One year percent change is 14 percent.
What is percentage?A portion of a whole expressed in hundredths the number of students present was high. B: The outcome of dividing a number by a percentage is that the percentage equals the rate divided by the base. A portion of victories or profits (2a).
Given that,
Berkshire Hathaway closed at 185,690 per share on February 26.
One share's closing price from one year ago was 215,970.
So,the percentage of one year is 215970 × 185690/185690 × 100
So, the percent of one year is 14 percent.
Therefore, One year percent change is 14 percent.
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How to place 7 2/11 on a number line
Andrea is given AABC and told that a² + b² = c². She draws right triangle RTS with
legs measuring a and b and hypotenuse measuring x. Which best describes what
Andrea should do in order to prove th at ABC is a right triangle?
Andrea should show that c = 2 so ΔABC = ΔRTS and ∡C = ∡S hence ∡C may be a right angled triangle since it's the angle opposite to the hypotenuse c and so, ΔABC could be a trilateral.
According to the statement
We have to prove that the ABC is a right triangle.
So, For this purpose, we know that the
A right-angled triangle is a type of triangle that has one of its angles equal to 90 degrees.
From the given information:
Andrea should show that c = 2, so: ∡ABC = ∡RTS and ∡C = ∡S. Hence, ∡C could be a right angled triangle, hence ΔABC could be a trilateral.
And
In this question, we are told that the given sides of the Triangle are a, b and c. Now, Andrea is in a position to draw the 2 sides of the correct triangle with sides = a and b and therefore the third, hypotenuse capable 2. Since the length of the hypotenuse = 2, then we have;
2² = a² + b²
However, we are told that c² = a² + b²
Therefore, c = 2
Hence, Andrea should show that c = 2 so ΔABC = ΔRTS and ∡C = ∡S hence ∡C may be a right angled triangle since it's the angle opposite to the hypotenuse c and so, ΔABC could be a trilateral.
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For each equation, find the center and radius of the circle.
(x+6)²+y²=121
The equation of the circle (x + 6)^2 + y^2 = 121 has a radius of 11 and a center located at (-6 , 0).
The standard form of the equation of circle is given by
(x - h)^2 + (y - k)^2 = r^2
where (h , k) is the location of the center and r is the radius of the circle.
On the other hand, the general form of the equation of circle is given by
x^2 + y^2 + Dx + Ey + F = 0
where D = -2h, E = -2k, and F = h^2 + k^2 -r^2.
If the equation of the circle, (x + 6)^2 + y^2 = 121, is in standard form, then
h = -6
k = 0
r = 11
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I need this answered please
A container holds 15,000 milliliters (mL) of water. How many liters is this?
1,000 mL = 1 L
Answer:
Step-by-step explanation:
15L
15000 divided by 1000
Answer:
15 liters
Step-by-step explanation:
1000=1
15000=x..... (cross multiply)
15000=1000x...... (divide both sides by 1000)
=15
TRAVEL A car leaves Seattle traveling at a speed of 60 miles per hour. Two hours later, a second car leaves
Seattle traveling at a speed of 50 miles per hour. The cars' distances from Seattle at time t hours are shown in
the table.
CAR A B
Distance (miles) 60t 50(t-2)
After how much time t will the two cars be the same distance from Seattle?
O 5 hours
O 10 hours
O The cars will never be the same distance from Seattle.
O 12 hours
The correct option regarding when the two cars will have the same distance from Seattle is:
The cars will never be the same distance from Seattle.
When will the two cars be at the same distance from Seattle?The distances for each car are given according to the following function:
A(t) = 60t.B(t) = 50(t - 2).They will have the same distance when:
A(t) = B(t).
Hence:
A(t) = B(t)
60t = 50(t - 2)
60t = 50t - 100
10t = -100.
t = -10.
Time cannot assume negative values, hence the cars will never be the same distance from Seattle.
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12 hours
Step-by-step explanation:
Write the specified type of proof. two-column proof
Given: ®C
Prove: ΔKML ΔJMH
Answer:
hi
Step-by-step explanation:
Use the graph to determine the solution of the
inequality |x+1| + 2 > 5.
O (-∞,-4) (2,00)
(-4, 2)
O (0,3)
O
(-∞,0) (3,0)
DONE✔
(-∞,-4) U (2, ∞)
====================================================
Work Shown:
|x+1| + 2 > 5
|x+1| > 5 - 2
|x+1| > 3
x+1 > 3 or x+1 < -3
x > 3-1 or x < -3-1
x > 2 or x < -4
x < -4 or x > 2
The portion x < -4 translates to the interval notation of (-∞,-4)
It might be helpful to think of x < -4 as -∞ < x < -4
The x > 2 is the same as 2 < x and the same as 2 < x < ∞. This turns into the interval notation of (2, ∞)
Therefore, we end up with the solution set of (-∞,-4) U (2, ∞)
The U symbol is the union operator to glue together the two intervals.
