Given the measured value of mass M in the experiment the error in 2M is ; dM
Given data :
Measured value of mass M = ( 0.743 ± 0.005 ) kg
The error in 2M in the measured valueThe error in 2M in the measured value M = 0.743 ± 0.005 kg is dM while the error in M² will be 2dM
Hence we can conclude that the measured value of mass M in the experiment the error in 2M is ; dM.
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A lamp is 15% efficient. How much electrical energy must be supplied to the lamp each second if it produces 30 J of light energy per second? *WILL MARK BRAINLIEST*
200 Joules should be supplied in the circuit.
Efficiency = output/inuptHere the output is 30J and input is missing
[tex]\sf \dfrac{30}{I} * 100 = 15[/tex]
multiplied with 100, to covert it into percentage
[tex]\sf 3000 = 15(I)[/tex]
[tex]\sf I = \dfrac{3000 }{15}[/tex]
[tex]\sf I = 200J[/tex]
Let that be X
Efficiency is 15% means the lamp produces 15J of light energy when 100J energy applied.[tex]\\ \rm\Rrightarrow \dfrac{30}{x}(100)=15[/tex]
[tex]\\ \rm\Rrightarrow 3000=15x[/tex]
[tex]\\ \rm\Rrightarrow x=200J[/tex]
a car 150m to the east then backtracks 30m to the west. Describe the mathematical operation you will use to determine the net movement of the car
Answer:
Total displacement will be 120m
Explanation:
Since displacement is shortest distance travelled
Td= 150m east - 30m west ( Since they are opposite in direction)
Td= 120m East
A rocket designed to place small payloads into orbit is carried to an altitude of 12.0 km above sea level by a converted airliner. When the airliner is flying in a straight line at a constant speed of 850 km/h, the rocket is dropped. After the drop, the airliner maintains the same altitude and speed and continues to fly in a straight line. The rocket falls for a brief time, after which its rocket motor turns on. Once its rocket motor is on, the combined effects of thrust and gravity give the rocket a constant acceleration of magnitude 3.00g directed at an angle of 30.0° above the horizontal. For reasons of safety, the rocket should be at least 1.00 km in front of the airliner when it climbs through the airliner’s altitude. Your job is to determine the minimum time that the rocket must fall before its engine starts. You can ignore air resistance. Your answer should include (i) a diagram showing the flight paths of both the rocket and the airliner, labeled at several points with vectors for their velocities and accelerations; (ii) an x-t graph showing the motions of both the rocket and the airliner; and (iii) a y-t graph showing the motions of both the rocket and the airliner. In the diagram and the graphs, indicate when the rocket is dropped, when the rocket motor turns on, and when the rocket climbs through the altitude of the airliner.
Answer:
Explanation:
A rocket designed to place small payloads into orbit is carried to an altitude of 12.0 km above sea level by a converted airliner. When the airliner is flying in a straight line at a constant speed of 850 km/h, the rocket is dropped. After the drop, the airliner maintains the same altitude and speed and continues to fly in a straight line. The rocket falls for a brief time, after which its rocket motor turns on. Once its rocket motor is on, the combined effects of thrust and gravity give the rocket a constant acceleration of magnitude 3.00g directed at an angle of 30.0° above the horizontal. For reasons of safety, the rocket should be at least 1.00 km in front of the airliner when it climbs through the airliner’s altitude. Your job is to determine the minimum time that the rocket must fall before its engine starts. You can ignore air resistance. Your answer should include (i) a diagram showing the flight paths of both the rocket and the airliner, labeled at several points with vectors for their velocities and accelerations; (ii) an x-t graph showing the motions of both the rocket and the airliner; and (iii) a y-t graph showing the motions of both the rocket and the airliner. In the diagram and the graphs, indicate when the rocket is dropped, when the rocket motor turns on, and when the rocket climbs through the altitude of the airliner.
A scientist decreases the wavelength of the light used in a double-slit experiment and keeps every other aspect the same. What will be true
about the new interference pattern seen on the screen compared to the original interference pattern? (point)
O The spacing between the bright fringes will increase.
O The spacing between the dark fringes will remain the sam
same.
O The spacing between the bright fringes will decrease.
O The spacing between the dark fringes will increase.
