PLSS HELP ME THXS YOUUUUU!!!!!

Answer:

d = 0.0175n    ---> required equation

Billy can buy 285.714 gram nut with $5

Step-by-step explanation:

cost of 100g loose nut = $1.75

dividing LHS and RHS by 100

cost of 100/100g loose nut = $1.75

Thus, cost of 1 gm loose nut = $0.0175

let the weight of loose nut be n gm

Multiplying LHS and RHS by n

cost of x g loose nut = $0.0175*n =  $0.0175n

It is given that Billy spent d dollars to buy n gm nuts

thus,

d = 0.0175n    ---> required equation

________________________________________________

He spent $5 to buy nuts

substituting value of d as 5 we have

0.0175n = 5

=>n = 5/0.0175 = 285.714

Thus, Billy can buy 285.714 gram nut with $5.

Answer:

Step-by-step explanation:

If point D is located on the segment CE, then point C, D and E lies on the same line i.e they are collinear. Mathematically, CD+DE = CE

Given CD = 24 and DE = x and CE = 5x, on substituting this values in the equation we have;

[tex]24+x = 5x\\5x-x = 24\\4x = 24\\x = 24/4\\x = 6[/tex]

Since CE = 5x, CE = 5(6) = 30

The measure of segment CE is 30

Answer:

The Value of 9a+6b is 27. and the value of 4x+3y is 30.

Explanation

1)

3a+2b=9

multiplying both by side by 3

or, 3×( 3a+2b)=3×9

Hence, 9a+6b=27

2)

8x+6y=60

Dividing both by side by 2

or, (8x+6y)/2 = 60/2

Hence, 4x+3y=30

Answer:

First step=13x+7x=18+42

Step-by-step explanation:

13x-42=18-7x

First step

It is to collect like terms of the equation

13x+7x=18+42

20x=60

x=60/20

x=3

Answer:  [tex]\bold {1)\ \cos\ \theta}=\dfrac{\sqrt2}{2}\qquad 2)\ \tan \theta =\dfrac{1}{3}\qquad 3)\ \cos\ \theta=\dfrac{3\sqrt{13}}{13}\qquad 4)\ \cos\ \theta = \dfrac{2\sqrt5}{5}}[/tex]

Step-by-step explanation:

Pythagorean Theorem is: a² + b² = c², where "c" is the hypotenuse

[tex]1)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{2}{2\sqrt2}\quad =\large\boxed{\dfrac{\sqrt2}{2}}[/tex]

Note: 2² + 2² = hypotenuse²  →  hypotenuse = 2√2

[tex]2)\ \tan \theta=\dfrac{\text{side opposite to}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{2}{2\sqrt2}\quad =\dfrac{5}{15}\quad \rightarrow \large\boxed{\dfrac{1}{3}}[/tex]

Note: hypotenuse not needed for tan θ

[tex]3)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{3}{\sqrt{13}}\quad =\large\boxed{\dfrac{3\sqrt{13}}{13}}[/tex]

Note: 2² + 3² = hypotenuse²  →  hypotenuse = √13

[tex]4)\ \cos \theta=\dfrac{\text{side adjacent to}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{2\sqrt5}\quad =\large\boxed{\dfrac{2\sqrt5}{5}}[/tex]

Note: hypotenuse given in problem

Answer:

Each Cup has 3/8

Step-by-step explanation:

Divide

Answer:

x = 5, y = 9.

Step-by-step explanation:

8^x / 2^y = 64

3^4x * (1/9)^(y -1) = 81

From the first equation

2^3x / 2^y = 2^6

2^(3x-y) = 2^6

So 3x - y = 6  ..........(1)

From the second equation:

3^4x * 9^(-(y-1)) =  3^4

3^4x * 3^2(-(y-1)) = 3^4

3^(4x+ 2(1 - y)) = 3^4

So 4x + 2(1 - y) = 4

4x - 2y = 2

2x - y = 1   .............(2)

Subtract: (1) - (2):

x = 5.

and  2(5) - y = 1

so y = 9.

Solving the simultaneous equations we get x is 5  and y is 9 .

Simultaneous equations in algebra are those that concurrently involve two or more variables, such as x and y. Even though they are solved simultaneously, the equations are known as simultaneous equations. Just these equations alone have innumerable answers.

A system of equations, often known as an equation system, is a collection of finite equations for which common solutions are sought.

The two given equations can be simplified as:

[tex]8^x \div 2^y = 64\\\\or,\frac{2^{3x}}{2^y} =2^6\\\\or, 2^{3x-y}=2^6\\\\or, 3x-y = 6[/tex]

And :

[tex]3^{4x} \times (\frac{1}{9})^{y-1}=81\\\\or, 3^{4x} \times 3^{-2(y-1)}=3^4\\\\or, 3^{4x+2-2y}=3^4\\\\or, 4x-2y = 2\\\\or,2x-y=1[/tex]

Now we can solve the two simultaneous equations :

3x - y = 6 and 2x - y = 1

Subtracting the equations we get:

x = 5

and

y = 9

Solving the simultaneous equations we get the value of x as 5 and the value of y as 9 .