PLEASEEEEE HELPPPPPP
URGENT!! ILL GIVE BRAINLIEST! AND 100 POINTS
[tex] \bf \implies \frac{ - 1}{2} [/tex]
Step-by-step explanation:[tex] \bf \longrightarrow({ - 2}^{3})( {3}^{0})({4}^{ - 2} )[/tex]
[tex] \bf \longrightarrow( - 8)(1)( \frac{1}{16}) [/tex]
[tex] \bf \longrightarrow( - 8)( \frac{1}{16})[/tex]
[tex] \bf \longrightarrow \frac{ \cancel{- 8}}{ \cancel{16}} \frac{ \cancel{ - 4}}{ \cancel{8}} \frac{ \cancel{ - 2}}{ \cancel{4}} \frac{ - 1}{2} [/tex]
[tex] \bf \longrightarrow \frac{ - 1}{2} [/tex]
With flu season coming up, josh decides to make get-well-soon kits. he has 12 cans of chicken soup and 18 boxes of tissue, which he wants to use to make identical kits with no materials left over. what is the greatest number of get-well-soon kits josh can make?
Using greatest common factor (GCF), Josh can make 6 identical get-well-soon kits.
The greatest common factor (GCF) of a set of numbers is defined as the largest common positive integer that divides each number into equal parts with zero remainder.
If Josh has to distribute 12 cans of chicken soup and 18 boxes of tissue to make identical get-well-soon kits with no material left over, solve the amount of kits he could make by solving the GCF of 12 and 18.
List down the factors of each number.
12 : 1, 2, 3, 4, 6, 12
18 : 1, 2, 3, 6, 9, 18
Common factors : 1, 2, 3, 6
Greatest Common Factor : 6
Hence, without any left over material, Josh can make 6 identical kits.
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Is the sequence geometric? If it is, what are a₁ and r ?
b. 1,5,9,13,17, . . . . . . . .
No, the given sequence is not geometric.
What is a geometric progression?
A geometric progression, sometimes referred to as a geometric sequence in mathematics, is a series of non-zero numbers where each term following the first is obtained by multiplying the preceding one by a constant, non-zero value known as the common ratio.
Given: 1, 5, 9, 13, ....
Here, we can see that: [tex]\frac{5}{1}\neq \frac{9}{5}\neq \frac{13}{9}[/tex] and so on.
Hence, it is not a geometric sequence, since it does not follow the definition of a geometric progression, that the ratio of each adjacent term to the previous term should be equal.
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Write a two-column proof for each case of Theorem 10.6 Case 2
Given: P lies inside
Prove: m< ABC = 1/2 m AC
The length of an inscribed angle is half the length of the central angle. The circumscribed angle's measure is 180 degrees less the central angle's measure.
What is the inscribed angle and the circumscribed angle?In geometry, an inscribed angle is the angle formed in the interior of a circle when two chords intersect on the circle. It is also the angle formed by two given points on a circle at a given point on the circle.
The length of an inscribed angle is half the length of the central angle. The circumscribed angle's measure is 180 degrees less the central angle's measure.
m ∠ABC = m ∠ABD + m ∠DBC (∠ Addition Postulate)
m ∠ABD = 1/2 m(arc AD)
m ∠DBC = 1/2 m(arc DC)
(The measure of an inscribed ∠ whose side is diameter is half the measure of the intercepted arc (Case 1)).
m ∠ABC = 1/2 m(arc AD) + 1/2 m(arc DC) (Substitution)
m ∠ABC = 1/2 [m(arc AD) + m(arc DC)] (Factor)
m(arc AD) + m(arc DC) = m(arc AC) (Arc Addition Postulate)
m ∠ABC = 1/2 m(arc AC) (Substitution)
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I have no idea what to do someone please help im desperate
Answer/Step-by-step explanation:
1)
3 ?
|-------|-----------------------|
G H I
|<---------------------------->|
14
3 + ? = 14
-3 -3
? = 11
HI = 11
2)
9 ?
