Answer:
W = 62.5 J
Explanation:
Given that,
Mass of a baseball, m = 0.2 kg
Initial speed of first student, u = 25 m/s
Finally, the ball stops, v = 0
We need to find the work done by the second student in stopping the ball. We know that, work done is equal to the change in kinetic energy. It can be given by :
[tex]W=\dfrac{1}{2}m(v^2-u^2)\\\\W=-\dfrac{1}{2}mu^2\\\\W=-\dfrac{1}{2}\times 0.2\times(25)^2\\\\W=-62.5\ J[/tex]
So, the required work done is 62.5 J.
volleyball falls on sand at timet 0 ms and quickly comes to rest. ... The Net Force On The Ball Over Time Is Shown Below Force (N) 3 2 T-> Time(ms ) 15 10 15 20 25 ... Note That Time Is In Ms. Kg M ..
Answer:.05 kg*m over s
Explanation:did the work
A tourist leaves Pittsburgh and travels 60 miles South on I-79 in 45 minutes. They exit after Wheeling and head west on I-70 and drive an additional 100 miles in 1 hour and 15 minutes. What is the tourist’s average speed?
Answer:
The tourist's average speed was 80 mph
Explanation:
Average Speed
If an object travels a distance d in a time t regardless of the direction, the average speed is the quotient of the distance over the time:
[tex]\displaystyle v=\frac{d}{t}[/tex]
The tourist leaves Pittsburgh and travels 60 miles South in 45 minutes. Then he heads West and travels 100 miles in 1 hour and 15 minutes.
The total distance traveled is:
d = 60 miles + 100 miles = 160 miles
The total time is:
t = 45 minutes + 1 hour + 15 minutes = 2 hours
The average speed is:
[tex]\displaystyle v=\frac{160}{2}[/tex]
v = 80 mph
The tourist's average speed was 80 mph
Examine the picture of the screw on page 214. Explain how to calculate the mechanical advantage of the screw.
Answer:
1.4
Explanation:
A child is playing with a toy car, and it accelerates
to the south from 1.2 m/s to 6.3 m/s. If the toy car's
acceleration is 2.75 m/s2, what is the amount of time
that the child takes to accelerate the car?
Answer:
1.86s
Explanation:
Given parameters:
Initial velocity = 1.2m/s
Final velocity = 6.3m/s
Acceleration = 2.75m/s²
Unknown:
Time it takes for the child to accelerate the car = ?
Solution:
Acceleration is the rate of change of velocity with time.
a = [tex]\frac{v - u}{t}[/tex]
a is the acceleration
v is the final velocity
u is the initial velocity
t is the time taken
2.75 = [tex]\frac{6.3 - 1.2}{t}[/tex]
5.1 = 2.75t
t = 1.86s
3. A large passenger ship required a force of 1,600,000 N to move 2000 m. How much work is done on the ship?
Answer:
3,200,000,000 J
Explanation:
Work is defined as the amount of energy transferred as an object is moved a certain distance with a certain force. Mathematically, we express this with the equation
[tex]W=Fs[/tex]
where W is work (measured in joules), F is the force applied (in Newtons), and s is the distance, also called the displacement (in meters).
Here, we have F = 1,600,000 N and s = 2000 m, so our work will be
[tex]W=1.600.000(2.000)=3.200.000.000[/tex] J
a bottle of soft drink was moved from the refrigerator after sometime it was observed that his temperature has increased by 15 rakine what is the temperature change in Fahrenheit and Celsius
Answer:
8.333C 15F
Explanation:
15R in C - 0R in C = 8.3333C
15R in F - 0R in F = 15F
Explain how neutrons enable a nuclear chain reaction to take place. (2)
Answer:
Explanation:
In addition to the 'daughter' products, two or three neutrons also explode out of the fission reaction and these can then collide with other uranium nuclei which are unstable so these cause further fission reactions. This is known as a chain reaction .