To learn more about simultaneous equations visit:

brainly.com/question/16763389

#SPJ1

Answer: 26

Step-by-step explanation:

Two Angles are Complementary when they add up to 90 degrees (a Right Angle). Then

∠A + ∠B = 90

∠A =90- ∠B

∠A  = 26

Answer:

The measure of [tex]\angle A[/tex]:

[tex]\angle A = 26\textdegree[/tex]

Step-by-step explanation:

Since both [tex]\angle A[/tex] and [tex]\angle B[/tex] are complementary (Which they both add up to 90°), and you want to find the measure of

Measure of [tex]\angle A[/tex]: unknown

Measure of [tex]\angle B[/tex]: 64°

Finding the measure of [tex]\angle A[/tex]:

[tex]90 - 64 = 26[/tex]

[tex]\angle A = 26\textdegree[/tex]

So, the measure for [tex]\angle A[/tex] is [tex]26\textdegree[/tex].

Answer:

see below

Step-by-step explanation:

g(x) = sqrt(x+3)

g(-6) = sqrt(-6+3) = sqrt(-3)  not a real number not in domain

g(-3) = sqrt(-3+3) = sqrt(0)  0  in domain

g(3) = sqrt(3+3) = sqrt(6)    in domain

Answer:

(a) 11.64%

(b) 8.15%

Step-by-step explanation:

Airborne airlines has an annual interest of payment= $102

Principal payment= $1,000

Time to maturity= 20 years

Current price of the bond= $880

The formular for calculating the yield on maturity is

[ Annual interest payment+Principal payment-(price of the bond/number of years to maturity)] / 0.6(price of the bond) + 0.4(principal payment)

(a) [102+(1000-880)/20)]/ [0.6(880) + 0.4(1000)]

= [102+ (120/20)]/ [528+400]

= [102+6]/ 928

= 108/928

= 11.637%

= 11.64% ( to 2 decimal places)

(b) Kd= Yield(1-T)

Kd= 11.64(1-0.30)

Kd= 11.64×0.7

Kd= 8.145%

Kd= 8.15%( to 2 decimal places)

Hence the yield to maturity on the new issue is 11.64% and the aftertax cost of debt is 8.15%

Answer:

18.2%

Step-by-step explanation:

The total number of trees in the wood = 420 + 160 + 300

                                                                = 880 trees

∴ The percentage of the oak trees = [tex]\frac{160}{880} * \frac{100}{1}[/tex]

                                                            = [tex]\frac{2 * 100}{11}[/tex]%

                                                            = [tex]\frac{200}{11}[/tex]%

                                                            = 18.181818...%

In 1 decimal place = 18.2%

Hope this helps!!

Answer:  -7/9

Step-by-step explanation:

10-3

1-10

The slope of the line is - 7/9

please see the attached picture for full solution

Hope it helps

Good luck on your assignment

Answer:

(x)1.4=Y

Step-by-step explanation:

40% increase of memeber so ita 140% of X

Answer:

ABE

DBC

CBE

Step-by-step explanation:

They all have B as the middle one, and B is the vertex

I think

Answer:

t12= -8

Step-by-step explanation:

t3

a+2d=10 (1)

t10

a+9d=-4. (2)

From (1)

a=10-2d. (3)

Sub into (3) into equ (2)

a+9d=-4

10-2d+9d=-4

10+7d=-4

7d=-4-10

7d=-14

Divide both sides by 7

d=-14/7

d= -2

10=a+2d

10=a+2(-2)

10=a-4

10+4=a

14=a

a=14

t12=a+11d

= 14+11(-2)

=14-22

= -8

t12= -8

Answer:

a=1 and b=13

do you need the working out?

Answer:

False, it could be.

Answer:

Number of people in a room

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Answer:

x = 20

Step-by-step explanation:

The angles are vertical angles and we know that vertical angles are equal

x+40 = 3x

Subtract x from each side

x+40-x = 3x-x

40 = 2x

Divide each side by 2

40/2 = 2x/2

20 =x

Answer:

The value of [tex]x[/tex]:

[tex]x = 20[/tex]

Step-by-step explanation:

-Since, one angle with the measure [tex]x + 40[/tex] and another angle with measure [tex]3x[/tex] are vertical angles, they equal each other. So, it will be written as:

[tex]x + 40 = 3x[/tex]

-After you have formed an equation, you switch the equation and you solve for the value of [tex]x[/tex]:

[tex]x + 40 = 3x[/tex]

[tex]x - x + 40 = 3x -x[/tex]

[tex]40 = 2x[/tex]

[tex]\frac{40}{2} = \frac{2x}{2}[/tex]

[tex]20 = x[/tex]

So, the final answer is [tex]20 = x[/tex] or [tex]x = 20[/tex] (They are both the same, you just switch them).

Answer:

I believe D

Step-by-step explanation:

If you multiplied -3 times 3 that would make -9

you can then add 9 + -9 and cross y off

Answer:

Step-by-step explanation:

The graph of a function and its inverse will always reflect through the line

y = x.