A scientist decreases the wavelength of the light used in a double-slit experiment and keeps every other aspect the same. The new interference pattern seen on the screen compared to the original interference pattern is the spacing between the bright fringes will increase. Thus, the correct option is A.
What is Interference pattern?Interference is the net effect of the combination of two or more wave forms or trains which are moving on intersecting or coincident paths in a medium. The effect of this pattern is that of the addition of the amplitudes of the individual waves at each point which are affected by more than one wave in the medium.
A scientist when decreases the wavelength of the light used in a double-slit experiment and it keeps every other aspect of the wave the same. The new interference pattern seen on the screen as compared to the original interference pattern is that the spacing between the bright fringes will increase.
Therefore, the correct option is A.
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Friction helps your vehicle stop quickly.
A. TRUE
B. FALSE
Answer:
true
Explanation:
Friction helps your vehicle stop quickly. this statement ids true. Hence option A us correct. A vehicle can stop more rapidly because to friction. The brake pads rub on the turning braking discs or drums when the brakes are applied.
The friction slows the moving vehicle down and eventually causes it to halt by converting its kinetic energy into heat energy. The effectiveness of the braking action will increase with the level of friction between the brake parts. For rapid stops, friction between the tyre and the road is also important.
The vehicle's forward motion is opposed by friction created by the tyres' gripping action on the road surface, which helps in stopping and decelerating. Rapid vehicle stopping would be incredibly difficult and risky without friction.
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stion 3
Define the law of moments. It is applicable to a certain condition of the acting forces.
Name the condition.
Answer:
algebraic sum of moments of all the forces acting on the body about the axis of rotation is zero, the body is in equilibrium. According to the principle of moments, in equilibrium: Sum of anticlockwise Moments = Sum of clockwise moments.
Condition:
For an object to be in equilibrium, it must be experiencing no acceleration.
Hope it may helpful to you
All machines are less than 100% efficient. True False
Answer:
false
Explanation:
because no machines have 100% efficient
The denizens of a distant planet live under an atmosphere made predominantly of CO2 which is a dispersive medium while attending a concert which of the following would be true for a spectator seated in the back of a large amphitheater?
I. They would hear the low notes and high notes at different times
II. They would hear the low notes and high notes at the same time
Since the frequency of sound in a medium is constant, therefore, the concert-goers would hear the low notes and high notes at the same time.
What is a dispersive medium?A dispersive medium is a medium which spreads out or disperses a substance passing through it.
Since CO2 is a dispersive medium, it means sound waves passing through it would be dispersed based on wavelength.
The note of a sound depends on its frequency, the higher the frequency, the higher the note.
Frequency of sound is constant, therefore, the concert-goers would hear the low notes and high notes at the same time.
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What is one benefit of smart meters?
Answer:
You get up-to-date readings
Explanation:
Which best illustrates projectile motion?
A pictorial diagram showing a hot air balloon in four different positions, each the same height from the ground and equally spaced.
A pictorial diagram with a rocket launched straight upward. The first three positions of the rocket are shown with equal spacing between them.
A pictorial diagram with a person swimming and position shown in equal time intervals and equally spaced.
A pictorial diagram of a person hopping sideways at 5 different positions. The start and end positions are on the ground. The third image is the highest off the ground.
The pictorial diagram with a rocket launched straight upward, showing the first three positions of the rocket with equal spacing between them, best illustrates projectile motion. In this case, the rocket is projected upward into the air, and its path follows a parabolic trajectory due to the influence of gravity.
What is projectile motion?Projectile motion refers to the motion of an object that is thrown, launched or otherwise projected into the air and then moves under the influence of gravity alone. In this type of motion, the object moves along a curved path, called a parabola, due to the combined effect of its initial velocity and the force of gravity acting on it.
When a rocket is launched straight upward, it experiences a projectile motion. The rocket's initial velocity is upwards, but gravity causes it to decelerate until it eventually stops at the highest point of its trajectory. The rocket then starts to fall back down, accelerating due to gravity until it reaches the ground. If we take three equal intervals of time, we can show the rocket's positions at those times. Initially, the rocket will be moving upwards with a decreasing velocity, then it will reach its maximum height before falling back down with an increasing velocity.
