Solve using a proportion.
A carpet store charges $150 to install 12 square yards of carpet. How much should it cost to
install 24 square yards?

A. $250
B. $300
C. $3,600
D. $192

Using linear function concepts, it is found that a set of ordered pairs with a slope of 3 is perpendicular to the set (12,3), (9,4).

A linear function is modeled by:

y = mx + b

In which:

If two lines are perpendicular, the multiplication of their slopes is of -1. The set (12,3), (9,4) has the slope given by:

m = (4 - 3)/(9 - 12) = -1/3.

Hence, for the perpendicular set:

[tex]-\frac{1}{3}m = -1[/tex]

m = 3.

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The correct expression is : [tex]\frac{4 cm }{1 year}[/tex] x [tex]\frac{10 mm}{1 cm}[/tex] x [tex]\frac{ 1 year }{365 days}[/tex]

What is the correct expression?

The first step is to convert year to days.

1 year = 365 days

The next step is to convert cm to mm.

1cm = 10 mm

4 x 10 = 40mm

Now, divide 40 mm by 365 days

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Answer:

i think the answer would be 53?

Step-by-step explanation:

i could be wrong

Step-by-step explanation:

the answer is d= -46/-7

or in simplest form

d= 6.57

hope this is correct...

Answer:

x^2-3x-1

Step-by-step explanation:

So we have the equation:

x^3-2x^2-4x-1/x+1

First factor the equation:

(x+1)(x^2-3x-1)/x+1

Then cancel the common factor: x+1 to solve the equation:

x^2-3x-1

The formula for number of buses per person is b = p/50

This is a way of using a variable to represent other variables in a function.

Given the expression

p = kb

If k = 50, then;

p = 50b

Make b the subject of the formula

p/50 = 50b/50
b = p/50

Hence the formula for number of buses per person is b = p/50
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There is no absolute value function when graphed, will be wider than the graph of the parent function f(x) = |x|

An absolute value function is a function such that,

[tex]|x|=-1 when x\geq 0 and |x|=1 when x\leq 0[/tex]

For the given example,

We have been given a parent function f(x) = |x|

We need to find the absolute value function, when graphed, will be wider than the graph of the parent function.

Consider the graph of all absolute value functions.

The graph of f(x) = |x| + 3 is represented blue color.

The graph of f(x) = |x − 6| is represented green color.

The graph of f(x) = |x| is represented red color.

The graph of f(x) = 9|x| is represented violet color.

From this graph, we can observe that,

f(x) = |x| + 3 is as wise as the parent absolute value function f(x) = |x| translated up by 3 units.

Similarly, the function f(x) = |x - 6| is as wise as the parent absolute value function f(x) = |x| translated right by 6 units.

This means, there is no absolute value function when graphed, which will be wider than the graph of the parent function f(x) = |x|

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Answer:

I believe the answer is C. F(x)= 1/3|x|

Step-by-step explanation:

i hope this helps.

Answer:

it would look like this

Step-by-step explanation:

The conversion to logarithm function will be that log3 27 = 3.

From the information given, we are to convert the exponential equation to logarithm function. This will be:

log 3 27

This will be log 3 3³

= 3 × log 3^3

= 3 × 1

= 3

Therefore, x = 3.

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The sum of the triangular numbers is [tex]\frac{n(n+1)(n+2)}{6}[/tex]

According to the question, the series of triangular numbers is given as in the form of the number of dots constituting the equilateral triangles i.e.
1, 3, 6, 10, 15 . . . . .n

triangular number are the sequence and series of the numbers and each number represents and constitute in visualization of  series of  equilateral triangle.

given series in the figure
1, 3, 6, 10, 15, . . . . . .  ., n
each number represents the number of dots containing in triangle
now the series can be given by
[tex]S = \frac{n(n+1)}{2}[/tex]  for n = 1, 2, 3, 4,. . . . .n
now , according to the question the sum of the series can be given as
⇒  ∑S
⇒   ∑[tex]\frac{n^2+n}{2}[/tex]
⇒  [tex]\frac{1}{2}[\sum n^2+\sum n]\\\frac{1}{2}[\frac{n(n+1)(2n+1)}{6}+\frac{n(n+1)}{2}] \\\frac{n(n+1)}{4}[\frac{(2n+1)}{3}+1] \\\frac{n(n+1)}{4}[\frac{(2n+1+3)}{3}] \\\frac{n(n+1)}{4}[\frac{(2n+4)}{3}] \\\frac{n(n+1)}{4}2[\frac{(n+2)}{3}]\\\frac{n(n+1)(n+2)}{6}[/tex]

Thus, the sum of the triangular number is given by [tex]\frac{n(n+1)(n+2)}{6}[/tex]

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Each step of the proof are:

The given parameter is:

Lines a and b are parallel.

This is represented as; a || b

Corresponding angles are equal.

∠1 and ∠5 are corresponding angles.

So, we have: ∠1 ≅ ∠5

Also, they are congruent.

So, we have ∠1 ≅ ∠5

Vertical angles are equal.

∠5 and ∠7 are vertical  angles.

