Mila is preheating her oven before using it to bake. The initial temperature of the oven is 75° and the temperature will increase at a rate of 10° per minute after being turned on. What is the temperature of the oven 15 minutes after being turned on? What is the temperature of the oven t minutes after being turned on?

Temp after 15 minutes:
Temp after t minutes
need answer quickly

Answer:

x = 20°

Step-by-step explanation:

x° + 2x°+ (x+10)° = 90°

4x° + 10° = 90°

4x° = (90 -10)°

x° = (80/4)°

x = 20°

Hope this helps

Answer:

x = 20

Step-by-step explanation:

Key points:

Diagram notation

In the diagram, there are three angles, each with an expression representing the measure of their angle (in degrees).  Angles are adjacent (next to each other with the same vertex) such that collectively they form one large angle.

The small square in the lower left corner means that the large angle is a right angle.  All right angles are 90°.

Note:  The expressions for each angle all have a degree marking, so each angle is measured in degrees.  The unknown value x, is a number without any units, the expression is simplified, and then the units "degrees" are applied.  So in the end, the answer for "x" will not have units; "x" will just be a number.

Angle Addition Postulate

The Angle Addition Postulate states that the sum of the measures of two adjacent angles is equal to the measure of the large angle formed by those adjacent angles.  

[tex](\text{measure of first angle})+(\text{measure of second angle})=(\text{measure of the combined angle})[/tex]

Solving the given problem

By applying the Angle Addition Postulate a couple times, the sum of the measures of all three angles in the diagram is equal to the measure of the large angle formed by those three angles.

[tex](\text{measure of first angle})+(\text{measure of second angle})+(\text{measure of third angle})=(\text{measure of the large right angle})[/tex]

or

[tex](x)+(2x)+(x+10)=(90)[/tex]

From here, to solve for x, we'll need to combine like terms, isolate x, and simplify.

Start with the Associative Property of Addition to combine like terms:

[tex](x+2x+x)+10=90\\4x+10=90[/tex]

To isolate x, subtract 10 from both sides and simplify...

[tex](4x+10)-10=(90)-10\\4x=80[/tex]

... then divide by 4 on both sides and simplify.

[tex]\dfrac {4x}{4}=\dfrac {80}{4}\\x=20[/tex]

So, x=20

Camila's data set has the greatest interquartile range and the value of IQR = 8 option third is correct.

It is defined as the difference between the maximum value in the data set to the minimum value in the data set.

We have:

The amount of money in tips earned by four restaurant servers waiting on 10 tables is represented by the following data sets:

Alyssa {3, 6, 2, 8, 12, 14, 5, 7, 7, 8}

Bryant {9, 2, 7, 50, 0, 5, 2, 8, 6, 8}

Camila {1, 9, 10, 3, 0, 12, 10, 9, 8, 2}

Devon {4, 2, 8, 15, 20, 7, 5, 0, 6, 2}

The IQR for Alyssa:

IQR = Q3 - Q1

IQR = 8 - 5 = 3

The IQR for Bryant:

IQR = Q3 - Q1

IQR = 8 - 2 = 6

The IQR for Camila:

IQR = Q3 - Q1

IQR = 10 - 2 = 8

The IQR for Devon:

IQR = Q3 - Q1

IQR = 8 - 2 = 6

Thus, Camila's data set has the greatest interquartile range and the value of IQR = 8 option third is correct.

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Answer:

Step-by-step explanation:

[tex]\bf 2(xy-7)[/tex]  [tex]\bf when[/tex]  [tex]\bf x=-1/y=3[/tex]

Substitute with x and y with 3:-

[tex]\bf 2\left(\left(-1\right)(3)-7\right)[/tex]

First, Multiply -1 and 3 = -3

[tex]\bf 2(-3-7)[/tex]

Subtract  7 from -3 = -10

[tex]\bf 2(-10)[/tex]

Multiply 2 and -10 = -20

[tex]\bf -20[/tex]

Step-by-step explanation:

the product of segments theorem :

products of segments of intersecting chords are equal.

the 2 chords helping us are

the "4 + 25" chord.

the "x + x" chord (that connects then outwards to the 20 segment).

so, based on that theorem

4 × 25 = x × x

100 = x²

x = sqrt(100) = 10

The equation is y = 250(0.89)^x and the decay rate is 11%.

The initial value will be:

= 250(0.89)^x

= 250(0.89^0)

= 250

The decay rate will be:

= 1 - 0.89

= 0.11

= 11%

In conclusion, the equation is y = 250(0.89)^x and the decay rate is 11%.

