Given 2 and 4 are vertical angles

prove 2 and 4.

Statements and reasons.

help

The number of employees taking the bus to an office is reduced by 1.1% from the last year. The relative change will be 1.1%.

Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Given that:-

28.6% of city employees ride the bus to work. Last year,29.7% of city employees rode the bus to work.

The relative change will be calculated as follows:-

Relative change =  Present year data - Last year's data

Relative change = 28.6 - 29.7

Relative change  = -1.1%

Therefore the number of employees taking the bus to an office is reduced by 1.1% from the last year. The relative change will be 1.1%.

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Answer:

Your answer would be A.

Step-by-step explanation:

okay so, with a best fit line, it needs to match up with your points. unless your points go up evenly. its not going to connect to all your points.

[tex] \normalsize\blue{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]

Answer:

Area of smaller square = [tex]\tt\underline{5cm}[/tex][tex]\tt{\times 5cm = }[/tex][tex]\tt\underline\green{25}[/tex] [tex]\tt{sq.cm}[/tex]

Area of bigger square = [tex]\tt{15cm \times}[/tex][tex]\tt\underline{ 15cm }[/tex][tex]\tt{=}[/tex] [tex]\tt\underline\green{225}[/tex] [tex]\tt{sq.cm}[/tex]

Total Area = [tex]\tt\underline\green{25sq.cm}[/tex] [tex]\tt{+}[/tex] [tex]\tt\underline\green{225sq.cm}[/tex] [tex]\tt{=}[/tex] [tex]\normalsize \underline{\boxed{\tt \red{250}}}[/tex] [tex]\tt\underline{sq.cm}[/tex]

[tex]\\[/tex]

Area of square A = [tex]\tt\underline{7m}[/tex][tex]\tt{\times}[/tex][tex]\tt\underline{7m}[/tex][tex]\tt{=}[/tex][tex]\tt\green{49}[/tex] [tex]\tt{sq.m}[/tex]

Area of square B = [tex]\tt{7m}[/tex][tex]\tt{\times}[/tex][tex]\tt{7m}[/tex][tex]\tt{=}[/tex][tex]\tt\underline\green{49}[/tex] [tex]\tt{sq.m}[/tex]

Area of square B = [tex]\tt{14m}[/tex][tex]\tt{\times}[/tex][tex]\tt\underline{14m}[/tex][tex]\tt{=}[/tex][tex]\tt\green{196}[/tex] [tex]\tt{sq.m}[/tex]

Total Area = [tex]\tt\underline\green{49m}[/tex] [tex]\tt{+}[/tex] [tex]\tt\underline\green{49m}[/tex] [tex]\tt{+}[/tex] [tex]\tt\underline\green{196}[/tex] [tex]\tt{=}[/tex][tex] \normalsize \underline{\boxed{\tt \red{294}}}[/tex][tex]\tt{sq.m}[/tex]

====================================

To find the area of square use this formula [tex]\large\tt{A = s \times s}[/tex]. Means side of the square multiply to the same side of the square

[tex] \normalsize\blue{\overline{\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad\quad \ \ \ }}[/tex]

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૮₍´˶• . • ⑅ ₎ა

Answer:

445

Step-by-step explanation:

I think it is 445 because each term is +1 and time is the number of terms you want to find.

So

(2+1) time 2 = 6

(6+1) time 3 = 7

(88+1)  time 5 = 445

The area of the sector, to 4 decimal places, is: 78.6794 cm².

Area of sector = ∅/360 × πr².

Given the following:

Area of sector = 46/360 × π(14²)

Area of sector ≈ 78.6794 cm²

The area of the sector is approximately 78.6794 cm².

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None of the options is true.

Three Different, Regular tessellation is formed 1. if we join regular polygons of side 3, called equilateral triangle,2. Regular polygon of side 4, called Square, and 3. Regular polygon of side,6 called hexagon,

to form a pattern.

A polygon is said to be regular if all interior angles and all sides are equal.

The regular polygon of side 3, when joined together can be named: 3.3.3.

The regular polygon of side 4, when joined together can be named 4.4.4.

The regular polygon of side 6, when joined together can be named 6.6.6.

So, a regular tessellation is formed, from a regular polygon having,3,4, and 6 Sides.

None of the sides of the polygon, which is given in the option, can be used to form a regular tessellation.

None of the options is true.

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Answer:

Blank 1 = SAS

Blank 2 = HL

Black 3 = ASA

Blank 4 = SSS

Answer:

The standard deviation is about 2.915

Step-by-step explanation:

Answer:

=  2.9154759474227

Step-by-step explanation:

The concentration could not be 59.

The concentration of a solution is a measure of the amount of solute that has been dissolved in a given amount of solvent or solution.

Given:

solutions one of 45% concentration

other of 55% concentration.

The concentration should lie between 45 % to 55 %.

This is because it is not possible to get a mixture concentration which is lower than the lower concentrated acid or higher than the higher concentration acid.

Hence, Mixture concentration must be between 45% and 55%.

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Answer:

height = 8m

radius = 6m

Surface area of the cylinder = 2 Pie r h

= 2* 3.14 * 6 * 8

= 6.28 * 48

= 301.4 sq meters

The value of TC(10) is 5300 Dollars

Given function is TC(Q) = 500Q +300 dollars

We need to calculate the value for TC (10)

As we know that the equation given is TC(Q) = 500Q + 300 dollars

Q is the number of TVs produced

Therefore, The value of Q is 10 for TC(10)

Substituting the value of Q

in the total cost of flatiron TVs given by function TC(Q) = 500Q + 300 dollars That Q= 100,

TC(10) = 500(10)+300 dollars

∴ TC (10) = 5000+300 dollars

∴ TC (10) = 5300 dollars

Hence the value of TC(10) is 5300 Dollars

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Answer: Length = 13 ft. , Width = 9 ft.