Hope this helps
A 20-kilogram object strikes the ground with 1960 J of kinetic energy after falling freely from rest. How far above the ground was the object when it was released? *
Answer:
h = 10 m
Explanation:
Given that,
Mass of an object, m = 20 kg
It strikes the ground with 1960 J of kinetic energy after falling freely from rest.
We need to find how far above the ground was the object when it was released. Let it is h.
The kinetic energy is converted to potential energy. It can be given by the relation as follows :
[tex]E=mgh\\\\h=\dfrac{E}{mg}\\\\h=\dfrac{1960}{20\times 9.8}\\\\h=10\ m[/tex]
So, it was at a height of 10 m when it was released.
Can you please help me in this question? Help would be REALLY appreciated :)
An unknown material has a refractive index of 2.78 x106. How fast is light traveling in in this material?
Answer:
294.68
Explanation:
I hope you right answer
The velocity of light travelling in that medium = v= 107.9 m/s
What is refractive index?
It is a ratio of the velocity of light in vacuum to velocity of light in a specific medium
given
refractive index of material( u) : 2.78 * 10 ^6
c = 3* 10 ^8 m/s
velocity of light travelling in that medium(v) = ?
u = speed of light / v
v = speed of light / u
v= 3* 10 ^8 / 2.78 * 10 ^6
v= 107.9 m/s
velocity of light travelling in that medium = v= 107.9 m/s
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Q1) An aeroplane covers a certain distance at a speed of 240 kmph in 5 hours.To cover the same distance in 1(2/3) hours, it must travel at a speed of;
A)300kmph
B)360kmph
C)600kmph
D)720kmph
Explain how you got the answer
Answer:
D) 720 kmph
Explanation:
First, let's find what distance this aeroplane covered. Distance (d) is the product of speed and time - here, we have a speed of 240 kmph and a time of 5 hours, gives us
[tex]d=240\cdot5=1200[/tex] km
Using that same fact, we can set up a new equation to solve for speed (s) when we have a distance of 1200 km and a time of 1 2/3 hours. For the sake of cleanliness, I'm gonna rewrite 1 2/3 as the improper fraction 5/3:
[tex]1200=(5/3)s[/tex]
Multiplying both sides of the equation by 3/5:
[tex]s=(3/5)(1200)=720[/tex] kmph
So our answer is D.
Answer: 720km/h
Explanation:
3. A 0.145 kg ball moving horizontally at 20 m/s is struck by a bat that causes the ball to move in the
opposite direction at 15 m/s. If the ball and bat were in contact for 5 ms, how much force did the bat
apply to the ball?
Answer:
F = 1015 N
Explanation:
Given that,
Mass of a ball, m = 0.145 kg
Initial speed, u = 20 m/s
Final speed, v = -15 m/s (as it moves in opposite direction)
The ball and bat were in contact for 5 ms
We need to find the force the bat applies to the bat. We know that,
F = ma
[tex]F=\dfrac{m(v-u)}{t}\\\\F=\dfrac{0.145\times (-15-20)}{5\times 10^{-3}}\\\\F=-1015\ N[/tex]
So, the bat will apply 1015 N force to the ball.
Suppose the Pathfinder moves at a rate of 0.2m/s for 20 seconds and then turns around and travels at the same speed for 3 seconds, what is the Pathfinder's current position?
Answer:
PLEASE BE MORE SPECIFIC
Explanation:
The pathfinder is currently 3.4 m away from its initial position. Speed can be defined by the change in position of the object over time.
What is Speed?
It can be defined by the change in position of the object over time. The distance can be calculated by the formula,
[tex]d = s \times t[/tex]
Where,
[tex]d[/tex]- distance
[tex]s[/tex] - speed
[tex]t[/tex] - times -
Initially, Pathfinder moves,
[tex]d = 0.2 \times 20 \\\\d = 4 \rm \ m[/tex]
Then he turns back and moves,
[tex]d' = 0.2 \times 3 = 0.6 \rm m[/tex]
So the current position is:
[tex]D = d - d'\\\\D = 4 - 0.6 \\\\D = 3.4\rm m[/tex]
Therefore, the pathfinder is currently 3.4 m away from its initial position.