|---------|---------------------|
E F G
|<---------------------------->|
21
9 + ? = 21
-9 -9
? = 12
FG = 12
3) Find RS
Q----------------R-----S-----------------T
|<----------------------------------------->|
19
|<---------------------->|
10
|<----------------------->|
10
QS = 10
QR = 9
RT = 10
ST = 9
RS = 1
4) Find SV
7
S-----------------T-------------U--------V
|<---------------------->|
8
|<--------------------------------->|
12
SU = 12
TV = 8
TU = 7
UV = 1
ST = 5
SV = 13
5) Solve for x
2x + 29 4
M--------------------L---------K
|<---------------------------->|
x + 22
2x + 29 + 4 = x + 22
2x + 33 = x + 22
-x -x
x + 33 = 22
-33 -33
x = -11
6) Solve for x
2x + 14 x + 11
J-------------I-------------H
|<------------------------>|
10
2x + 14 + x + 11 = 10
3x + 25 = 10
-25 -25
3x = -15
÷3 ÷3
x = -5
I hope this helps!
find a point which satisfies the linear equation X + Y is equal to 8 measure on it is 3 times it services
Answer:
Step-by-step explanation:
the horizontal line is x and 8=x so the point has to be where 8 is in the horizontal line. Then y is 3 so the point is gonna be in the vertical line then you connect those two-points and you have your line.
A bag of mangoes has a total mass of 56kg. If the average mass of a mango is 13/5 kg, find the number of mangoes in the bag. (Ignore the mass of the bag).
Answer:
About 22 mangoes.
Step-by-step explanation:
If we need to find the number of mangoes in a bag, and we have the total mass of the bag, and the average mass of a mango...
Total mass / Average mass = Number of mangoes
56kg / 13/5 kg = n
We can divide the fraction by flipping it and multiplying...
[tex]\frac{56}{1} /\frac{13}{5} = \frac{56}{1} *\frac{5}{13} \\\\56*5 / 13 \\\\280 / 13 = 21.54[/tex]
Because there are probably only whole mangoes in the bag, 21.5 is rounded up to 22 mangoes.
If a precise answer is necessary than stick with 21.54
Mary has yards of ribbon. For an art project, she cuts of the total ribbon into pieces of equal length. If each piece is of a yard long, how many pieces of ribbon does Mary make?
Approximately 17 ribbons of ¾ yards can make from a 12 ½ yards of ribbon
Given,
The length of ribbon Mary had with her = 12 ( ½ ) yards
Length of single piece of ribbon = ¾ yard
We have to find the number of pieces of ribbon made by Mary:
Then,
Number of pieces of ribbon = (Total length of ribbon / Length of single piece of ribbon)
Number of pieces of ribbon = (12 ( ½ ) / ¾ ) = (25/2) / ¾ = (25 x 2) / 3 = 50/3 = 16.66 ≈ 17
Approximately 17 ribbons of ¾ yards can make from a 12 ½ yards of ribbon.
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which net represents this rectangular prism
The repeating decimal 0.7333... is equal to the fraction k/45 what is the value of k
Answer:
K=45×0.7333
K=32.9985
Find the measure of the missing angles
Answer:
remember angles on a straight ine add up to 180
2 questions. Q1. Write an absolute value equation that has -17 and 5 as the given values Q2. 11 and 48
∣∣−175∣∣=175 Write an absolute value equation that has -17 and 5
Rebecca needs 10 yards of fabric to make a quilt. She has one piece of fabric that is
2 yards and another piece of fabric that is 41 yards. How many more yards of
fabric does Rebecca need to make the quilt?
F
4/ yd
G
31 Y
33 yd
J 62 yd
H
yd
33 YARDS is the total length of fabric that Rebecca needs.
What exactly do you mean by YARDS?
a small, frequently walled, paved, and open to the sky area next to a structure: court; b: a building's or collection of buildings' grounds. a house's immediate surroundings, which are often grassy grounds.
A man's belt or girdle, as it was known, was originally one yard long. King Henry I of England established the yard as the distance between his nose and the thumb of his extended arm in the 12th century. It is 36 inches right now.
We must determine the length of fabric Rebecca needs to finish her quilt based on the provided facts.
The total length of fabric required is 10 yards
One piece of fabric is long. 2yards
Another piece of fabric is long 41
Let be the missing length. x
2+41+x=10
x=-33
the length of fabric that Rebecca need is 33.
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Question is below in the image. Please explain. Thanks
Answer:
E
Step-by-step explanation:
[tex]\lim_{x \to 0} f(1-x^2)=\lim_{x \to 1} f(x)[/tex]
which does not exist.
There are 66 markers
in the box. 20 markers
don't have tops. How
many more markers
don't have tops?
marketing
There are 20 markers with no tops and 46 markers with tops in the box.
What precisely are mathematical operations?A function in mathematics that converts zero or more input values (also known as "operands" or "arguments") to a well-defined output value is known as an operation.The complexity of the operation is determined by the number of operands.Binary operations (i.e., operations of arity 2), such as addition and multiplication, and unary operations (i.e., operations of arity 1), such as additive inverse and multiplicative inverse, are the most commonly studied operations.A constant is an operation with arity zero, also known as a nullary operation.An arity 3 operation, also known as a ternary operation, is the mixed product.So, there are 66 markers in the box.
