidents.

Answers

Answer:

Following are the solution to the given points:

Step-by-step explanation:

As a result, Poisson for each driver seems to be the number of accidents.

Let X be the random vector indicating accident frequency.

Let, [tex]\lambda=[/tex]Expected accident frequency

[tex]P(X=0) = e^{-\lambda}[/tex]

For class 1:

[tex]P(X=0) = \frac{1}{(1-0.2)} \int_{0.2}^{1} e^{-\lambda} d\lambda \\\\P(X=0) = \frac{1}{0.8} \times [-e^{-1}-(-e^{-0.2})] = 0.56356[/tex]

For class 2:

[tex]P(X=0) = \frac{1}{(2-0.4)} \int_{0.4}^{2} e^{-\lambda} d\lambda\\\\P(X=0) = \frac{1}{1.6} \times [-e^{-2}-(-e^{-0.4})] = 0.33437[/tex]

For class 3:

[tex]P(X=0) = \frac{1}{(3-0.6)} \int_{0.6}^{3} e^{-\lambda} d\lambda\\\\P(X=0) = \frac{1}{2.4} \times [-e^{-3}-(-e^{-0.6})] = 0.20793[/tex]

The population is equally divided into three classes of drivers.

Hence, the Probability

[tex]\to P(X=0) = \frac{1}{3} \times 0.56356+\frac{1}{3} \times 0.33437+\frac{1}{3} \times 0.20793=0.36862[/tex]

father of economics

Answers

I’m going to assume you meant who is the father of economics

Answer: Adam Smith

Identify the X intercept and the yIntercept of the line 4x-2y=-12

Answers

Answer:

X-intercept = -3 and y-intercept = 6

Step-by-step explanation:

We can start off by isolating the y term. To do that, we must add 2y to both sides to get

[tex]4x=2y-12[/tex]

Now, we must add 12 to both sides and the y term will be all alone on the right side:

[tex]4x+12=2y[/tex]

Now, to have only y on the right side, we must divide by 2 to get:

[tex]y=2x+6[/tex]

In slope-intercept form, b is the y-intercept, and 'b' in this equation is 6. We have our y-intercept.

To find our x-intercept, y must be equal to zero. We can plug in that value for y and solve for x:

[tex]0=2x+6[/tex]

We can start off by subtracting 6 from both sides to get:

[tex]2x=-6[/tex]

We can then divide both sides to get [tex]x=-3[/tex] when y is equal to 0. Thus, we have our x-intercept.

Answer:

y-intercept= -6

x-intercept= 3

Step-by-step explanation:

First, rearrange the equation to be in y=mx+b.

4x-2y=12

4x-12=2y

(1/2)(4x-12)=y

y=2x-6

From here, we know that the 'b' in an equation in form y=mx+b is the y-intercept, which is -6.

To find the x intercept make y=0 and solve.

You can also solve without rearranging the equation and simply making x=0 and solving to find the y-intercept. and making y=0 and solving to find the x-intercept.

The domain for all variables in the expressions below is the set of real numbers. Determine whether each statement is true or false.(i)∀x ∃y(x+y≥0)

Answers

The domain of a set is the possible input values the set can take.

It is true that the domain of ∀x ∃y(x+y≥0) is the set of real numbers

Given that: ∀x ∃y(x+y≥0)

Considering x+y ≥ 0, it means that the values of x + y are at least 0.

Make y the subject in x+y ≥ 0

So, we have:

[tex]\mathbf{y \le -x}[/tex]

There is no restriction as to the possible values of x.

This means that x can take any real number.

Hence, it is true that the domain of ∀x ∃y(x+y≥0) is the set of real numbers.

Read more about domain at:

https://brainly.com/question/15110684

a test for diabetes results in a positive test in 95% of the cases where the disease is present and a negative test in 07% of the cases where the disease is absent. if 10% of the population has diabetes, what is the probability that a randomly selected person has diabetes, given that his test is positive

Answers

Answer:

0.9378 = 93.78% probability that a randomly selected person has diabetes, given that his test is positive.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive test

Event B: Person has diabetes.

Probability of a positive test:

0.95 out of 0.1(person has diabetes).

0.007 out of 1 - 0.1 = 0.9(person does not has diabetes). So

[tex]P(A) = 0.95*0.1 + 0.007*0.9 = 0.1013[/tex]

Probability of a positive test and having diabetes:

0.95 out of 0.1. So

[tex]P(A \cap B) = 0.95*0.1 = 0.095[/tex]

What is the probability that a randomly selected person has diabetes, given that his test is positive?

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.095}{0.1013} = 0.9378[/tex]

0.9378 = 93.78% probability that a randomly selected person has diabetes, given that his test is positive.