So, we have: ∠5 ≅ ∠7

Also, they are congruent.

So, we have ∠5 ≅ ∠7

According to the transitive property;

If ∠1 ≅ ∠5 and ∠5 ≅ ∠7, then ∠1 ≅ ∠7

Hence, it has been proved that ∠1 ≅ ∠7

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Answer:

x=(y-3)/4

Step-by-step explanation:

y=4x+3

y-3=4x

x=(y-3)/4

The solution to the given compound inequality 2x - 3 < x + 2 ≤ 3x + 5 is 5 > x ≥ -3/2

2x - 3 < x + 2 ≤ 3x + 5

solve differently

2x - 3 < x + 2

2x - x < 2 + 3

x < 5

x + 2 ≤ 3x + 5

x - 3x ≤ 5 - 2

-2x ≤ 3

x ≥ 3/-2

x ≥ -3/2

Therefore, the solution of the compound inequality is 5 > x ≥ -3/2

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If x is the largest side :

If 4.1 is the greatest side :

Range of possible sizes for side 'x' :

The statement D is false that No irrational number is rational.

The set of real numbers includes integers, rational numbers, and irrational numbers.

This implies that all irrational numbers and integers are also real numbers.

Thus, statements A and B are correct.

Rational numbers are numbers that can be written as the division of two integers, which thus also include all integers.

The set of irrational numbers then contains all real numbers that are NOT rational numbers

Therefore, the set of irrational numbers does not include integers, which implies that statement D is false.

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Solution: 8p+44

Detailed explanation:

First we can "expand" by multiplying 6 times the parentheses and then 2 times the other set of parentheses.

[tex]--\mapsto\boldsymbol{6(p+6)+2(p+4)}\\\\---\mapsto\boldsymbol{6p+36+2p+8}[/tex]

To make life easier let's just put the p's next to each other.

[tex]--\mapsto\boldsymbol{6p+2p+36+8}[/tex]

Now let's add the p's

[tex]---\mapsto\boldsymbol{8p+44}[/tex]

Voila! There's our answer!

__________________

Hope I helped! Best wishes.

Reach far. Aim high. Dream big.

____________________

Answer:

[tex]\huge\boxed{\sf Option \ D}[/tex]

Step-by-step explanation:

[tex]\displaystyle =\frac{36}{25} \\\\[/tex]

36 and 25 have no common factor as:

and

So, No factor can be cancelled out and thus, the expression can not be simplified further. So, It will remain the same.

[tex]\rule[225]{225}{2}[/tex]

Answer:

d

Step-by-step explanation:

i did it

since we were given the key ( how it should be sort out or used )

then we get all the numbers out which are:

21, 23, 30, 32, 32, 35, 43, 44, 46, 48, 49, 49, 50, 52, 52, 53, 55

then we go ahead to answer the questions:

a) Range = highest number minus Lowest number

55 - 21 = 34

b) 17 (by counting all individual ages ).

c) Median = the middle age

(but before that, we must arrange the ages either a cording to their sizes either from biggest to smallest (descending order) or from smallest to biggest (ascending order)

so we arrange in ascending order but the numbers are already arranged so we don't have to stress ourselves:

Median = 46 (the number in the middle ).

Hope you ace your tests, Good luck ✅.

Answer:

(2*2*1.5*1/3)+(2*1.5*4)= 14

Step-by-step explanation:

To find the area of a pyramid, you use the equation of 1/3 *lwh. When we place the values in there, we get 2*2*1.5*1/3, which is equal to 2. Then we solve the bottom part. Since it is a rectangular prism, we use the equation of lwh. When we insert the values, we get 2*1.5*4, which is equal to 12. Now, we take these two values of 2 and 12 and we combine them, giving us our final answer of 14.

The statement about using the line of best fit for the given scatter plot is; False

When we have a scatter plot, it is always best to look for the line of best fit or curve of best fit depending on the nature of the variation of the plotted points.

Now, from the scatter plot image attached, we can see that the points are already looking like a curved plot form and so what we will need her will be a curve of best fit and not a line of best fit plot and as such the statement about using a line of best fit plot is false.

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Answer:

Yes

Step-by-step explanation:

Answer:

2: no

3: no

4: no

5: yes

6: no

8: no

9: no

10: no

11: yes

Step-by-step explanation:

there are some simple divisibility rules that we can utilize here:

a number is divisible by __ if...

2: ends in [last digit] 0, 2, 4, 6, 8

so 275 is not divisible by 2

3: sum of digits is 3

2 + 7 + 5 = 14 [14 is not divisible by 3]

so 275 is not divisible by 3

4: last two digits are divisible by 4

75 is not divisible by 4

so 275 is not divisible by 4

5: last digit is 0 or 5

so 275 is divisible by 5

6: number is divisible by both 2 and 3

we know that 175 is not divisible by 2 or 3, so 275 is not divisble by 6

8: last three digits are divisible by 8

>> we also know that any number that 8 goes into, 4 also goes into [not always the other way around], meaning that because 175 is not divisible by 4, it must not be divisible by 8

so, 275 is not divisible by 8

9: sum of digits is divisible by 9

>> we also know that 9 only can go into numbers that 3 can go into, so because 175 is not divisible by 3, it must not be divisible by 9

so, 275 is not divisible by 9

10: last digit is 0

so, 275 is not divisible by 10

11 is a bit complicated:

sum of digit in odd places and sum of digit in even places has a difference is divisible by 11 [or is 0]

