How many moles of HCl are needed to react with 0.87 moles of Na?

A:0.87 mol HCl

B:0.82 mol HCl

C:1.0 mol HCl

D:0.96 mol Na

Answers

Answer 1

The moles of HCl are needed to react with 0.87 moles of Na are the A:0.87 mol HCl.

How do you calculate moles of HCl?

M = mol / L Calculate the molarity of an HCl answer which includes 18.23 g of HCl in 355. zero mL of answer. Calculate the wide variety of moles of HCl. Divide the wide variety of moles of HCl with the aid of using the overall quantity in liters.

We'll start with the aid of using writing the balanced equation for the reaction. This is illustrated below:Na+HCl->NaCl +H From the balanced equation above, 1 mole of Na reacted with 1 mole of HCI.Finally, we will decide the wide variety of moles of HCI required to react with 0.87 moles of Na. This may be acquired as illustrated below:From the balanced equation above,1 mole of Na reacted with 1 mole of HCI.

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Related Questions

Polyester and Nylon are examples of synthetic materials called polymers.
A. True
B. False

Answers

Answer:

true is correct

Polyester and Nylon are examples of synthetic materials called polymers. This statement is True.

Polymers are large molecules composed of repeating subunits called monomers, which are chemically bonded together. In the case of polyester, it is made from a polymer called polyethylene terephthalate (PET), while Nylon is made from polyamide monomers. These polymers are created through polymerization processes that combine smaller molecules to form long chains.

Synthetic polymers like polyester and nylon are widely used in various applications due to their desirable properties, such as strength, durability, and resistance to chemicals and moisture.

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What is the freezing point of an aqueous suger (C12H22O11) solution that boils at 110C°?

Answers

Sucrose doesn't show appreciable dissociation in water, so i≈1 in this case. by extension, −7.3°C is the approximate freezing point of this solution.

What is the freezing point?

The temperature at which a liquid solidifies.

Sucrose doesn't show appreciable dissociation in water, so i≈1 in this case. by extension, −7.3°C is the approximate freezing point of this solution.

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Al + 0₂ → Al₂O3 help

Answers

Answer:

4Al +3O₂ → 2Al₂O₃

Explanation:

To balance the chemical equation, start by identifying the number of atoms of each element on both sides of the equation.

Al +O₂ → Al₂O₃

Reactants (right-hand side of the arrow)

Al➭ 1

O➭ 2

Products (left-hand side of the arrow)

Al➭ 2

O➭ 3

Balancing the equation means that we need to ensure the number of atoms of each element is the same on both sides of the equation.

Let's balance the number of O atoms.

Al +3O₂ → 2Al₂O₃

Reactants

Al➭ 1

O➭ 3(2)= 6

Products

Al➭ 2(2)= 4

O➭ 2(3)= 6

Balancing the number of Al atoms:

4Al +3O₂ → 2Al₂O₃

Reactants

Al➭ 4

O➭ 6

Products

Al➭ 4

O➭ 6

The equation is now balanced.

Additional:

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Question 5 of 30
Which best describes a gamma ray that is given off during nuclear decay?
A. High-energy electromagnetic waves
B. A stream of small, positively charged particles
C. Low-energy electromagnetic waves
D. A stream of small, negatively charged particles

Answers

Gamma rays are high-energy electromagnetic waves given off during nuclear decay; option A.

What are electromagnetic waves?

Electromagnetic waves are waves which are produced as a result of the interaction of the magnetic and electric fields.

Types of electromagnetic waves include gamma rays, radio waves, ultraviolet waves.

Gamma rays are high-energy electromagnetic waves given off during nuclear decay

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? If a weaker solution of sodium bicarbonate was used in beaker b, would that solution require more or less hydrochloric to neutralize it and why?

Answers

Answer:

less HCL acid is required to neutralize a weaker solution of base (sodium bicarbonate).