Các mô hình h i quy sau đây có ph i mô hình tuy n tính hay không? N u là môồảếếhình h i quy phi tuy n, hãy đ i v mô hình h i quy tuy n tính?ồếổềồếa) iiiuXY++=21lnββb) iiiuXY++=lnln21ββc) iiiuXY++=1ln21ββd) eiiuXiY++=21ββe) eiiu

Answers

Yes! This work is all correct.

What type of model does the pattern show (linear or exponential)and explain please !!!!

Please and thanks

Answers

Answer:  Exponential

Explanation:

The first figure has 2 blocks.

The second figure has 4 blocks.

The third figure has 8 blocks

The pattern 2,4,8,... follows the rule "double the current value to get the next one". Because we have this going on, we have an exponential pattern here.

A linear pattern would be something like 2,4,6,8,10,... showing that we add on 2 each time, rather than multiply by 2 each time. So as you can guess, or already know, exponential patterns grow much quicker compared to linear ones.

What's the dependent variable shown in the table?


A)

The amount of water given to the plant

B)

The color of the flowers

C)

The number of flowers on the plant

D)

The speed at which the plant grows

Answers

Answer:

The number of flowers on the plant

Step-by-step explanation:

Answer:

C: Number of flowers on the plant

Step-by-step explanation:

i got it right on my test

plz help I will give Brianly
A pair of linear equations is shown below: y = −x + 1 y = 2x + 4 Which of the following statements best explains the steps to solve the pair of equations graphically? (4 points) Select one: a. On a graph, plot the line y = −x + 1, which has y-intercept = −1 and slope = 1, and y = 2x + 4, which has y-intercept = 2 and slope = 4, and write the coordinates of the point of intersection of the two lines as the solution. b. On a graph, plot the line y = −x + 1, which has y-intercept = 1 and slope = 1, and y = 2x + 4, which has y-intercept = 1 and slope = 4, and write the coordinates of the point of intersection of the two lines as the solution. c. On a graph, plot the line y = −x + 1, which has y-intercept = 1 and slope = −1, and y = 2x + 4, which has y-intercept = −2 and slope = 2, and write the coordinates of the point of intersection of the two lines as the solution. d. On a graph, plot the line y = −x + 1, which has y-intercept = 1 and slope = −1, and y = 2x + 4, which has y-intercept = 4 and slope = 2, and write the coordinates of the point of intersection of the two lines as the solution.

Answers

Answer:

the answer is 89

Step-by-step explanation:

this is a hard one to salve but basically if you know and lern hout to do it it is not that hard

You can work a total of no more than 35 hours each week at your two jobs. Housecleaning pays $7 per hour and your sales job pays $9 per hour. You need to earn at least $314 each week to pay your bills. Write a system of inequalities that shows the various numbers of hours you can work at each job.​

Answers

Answer: 7x + 9y >_ (more or equal) 314

X + Y <_ ( less or equal) 35

Step-by-step explanation:

Answer:

h+s≤35 and 7h + 9s >_314

Step-by-step explanation:

Your help is very much appreciated I will mark brainliest:)

Answers

Answer:

B. Yes. By SSS~

Step-by-step explanation:

From the diagram given, we have the corresponding sides of both triangles as follows:

RQ/KL = 24/20 = 6/5

QP/LM = 18/15 = 6/5

RP/KM = 12/10 = 6/5

From the above, we can see that the ratio of the corresponding side lengths of both triangles are equal. This means that all three sides of one triangle are proportional to all corresponding sides of the other triangle.

The SSS similarity theorem states that if all sides of one triangle are proportional to all corresponding sides of another, then both triangles are similar to each other.

Therefore, ∆KLM ~ ∆RQP by SSS similarity.

Which answer is it I’m confused ... ???

Answers

Answer is D hope it helps

Answer:

the answer is D

Step-by-step explanation:

v=πr²h

divide both side by πh

r²=v/πh

square both sides

r=√v/πh

Instructions: Given the following constraints, find the maximum and minimum values for
z
.

Constraints: 2−≤124+2≥0+2≤6 2x−y≤12 4x+2y≥0 x+2y≤6
Optimization Equation: =2+5
z
=
2
x
+
5
y
Maximum Value of
z
:
Minimum Value of
z
:

Answers

Answer:

z(max) = 16

z(min) = -24

Step-by-step explanation:

2x - y = 12  multiply by 2

4x - 2y = 24  (1)

4x + 2y = 0  add equations

8x = 24

x = 3

4(3) + 2y = 0

y = -6

so (3, -6) is a common point on these two lines

z = 2(3) + 5(-6) = -24

4x - 2y = 24   (1)

x + 2y = 6   add equations

      5x = 30

        x = 6

6 + 2y = 6

         y = 0

so (6, 0) is a common point on these two lines

z = 2(6) + 5(0) = 12

4x + 2y = 0    multiply by -1

-4x - 2y = 0

  x + 2y = 6  add equations

       -3x = 6

         x = -2

-2 + 2y = 6

         y = 4

so (-2, 4) is a common point on these two lines

z = 2(-2) + 5(4) = 16

Complete the remainder

Answers

the answer is -14, plug in -3 for x.