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Answer: I believe it should be the final answer,
A pictorial diagram of a person hopping sideways at 5 different positions. The start and end positions are on the ground. The third image is the highest off the ground
Explanation:
Which angle is the angle of refraction?
Explanation:
[tex]\longmapsto\: \red{ hello \: mate}[/tex]
OPTION (C) 3
is the angle of refraction
Answer:
Option C. 3
Explanation:
Refraction is the change in direction of light passing from one medium to another. Angle 1 and 2 are reflection due to the bouncing of light.
what is the centripetal acceleration of an air plug on a car tire 250 rpm raduius of 0.45 m
The magnitude of the centripetal acceleration of the air plug on a car tire is 308.43 m/s².
What is centripetal acceleration?
Centripetal acceleration of an object is the rate of change of object's velocity with time, and it is directed inwards.
The magnitude of the centripetal acceleration of the air plug on a car tire is calculated as follows;
ac = ω²r
where;
ω angular speed (rad/s)r is radius of the tireAngular speed in radian per second[tex]\omega = 250 \ \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1 \min}{60 \ s} \\\\\omega = 26.18 \ rad/s[/tex]
ac = (26.18)² x 0.45
ac = 308.43 m/s²
Thus, the magnitude of the centripetal acceleration of the air plug on a car tire is 308.43 m/s².
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Select all the correct answers.
A worker is holding a filled gas cylinder still. Which two sentences are true about the energy of the filled gas cylinder?
it has no energy because it's being held still.
It has gravitational potential energy because of its height
Its atoms and molecules have thermal energy.
0 It has motion energy because it will fall if let go.
its kinetic energy is being converted to potential energy.
Answer:
It has gravitational energy because of its height above some reference point.
It also contains thermal energy due to the motion of the contained atoms and molecules.
Answer:
b and c :)
Explanation:
• (-/1 Points) DETAILS OSCOLPHYS2016 9.5.WA.040.
MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER
A supertanker uses a windlass (a type of winch) like the one shown in the figure below to hoist its 21,200-kg anchor. Determine the force that must be exerted on the
outside wheel to lift the anchor at constant speed, neglecting friction and assuming the anchor is out of the water.
IN
doorg
-0.45 m
- 1.5m
The force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.
Force exerted outside the wheelThe force exerted on the outside of the wheel can be determined by applying the principle of conservation of angular momentum as shown below.
∑τ = 0
Let the distance traveled by the load = 1.5 mLet the radius of the wheel or position of the force = 0.45 m∑τ = R(mg) - r(F)
rF = R(mg)
0.45F = 1.5(21,200 x 9.8)
F = 6.925 x 10⁵ N.
Thus, the force that must be exerted on the outside wheel to lift the anchor at constant speed is 6.925 x 10⁵ N.
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What would be the potential difference of the capacitor if it is connected to a battery of 3v?
Answer: 3V
Explanation:
If the capacitor is connected to a 3V battery:
[tex]\bold{V = \frac{Q}{C} }[/tex]
The potential difference is also 3V on the capacitor
A revolving door continues to rotate even after the person pushing it exits. Is it Newton's first law of motion, Newton's second law of motion. or Newton's third law of motion?
Answer:
Newton's third Law
Explanation:
Newton’s first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.
An unknown fluid flows at a speed of 31 m/s. Suppose the fluid has a mass of 47 kg runs at this speed. What is the fluid’s kinetic energy?
Answer:
22583.5J
Explanation:
KE=1/2 mv^2
=1/2*47Kg*(31m/s^2)
=23.5Kg * 961m/s^2
=22583.5J
The force between a pair of charges is 900 newtons. The distance between the charges is 0.01 meters. If one of the charges is 2e-10 C what is the strength of the other charge ?
Answer:
[tex] \fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}[/tex]
Explanation:
Given:
Force between pair of charges= 900 newtons
The distance between the charges = 0.01 meters
Strength of Charge first q1 = 2e-10 Coulomb
To find:
Strength of Charge second q2 = ____ Coulomb?