Explanation:

Which compound is water soluble?
O Li₂S
O PbBr₂
O Au(OH)3
O KCI

Answers

Answer:

Li2S is soluble in water

PbBr2 is soluble in hot water

KCI is soluble in water

How many valence electrons will a Cl- ion have?

Answers

Answer:

8

Explanation:

im pretty sure it'll be 8 electrons

How many grams S03
are needed to make 400g
H₂So4 in 49%

Answers

160 g of SO3 are needed to make 400 g of 49% H2SO4.

How many grams of SO3 are required to prepare 400 g of 49% H2SO4?

The equation of the reaction for the formation of H2SO4 from SO3 is given below as follows:

[tex]SO_{3} + H_{2}O \rightarrow H_{2}SO_{4}[/tex]

1 mole of SO3 produces 1 mole of H2SO4

Molar mass of SO3 = 80 g/mol

Molar mass of H2SO4 = 98 g/mol

80 g of SO3 are required to produce 98 og 100%H2SO4

mass of SO3 required to produce 400 g of 100 %H2SO4 = 80/98 × 400 = 326.5 g of SO3

Mass of SO3 required to produce 49% of 400 g H2SO4 = 326.5 × 49% = 160 g

Therefore, 160 g of SO3 are needed to make 400 g of 49% H2SO4.

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Calculate the pH of a solution that is 0.113 M HCI.

Answers

Simplified concentration

[tex]\\ \rm\Rrightarrow 1.13\times 10^{-2}M[/tex]

Now

[tex]\\ \rm\Rrightarrow pH=-log[H^+][/tex]

[tex]\\ \rm\Rrightarrow pH=-log(1.13\times 10^{-2})[/tex]

[tex]\\ \rm\Rrightarrow pH=-log1.13-log10^{-2}[/tex]

[tex]\\ \rm\Rrightarrow pH=-0.05+2[/tex]

[tex]\\ \rm\Rrightarrow pH=1.95[/tex]

Highly acidic

What is the pH of 0.0025M H2SO4

Answers

Answer:

pH=2.3

Explanation:

One H2SO4 molecule produce two H+ ions.

So conc. of H+ = 2(0.0025)

=0.005

Now, pH=-log (conc. of H+)

=-log(0.005)

=2.3

Describe the subatomic structure of the nucleus, including the structure of each nucleon. Draw a picture. Describe the forces that hold the nucleus together and draw them on your diagram. Explain how beta emission works.

Answers

The nucleus of the atom is the heaviest part of the atom.

The nucleus consists of neutrons and protonsBoth neutrons and protons have masses, but only protons have chargesThe nucleus contains all the positive charges of an atomThe mass of an atom is the sum of the numbers of protons and neutrons in a nucleus

When the ratio of neutrons to protons is too high, the nucleus becomes unstable and Beta emission has to take place.

In beta emission, an extra neutron gives rise to a proton and an electronThe electron is ejected from the nucleus

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QUESTION TO
What would I have to change to have a lunar eclipse happen every month?

Answers

You would have to fix the tilt of the Moon's orbit and make the Moon orbit planet Earth within the same plane that the Earth orbits the Sun.

What is a lunar eclipse?

A lunar eclipse can be defined as a phenomenon which occurs when the planet Earth comes in between the Moon and the Sun, thereby causing the Earth to cover the Moon with its shadow.

In order to have a lunar eclipse occur every month, you would have to fix the tilt of the Moon's orbit and make the Moon orbit planet Earth within the same plane that the Earth orbits the Sun, so as to block any ray of sunlight from reaching the Moon.

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37) Which chemical equation is correctly balanced?
a) Al(OH)3(s) → Al₂O3(s) + 2 H₂O(g)
b) KI(aq) + Pb(NO3)2(aq) → KNO3(aq) + 4 Pbl₂(aq)
c) 2 Na3PO4(aq) + 3 CaCl₂(aq) →6 NaCl(aq) + Ca3(PO4)2(aq) to S
d) CsH12) +6 O₂(g)→ 5 CO₂(g) + 6 H₂O(g)
0 (0

Answers

Answer: c) [tex]2\text{Na}_{3}\text{PO}_{4}+3\text{CaCl}_{2} \longrightarrow 6\text{NaCl}+\text{Ca}_{3}\text{(PO}_{4})_{2}[/tex]

How many orbitals are contained in the third principal level (n = 3) of a given atom?