Answer:

-14 is the answer for the second term (?)

HELP PLEASE! I tried everything from adding to dividing, subtracting, multiplying but still no correct answer. Can someone help me out here please?

Answers

Answer:

46%

Step-by-step explanation:

Divde the smaller # by the bigger # to get the precentage

An average San Francisco customer uses what percent of electricity used by an average Houston customer?

In other words, San Francisco is what part of Houston?

---Just like, 7 is what part of 49? These are the same questions and would be solved in the same way

San Francisco / Houston

6753 / 14542

0.4644 = 46.44%

ANSWER: 46%

Hope this helps!

Does the function ƒ(x) = (1∕2) + 25 represent exponential growth, decay, or neither?
A) Exponential growth
B) Impossible to determine with the information given.
C) Neither
D) Exponential decay

Answers

Answer:

A) Exponential growth

Step-by-step explanation:

X+y=11
Graphing which function

Answers

Answer:

Step-by-step explanation:

slopee -1

y-intercept (0,11)

 x   y

0    11

1     10

If A is the center of the circle, then which statement explains how segment GH is related to segment FH? Circle A with inscribed triangle EFG; point D is on segment EF, point H is on segment GF, segments DA and HA are congruent, and angles EDA and GHA are right angles.

Answers

Answer:

I can say for sure that the answer is not segment GH ≅ segment FH because the tangents that create the segment FG share a common endpoint.  I believe the answer is segment GH ≅ segment FH because arc EF ≅ arc GF.

Step-by-step explanation:

Again, I'm not sure about the correct answer but I know for sure it isn't segment GH ≅ segment FH because the tangents that create the segment FG share a common endpoint.  

The segment GH and the segment FH are equal to each other because the line AH is coming from the center of the circle and is bisecting the line GF.

What is a circumscribed circle?

The circumcenter of a triangle can be constructed by drawing any two of the three perpendicular bisectors. For three non-collinear points, these two lines cannot be parallel, and the circumcenter is the point where they cross.

Any point on the bisector is equidistant from the two points that it bisects, from which it follows that this point, on both bisectors, is equidistant from all three triangle vertices

Hence the segment GH and the segment FH are equal to each other because the line AH is coming from the center of the circle and is bisecting the line GF.

To know more about a Circumscibed circle follow

https://brainly.com/question/2699432

Find the value of each determinant

Answers

Answer:

−4304

Step-by-step explanation:

1. The given determinant is :

[tex]\begin{vmatrix}7 &31 \\ 142& 14\end{vmatrix}[/tex]

We need to find its determinant . It can be solved as follows :

[tex]\begin{vmatrix}7 &31 \\ 142& 14\end{vmatrix}=7(14)-142(31)\\\\=-4304[/tex]

So, the value of determinant is equal to −4304.

Answer:

A= -4269

B= 1768

C= 647.36

Step-by-step explanation:

What is the product?

Answers

Answer:

Step-by-step explanation:

[tex]\begin{bmatrix}3 & 6 & 1\\ 2 & 4& 0\\ 0 & 6 & 2\end{bmatrix}\times\begin{bmatrix}2\\ 0\\ 1\end{bmatrix}[/tex]

Multiply the terms of the rows of the first matrix with the terms given in the column of the second matrix.

[tex]=\begin{bmatrix}(3\times 2+6\times 0+1\times 1)\\ (2\times 2+4\times 0+0\times1)\\ (0\times 2+6\times 0+2\times 1)\end{bmatrix}[/tex]

[tex]=\begin{bmatrix}7\\ 4\\ 2\end{bmatrix}[/tex]

[tex]\lim_{x\to \ 0} \frac{\sqrt{cos2x}-\sqrt[3]{cos3x} }{sinx^{2} }[/tex]

Answers

Answer:

[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{1}{2}[/tex]

General Formulas and Concepts:

Calculus

Limits

Limit Rule [Variable Direct Substitution]:                                                                     [tex]\displaystyle \lim_{x \to c} x = c[/tex]

L'Hopital's Rule

Differentiation

DerivativesDerivative Notation

Basic Power Rule:

f(x) = cxⁿ f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                    [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Step-by-step explanation:

We are given the limit:

[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)}[/tex]

When we directly plug in x = 0, we see that we would have an indeterminate form:

[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \frac{0}{0}[/tex]

This tells us we need to use L'Hoptial's Rule. Let's differentiate the limit:

