Need help please due in 1 hour and 30 mins

Answer:

8 feet

Step-by-step explanation:

12 x 2 =24

40 - 24 = 16

16 /2 = 8

Hope it helps :)

[tex]perimeter = 17 + 19 + 7 + 11 + 10 + 8 \\ [/tex]

[tex]perimeter = 72 \: \: cm[/tex]

Answer:

9.25 would be the value of x

Explanation:

Perimeter = 2(l + w)

2(13.25 + 9.25)

= 45

Step-by-step explanation:

when the scale says 1:500000, then that means 1 unit in the map corresponds to 500000 units in reality.

and so, 3.2 cm on the map are

3.2 × 500000 cm in reality.

3.2 × 500000 = 1,600,000 cm = 16,000 m = 16 km

Answer:

Step-by-step explanation:

y = mx + b

slope m is found as the change in y over the change in x

as y decreases 3 units for a 3 unit increase in x, the slope is -3/3 = -1

The y intercept b is where the plot crosses the y axis, 4 units above the x axis

y = -1x + 4

or

y = 4 - x

Answer:

Length = 24

Step-by-step explanation:

It says, " Both the length and  width are increased by the same amount..." this means that both 12m and 5m were increased. So 12 + 12 = 24 and 5 + 5 = 10.

lol Looks like someone has the same math assignment as me

Answer:

Geometric

Step-by-step explanation:

The ratios of the terms are constant

Step-by-step explanation:

1. 0.9862

2. 2.3

3. 7

4. 45.1

5. 18.735

Answer:

Divide both sides by 18. The new coefficients will be the reciprocals of the intercepts:

[tex]6x-3y=18 \rightarrow \frac6{18}x - \frac3{18}y = 1 \rightarrow \frac x3-\frac y6 =1[/tex] The two intercepts are then 3 and -6.

(I know, dividing by 3 both sides of the equations would have made the whole process way easier).

Alternatively, plug x = 0 to find the y intercept and y=0 to find the x intercept. Either way the graph will look something like the one I'm sketching on paint.

Answer:

The 95% confidence interval for the true mean score is [tex][73.539,76.461][/tex]

Step-by-step explanation:

Note that [tex]CI=\bar x\pm z\frac{s}{\sqrt{n}}[/tex] where [tex]\bar x[/tex] is the sample mean, [tex]z[/tex] is the upper critical value for the desired confidence level, [tex]s[/tex] is the sample standard deviation, and [tex]n[/tex] is the sample size.

Therefore, [tex]CI=75\pm 1.96\frac{5}{\sqrt{45}}\approx[73.539,76.461][/tex]

Proportional and linear functions are very similar. The only difference is the addition of the “​b​” constant to the linear function. A proportional relationship is just a linear relationship where ​B​ = 0, or where the line passes through the origin (0, 0).

Answer:

To evaluate an algebraic expression, you have to substitute a number for each variable and perform the arithmetic operations. For example 0.54+0.27 and 0.24 +0.57, If we know the value of our variables, we can replace the variables with their values and then evaluate the expression.

hope this helps.

Answer: That makes no sense. Maybe did your copy and paste corrupt? Or mistyped the question? Get back to me and I’ll help!!

Step-by-step explanation:

Bill was for $28.35.  A 20% tip would come to $5.67.  If we add this tip to the $28.35 bill, we get a total of $28.35 + $5.67 + 0.0625($28.35)

                                                 = $35.79 (total)

please give brainlist

Answer:

  D.

Step-by-step explanation:

There is nothing in the figure to indicate the triangles are isosceles. This eliminates answer choices A, B, C.

Answer choice D is a required step in the proof, but only gets part of the way. The triangle similarity means ...

  SQ/PQ = TQ/RQ

From here, you need to decompose each of the sides PQ and RQ into parts. Then you can get to the desired relationship.

  (PQ -PS)/PQ = (RQ -RT)/RQ . . . segment sum theorem

  1 - PS/PQ = 1 -RT/RQ . . . . . . . do the division

  -PS/PQ = -RT/RQ . . . . . . . . subtract 1 (subtraction property of equality)

  PS/PQ = RT/RQ . . . . . . . . multiply by -1 (multiplication property of equality)

Answer:

The Y-Int. is 60

Step-by-step explanation:

0 marks the x axis, which leads me to believe 60 is the Y-int so (0,60)

Answer:

more info??? bc that doesn't make sense i guess

Answer:

2(3x + 6)

Step-by-step explanation:

Answer:

12

Step-by-step explanation:

8x+4x = 12x

-3+3= 0

12x+0=180

x=180/12

x=15

Answer:

B

Step-by-step explanation:

To do this, we'll need to understand the skeleton form of transformations and what each variable represents in the equation. We have y = a(x-h) + k, where a represents vertical scaling, h the horizontal shift, and k the vertical shift.

So in this case, we need to reflect the graph over the y axis and horizontally scale it by a factor of 2 (i.e. stretch the graph horizontally). The answer is B.

Answer:

hello which grade question i

Check the picture below.

Answer:

There are two stationary points

Note that 1/2 = 0.5

==========================================================

How to get those answers:

Stationary points occur when the derivative is zero, when the graph is neither increasing nor decreasing (i.e. it's staying still at that snapshot in time).

Apply the derivative to get:

f(x) = 4x^3 - 3x + 3

f ' (x) = 12x^2 - 3

Then set it equal to zero and solve for x.

f ' (x) = 0

12x^2 - 3 = 0

12x^2 = 3

x^2 = 3/12

x^2 = 1/4

x = sqrt(1/4) or x = -sqrt(1/4)

x = 1/2 or x = -1/2

x = 0.5 or x = -0.5

----------------------

Let's do the first derivative test to help determine if we have local mins, local maxes, or neither.