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A man is running up an escalator. He is moving 5 m/s, but the escalator is also moving up at 3.5 m/s. Find the resultant velocity.
The man's resultant velocity is
8.5 m/s up .
Two charges repel each other with a force. If the magnitude of both charges double, but the distance between them remains constant, the force between them will
A. Double
B. Triple
C. Quadruple
D. Remain the same
Answer:
C.
Explanation:
what formula can you use to calculate average speed
Answer:
the DTS triangle
Explanation:
DTS stands for distance, time, and speed, which you can use to calculate any of the three if you have the other two.
What is accuracy
Classification of error
Answer:
The description of the frame of reference is characterized below.
Explanation:
Accuracy, as well as regression coefficients, seem to be the new standard measures besides summing up the validity of the developed modeling techniques. Classification accuracy unfortunately due to the presuppositions established by professionals on data sources with such an equitable classification process on supervised learning mostly with completely skewed category apportionmentNeed help asapppp
Thanks + BRAINLIST only if you know correct answer
1.Electromagnetic waves are
a. forms of matter
b. forms of space
C. longitudinal waves
d. transverse waves
2. A filter with vertical slits allows only waves that vibrate from side to side to pass
through
a.True
b. False
3.An electromagnetic wave is made up of vibrating an electric and magnetic fields.
a. True
b. False
Answer:
1. d. transverse waves
2. False
3. True
Weighing 15,000 N is parked on a 10 m2 hydraulic lift platform. What is the area of a small piston if a 1,100 N nozzle is used to lift the vehicle?
Answer:
[tex]A_2=0.74\ m^2[/tex]
Explanation:
Given that,
Weight, F₁ = 15,000 N
Area, A₁ = 10 m²
Weight, F₂ = 1100 N
We need to find the area of the small piston. The pressure exerted on both piston will be equal such that,
[tex]\dfrac{F_1}{A_1}=\dfrac{F_2}{A_2}\\\\A_2=\dfrac{F_2A_1}{F_1}\\\\A_2=\dfrac{1100\times 10}{15000}\\\\A_2=0.74\ m^2[/tex]
So, the area of the smaller piston is [tex]0.74\ m^2[/tex].
I really need some help with this. The question is in the photo
A relative asks your advice about a skin cream that reduces oxidation of
the lower skin layers and, thereby, reduces skin aging. Explain to her the
effectiveness of the skin cream based on that claim.
?
Answer:
Hmm
Explanation:
Answer:
Are antioxidant-rich skincare products as effective as they say they are? Best Health checked the science behind the claims.
Rusting iron and the browning flesh of an avocado both have something in common with the discoloration, wrinkles and fine lines of our aging skin: oxidation. Antioxidants counter this natural aging process, and that’s why they have been taking top billing in skin care.
Explanation:
a 28 kg ball is rolling across the top of a 0.75 m tall table. the ball has 350 J of kinetic energy. how fast is the ball moving
calculate electrostatic force. PLEASE HELP ASAP !!!!!! thank you so so so much!!!! will give brainliest!!!!
Answer:
Force = 2.4 10^(-17) N
Explanation:
Recall that if you have the field, the force is easily obtained by multiplying E times the charge:
F = E * q = 150 * 1.6 10^(-19) N = 240 * 10^(-19) N = 2.4 10^(-17) N
which agrees with answer C in your list of possible answers.
You have a transformer with 50 turns in the primary coil if you want to increase the voltage from 5V26V how many times should be in the secondary coil
Correct question:
You have a transformer with 50 turns in the primary coil if you want to increase the voltage from 5V to 6V how many turns should be in the secondary coil ?
Answer:
the number of turns in the secondary coil is 60 turns.
Explanation:
Given;
number of turns in the primary coil, P = 50 turns
primary voltage, Ep = 5V
secondary voltage, Es = 6V
The number of turns in the secondary coil is calculated as;
[tex]\frac{N_s}{N_p} = \frac{E_s}{E_p} \\\\\frac{N_s}{50} = \frac{6}{5} \\\\N_s = \frac{50\times 6}{5} \\\\N_s = 60 \ turns[/tex]
Therefore, the number of turns in the secondary coil is 60 turns.
