The mean of the remaining temperature will be 1.7°C
How to calculate the value?Since the mean of her six recorded temperatures was 2.1 °C, the total temperature will be:
= 6 × 2.1
= 12.6°
Since the temperature on one of the days was 4.1 °C, the mean of the remaining temperature will be:
= (12.6 - 4.1)/5
= 8.5 / 5
= 1.7
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2. Ms.Walker arrange her students into groups for the next school debate. When she groups them in 5s, 2 students are left out. When she groups them in 4s, 1 student is left out. When she groups them in 7s, 4 students are left out. What is the least number of students Ms.Walker has?
Answer:
8
Step-by-step explanation
we must find the total of the students to do that we look at when she grouped them in 7, 4 are left out so we multiple 4 miltiplied by 7 and we get 28, there are 4 left out so we add them. now we have a total of 32 students. 32 divided by 4 is 8
5/18 + 7/18
9/17+ 2 8/17
3 9/10 + 1 3/10
11/16 + 3/16
5 13/16 + 6 1/16
7/19 + 14/19
7/25 + 16/25
13/15 + 8/15
9/11 + 5/11
12 11/25
11 9/25
1.) 0.66666666666
2.) 3
3.) 5.2
4.) 0.875
5.) 11.875
6.) 1.10526315789
7.) 0.92
8.) 1.4
9.) 1.27272727273
10.) 12.44
11.) 11.36
Here ya go!
The problem is in the attached png. Thanks!
(Geometry)
The unknown angles when line BD bisect the angle ABC is as follows:\
m∠ABD = 28°m∠ABC = 84°How to find an angle when a line bisect an angle?An angle bisector divides and angle into 2 equal angles.
Therefore, line BD bisect angle ABC.
Hence,
let's find m∠ABD
if m∠ABD = 6x + 4
m∠DBC = 8x - 4
Therefore,
m∠ABD = m∠DBC
6x + 4 = 8x - 4
6x - 8x = -4 - 4
-2x = -8
x = -8 / -2
x = 4
Therefore,
m∠ABD = 6x + 4 = 6(4) + 4 = 24 + 4 = 28°
let's find m∠ABC
If m∠ABD = 5y - 3
m∠DBC = 3y + 15
Hence,
m∠ABD = m∠DBC
5y - 3 = 3y + 15
5y - 3y = 15 + 3
2y = 18
y = 18 / 2
y = 9
Therefore,
m∠ABC = m∠ABD + m∠DBC
m∠ABC = 5(9) - 3 + 3(9) + 15
m∠ABC = 45 - 3 + 27 + 15
m∠ABC = 84°
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URGENT!! ILL GIVE BRAINLIEST! AND 100 POINTS
[tex] \bf \implies \frac{ - 1}{2} [/tex]
Step-by-step explanation:[tex] \bf \longrightarrow({ - 2}^{3})( {3}^{0})({4}^{ - 2} )[/tex]
[tex] \bf \longrightarrow( - 8)(1)( \frac{1}{16}) [/tex]
[tex] \bf \longrightarrow( - 8)( \frac{1}{16})[/tex]
[tex] \bf \longrightarrow \frac{ \cancel{- 8}}{ \cancel{16}} \frac{ \cancel{ - 4}}{ \cancel{8}} \frac{ \cancel{ - 2}}{ \cancel{4}} \frac{ - 1}{2} [/tex]
[tex] \bf \longrightarrow \frac{ - 1}{2} [/tex]
2 3 4 5 6 7 DOD
9
Look at the graph of the linear function.
-5-4-3-2-1
A
8
5
4
3
2
4
3
4
5
V
C
1
D
5
X
8
10
The rate of change between point A and point B is 2. What is the rate of change between point C and
-2
1
C
Answer:
show a picture
Step-by-step explanation:
There are 66 markers
in the box. 20 markers
don't have tops. How
many more markers
don't have tops?
marketing
There are 20 markers with no tops and 46 markers with tops in the box.
