Answer: A'(-3, 7), B'(3, 6), C'(-7, -2)
Step-by-step explanation:
Reflecting over y = x maps (x,y) onto (y,x).
Find the product write your answer in exponential form 7^-1•7^-7
Answer:
1/5764801
Step-by-step explanation:
7^-1 × 7^-7
= 1/7(7^-7)
= 1/7(1/823543)
= 1/5764801
833.30/
1-(1+0.00833)^-360
Answer:
833.25 or 877.59
Step-by-step explanation:
I solved this in two different ways because I wasn't sure on how the question was meant to be read.
Attempt 1:
(833.3/1)-(1+0.00833)^-360
(1+0.00833)^-360 = 0.0505
so:
833.3 - 0.0505 = 833.25
Attempt 2:
833.3/(1-(1+0.00833)^-360)
1- 0.0505 = 0.9495
833.3/0.9495 = 877.59
Angle PQT and Angle SQR are supplementary angles. If the measure of PQT is (3x+43)° and the measure of Angle SQR is (6x-25)°, what is the numeric measure of Angle PQT and Angle SQR?
Answer:
∠PQT = 97°
∠SQR = 83°
Step-by-step explanation:
Supplementary angles sum to 180°
⇒ ∠PQT + ∠SQR = 180°
Given:
∠PQT = (3x + 43)°∠SQR = (6x - 25)°Therefore:
⇒ (3x + 43) + (6x - 25) = 180
⇒ 3x + 6x + 43 - 25 = 180
⇒ 9x + 18 = 180
⇒ 9x = 162
⇒ x = 18
Substitute the found value of x into the expression for each angle:
⇒ ∠PQT = (3x + 43)°
⇒ ∠PQT = (3(18) + 43)°
⇒ ∠PQT = 97°
⇒ ∠SQR = (6x - 25)°
⇒ ∠SQR = (6(18) - 25)°
⇒ ∠SQR = 83°
Check
⇒ ∠PQT + ∠SQR = 97° + 83° = 180°
The power of an exponential expression raised to a power is the product of the exponents.
Answer:
[tex](y {}^{c} ) {}^{d } = y {}^{c \times d} \\ = y {}^{cd} \\ \\ \\ \\ \\ (v {}^{3} ) {}^{7 } \\ = v {}^{3 \times 7} \\ = v {}^{21} [/tex]HOPE THAT HELPS.a + b = c
a + b + c =36
Given that a and b have the same value, work out the values of a,b and c
Answer:
a=9
b=9
c=18
Step-by-step explanation:
c(a+b)+a+b=36
2a+2b=36
a+b=18
c=18
The ratio of (1/5 of 245ml) to (0.2 of 0.84l)
The ratio is given by 98:0.34.
The ratio of (1/5 of 245ml) to (0.2 of 0.84ml).
What is the Ratio?The ratio can be defined as the comparison of the fraction of one quantity towards others. e.g.- water in milk.
we have (1/5 of 245ml) to (0.2 of 0.84ml).
⇒ [tex]\frac{1}{5} 245 :0.2*0.84[/tex]
⇒[tex]98:0.34[/tex]
Thus, the required ratio is 98:0.34.
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To purchase 13700 worth of restaurant equipment for her business Maria made a down payment of 1500 and took out a business loan for the rest after 3 years of paying monthly payments of 371.16 she finally paid off the loan
What was the total amount Maria ended up paying for the equipment
How much internet did Maria pay on the loan
The total amount Maria ended up paying for the equipment will be $14,861.76. And The interest of Maria on the loan will be 8.48%.
What is Algebra?The analysis of mathematical representations is algebra, and the handling of those symbols is logic.
To purchase 13700 worth of restaurant equipment for her business.
Maria made a down payment of 1500 and took out a business loan for the rest, after 3 years of paying monthly payments of 371.16 she finally paid off the loan.
The total amount Maria ended up paying for the equipment will be
Total amount = 371.16 × 3 × 12 + 1500
Total amount = $14,861.76
The interest of Maria on the loan will be
Interset = [(14861.76 – 13700) / 13700] x 100
Interset = 8.48%
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the equation of lime 1 is 3x-2y=5, and the equation of lime 2 is x+2y=7. What is the point of intersection of the two lines?
To find the point of intersection for two lines, we can use substitution to solve for the coordinates.