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The percentage increase is 22.72%

The given parameters are:

Initial = 440 coins

Final = 540 coins

The percentage increase is calculated as:

%Increase = (Final - Initial)/Initial * 100%

So, we have:

%Increase = (540 - 440)/440 * 100%

Evaluate the difference

%Increase = 100/440 * 100%

Evaluate the quotient

%Increase = 0.2272 * 100%

Evaluate the product

%Increase = 22.72%

Hence, the percentage increase is 22.72%

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The graphed that represents the new function with the same slope and y-intercept is: graph Y.

Slope = rise/run along a line.

Y-intercept is the y-value of the point on the y-axis that the line intercepts.

Slope of the function given = rise/run = 2/1 = 2

2 multiplied by 1/2 = 2/2 = 1.

Y-intercept of the given function is: 1

1 increased by 3 units is: 1 + 3 = 4

The slope of graph Y = rise/run = 2/2/ = 1

The y-intercept is also 4

Therefore, the answer is: Graph Y

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Answer:

60

Step-by-step explanation:

Total degree of triangle interior angles is 180

So x+2x+3x=180

6x=180

x=30

Measurement of angle C is 2x which is 60 degree

Answer:

4y⁷x²

Step-by-step explanation:

    Prime factorize each expression.

28y⁷x² = 2 * 2 * 7 * y⁷ * x²

8y⁸v⁴x⁶ = 2 * 2 * 2 * y⁸ * v⁴ * x⁶

GCF = 2 * 2 *y⁷*x²

        = 4y⁷x²

Answer:

Step-by-step explanation:

Comment

If two secants intersect outside a circle (as these two do) then the angle at which they meet is 1/2 the difference between the intersected arcs. Put much simpler <DCF = 1/2 (arc EG - arc DF)

Givens

Arc EG = 127

Arc DF = 49

Solution

<DCF = 1/2(127 - 49)

<DCF = 1/2(78)

<DCF = 39

The difference of the polynomials is [tex]1.3t^{3}-0.2t^{2}-6t-8[/tex] and the additive inverse of the polynomial being subtracted is [tex]-0.6t^{2} +8+18t[/tex].

The given polynomials are [tex](1.3t^{3}+0.4t^{2} -24t )[/tex] and [tex]0.6t^{2} +8-18t[/tex].

We need to find the additive inverse of the polynomial being subtracted.

In mathematics, the additive inverse of a number a is the number that, when added to a yields zero. This number is also known as the opposite, sign change, and negation.

Now, [tex](1.3t^{3}+0.4t^{2} -24t )-(0.6t^{2} +8-18t)[/tex]

[tex]=1.3t^{3}+0.4t^{2}-0.6t^{2}-24t+18t-8[/tex]

[tex]=1.3t^{3}-0.2t^{2}-6t-8[/tex]

The additive inverse of the polynomial being subtracted is [tex]-0.6t^{2} +8+18t[/tex].

Therefore, the difference of the polynomials is [tex]1.3t^{3}-0.2t^{2}-6t-8[/tex] and the additive inverse of the polynomial being subtracted is [tex]-0.6t^{2} +8+18t[/tex].

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Answer:

18

Step-by-step explanation:

We know that y is 1.5 times x, so when x = 12, y = (1.5)(12)=18

This directly proportional relationship between p and q is written as p∝q  where that middle sign is the sign of proportionality. The value of x is 8, when the value of y is 12.

Let there are two variables p and q

Then, p and q are said to be directly proportional to each other if

 p = kq

where k is some constant number called the constant of proportionality.

This directly proportional relationship between p and q is written as p∝q  where that middle sign is the sign of proportionality.

In a directly proportional relationship, increasing one variable will increase another.

Now let m and n be two variables.

Then m and n are said to be inversely proportional to each other if

[tex]m = \dfrac{c}{n} \\\\ \text{or} \\\\ n = \dfrac{c}{m}[/tex]

(both are equal)

where c is a constant number called the constant of proportionality.

This inversely proportional relationship is denoted by

[tex]m \propto \dfrac{1}{n} \\\\ \text{or} \\\\n \propto \dfrac{1}{m}[/tex]

As visible, increasing one variable will decrease the other variable if both are inversely proportional.

Given Variables y and x have a proportional relationship, therefore, we can write,

y ∝ x

y = k × x

21 = k × 14

21/14 = k

k = 1.5

Therefore, the equation for the relationship between x and y can be written as,

y = 1.5x

now, the value of x when the value of y is 12 is,

12 = 1.5 × x

x = 8

Hence, the value of x is 8, when the value of y is 12.