Step-by-step explanation:

Rectangle area = Length x width

Area = 117 ft.

Length = x + 4

Width = x

To solve

(x)(x + 4) = 117

x^2 + 4x = 117

x^2 + 4x - 117 = 0

(x - 9)(x + 13)

x = 9, -13

x = 9 (measurement cannot be negative)

Length

x + 4

9 + 4 = 13

Answer

T-axis of his graph should go from 0 to at least 720, and the h-axis of his graph should go from 0 to at least 40.

Explanation

We know form our problem that  is the total pay,  is the number of hours, and $18 is the rate per hour, so putting it all into an equation we get:

We also know that James works between 25 and 40 hours each week, so we can replace the number of hours in our equation to get how much he can make per week:

- For

- For

Now we know that he can make between $450 and $720 working between 25 and 40 hours per week. So, to best show this information the T-axis should go from 0 to at least 720; otherwise, we won't be able to show values between $450 and $720. Similarly, the h-axis should go form 0 to at least 40; otherwise, we wont be able to show values between 25 and 40 hours.

The amount of pounds of his weight is made up of fat is 28.7lbs

Given the following parameters

Total weight of body = 164lbs

Percentage fat = 17.5%

Determine the amount made up of fat

Fat amount = 17.5% of 164

Fat amount = 0.175 * 164

Fat amount = 28.7lbs

Hence the amount of pounds of his weight is made up of fat is 28.7lbs

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Answer:

1/4 + x = (-5)/4

x = -5/4 - 1/4

x = (-5)-1 /4

x = (-6)/4

Answer:

6.708.

Step-by-step explanation:

hope this helps

The parabola has roots at x=3 and x=-1, so its vertex is halfway between those points, at x=1, and so the y-coordinate of the vertex is -(1-3)(1+1)=4.

Another point that lies on the parabola is (-1, 0).

Answer:

C

Step-by-step explanation:

A and B are wrong because 37 is prime. 31 is prime and 33 is divisible by 11 and 3 so C

Answer:

My guess would be D

Step-by-step explanation:

The value of e:g is 2:7.

A ratio indicates how many times one number contains another.

Given:

e:f=3:7

f:g=2:3

Now take LCM of 2 and 7 i.e., 14.

e/f= 3/7= 3*2/7*2= 6/14

and, f/g= 2/3= 2*7/3*7= 14/21

So,

e/g= e/f *f /g

     = 6/14*14/21

     = 6/21

e:g = 2:7

Hence, the value of e:g is 2:7.

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The expression given can be written as [tex]\rm \dfrac{(16x^2 + 35 )}{28x^2}[/tex]

Expression is a mathematical statement consisting of variables , constants and mathematical operators .

It is given in the question to solve the expression

[tex]\rm \dfrac{4x}{7} + \dfrac{5}{4x^2}[/tex]

Taking LCM , LCM = 28x²

[tex]\rm \dfrac{(16x^2 + 35 )}{28x^2}[/tex]

Therefore the expression given can be written as [tex]\rm \dfrac{(16x^2 + 35 )}{28x^2}[/tex]

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I presume you meant [tex]y=-2\sqrt{x-3}+2[/tex].

The graph is shown in the attached image.

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:sin(\theta) = \cfrac{2}{3} [/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex]\qquad \tt \rightarrow \: \cos {}^{2} ( \theta) + \sin {}^{2} ( \theta) = 1[/tex]

[tex]\qquad \tt \rightarrow \: {\bigg( \cfrac{ \sqrt{5}}{3} \bigg) }^{2} + \sin {}^{2} ( \theta) = 1[/tex]

[tex]\qquad \tt \rightarrow \: \cfrac{5}{9} + \sin {}^{2} ( \theta) = 1[/tex]

[tex]\qquad \tt \rightarrow \: \sin {}^{2} ( \theta) = 1 - \cfrac{5}{9} [/tex]

[tex]\qquad \tt \rightarrow \: \sin {}^{2} ( \theta) = \cfrac{9 - 5}{9} [/tex]

[tex]\qquad \tt \rightarrow \: \sin {}^{2} ( \theta) = \cfrac{4}{9} [/tex]

[tex]\qquad \tt \rightarrow \: \sin {}^{} ( \theta) = \sqrt \cfrac{4}{9} [/tex]

[tex]\qquad \tt \rightarrow \: \sin {}^{} ( \theta) = \pm \cfrac{2}{3} [/tex]

Generally, only positive value is taken :

[tex]\qquad \tt \rightarrow \: \sin {}^{} ( \theta) = \cfrac{2}{3} [/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

Answer:

option 4 and option 3 are the answers respectively

Answer:

[tex] \sqrt{ {2}^{3} } \\ \sqrt{3} \\ .............[/tex]

Answer:

3 gallons

Step-by-step explanation:

For every value of green ( 'x') ....white is 3 times as much

  for 1 gallon green     ====> 3 gallons white

The one which is not part of the solution is option D. Using the commutative property.

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

Given;

5(2x-8)= 20

By Using the distributive property

10x-40-20 = 0

Combining like terms

10x-40+40-20 + 40 = 0

Dividing both sides by 10 to isolate the variable

10x = 60

x = 6

Thus, we can see that all the options are included except option D.

So, the one which is not part of the solution is option D. Using the commutative property.

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The count of patients needing a blood transfusion can be modelled as a continuous distribution.

A continuous distribution is a distribution that can take on an infinite number of possible values. A continuous distribution is not defined at specific values. The number of patients can be 1 or 10 or 50 or even 0.

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