Answers

The third principal level(n=3) of a given atom has 9 orbitals.

what are orbitals?

orbitals are different energy sub-levels.orbitals are of 4 types.each orbital has a unique and different shape.four types of orbital are-s, p, d, f

The 3rd electron shell has 3 subshells - 3s, 3p, 3d

s subshell only has one orbital.p subshell has three orbitals.d subshell has five orbitals.

therefore, the total number of orbitals in the third electron shell is:

1+3+5=9 orbitals

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Which of the following best describes a neutralization reaction?

Answers

Answer:

A

The H+ from acid and OH- from base forms water, the other parts form the salt.

Of protons, neutrons, and electrons, the least massive particle is the electron.is it True or False

Answers

The least massive particle is the electron. Hence, the option true is correct.

What are subatomic particles?

Sub-atomic particles are tiny particles of matter that together constitute an atom. There are three subatomic particles, which are namely electrons, protons and neutrons.

Protons and neutrons have approximately the same mass, but they are both much more massive than electrons (approximately 2,000 times as massive as an electron).

Hence, the option true is correct.

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Balance the following chemical equation:
P4(s)+ O2(g) - P4 O10 (s)

Answers

Answer:

The balanced chemical equation is P₄ (s) + 5O₂ (g) → P₄O₁₀ (s)

Explanation:

In order to balance the chemical equation, you first need to see what's out of balance.

In this case our Oxygen is not balanced, so in order to make the two the same, we need to see what coefficient we need to add to the compounds to balance the problem.

So, adding a coefficient of 5 to  the O₂ will result in an equal number of oxygen on both sides.

Answer: 1P4(s) + 5O2(g) -> 1P4O10(s)

Explanation: On the right side, there are 4 phosphorus and 2 oxygen. In order to balance the equation with 4 phosphorus and 10 oxygen on the left side, a coefficient of 5 is added to the 2 oxygens on the right side.

Hope that helps!

Perform the following
mathematical operation, and
report the answer to the
appropriate number of
significant figures.
15.225 - 3.88 =

Answers

The answer is 11.345

Which of the following is the electron configuration of an atom in the ground state?
(a) 1s2 2s1
(b) 1s2 2s2 2p5 3s2
(c) 1s2 2s1 2p6
(d) 1s1 2s2

Answers

Answer:

(a) 1s2 2s1

Explanation:

Electron configurations of atoms are in their ground state when the electrons completely fill each orbital before starting to fill the next orbital.

Understanding the notation

It's important to know how to read and interpret the notation.

For example, the first part of option (a) says "1s2"

The "1" means the first level or shellThe "s" means in an s-orbitalThe "2" means there are 2 electrons in that orbitalOther things to know about electron orbitals

It important to know which orbitals are in each shell:

In level 1, there is only an s-orbitalIn level 2, there is an s-orbital and a p-orbitalin level 3, there is an s-orbital, a p-orbital, and a d-orbital (things get a little tricky when the d-orbitals get involved, but this problem is checking on the basic concept -- not the higher level trickery)

So, it's also important to know how many electrons can be in each orbital in order to know if they are full or not.  The electrons should fill up these orbitals for each level, in this order:

s-orbitals can hold 2p-orbitals can hold 6d-orbitals can hold 10 (but again, that's beyond the scope of this problem)

Examining how the electrons are filling the orbitals

For option (a):

the 1s orbital is filled with 2, andthe 2s orbital has a single electron in it with no other orbitals involved.

This is in it's ground state.

For option (b):

the 1s orbital is filled with 2, the 2s orbital is filled with 2,the 2p orbital has 5 (short of a full 6), andthe 3s orbital has a single electron in it.