Set up a sign chart as shown below. Note the three distinct regions A,B,C

The values -0.5 and 0.5 are not in any of the three regions. They are the boundaries.

The reason why I split things into regions like this is to test each region individually. We'll plug in a representative x value into the f ' (x) function.

To start off, we'll check region A. Let's try something like x = -2

f ' (x) = 12x^2 - 3

f ' (-2) = 12(-2)^2 - 3

f ' (-2) = 45

The actual result doesn't matter. All we care about is whether if its positive or negative. In this case, f ' (x) > 0 when we're in region A. This tells us f(x) is increasing on the interval [tex]-\infty < x < -0.5[/tex]

Let's check region B. I'll try x = 0.

f ' (x) = 12x^2 - 3

f ' (0) = 12(0) - 3

f ' (0) = -3

The result is negative, so f ' (x) < 0 when [tex]-0.5 < x < 0.5[/tex]. The f(x) curve is decreasing on this interval.

The change from increasing to decreasing as we pass through x = -0.5 indicates that we have a local max here.

Plug x = -0.5 into the original function to find its paired y coordinate.

f(x) = 4x^3 - 3x + 3

f(-0.5) = 4(-0.5)^3 - 3(-0.5) + 3

f(-0.5) = 4

The point (-0.5, 4) is a stationary point. More specifically, it's a local max.

Side note: This is the same as the point (-1/2, 4) when written in fraction form.

----------------------

Let's check region C

I'll try x = 2

f ' (x) = 12x^2 - 3

f ' (2) = 12(2)^2 - 3

f ' (2) = 45

The positive outcome tells us that any number from region C does the same, and f ' (x) > 0 when [tex]0.5 < x < \infty[/tex]. The function f(x) is increasing on this interval.

Region B decreases while C increases. The change from decreasing to increasing indicates we have a local min when x = 0.5

Plug this x value into the original equation

f(x) = 4x^3 - 3x + 3

f(0.5) = 4(0.5)^3 - 3(0.5) + 3

f(0.5) = 2

The local min is located at (0.5, 2) which is the other stationary point.

The graph and sign chart are shown below.

The local min is located at (0.5, 2) which is the other stationary point.

Stationary points occur when the derivative is zero, when the graph is neither increasing nor decreasing.

Apply the derivative to get:

f(x) = 4x^3 - 3x + 3

f ' (x) = 12x^2 - 3

Then set it equal to zero and solve for x.

f ' (x) = 0

12x^2 - 3 = 0

12x^2 = 3

x^2 = 3/12

x^2 = 1/4

x = 1/2 or x = -1/2

x = 0.5 or x = -0.5

The first derivative test to help determine if we have local mins, local maxes, or neither.

A = numbers to the left of -0.5

B = numbers between -0.5 and 0.5 excluding both endpoints

C = numbers to the right of 0.5

Thus, The values -0.5 and 0.5 are not in any of the three regions. They are the boundaries.

Let's try something like x = -2

f ' (x) = 12x^2 - 3

f ' (-2) = 12(-2)^2 - 3

f ' (-2) = 45

In this case, f ' (x) > 0 when we're in region A.

Let's check region B x = 0.

f ' (x) = 12x^2 - 3

f ' (0) = 12(0) - 3

f ' (0) = -3

The result is negative, so f ' (x) < 0 when f(x) curve is decreasing on this interval.

The change from increasing to decreasing as we pass through x = -0.5 indicates that we have a local max here.

Substitute x = -0.5 into the original function to find its paired y coordinate.

f(x) = 4x^3 - 3x + 3

f(-0.5) = 4(-0.5)^3 - 3(-0.5) + 3

f(-0.5) = 4

The point (-0.5, 4) is a stationary point, it's a local max.

Let's check region C x = 2

f ' (x) = 12x^2 - 3

f ' (2) = 12(2)^2 - 3

f ' (2) = 45

The positive outcome tells us that any number from region C does the same, and f ' (x) > 0 when The function f(x) is increasing on this interval.

Susbtitute this x value into the original equation

f(x) = 4x^3 - 3x + 3

f(0.5) = 4(0.5)^3 - 3(0.5) + 3

f(0.5) = 2

Hence, The local min is located at (0.5, 2) which is the other stationary point.

Learn more about equations here;

https://brainly.com/question/10413253

#SPJ2

Answer:

63.1°

Step-by-step explanation:

Complementary angles sum 90°

90 - 26.9 = 63.1°

Answer:

18/100 or 9/50

Step-by-step explanation:

First, put 0.18 over 100 because there are 2 digits in the decimal, so you convert it to 18/100. Then, simplify it, and because the GCF is 2, divide the numerator and denominator. The final fraction ins 9/50.

Answer: Give me the table and ill answer..

Step-by-step explanation:

Answer:

(0,-15)

Step-by-step explanation:

i think.. trust someone else!! I'm not 100% sure...

Answer:

y = 2x-7

Step-by-step explanation:

I'm not really sure this is the slope-intercept form, as I've never called it like that before, but if it is, there you go.

Answer:

[tex]\huge\boxed{\sf y = 2x - 7}[/tex]

Step-by-step explanation:

Given equation is:

2x - y = 7

Add y to both sides

2x = 7 + y

Invert the equation

7 + y = 2x

Subtract 7 to both sides

y = 2x - 7

This is the required equation in slope-intercept form y = mx + b where m is slope and b is y-intercept.

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!