What precisely are mathematical operations?A function in mathematics that converts zero or more input values (also known as "operands" or "arguments") to a well-defined output value is known as an operation.The complexity of the operation is determined by the number of operands.Binary operations (i.e., operations of arity 2), such as addition and multiplication, and unary operations (i.e., operations of arity 1), such as additive inverse and multiplicative inverse, are the most commonly studied operations.A constant is an operation with arity zero, also known as a nullary operation.An arity 3 operation, also known as a ternary operation, is the mixed product.So, there are 66 markers in the box.
20 markers don't have tops.Markers with tops:
66 - 20 = 46Therefore, there are 20 markers with no tops and 46 markers with tops in the box.
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The correct question is given below;
There are 66 markers in the box. 20 markersdon't have tops. How many more markers have tops?
I have no idea what to do someone please help im desperate
Answer/Step-by-step explanation:
1)
3 ?
|-------|-----------------------|
G H I
|<---------------------------->|
14
3 + ? = 14
-3 -3
? = 11
HI = 11
2)
9 ?
|---------|---------------------|
E F G
|<---------------------------->|
21
9 + ? = 21
-9 -9
? = 12
FG = 12
3) Find RS
Q----------------R-----S-----------------T
|<----------------------------------------->|
19
|<---------------------->|
10
|<----------------------->|
10
QS = 10
QR = 9
RT = 10
ST = 9
RS = 1
4) Find SV
7
S-----------------T-------------U--------V
|<---------------------->|
8
|<--------------------------------->|
12
SU = 12
TV = 8
TU = 7
UV = 1
ST = 5
SV = 13
5) Solve for x
2x + 29 4
M--------------------L---------K
|<---------------------------->|
x + 22
2x + 29 + 4 = x + 22
2x + 33 = x + 22
-x -x
x + 33 = 22
-33 -33
x = -11
6) Solve for x
2x + 14 x + 11
J-------------I-------------H
|<------------------------>|
10
2x + 14 + x + 11 = 10
3x + 25 = 10
-25 -25
3x = -15
÷3 ÷3
x = -5
I hope this helps!
Is the sequence geometric? If it is, what are a₁ and r ?
b. 1,5,9,13,17, . . . . . . . .
No, the given sequence is not geometric.
What is a geometric progression?
A geometric progression, sometimes referred to as a geometric sequence in mathematics, is a series of non-zero numbers where each term following the first is obtained by multiplying the preceding one by a constant, non-zero value known as the common ratio.
Given: 1, 5, 9, 13, ....
Here, we can see that: [tex]\frac{5}{1}\neq \frac{9}{5}\neq \frac{13}{9}[/tex] and so on.
Hence, it is not a geometric sequence, since it does not follow the definition of a geometric progression, that the ratio of each adjacent term to the previous term should be equal.
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Question is below in the image. Please explain. Thanks
Answer:
E
Step-by-step explanation:
[tex]\lim_{x \to 0} f(1-x^2)=\lim_{x \to 1} f(x)[/tex]
which does not exist.
I need this answered please
In a cumulative frequency distribution, the last class will always have a cumulative frequency equal to _____.
The last class will always have a cumulative frequency equal to the sum total of all observations in a cumulative frequency distribution.
The cumulative frequency can be used to find the exact number of observations that lie before or after a certain value in the data. The cumulative frequency is calculated from the frequency distribution table, which is constructed directly from the data.
The cumulative frequency is calculated by adding every data' s frequency from the frequency distribution table to the sum of its preceding values.
Thus, the last value will always be equal to the total of all observations, as all frequencies have already been added to the previous total.
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The repeating decimal 0.7333... is equal to the fraction k/45 what is the value of k
Answer:
K=45×0.7333
K=32.9985
2 questions. Q1. Write an absolute value equation that has -17 and 5 as the given values Q2. 11 and 48
∣∣−175∣∣=175 Write an absolute value equation that has -17 and 5
I need help with 1 and 2
PLEASEEEEE HELPPPPPP
Simplify the following expression completely :
Answer: x^29
Step-by-step explanation:
x^11 * x^18=
x^(11+18)=x^29
Answer:
= x²⁹
Step-by-step explanation:
x¹¹ · x¹⁸
= x¹¹ ⁺ ¹⁸
= x²⁹
Which function has the following domain and range?