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[tex]a\cdot b=(7)(4)+(3)(-1)=25\\\\|a|=\sqrt{7^{2}+3^{2}}=\sqrt{58}\\\\|b|=\sqrt{4^{2}+(-1)^{2}}=\sqrt{17}\\\\\cos \theta=\frac{25}{\sqrt{58}\sqrt{17}}\\\\\theta=\cos^{-1} \left(\frac{25}{\sqrt{58}\sqrt{17}} \right) \approx 37.235^{\circ}[/tex]

The value of y is 11 if the measure of the angle (x + 6y) is 90 degree and x = 24 option first is correct.

Lines that intersect at a right angle are named perpendicular lines. Lines that are always the same distance apart from each other known as parallel lines.

We have a perpendicular line shown in the picture.

The measure of the angle (4x - 6) is equal to 90 degree.

4x - 6 = 90

4x = 96

x = 24

Similarly, the measure of the angle (x + 6y) is equal to 90 degree:

x + 6y = 90

Plug x = 24

24 + 6y = 90

y = 11

Thus, the value of y is 11 if the measure of the angle (x + 6y) is 90 degree and x = 24 option first is correct.

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0 planes contain points J, K, and N.

Given that, planes X and Y and points J, K, L, M and N.

We need to find exactly how many planes contain points J, K, and N.

From the figure, we can see Point J doesn't belong to the planes X and Y and Point K and N belong to the plane X.

Since, points J, K, and N together do not belongs to any single plane, the planes contain points J, K, and N is 0.

Therefore, 0 planes contain points J, K, and N.

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Answer:

2 planes.

Step-by-step explanation:

The third option is correct.

Answer:

  (b)  8.9 m

Step-by-step explanation:

The mirror ensures that angle 1 is congruent to angle 2, so the triangles in the diagram are similar. The ratios of height to mirror distance are proportional.

__

The height of the object is proportional to its distance from the mirror, so we have ...

  (tree height)/(tree-to-mirror) = (person height)/(person-to-mirror)

  (tree height)/(2.5 m) = (1.78 m)/(0.5 m)

Multiplying this proportion by 2.5 m, we find ...

  tree height = (2.5 m)(1.78/0.5) = 8.9 m

The height of the palm tree is 8.9 meters.

The volume of the copper wire is 226.080 cm³ and the mass of the wire is 2,012.112 g/cm³.

Given that, the length of copper wire=200 m=200000 mm and the diameter of the copper wire=1.2 mm.

We need to find the volume of the copper wire.

The formula to find the volume of a cylinder is πr²h.

Now, the volume of the copper wire=πr²h=[tex]\frac{22}{7} \times (0.6)^{2} \times 200000=2,26,080[/tex] mm³=226.080 cm³

If the density of copper is 8.9 g/cm³, find the mass of the wire.

We know that [tex]Density=\frac{Mass}{Volume} }[/tex].

⇒8.9 g/cm³=[tex]\frac{Mass}{226.080}[/tex]

⇒Mass=2,012.112 g/cm³

Therefore, the volume of the copper wire is 226.080 cm³ and the mass of the wire is 2,012.112 g/cm³.

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The equivalent expression of [tex](3m^{-4})^3 * (3m^3)[/tex] is [tex]729m^{-9}[/tex]

The expression is given as:

[tex](3m^{-4})^3 * (3m^3)[/tex]

Expand the brackets

[tex]27m^{-12} * 27m^3[/tex]

Apply the law of indices

[tex]729m^{-12+3}[/tex]

Evaluate the sum

[tex]729m^{-9}[/tex]

Hence, the equivalent expression of [tex](3m^{-4})^3 * (3m^3)[/tex] is [tex]729m^{-9}[/tex]

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Answer:

Jane is 11 1/4 years old.

Step-by-step explanation:

Subtract all of the numbers given.

[tex]13\frac{5}{6} -1\frac{1}{3} -1\frac{1}{4}[/tex].

To subtract this, we need to find a common denominator.

A common denominator in this situation is 12. To do this multiply the 5 and the 6 of 5/6 by 2. Multiply the 1 and the 3 of 1/3 by 4. And multiply the 1 and the 4 1/4 by 3.

The new expression will look like this:

[tex]13\frac{10}{12} -1\frac{4}{12} -1\frac{3}{12}[/tex].

Now we can subtract.

[tex]13\frac{10}{12} -1\frac{4}{12} -1\frac{3}{12}=11\frac{3}{12}[/tex]

Reduce the answer.

[tex]11\frac{3}{12}=11\frac{1}{4}[/tex]

In decimal form 11.25

Hope this helps!

If not, I am sorry.

Answer:

D. 531[tex]in^{2}[/tex]

Step-by-step explanation:

I suppose these are rectangles and not triangles.