Solving the QuestionWe're given:
[tex]3x-2y=5[/tex][tex]x+2y=7[/tex]With these two equations, we can:
First isolate x in the second equationUse substitution to input in second equation into the first and solve for yUse the y-coordinate to find the corresponding x-coordinate using substitutionIsolate x in the second equation:
[tex]x+2y=7\\x =7-2y[/tex]
Substitute the second equation into the first:
[tex]3x-2y=5\\3(7-2y)-2y=5\\21-6y-2y=5\\21-8y=5\\21-8y=5[/tex]
Solve for y:
[tex]21-6y-2y=5\\21-8y=5\\-8y=-16\\y=2[/tex]
Solve for x:
[tex]x+2y=7\\x+2(2)=7\\x+4=7\\x=3[/tex]
AnswerThe point of intersection of the lines is (3,2).
the line y=-3x+4 is reflected on the y-axis what is the equation of the reflected line
Answer:
x=0
Step-by-step explanation:
when the reflection falls on the y-axis the answer is x=0
The diagonal of a TV is 30 inches long. Assuming that this diagonal forms a pair of 30-60-90 right triangles, what are the exact length and width of the TV? A. 60 inches by 60,3 inches B. 602 inches by 60 2 inches O C. 15/2 inches by 15/2 inches OD. 15 inches by 15√3 inches
The dimensions of the TV are 15 inches by (√3)*15 inches, so the correct option is D.
How to get the length and the width of the TV?
We can think of this as a right triangle, where the hypotenuse measures 30 inches, and the angles of the triangle are 30°, 60° and 90°.
If we step on the 30° angle, the length will be the opposite cathetus, then we can use the trigonometric relation:
sin(θ) = (opposite cathetus)/(hypotenuse).
Replacing what we know:
sin(30°) = length/30 in
length = sin(30°)*30in = (1/2)*30 in = 15in
And the adjacent cathetus will be the width, then we can use:
cos(θ) = (adjacent cathetus)/(hypotenuse).
Replacing what we know:
cos(30°) = width/(30 in)
width = cos(30°)*30in = (√3/2)*30in = (√3)*15in
Then the dimensions of the TV are 15 inches by (√3)*15 inches, so the correct option is D.
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Determine whether or not each of the following is a partition of set N of natural numbers. (With reason)
(a) {{n | n > 5}, {n | n < 5}]
(b) [{n | n > 6}, {1, 3,5} , {2, 4}]
(c) {{n | n^2 > 11}, {n | n^2 < 11}
Only Set B is a partition of set N of natural numbers .
What are Natural Numbers ?Numbers starting from 1 to infinity comes under Natural Numbers.
It is asked in the question that to determine whether or not each of the following is a partition of set N of natural numbers
A ) {{n | n > 5}, {n | n < 5}]
It is not a set of natural numbers as it does not include 5.
B ) [{n | n ≥ 6}, {1, 3,5} , {2, 4}]
{1,3,5} {2,4}and {n|n≥6} include all the natural numbers
Therefore , it forms a partition of N.
C ) {{n | n^2 > 11}, {n | n^2 < 11}
Every natural number n must satisfy either n^2 > 11 or n^2 < 11
This cannot be possible , therefore it is not the partition of Natural Numbers.
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HELP! ASAP!
2.A cube-shaped plant box has edges that are 13 cm long. The plant box is filled with potting soil that has a density of 1.33 g/cm³.
(a) Is it safe to place the plant box on a window ledge that can support a maximum weight of 2400 grams? Explain why or why not.
(b) Would the density of the soil change if the plant box was only half full? Explain.
Step-by-step explanation:
2.
the volume of the box is
length × width × height = 13×13×13 = 13³ = 2197 cm³
the ratio of the density indignation tells us that every cm³ of soil weighs 1.33 g (or every unit of 1.33g soil fits into 1 cm³).
we have 2197 cm³.
their weight is
2197 × 1.33 = 2,922.01 g
so, the filled box clearly exceeds the max. weight of the window ledge, and it is NOT safe to put it there.
b
yes, it would be a little bit less dense.
because every bit of weight you put on top of something increases the pressure on and therefore the density of that something.
What is the slope of this line? the equation for a line that passes through the points (5,-3) and (-10,15)?
Part 1: Finding slope
The slope is [tex]\frac{-3-15}{5-(-10)}=\frac{-18}{15}=\boxed{-\frac{6}{5}}[/tex]
Part 2: Finding the equation
Using the point (-10, 15) to substitute into point-slope form,
[tex]y-15=-\frac{6}{5}(x+10)\\\\y-15=-\frac{6}{5}x-12\\\\\boxed{y=-\frac{6}{5}x+3}[/tex]
Answer:
Using the given points we find that the slope is -1.2 and using the slope-point form we find that the equation of line is y+1.2x = 3.