Solution:
We know that,
Force between two charges separate by distance r is given by the equation,
[tex]|F| = K_e \frac{q1 \cdot \: q2}{ {r}^{2} } \\ 900 =K_e \frac{(2e - 10)\cdot \: q2}{ {0.01}^{2} } \\ 900 \times {10}^{ - 4} = K_e {(2e - 10)\cdot \: q2} \\ q2 = \frac{9 \times {10}^{ - 2} }{(2e - 10) K_e} \\ \\ \fbox{We \: know \: that \: e = 2.71 } \\ substituting \: the \: value \: \\ q2 = \frac{9 \times {10}^{ - 2} }{(2 \times 2.71 - 10)K_e} \\ q2 = \frac{0.09}{ - 4.58 K_e} \\ q2 = \frac{-0.0196}{K_e}\: coulomb[/tex]
[tex] \fbox{strength \: of \: the \: other \: charge = - 0.0196 Ke \: Coulomb}[/tex]
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A wheel rotates at 24 revolutions every 3 minutes. This is equivalent to
At a typical bowling alley the distance from the line where the ball is released (foul line) to the first pin is 60ft. Assume it takes 5.0s for the ball to reach the pins after you release it, if it rolls without slipping and has a constant translational speed. Also assume the ball weights 12lb and has a diameter of 8.5 inches.
A- Calculate the rotation rate of the ball in rev/s
B- What is the total kinetic energy in pound-feet? Ignore the finger holes and treat the bowling ball as a uniform sphere
A) The rotation rate of the ball in rev/secs is ; 10.79 rev/secs
B) The total kinetic energy of in pound-feet ignoring the finger holes is : 37.6157 pound-feet
Given data :
mass of ball = 12 Ib
diameter of ball = 8.5 inches
Radius = 4.25 inches = 0.10795 m
Time = 5 secs
distance travelled = 60 ft = 18.288 m
A) Determine the rotation rate of the ballFirst step : calculate the velocity of ball
V = distance / time
= 18.288 / 5 = 3.66 m/s
Next step :
angular velocity ( w ) = V / r
= 3.66 / ( 0.10795 ) = 33.90 rad/sec
convert to rev/sec = 33.90 / π
= 10.79 rev/secs
B) Determine the total kinetic energy
given that ball rolls without slipping
Vcon = Rw
Total K.E = 1/2 IW² + 1/2 mv²
= 7/10 MR²W²
Total K.E = 7/10 * 5.44 * ( 0.10795 )² * 33.90²
= 50.99 ≈ 51 J
convert to pound-feet = 37.6157 pound-feet
Hence we can conclude that The rotation rate of the ball in rev/secs is ; 10.79 rev/secs and The total kinetic energy of in pound-feet ignoring the finger holes is : 37.6157 pound-feet.
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How Does a Broken Bone Heal? Interactivity. Please i need the answer soon.
Answer:
The body develops a blood clot over the fractured bone in the first few days of a fracture to protect it and deliver the requisite cells for healing. Then, around the fractured bone, a field of healing tissue grows. This is referred to as a callus.
Explanation:
Answer:
Bone heals by making cartilage to temporarily plug the hole created by the break. This is then replaced by new bone. Many people think of bones as being solid, rigid, and structural. Bone is, of course, key to keeping our bodies upright, but it is also a highly dynamic and active organ
Explanation:
A 2 kg solid disk with a radius of 0.22 m has a tangential force of 300N applied to it.
a) What is the torque acting on the disk?
b) What is the moment of inertia of the disk?
c) What angular acceleration is produced by the torque?
d) If the disk starts from rest and the acceleration is constant for 3.0s, what is the angular velocity of the disk at the end of 3.0s?
e) Through what angle in radians has the disk rotated during this time?
(a) The torque acting on the disk is 66 Nm.
(b) The moment of inertia of the disk is 0.05 kgm².
(c) The angular acceleration is produced by the torque is 1,320 rad/s².
(d) The final angular velocity of the disk is 3,960 rad/s.
(e) The angle of rotation of the disk is 5,940 rad.
Torque acting on the diskThe torque acting on the disk is calculated as follows;
τ = Fr
τ = 300 x 0.22
τ = 66 Nm
Moment of inertiaThe moment of inertia of a solid disk is calculated as follows;
I = ¹/₂MR²
I = ¹/₂ x 2 x (0.22)²
I = 0.05 kgm²
Angular acceleration of the diskThe angular acceleration of the disk is calculated as follows;
τ = Iα
[tex]\alpha = \frac{\tau }{I} \\\\\alpha = \frac{66}{0.05} \\\\\alpha = 1,320 \ rad/s^2[/tex]
Angular velocity of the disk after 3 sωf = ωi + αt
ωf = 0 + (1320 x 3)
ωf = 3,960 rad/s
Angle of rotation of the diskωf² = ωi²+ 2αθ
(3,960)² = 0 + 2(1320)θ
θ = (3,960²) / (2 x 1320)
θ = 5,940 rad
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What season would Texas be having at point D?