Domain: {-12, - 7, 0, 4, 12}
Range: {0, 1, 2}
O {(-12, 12), (0, 2)}
O {(4, 1), (-7, 0), (12, 2), (0, 0), ( − 12, 1)}
O {(-12, 0), ( – 7, 1), (0, 2), ( – 4, 5), (3, -1)}
O {(0,4), (2, 12), (1, -7), (0, - 12), (1, 0)}
Answer:
im think the answer is the first?
Answer: B. {(4, 1), (-7, 0), (12, 2), (0, 0), ( − 12, 1)}
Step-by-step explanation:
I got it right on the test
Find the measure of the missing angles
Answer:
remember angles on a straight ine add up to 180
TRAVEL A car leaves Seattle traveling at a speed of 60 miles per hour. Two hours later, a second car leaves
Seattle traveling at a speed of 50 miles per hour. The cars' distances from Seattle at time t hours are shown in
the table.
CAR A B
Distance (miles) 60t 50(t-2)
After how much time t will the two cars be the same distance from Seattle?
O 5 hours
O 10 hours
O The cars will never be the same distance from Seattle.
O 12 hours
The correct option regarding when the two cars will have the same distance from Seattle is:
The cars will never be the same distance from Seattle.
When will the two cars be at the same distance from Seattle?The distances for each car are given according to the following function:
A(t) = 60t.B(t) = 50(t - 2).They will have the same distance when:
A(t) = B(t).
Hence:
A(t) = B(t)
60t = 50(t - 2)
60t = 50t - 100
10t = -100.
t = -10.
Time cannot assume negative values, hence the cars will never be the same distance from Seattle.
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12 hours
Step-by-step explanation:
For each equation, find the center and radius of the circle.
(x+6)²+y²=121
The equation of the circle (x + 6)^2 + y^2 = 121 has a radius of 11 and a center located at (-6 , 0).
The standard form of the equation of circle is given by
(x - h)^2 + (y - k)^2 = r^2
where (h , k) is the location of the center and r is the radius of the circle.
On the other hand, the general form of the equation of circle is given by
x^2 + y^2 + Dx + Ey + F = 0
where D = -2h, E = -2k, and F = h^2 + k^2 -r^2.
If the equation of the circle, (x + 6)^2 + y^2 = 121, is in standard form, then
h = -6
k = 0
r = 11
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How many groups of 1/9 are there In 2
Answer:
18
Step-by-step explanation:
A bag of mangoes has a total mass of 56kg. If the average mass of a mango is 13/5 kg, find the number of mangoes in the bag. (Ignore the mass of the bag).
Answer:
About 22 mangoes.
Step-by-step explanation:
If we need to find the number of mangoes in a bag, and we have the total mass of the bag, and the average mass of a mango...
Total mass / Average mass = Number of mangoes
56kg / 13/5 kg = n
We can divide the fraction by flipping it and multiplying...
[tex]\frac{56}{1} /\frac{13}{5} = \frac{56}{1} *\frac{5}{13} \\\\56*5 / 13 \\\\280 / 13 = 21.54[/tex]
Because there are probably only whole mangoes in the bag, 21.5 is rounded up to 22 mangoes.
If a precise answer is necessary than stick with 21.54
The approximate weights of two animals are 5.36 x 104 lbs. and 6.2 x 104 lbs. find the total weight of the two animals. write the final answer in scientific notation with the correct number of significant digits. 12 x 104 lbs. 5.9 x 104 lbs. 1.22 x 105 lbs. 1.2 x 105 lbs.
The total weight of the two animals is 5.9×10⁴ lbs.
In order to solve the question easily, firstly lets write the weight of each animal in standard form.
Weight of first animal = 5.36×10⁴
Weight of first animal = 53,600
Weight of first animal = 6.2×10⁴
Weight of first animal = 62,000
Now, the total weight of animals will be calculated by summing the two values.