How will the electrostatic force between two electric charges change if one charge is doubled and the second charge is tripled?
a. 1/6 times the original force
b. 6 times the original
c. 18 times the original
d. 1/36 of the original
Answer:
b. The force is 6 times the original
Explanation:
Coulomb's Law
The electrostatic force between two charged objects is directly proportional to the product of their charges and inversely proportional to the square of the distance between the two objects.
Written as a formula:
[tex]\displaystyle F=k\frac{q_1q_2}{d^2}[/tex]
Where:
[tex]k=9\cdot 10^9\ N.m^2/c^2[/tex]
q1, q2 = the objects' charge
d= The distance between the objects
Suppose one of the charges is doubled, i.e., q1=2q1 and the other charge is tripled (q2'=3q2). The new force F' would be:
[tex]\displaystyle F'=k\frac{(2q_1)(3q_2)}{d^2}[/tex]
Operating:
[tex]\displaystyle F'=k\frac{6q_1q_2}{d^2}[/tex]
[tex]\displaystyle F'=6\cdot k\frac{q_1q_2}{d^2}[/tex]
Substituting the original value of the force:
[tex]F'=6\cdot F[/tex]
b. The force is 6 times the original
The electrostatic force between two electric charges will change by 18 times the original force if one charge is doubled and the second charge is tripled. Option c. is correct .
Coulomb's law is a basic principle of electromagnetism that describes how the electric charge exerts force on other charges. The force between two charges is proportional to the product of the charges and inversely proportional to the square of the distance between them. When one charge is doubled and the other is tripled, the force between the two will be 18 times the original force. The electrostatic force between two electric charges is directly proportional to the product of the charges.
Therefore, when one charge is doubled and the second charge is tripled, the electrostatic force will be 18 times the original. Thus, the correct option is c. 18 times the original force.
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How many molecules are in 0.5 mol?
Answer:
1 mol of any compound (including of course CO2 and O2) contains 6.022*10^23 molecules
Therefore 0.5 mol of CO2 and O2 contains 3.01*10^23 molecules of each.
A 2160 kg car moving east at 10.4 m/s collides with a 3250 kg car moving east. The cars stick together and move east as a unit after the collision at a velocity of 5.16 m/s. a) What is the velocity of the 3250 kg car before the collision? Answer in units of m/s. 009 (part 2 of 2) 10.0 points b) What is the decrease in kinetic energy during the collision? Answer in units of J.
Answer:
Explanation:
10
How is mass related to potential energy?
Answer:
Potential energy is the stored energy of position possessed by an object. In the above equation, m represents the mass of the object, h represents the height of the object and g represents the gravitational field strength (9.8 N/kg on Earth) - sometimes referred to as the acceleration of gravity.
Explanation:
How much force is required to accelerate a 14 kg mass at a rate of 2.5
m/s2?
Answer:
The answer is 35.
Explanation:
We use the formula F=ma
A force, 10 N drags a mass 10 kg on a horizontal table with an acceleration of 0.2
m/s2. If the acceleration due to gravity is 10 m/s2, the coefficient of friction between
the moving mass and the table is?
Answer:
20&£+)##&843&()-_££-()&_2+0&&-£_!)
A satellite is in orbit 3.110106 m from the center of Earth. The mass of Earth is 5.98011024 kg Calculate the orbital
period of the satellite.
Answer:
9194.4278 seconds
Explanation:
Orbital period is given by :
T² = (4π²r³) /GM
G = Gravitational constant = 6.67 * 10^-11
M = 5.9801 * 10^24 kg
r = (3.110 * 10^6 m + 6378000 m) =3110000 + 6378000 = 9488000 m
T² = (4π² * 9488000^3) / (6.67* 10^-11 * 5.9801*10^24)
T² = 3.37197 * 10^22 / 398872670000000
T² = 84537504.161415
T = sqrt(84537504.161415)
T = 9194.4278 seconds