Step-by-step explanation:
In the question, two points are given, (5,-3) and (-10,15). Using them we can find the slope using the formula, (y2 - y1) / (x2 - x1). So, the slope is
(-3-15) / (5+10) = -18 / 15 = -1.2
Now, we have to find the equation of line. We have two points and a slope. Using any one point and the slope, we can find the equation of line using slope-point form of line. Let us take (5,-3).
(y+3) / (x-5) = -1.2
y+3 = -1.2(x-5)
y+3 = -1.2x + 6
y+1.2x = 3
So, the slope of line is -1.2 and the equation of line is y+1.2x = 3.
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A soccer field (football pitch) has a length of 101.0 m and a
width of 70.2 m. Find the total area of the field in square
meters (m²) and convert this measurement to square yards
(yd2). Use the fact that 1 yard = 0.9144 m. Round your answer
to the nearest whole number.
Answer:
7754
Step-by-step explanation:
give brainiest, please. <3
Answer:
about 7,754 m
Step-by-step explanation:
101 * 70.2 = 7,090.2
7,090.2/0.9144 = 7,753.9
Find the acute x given that tan x=2sinx
The measure of the acute angle is 60 degrees
Trigonometry identityGiven the following trigonometry equation
tan x=2sinx
This can also be written as;
sinx/cosx=2sinx
Simplify to have:
1/cosx =2
2cosx = 1
cosx = 1/2
x = arccos(1/2)
x = 60 degrees
Hence the measure of the acute angle is 60 degrees
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binomial expansion of (2+3x)^5
Base of a prism is a right triangle with legs 3 feet and 4 feet. The height is 13 feet , what is the volume?
Answer:
Triangular prisms
Remember the formula for calculating volume is: Volume = Area by height. V = A X h.
For a triangle the area is calculated using the formula: Area = half of base by altitude. A = 0.5 X b X a.
So to calculate the volume of a triangular prism, the formula is: V = 0.5 X b X a X h
Step-by-step explanation:
Which function has a restricted domain?
Put the steps in order to solve the literal equation for y in terms of x.
6x+2y+ 8 = 180
Answer:
x = [tex]\frac{172-2y}{6}[/tex]
Step-by-step explanation:
6x + 2y + 8 = 180 ( subtract 8 from both sides )
6x + 2y = 172 ( subtract 2y from both sides )
6x = 172 - 2y ( divide both sides by 6 )
x = [tex]\frac{172-2y}{6}[/tex]
i need help. Part A: Create a five-number summary and calculate the interquartile range for the two sets of data. (5 points)
Part B: Are there any outliers present for either data set? Justify your answer mathematically. (5 points)
Five number summary and IQR of both the data sets are different.
For school A: Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17, IQR=9.5
For school B: Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19, IQR=7.5
No, the box plots are not symmetric.
Part A:
The given data sets are
School A : 9,14,15,17,17,7,15,6,6
School B : 12,8,13,11,19,15,16,5,8
Arrange the data in ascending order.
School A : 6,6,7,9,14,15,15,17,17
School B : 5,8,8,11,12,13,15,16,19
Divide each data set into four equal parts.
School A : (6,6),(7,9),14,(15,15),(17,17)
School B : (5,8),(8,11),12,(13,15),(16,19)
For school A:
Minimum=6, Q₁=6.5, Median= 14, Q₃=16, Maximum=17
The interquartile range of the data is
For school B:
Minimum=5, Q₁=8, Median= 12, Q₃=15.5, Maximum=19
[tex]IQR=Q_3-Q_1\\ =Q_3-Q_1\\ =16-6.2\\ =9.5[/tex]
The interquartile range of the data is
[tex]IQR=Q_3-Q_1\\ =Q_3-Q_1\\ =15.5-8\\ =7.5[/tex]
Part B:
The box plots are not symmetric because the data values are different. Five number summary and IQR of both the data sets are different.
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Which of the following is the graph of y=-(x-2)^3 -5
The graph is shown in the attached image.
Giving 20 points for the answer.