Answer:
Almost winter so fall
Explanation:
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You are pushing a 30 crate along a rough surface by applying a horizontal force. The coefficients of
frictions between the surface and the crate are 0.3 and 0.6. Sketch the situation and create a Free Body diagram
from it, then Calculate:
a. The normal force on the crate by the floor.
b. The force required to get the crate to move.
c. Determine the kinetic friction force that the floor applies on the object.
d. Determine the acceleration of the crate.
Answer:
ill say math too!
Explanation:
Why is gravitational force always towards the center?
Answer:
i beleave cuz of the Earth is spherical
Explanation:
✓ 4.) A certain molecule has an energy-level diagram for its vibrational energy in
which two levels are 0.0141eV apart. Find the wavelength of the emitted
line for the molecule as it falls from one of these levels to the other. [h
6.63 x 10-34 kgm s-?, C = 3 x 108ms-1, lev = 1.602 x 10^-19j
Answer:
Explanation:
You can use [tex]\Delta E=\frac{\hbar c}{\lambda} \rightarrow \lambda =\frac{\hbar c}{E} = \frac{1240 eV.nm}{0.0141 eV} \approx 87943.26[/tex] in nm.
Here the hc = 1240 eV.nm in eV and nanometer unit.
Is water Wet or Dry. Explain.
Explanation:
Water is wet, in the sense of being a liquid which flows easily, because its viscosity is low, which is because its molecules are rather loosely joined together.
Answer:
Liquid water is not itself wet, but can make other solid materials wet.
Wetness is the ability of a liquid to adhere to the surface of a solid, so when we say that something is wet, we mean that the liquid is sticking to the surface of a material.
Whether an object is wet or dry depends on a balance between cohesive and adhesive forces. Cohesive forces are attractive forces within the liquid that cause the molecules in the liquid to prefer to stick together. Cohesive forces are also responsible for surface tension. If the cohesive forces are very strong, then the liquid molecules really like to stay close together and they won't spread out on the surface of an object very much. On the contrary, adhesive forces are the attractive forces between the liquid and the surface of the material. If the adhesive forces are strong, then the liquid will try and spread out onto the surface as much as possible. So how wet a surface is depends on the balance between these two forces. If the adhesive forces (liquid-solid) are bigger than the cohesive forces (liquid-liquid), we say the material becomes wet, and the liquid tends to spread out to maximize contact with the surface. On the other hand, if the adhesive forces (liquid-solid) are smaller than the cohesive forces (liquid-liquid), we say the material is dry, and the liquid tends to bead-up into a spherical drop and tries to minimize the contact with the surface.
Water actually has pretty high cohesive forces due to hydrogen bonding, and so is not as good at wetting surfaces as some liquids such as acetone or alcohols. However, water does wet certain surfaces like glass for example. Adding detergents can make water better at wetting by lowering the cohesive forces . Water resistant materials such as Gore-tex fabric is made of material that is hydrophobic (water repellent) and so the cohesive forces within the water (liquid-liquid) are much stronger than the adhesive force (liquid-solid) and water tends to bead-up on the outside of the material and you stay dry.
What is electrical power and how is it measured?
Answer:
power is measured in watts and its the messure of work over time.
Explanation:
Radioactive isotopes can be used to find the age of rocks, fossils, or other artifacts. Carbon-14 has a half-life of 5,730 years. Suppose a sample of charcoal from a primitive fire pit contains one eighth of its original amount of carbon-14. How old is the sample?
Answer:
1/8 = (1/2)^3
This implies the sample has decayed for 3 half lives
3 * 5730 yrs = 17,200 years
An example of a natural electric field is thunder or lightning
Answer:
Lightning
Explanation:
Lightning during a thunderstorm is an example of electrical energy. It is the visible discharge of atmospheric electricity. As lightning heats the air, it creates a shock wave that causes the sound of thunder.
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