Total weight = 53,600 + 62,000
Performing addition of total weight of animals
Total weight = 1,15,600 lbs
Writing the total weight in scientific notation -
Total weight = 1.15×10⁵ lbs
On rounding off, we get -
Total weight = 1.2×10⁵ lbs
Hence, the total weight of the two animals is 1.2×10⁵ lbs.
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Mark grew 9 flowers with 3 seed packets. With 5 seed packets, how many total flowers can Mark have in his garden? Assume the relationship is directly proportional.
Answer:
15
Step-by-step explanation:
9 seeds in 3 packets is a 3:1 ratio which means that there are 3 seeds per packet. With 5 packets you simply multiply 5 by 3
Mary has yards of ribbon. For an art project, she cuts of the total ribbon into pieces of equal length. If each piece is of a yard long, how many pieces of ribbon does Mary make?
Approximately 17 ribbons of ¾ yards can make from a 12 ½ yards of ribbon
Given,
The length of ribbon Mary had with her = 12 ( ½ ) yards
Length of single piece of ribbon = ¾ yard
We have to find the number of pieces of ribbon made by Mary:
Then,
Number of pieces of ribbon = (Total length of ribbon / Length of single piece of ribbon)
Number of pieces of ribbon = (12 ( ½ ) / ¾ ) = (25/2) / ¾ = (25 x 2) / 3 = 50/3 = 16.66 ≈ 17
Approximately 17 ribbons of ¾ yards can make from a 12 ½ yards of ribbon.
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The cost to rent a car is $19.50 plus $0.25 per mile. If you have $44
to rent a car, what is the greatest number of miles that you can
drive?
40 times 40 equals what
Answer:
1600
Step-by-step explanation:
1600
Answer:
1600
Step-by-step explanation:
How to place 7 2/11 on a number line
Tutorial D
Subtract. Write your answer as a fraction or
as a whole or mixed number.
6-1/4-2 1/1 =
Submit
The value of the expression 6 - 1/4 - 2(1/1) as a mixed number is 2( 3/4 ).
Fraction: A number that is stated as a quotient in mathematics, when the numerator and denominator are divided. Both are integers in a simple fraction. A fraction appears in the numerator or denominator of a complex fraction. A suitable fraction has a numerator that is less than its denominator.
Consider the expression,
6 - 1/4 - 2(1/1)
Let x = 6 - 1/4 - 2(1/1)
First solving the mixed fraction,
x = 6 - 1/4 - 2(1/1)
x = 6 - 1/4 - ( (2 ×1 + 1) / 1 )
x = 6 - 1/4 - ( 2 +1 / 1)
x = 6 - 1/4 - 3
x = 3 - 1/4
x = ( 12 - 1)/4
x = 11/ 4
x = 2( 3 /4 )
The value of 6 - 1/4 - 2(1/1) as a mixed fraction is 2( 3/4 ).
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Andrea is given AABC and told that a² + b² = c². She draws right triangle RTS with
legs measuring a and b and hypotenuse measuring x. Which best describes what
Andrea should do in order to prove th at ABC is a right triangle?
Andrea should show that c = 2 so ΔABC = ΔRTS and ∡C = ∡S hence ∡C may be a right angled triangle since it's the angle opposite to the hypotenuse c and so, ΔABC could be a trilateral.
According to the statement
We have to prove that the ABC is a right triangle.
So, For this purpose, we know that the
A right-angled triangle is a type of triangle that has one of its angles equal to 90 degrees.
From the given information:
Andrea should show that c = 2, so: ∡ABC = ∡RTS and ∡C = ∡S. Hence, ∡C could be a right angled triangle, hence ΔABC could be a trilateral.
And
In this question, we are told that the given sides of the Triangle are a, b and c. Now, Andrea is in a position to draw the 2 sides of the correct triangle with sides = a and b and therefore the third, hypotenuse capable 2. Since the length of the hypotenuse = 2, then we have;
2² = a² + b²
However, we are told that c² = a² + b²
Therefore, c = 2
Hence, Andrea should show that c = 2 so ΔABC = ΔRTS and ∡C = ∡S hence ∡C may be a right angled triangle since it's the angle opposite to the hypotenuse c and so, ΔABC could be a trilateral.
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