Answer:
B, A, C
Step-by-step explanation:
add the like terms together (ending in x2 with x2, ending in x with x etc )
Answer:
B A C
Step-by-step explanation:
combining like terms
what is the Smallest numbers :
p = x^2 + 2x +2 / x+1 (x>-1)
t= 1/x + 4/1-x (0
Answer:
I exactly don't know the answer
Solve the compound inequality. Graph the solution set and write it in interval notation. x<2 and x>-3
Answer:
Answer is (-3, 2)
3a =2b + -6 (solve for a)
Answer:
shown below
Step-by-step explanation:
3a = 2b - 6
a = (2b - 6) / 3 or 2b / 3 - 2
Answer:
a = (2b-6)/3
Step-by-step explanation:
3a = 2b + -6
lets make a the subject of the formula
divide both sides of the equation by 3
3a/3 = a = (2b-6)/3
a = (2b-6)/3
please help ive been stuck on this question.
The value of the expression 8 / m - 11 / 3m is 13 / 3m
How to simplify an expression?8 / m - 11 / 3m
Therefore,
8 / m - 11 / 3m
The factor of the denominator is 3m
Therefore,
8 / m - 11 / 3m = 3(8) - 11/ 3m
3(8) - 11/ 3m = 24 - 11 / 3m
24 - 11 / 3m = 13 / 3m
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URGENT 30 points I need help
Answer:
- 112 + 100 n
Step-by-step explanation:
[tex]a_{n}[/tex] = [tex]a_{1}[/tex] + (n - 1 )d
~~~~~~~
[tex]a_{1}[/tex] = - 12
d = 100
[tex]a_{n}[/tex] = - 12 + 100( n - 1 )
[tex]a_{n}[/tex] = - 12 + 100n - 100
[tex]a_{n}[/tex] = - 112 + 100 n
Given the following functions, find and simplify (f+g)(-2).
Do not include "(f+g)(-2)=" in your answer.
f(x) = -3x² - 2x
g(x) = -2x +3
Answer:
43
Step-by-step explanation:
because if you add it up thats how you get that
Liz earns a salary of $2,200 per month, plus a commission of 5% of her sales. She wants to earn at least
$2,500 this month. Enter an inequality to find amounts of sales that will meet her goal.your
variable represents. Enter the commission rate as a decimal.
Answer:
2200 + 0.5x >= 2500
Step-by-step explanation:
x is the amount of sales
Tioga Company manufactures sophisticated lenses and mirrors used in large optical telescopes. The
company is now preparing its annual profit plan. As part of its analysis of the profitability of individual
products, the controller estimates the amount of overhead that should be allocated to the individual product lines from the following information.
Lenses Mirrors
Units produced ................................................................................................................ 25 25
Material moves per product line ........................................................................................ 5 15
Direct-labor hours per unit ................................................................................................ 200 200
The total budgeted material-handling cost is $50,000.
Required:
1. Under a costing system that allocates overhead on the basis of direct-labor hours, the materialhandling costs allocated to one lens would be what amount?
2. Answer the same question as in requirement (1), but for mirrors.
3. Under activity-based costing (ABC), the material-handling costs allocated to one lens would be
what amount? The cost driver for the material-handling activity is the number of material moves.
4. Answer the same question as in requirement (3), but for mirrors.
Tioga Company manufactures sophisticated lenses and mirrors used in large optical telescopes, the values are mathematically given as
MH1=$1,000MH2=$1,000MH3=$1500MH4=$1500What is the material handling costs allocated?Generally, the equation for Material-handling cost for one lens mathematically given as
MH1=Total projected costs for material handling /{Total number of direct labor hours x Direct labor hours per unit)
MH1={$50,000/10.000)x 200
MH1=$1,000
2)
Material-handling cost for one mirror
MH2=Total budgeted material handling cost/ Total number of direct labor hours x direct labor hours per unit
MH2={$50,000/10.000)x 200
MH2=$1,000
3) Material-handling cost per lens
[tex]MH3=\frac{Total projected costs for material handling}{\frac{Number of material moves per lens + Number of material moves per mirror}{(Total number of lenses)}}* Material moves per lens[/tex]
[tex]MH3=\frac{50,000}{\frac{5+15}{25}}*5[/tex]
MH3=$1500
4)
[tex]MH4=\frac{Total projected costs for material handling}{\frac{Number of material moves per mirror + Number of material moves per lens}{(Total number of mirror)}}* Material moves per mirror[/tex]
[tex]MH4=\frac{50,000}{\frac{5+15}{25}}*5[/tex]
MH4=$1500
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