20 markers don't have tops.Markers with tops:
66 - 20 = 46Therefore, there are 20 markers with no tops and 46 markers with tops in the box.
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The correct question is given below;
There are 66 markers in the box. 20 markersdon't have tops. How many more markers have tops?
Tutorial D
Subtract. Write your answer as a fraction or
as a whole or mixed number.
6-1/4-2 1/1 =
Submit
The value of the expression 6 - 1/4 - 2(1/1) as a mixed number is 2( 3/4 ).
Fraction: A number that is stated as a quotient in mathematics, when the numerator and denominator are divided. Both are integers in a simple fraction. A fraction appears in the numerator or denominator of a complex fraction. A suitable fraction has a numerator that is less than its denominator.
Consider the expression,
6 - 1/4 - 2(1/1)
Let x = 6 - 1/4 - 2(1/1)
First solving the mixed fraction,
x = 6 - 1/4 - 2(1/1)
x = 6 - 1/4 - ( (2 ×1 + 1) / 1 )
x = 6 - 1/4 - ( 2 +1 / 1)
x = 6 - 1/4 - 3
x = 3 - 1/4
x = ( 12 - 1)/4
x = 11/ 4
x = 2( 3 /4 )
The value of 6 - 1/4 - 2(1/1) as a mixed fraction is 2( 3/4 ).
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12 : 21 : 30 simplified to its lowest terms is
Answer:
4 : 7 : 10
Step-by-step explanation:
as 12, 21, 30 are all divisible by 3
hope this helps
In a cumulative frequency distribution, the last class will always have a cumulative frequency equal to _____.
The last class will always have a cumulative frequency equal to the sum total of all observations in a cumulative frequency distribution.
The cumulative frequency can be used to find the exact number of observations that lie before or after a certain value in the data. The cumulative frequency is calculated from the frequency distribution table, which is constructed directly from the data.
The cumulative frequency is calculated by adding every data' s frequency from the frequency distribution table to the sum of its preceding values.
Thus, the last value will always be equal to the total of all observations, as all frequencies have already been added to the previous total.
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The problem is in the attached png. Thanks!
(Geometry)
The unknown angles when line BD bisect the angle ABC is as follows:\
m∠ABD = 28°m∠ABC = 84°How to find an angle when a line bisect an angle?An angle bisector divides and angle into 2 equal angles.
Therefore, line BD bisect angle ABC.
Hence,
let's find m∠ABD
if m∠ABD = 6x + 4
m∠DBC = 8x - 4
Therefore,
m∠ABD = m∠DBC
6x + 4 = 8x - 4
6x - 8x = -4 - 4
-2x = -8
x = -8 / -2
x = 4
Therefore,
m∠ABD = 6x + 4 = 6(4) + 4 = 24 + 4 = 28°
let's find m∠ABC
If m∠ABD = 5y - 3
m∠DBC = 3y + 15
Hence,
m∠ABD = m∠DBC
5y - 3 = 3y + 15
5y - 3y = 15 + 3
2y = 18
y = 18 / 2
y = 9
Therefore,
m∠ABC = m∠ABD + m∠DBC
m∠ABC = 5(9) - 3 + 3(9) + 15
m∠ABC = 45 - 3 + 27 + 15
m∠ABC = 84°
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Which function has the following domain and range?
Domain: {-12, - 7, 0, 4, 12}
Range: {0, 1, 2}
O {(-12, 12), (0, 2)}
O {(4, 1), (-7, 0), (12, 2), (0, 0), ( − 12, 1)}
O {(-12, 0), ( – 7, 1), (0, 2), ( – 4, 5), (3, -1)}
O {(0,4), (2, 12), (1, -7), (0, - 12), (1, 0)}
Answer:
im think the answer is the first?
Answer: B. {(4, 1), (-7, 0), (12, 2), (0, 0), ( − 12, 1)}
Step-by-step explanation:
I got it right on the test
Help Please
Every item in the Just a Dollar store is priced $1.00. When Jack opens the store, there is $125.00 in the cash register. When he counts the money in the cash register at the end of the day, the total is $935.00. If the sales tax rate is8 %, how many items were sold that day? ____ items we sold that day.
Based on the price of each item in the store and the total cash in the register at the end of the day, the number of items sold for the day was 750 items.
How many things were sold?The cash that the Just a Dollar store made for the day was:
= 935 - 125
= $810
The cost of the items sold, less the sales tax was:
= 810 / (1 + 8%)
= $750
If each item costs $1, then the number of items sold was:
= 750 / 1 per item
= 750 items
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