[tex]\displaystyle \lim_{x \to 0} \frac{\sqrt{cos(2x)} - \sqrt[3]{cos(3x)}}{sin(x^2)} = \displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)}[/tex]

Plugging in x = 0 again, we would get:

[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \frac{0}{0}[/tex]

Since we reached another indeterminate form, let's apply L'Hoptial's Rule again:

[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-sin(2x)}{\sqrt{cos(2x)}} + \frac{sin(3x)}{[cos(3x)]^{\frac{2}{3}}}}{2xcos(x^2)} = \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)}[/tex]

Substitute in x = 0 once more:

[tex]\displaystyle \lim_{x \to 0} \frac{\frac{-[cos^2(2x) + 1]}{[cos(2x)]^{\frac{2}{3}}} + \frac{cos^2(3x) + 2}{[cos(3x)]^{\frac{5}{3}}}}{2cos(x^2) - 4x^2sin(x^2)} = \frac{1}{2}[/tex]

And we have our final answer.

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Limits

What is the smallest number that becomes 600 when rounded to the nearest hundred?
A. 545
B. 550
C. 555
D. 590

Answers

Answer:

B. 550

Step-by-step explanation:

550 is the smallest number that becomes 600 when rounded to the nearest hundred

Other Questions
Now that you have reviewed the causes and effects of both world wars, create an outline for an argumentative essay on whether the United States should have helped Germany recover from World War II. You will need to support your argument with at least three pieces of evidence to explain why. Use the historical facts that you have learned in this activity and in past lessons. You may also want to use the following resources:The Mackinac Center for Public Policy: "Germany and the Great Depression"PBS: "Berlin Blockade"Library of Congress: "The Marshall Plan"The Soviet Union and Europe After 1945***Rest of the assignment is below*** Can some please help please thank you Maximum range of a projectile is 1.6 m. Then the velocity of projection will be..... (g=10m/s) 8. The following is an image from the 1920s.The above image supports what 1920s movement?A. DarwinianB. FeministC. FundamentalistD. Modernist Let S be a sample of size 31 from a normally distributed population Omega . It is given that the average of the data in S is 120 and the standard deviation is 18. Construct a 90% confidence interval [a, b] for the population mean based on the data in the sample. . Write programming code in C++ for school-based grading system Of the travelers arriving at a small airport, 60% fly on major airlines, 20% fly on privately owned planes, and the remainder fly on commercially owned planes not belonging to a major airline. Of those traveling on major airlines, 50% are traveling for business reasons, whereas 70% of those arriving on private planes and 80% of those arriving on other commercially owned planes are traveling for business reasons. Suppose that we randomly select one person arriving at this airport. What is the probability that the persona. is traveling on business?b. is traveling for business on a privately owned plane?c. arrived on a privately owned plane, given that the person is traveling for business reasons?d. is traveling on business, given that the person is flying on a commercially owned plane? The French and Indian War Group of answer choices began a series of events that led up to the American Revolution led the Indians to realize it was pointless to fight against the British resulted in France giving up all but Louisiana in North America ended with Braddock's famous victory over the French at Fort Necessity Which of the following describes a predator? A a fish that is killed and eaten.B a bear that kills and eats fishC a worm that lives inside a bear D a bear that has a worms in its gut. write the equation in standard form. y=4/7x+3 At the New Years Eve Em hiu th no v ngha ca cu vn: "C cht hiu ra rng tuy c vn lm iu tng t vi cc em khc, nhng ha ra i vi Douglas bn tay c li mang ngha su xa, mt biu tng ca yu thng"? *Douglas l 1 a tr khuyt tt, khun mt khng c xinh xn, gia cnh li ngho kh* As discussed in class, the Fischer esterification reactants and products are at equilibrium. How was the equilibrium of the reaction that you performed shifted towards the products Will Mark Brainlest Helppp please Please help me with this! Name two important features of Mayan Civilization. Where do you usually find "YIELD RIGHT OF WAY" signs posted?At school crossing zones.Yield signs are usually placed where auxiliary roads lead into major roads.Near fire stations. PLEASE HELP SOON AND TRY TO EXPLAIN.Prove that if a, b, c, d are non zero real numbers, not all equal, and if a+1/b=b+1/c=c+1/d=d+1/a then |abcd|=1. Thx! Each time a patient comes to the clinic, the medical assistant must verify:A. whether the patient has had a change in address or phone number.B. which insurance plan the patient has.C. whether a co-pay is required.D. All of the above Light takes 1.2 sec to get from the moon to the Earth. Assume you are looking at the moon with noticeable earth shine. If the Sun burned out, you would eventually see the crescent of the moon disappear. The earth shine part of the moon would disappear Answer 2.4 s after the crescent disappeared.