Because the 3s orbital has an electron, but the lower 2p before it isn't full.  This is NOT in it's ground state.

For option (c):

the 1s orbital is filled with 2, the 2s orbital has 1 (short of a full 2), andthe 2p orbital is filled with 6

Although the 2p orbital is full, since the 2s orbital before it was not yet full, this is NOT in it's ground state.

For option (d):

the 1s orbital has 1 (short of a full 2), andthe 2s orbital is filled with 2

Again, despite that the final orbital (in this case, the 2s orbital), is full, since the 1s orbital before it was not yet full, this is NOT in it's ground state.

Which of the following stage is also known as the unstable stage?
a.Transient creep stage
b.Constant creep stage
c.Fracture stage
d.Steady stage creep stage

Answers

Transient stage is also called the unstable stage and in this stage, there is a gradual decrease in deformation rate to a definite constant value.

What is Transient stage ?

A transient state is when a process variable or variables changes, but before the system reaches a steady state.

Transient time is the time it takes for a circuit to change from one steady state to the next.

Therefore, Transient stage is also called the unstable stage and in this stage, there is a gradual decrease in deformation rate to a definite constant value.

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Determine the mass of SO₂ that contains 6.075 × 10^26 S atoms.​

Answers

Answer:

= 64584.7176 g

or

= 64.5847 kg

Explanation:

From our question, we have been asked to find the mass of SO₂ containing 6.075 × 10^26 S atoms.

We know that from Avogadro's constant,

1 mole of a substance contains 6.02 x 10²³ ions/atoms/units

Thus,

1 mole => 6.02 x 10²³ atoms

x moles=> 6.075 × 10² atoms

We cross multiply;

x moles = (6.075 × 10²⁶ x 1)/(6.02 x 10²³)

= 1009.1362 moles

1 mole of SO2 = 64 g

1009.1362 moles = ?

=>

[tex] \frac{1009.1362 \times 64}{1} [/tex]

= 64584.7176 g

= 64.5847 kg

A hot air balloon is filled with 1.89 x 10² liters of air at 21°C. If atmospheric pressure does not change,
how hot must the air become in order to increase the volume to 4.5 x 10² liters?

Answers

Answer:

7.0k x 10^2k

Explanation:

The answer is 7.0k x10.2k I think!!!

1. A balloon contains 100g of oxygen gas (O₂) when the volume is 110 dm³. Find the volume of the balloon when the mass of oxygen gas is decreased to 50g. [take O=16] 1. A balloon contains 100g of oxygen gas ( O₂ ) when the volume is 110 dm³ . Find the volume of the balloon when the mass of oxygen gas is decreased to 50g . [ take O = 16 ]​

Answers

The volume of the balloon when the mass of oxygen gas is decreased to 50g is 50L.

We will use the ideal gas equation-

PV=nRT

P=Pressure

V=volume

n=no. of moles

T=temperature

In this question temperature and pressure will remains constant then the above equation can be rewritten as-

[tex]V_{1} /n_{1} =V_{2} /n2[/tex]

where V1= initial volume of the balloon

            V2=  volume of the balloon when the mass of oxygen gas is decreased to 50g

now, substitute the values in the above equation-

V1=100dm3=100Ln1=100/32=3.12n2=50/32=1.56

       100/3.12=V2/1.56

V2=50 L

hence, the volume of the balloon when the mass of oxygen gas is decreased to 50g is 50L.

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What is the pH of a 8.4x10⁻6 M H+solution?
What is pH?

pH=[?]

Answers

The pH can be obtained directly from the concentration using the formula below pH = - log [H⁺]  Hence, pH of a 8.4x10⁻⁶ M H⁺ solution is 5.08.

What is pH ?

A figure expressing the acidity or alkalinity of a solution on a logarithmic scale on which 7 is neutral, lower values are more acid and higher values more alkaline.

Taking the negative logarithm of the concentration of hydronium ions that are in the solution:

pH = - log [H⁺]

     = - log [8.4x10⁻⁶ ]

     =  5.08

Hence, pH of a 8.4x10⁻⁶ M H⁺ solution is 5.08.