This is because a function has a specific set of coordiates, (x, y). That function's inverse has a set of coordinates that flips the x and y coordinates. For example, if a function has a set of coordinates (0, 1), (2, 3), (4, 5) then its inverse will have the coordinates (1, 0), (3, 2), (5, 4). If you plot the function's points and then the inverse's points in the same plane (meaning on the same graph) and connect the dots, you will see that the function and its inverse are reflections of each other through y = x. Below is an example of this. The dotted purplish line is the line y = x.

Answer:

Step-by-step explanation:

[tex]\sqrt{x} Distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\\\\\sqrt{(5-3)^{2}+(6-k)^{2}}=2\sqrt{2}\\\\\sqrt{(2)^{2}+[(6)^{2}-(2*6*k)+(k)^{2}]}=2\sqrt{2}\\\\\sqrt{4+[36-12k+k^{2}]}=2\sqrt{2}\\\\\sqrt{40-12k+k^{2}}=2\sqrt{2}\\[/tex]

Take square both side

[tex]40-12k+k^{2}=(2\sqrt{2})^{2}\\\\40-12k+k^{2}=4*2\\\\40-12k+k^{2}=8\\\\k^{2}-12k+40-8=0\\\\k^{2}-12k+32=0\\[/tex]

Factorize,

Sum = -12

Product = 32

Factors = -8 , -4

k² - 8k - 4k + (-8)*(-4) = 0

k(k - 8) - 4(k - 8) = 0

(k - 8)(k - 4) = 0

k = 8 or 4

The points are (3,k) and (5,6).

Given, distance = 2√2 units

Applying distance formula,

Distance = √(x2-x1)^2 + (y2-y1)^2

2√2 = √(x2-x1)^2 + (y2-y1)^2

Squaring both sides,

(2√2)^2 = [√(x2-x1)^2 + (y2-y1)^2]^2

8 = (x2-x1)^2 + (y2-y1)^2

8 = (5-3)^2 + (6-k)^2

8 = 2^2 + (6^2 - 2x6xk + k^2)

8 = 4 + 36 - 12k + k^2

8 = 40 - 12k + k^2

= k^2 - 12k + 32 = 0

On factorising,

=> k^2 - 4k - 8k + 32 = 0

=> k(k-4) -8(k-4) = 0

=> (k-4)(k-8) = 0

=> k-4 = 0 , k-8 = 0

=> k = 4 , k = 8

Answer:

Go to me. Click on your profile picture then click on your profile picture again to change it

Answer:

É necessário dividir por 3 para calcular a média simples das 3 notas.

Média = 7.

Step-by-step explanation:

O resultado deve ser dividido por três porque três notas com pesos iguais (projeto, prova e trabalho em grupo) foram somadas, portanto para calcular a média bimestral de Laura, a soma das três notas deve ser dividida por 3. A média de Laura é:

[tex]M=\frac{5,0+6,5+9,5}{3}\\ M=7[/tex]

Answer:

x-3

Step-by-step explanation:

f(x) = 3x-2

g(x) = 2x + 1

(f-g)(x) = 3x-2 - (2x+1)

Distribute the minus sign

          =3x-2-2x-1

Combine like terms

        = 3x-2x-2-1

        =x-3

Answer:

40 pens

Step-by-step explanation:

Let the total number of pens Ron had be x.

We need to find the fraction of the pen that were blue.

3/8 of them were black and 1/4 of them were red. This means that the fraction of the pens that were blue is:

1 - (3/8 + 1/4) = 1 - 5/8 = 3/8

There were 15 blue pens. This means that 3/8 of x is 15:

3/8 * x = 15

x = 15 * 8/3 = 40 pens

Ron had 40 pens.

The right answer is of:

option C

please see the attached picture....

Hope it helps.....

Good luck on your assignment.....

Answer:

0.3° = 0.3π/180

8° = 2π/45

Multiplying both

0.3π/180×2π/45

3/10π/180 × 2π/45

You will get

π/300 × π/45

= π²/13500 where a = π² b= 13500

Hope this helps.

Answer:

it is the last one

Step-by-step explanation:

Since a function is  based on a set of ordered pairs, where the first element in each pair is from the domain and the second is from the codomain. Also A function is a mapping from a set of inputs (the domain) to a set of possible outputs (the codomain).

The last one doesn't show the correct inputs and outputs

Answer:

d) [tex](\sqrt[8]{(10} )^{3 x}[/tex]

Step-by-step explanation:

Step(i):-

Given   [tex](\sqrt{10} )^{\frac{3 x}{4} }[/tex]

we will use formula

  [tex](a)^{m n} = (a^{m} )^{n}[/tex]

[tex](\sqrt{10} )^{\frac{3 x}{4} } =( (10)^{\frac{1}{2} } )^{\frac{3 x}{4} }[/tex]

              = [tex]( (10)^{\frac{1}{2} X\frac{3 x}{4} } )[/tex]

             = [tex]( (10)^{\frac{3 x}{8} } )[/tex]

            = [tex]((10)^{\frac{1}{8} } )^{3x}[/tex]

Step(ii):-

  we will  apply [tex](a)^{\frac{1}{n} } = \sqrt[n]{a}[/tex]

           = [tex](\sqrt[8]{(10} )^{3 x}[/tex]