Area of Rectangle = Length x Breadth

Area of Large Rectangle = 21 x 18

= 378[tex]in^{2}[/tex]

Area of Small Rectangle = 17 x 9

= 153[tex]in^{2}[/tex]

Total Area = Area of Large Rectangle + Area of Small Rectangle

= 378 + 153

= 531[tex]in^{2}[/tex]

Is that expression a polynomial expression?

yes because they are terms linked into one expression.

What if she wrote - signs between the expressions instead?

it would still be considered a polynomial.

What if she wrote × signs between the expressions instead?

no because it would be one huge term

The steps are shown below: -5<x<1

A statement of an order relationship—greater than, greater than or equal to, less than, or less than or equal to—between two numbers or algebraic expressions.

Given:

|x +2 | <-3

If we take the module is positive,

x+2 -2 < -3-2

x < -5

If we take the module is negative,

-( x+2)  < -3

-x -2 < -3

-x -2 +2 < -3 +2

-x< -1

x>1

Combining the inequalities,

-5<x<1

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Answer: The answer is x = +/- [tex]\sqrt{y+1}[/tex].

Step-by-step explanation: You can solve this by simply rearranging the equation to make x by itself.

-[tex]x^{2}[/tex] = -y - 1

Then cancel out the -1 by dividing it through to obtain.

[tex]x^{2} =y+1[/tex]

The final step is to square root both sides to get rid of the exponent.

x = [tex]\sqrt{y+1}[/tex]

This should be the answer since square roots have a +/-.

[tex]\\ \rm\Rrightarrow log_5512[/tex]

[tex]\\ \rm\Rrightarrow log_52^9[/tex]

[tex]\\ \rm\Rrightarrow 9log_52[/tex]

[tex]\\ \rm\Rrightarrow 9\dfrac{log2}{log5}[/tex]

[tex]\\ \rm\Rrightarrow 3.876[/tex]

If your question is something different let me know by which I can change my answer

Answer:

3.876  (3 d.p.)

Step-by-step explanation:

Given:

Please note:  The question gives two values of log base 10 which should be used to help find the value of [tex]\log_5512[/tex]

Log Law:  Change of Base

[tex]\log_ba=\dfrac{\log_xa}{\log_xb}[/tex]

Change the given expression to log base 10:

[tex]\implies \log_5512=\dfrac{\log_{10}512}{\log_{10}5}[/tex]

Replace 512 with 2⁹, and 5 with 10/2:

[tex]\implies \dfrac{\log_{10}{2^9}}{\log_{10}\frac{10}{2}}[/tex]

[tex]\textsf{Apply the Power Log law}: \quad \log_ax^n=n\log_ax[/tex]

[tex]\implies \dfrac{9\log_{10}{2}}{\log_{10}\frac{10}{2}}[/tex]

[tex]\textsf{Apply the Log Quotient law}: \quad \log_a\frac{x}{y}=\log_ax - \log_ay[/tex]

[tex]\implies \dfrac{9\log_{10}{2}}{\log_{10}10-\log_{10}2}[/tex]

[tex]\textsf{Apply log law}: \quad \log_aa=1[/tex]

[tex]\implies \dfrac{9\log_{10}{2}}{1-\log_{10}2}[/tex]

Given:

Substitute this into the expression and simplify:

[tex]\implies \dfrac{9(0.3010)}{1-0.3010}[/tex]

[tex]\implies \dfrac{2.709}{0.699}[/tex]

[tex]\implies 3.876\:(\sf 3\: d.p.)[/tex]

To form equations from word problems, we can derive mathematical operations as well as variables from the given information.

In this case, each time Walker reads a certain number of pages, we subtract that from the total number of pages left to know how many pages is left to read.

Let r represent the pages left to read.

792 pages in total

Walker reads 15 pages a day during the week and 25 pages a day during the weekend.

5 weeks have passed

r = 792 - (5×15 + 2×25)×5

The coordinates of the point that is 4/5 of the way from T to S is (2,10)

The given parameters are:

T = (6,-2)

S = (1,13)

Location = 4/5

The location 4/5 means

Ratio, m : n = 4 : 1

The coordinate is then calculated as:

[tex](x,y) = \frac{1}{m +n} * (mx_2 + nx_1,my_2 + ny_1)[/tex]

This gives

[tex](x,y) = \frac{1}{4 +1} * (4 * 1 + 1 * 6 , 4 * 13 + 1 * -2)[/tex]

Evaluate

[tex](x,y) = \frac{1}{5} * (10 , 50)[/tex]

This gives

(x,y) =  (2,10)

Hence, the coordinates of the point that is 4/5 of the way from T to S is (2,10)

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