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Need answer asap!! Molecules in the solid state

A) transfer heat to neighboring molecules by convection

B) have no motion

C) have no internal energy

D) vibrate in fixed positions

Answers

Answer:

c, have no internal energy

what is the relationship of work with distance and the force?
The good answer will be marked as brainlist.....​

Answers

Answer:

Work is the use of force to move an object. It is directly related to both the force applied to the object and the distance the object moves. Work can be calculated with this equation: Work = Force x Distance.

:)

You are given the following information: mass = 48 g; volume=24 cm. What is the density of this substance?

Answers

Answer:

Density = 0.0035 g/cm³

Explanation:

The density equation looks like this:

Density (g/cm³) = mass (g) / volume (cm³)

You have been given both the mass and volume. However, the given volume is not in the correct units. To convert cm to cm³, you should simply raise the given volume to the power of 3.

24 cm  =  (24 cm)³  =  24³cm³  =  13,834 cm³

Now, you can plug you mass and volume into the equation and solve for density. The final answer should have 2 sig figs to reflect the given values.

Density = mass / volume

Density = 48 g / 13,824 cm³

Density = 0.00347 g/cm³

Density = 0.0035 g/cm³

6.67 x 10-3 g of arsenic (As) is found in a 0.600 L sample of water. If the density of this
sample is 1.00 g/mL, what is the concentration of arsenic in ppm?

Answers

ppm = mg/L = mg/kg

6.67 x 10⁻³ g = 6.67 mg

ppm = 6.67 mg : 0.6 L = 11.12

6. Give the balanced full reaction and calculate the E° for galvanic cells based on the
following reactions. Draw diagrams indicating; the anode, cathode, flow of electrons,
salt bridge
(a) Zn^2 (aq) + 2e- = Zn(s)
Pb²(aq) + 2e- → Pb(s)
(b) Cr2O7 + 14H + 6e- 2Cr³+ 7H₂O
H₂O2 + 2H+ + 2e- →2H₂O

Answers

Electrochemical cell is one in which energy is released by a chemical action.

What is an electrochemical cell?

An electrochemical cell is one in which energy is released by a chemical action.

Now we have the reaction;

Zn^2 (aq) + 2e- = Zn(s)

Pb²(aq) + 2e- → Pb(s)

and

Cr2O7 + 14H + 6e- 2Cr³+ 7H₂O

H₂O2 + 2H+ + 2e- →2H₂O

In the first case, the Ecell is obtained from;

(-0.13 V) - (-0.76 V)

= 0.63 V

In the second case;

1.78 V - 1.33 V

= 0.45 V

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Calculate how many grams of the product form when 16.7 g of calcium metal completely reacts. Assume that there is more than enough of the chlorine gas.

Ca(s) + Cl2(g) → CaCl2(s)

Answers

39.96 g product form when 16.7 g of calcium metal completely reacts.

What is the stoichiometric process?

Stoichiometry is a section of chemistry that involves using relationships between reactants and/or products in a chemical reaction to determine desired quantitative data.

Equation:

[tex]Ca(s) + Cl_2(g)[/tex] → [tex]CaCl_2(s)[/tex]

In this case, for the undergoing reaction, we can compute the grams of the formed calcium chloride by noticing the 1:1 molar ratio between calcium and it (stoichiometric coefficients) and using their molar mass of 40 g/mol and 111 g/mol by using the following stoichiometric process:

[tex]m_{ca_C_l_2}[/tex]= 16.7 g Ca x [tex]\frac{1 mol \;of \;Ca}{40g Ca}[/tex] x [tex]\frac{1 mol \;of \;CaCl_2}{1 mol \;Ca}[/tex] x [tex]\frac{111g of \;CaCl_2}{1 mol \;CaCl_2}[/tex]

[tex]m_{ca_C_l_2}[/tex] = 39.96 g

Hence, 39.96 g product form when 16.7 g of calcium metal completely reacts.

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