2 7 5

odd places: 2, 5 (2 + 5 = 7)

even places: 7 (7 = 7)

difference between 7 and 7 is 0 (7-7 = 0),

so, 275 is divisible by 11

hope this helps!! :)

Answer:

The group that is most likely able to have a lower mean age of painting students is Group A

Step-by-step explanation:

mean = sum of all terms divided by total number of terms

Looking at the graph data you have provided you can see that group A's students are a younger than students in Group B.

Which means when you calculate the mean the group which would give you the lower ratio with the same denominator of K (let there is K number of students in the class) will have lower mean age

here group A students are younger therefore their ratio will be lower

hence lower mean age

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Placing the equations under the correct solution, we get

x = 3                                      x ≠ 3

-14x = -42                              -5 + x = -9

[tex]-\frac{3}{5} +x = \frac{12}{5}[/tex]                          [tex]\frac{x}{3} =9[/tex]

[tex]\frac{x}{4} =\frac{6}{8}[/tex]                                    

x -5 = -2            

From the question, we are to place the equations under the correct solution

To do this, we will solve the equations one after the other

x = -42/-14

x = 3

x = -9 + 5

x = -4

∴ x ≠ 3

[tex]x = \frac{12}{5} +\frac{3}{5}[/tex]

[tex]x = \frac{12+3}{5}[/tex]

[tex]x = \frac{15}{5}[/tex]

x = 3

[tex]x=\frac{6\times 4}{8}[/tex]

[tex]x=\frac{24}{8}[/tex]

x = 3

x = 3 × 9

x = 27

∴ x ≠ 3

x = -2 + 5

x = 3

Hence, placing the equations under the correct solution, we get

x = 3                                      x ≠ 3

-14x = -42                              -5 + x = -9

[tex]-\frac{3}{5} +x = \frac{12}{5}[/tex]                          [tex]\frac{x}{3} =9[/tex]

[tex]\frac{x}{4} =\frac{6}{8}[/tex]                                    

x -5 = -2            

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All the solution of the equation x³ + 8x² + 100x + 800 = 0 will be 10i, -10i, and -8. Then the correct option is D.

It is a method for dividing a polynomial into pieces that will be multiplied together. At this moment, the polynomial's value will be zero.

The equation is given below.

          x³ + 8x² + 100x = -800

x³ + 8x² + 100x + 800 = 0

Then the factor of the equation will be

x³ + 8x² + 100x + 800 = 0

x² (x + 8) + 100(x + 8) = 0

        (x² + 100)(x + 8) = 0

Then all the solution of the equation will be

x = 10i, -10i, and -8.

Then the correct option is D.

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Answer:

d

Step-by-step explanation:

The correct answer is option B that is Each white blood cell contains millions of haemoglobin molecules. All blood cells come from one pool of stem cells.

The complete question is given below:-

Which of the following statements are true?

I. Each white blood cell contains millions of haemoglobin molecules.

II. In a sample of blood, there are more red blood cells than white blood cells.

III. HIV destroys red blood cells.

IV. All blood cells come from one pool of stem cells.

A. II and IV only

B. I and IV only

C. II and III only

D. I, III, and IV only

E. I, II, and IV only

The most prevalent form of blood cell and the main source of oxygen for the bodily tissues of vertebrates, red blood cells are also known as red cells, red blood corpuscles, haematids, erythroid cells, or erythrocytes. They circulate through the blood through the circulatory system.

Therefore the correct answer is option B that is Each white blood cell contains millions of haemoglobin molecules. All blood cells come from one pool of stem cells.

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Answer:

An obtuse triangle can not have more than one angle measured greater than 90.

Step-by-step explanation:

Obtuse triangles have 2 acute angles (less than 90 degrees) and 1 obtuse angle (greater than 90).

[tex]\textsf {Simplifying the exponents :}[/tex]

[tex]\mathsf {\frac{3x^{-6}y^{-3}}{15x^{2}y^{10}}}[/tex]

[tex]\mathsf {\frac{1}{5x^{(2+6)}y^{(10+3)}}}[/tex]

[tex]\mathsf {\frac{1}{5x^{8}y^{13}}}[/tex]

Δ DGC is right angled triangle because Line E G is perpendicular-to CC', Option D is the correct answer.

Triangle is a polygon with three sides , angles and vertices.

It is given that the there are two Triangles , ABC and A'B'C' as an image of the ABC

* Line segment AA' has a midpoint at point F

*D is the mid point of the line joining BB' .*

The figure is attached with the answer.

the line of reflection of the object is always perpendicular to the object and the image.

it is also given that CGF is a right angle.

Therefore triangle DGC is right angled triangle , (the option given in the question is incorrect ) ,  Line E G is perpendicular-to CC'.

Option D is the correct answer.

Please Refer to the image for correct coordinates.

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