According to Puddicombe, the result of not taking any time out to simply look after our brains is that:
We get stressed. It also makes us to miss out on the most important things in life.What was Puddicombe's submission?In his popular talk, Puddicombe explained that we have been caught up with the internet and other activities so much so that we do not have time to look out for our brains.
For this reason, we stress our brains and become distant from the most important things in life.
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A body at rest is given an initial uniform acceleration of 8m/s2 for 30s after which the acceleration is reduced to 5m/s2 for the next twenty seconds. The body maintains the speed attained for 60s, after which it is brought to rest in 20s.
Explanation:
v=u+at, where v,u,a and t are the final velocity, initial velocity, acceleration and time, respectively.
For t=0 s to t=30 s , a =8 m/s 2.
For t=30 s to t=50 s , a = 5 m/s 2.
For t=50 s to t=110 s , a = 0 m/s 2.
For t=110 s to t=130 s , a is such that the body comes to rest at the end of this period.
For t=0 s to t=30 s ,v=0+8t⇒v=8t m/s.
At t=30s,v=8×30=240 m/s.
For t=30 s to t=50 s ,v=240+5(t−30)⇒v=90+5t m/s
At t=50s,v=90+5×50=340 m/s.
For t=50 s to t=110 s ,v=340 m/s.
For t=110 s to t=130 s ,v=340+a(t−110).
The body comes to a halt at t=130 s ⇒0=340+a(130−110).
0=340+20a⇒a=−34020=−17 m/s2.
For t=110 s to t=130 s ,v=340−17(t−110)=2210−17t m/s.
1.) Identify one component of the visible spectra
2.) identify the component of the electromagnetic spectra that has the shortest wavelength
Answer:
1.) color
2.) Gamma Rays
Explanation:
Now, let's look at how the distance from the charge affects the magnitude of the electric field. Select Values on the menu, and then click and drag one of the yellow E-Field Sensors. You will see the magnitude of the electric field given in units of V/m (volts per meter, which is the same as newtons per coulomb). Place the E-Field Sensor 1 m away from the positive charge (1 m is two bold grid lines away if going in a horizontal or vertical direction), and look at the resulting field strength. Consider the locations to the right, left, above, and below the positive charge, all 1 m away. For these four locations, the magnitude of the electric field is________________. the same. greatest to the left of the charge. greatest below the charge. greatest to the right of the charge. greatest above the charge.
Electric field strength decreases as the distance from the source increases.
How the distance from the charge affects the magnitude of the electric field?The strength of an electric field is inversely related to square of the distance from the source. This means that the electric field strength decreases when the distance from the source increases.
So we can conclude that Electric field strength decreases as the distance from the source increases.
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what is the speed of a wave that has a frequency of 11.5Hz and a wavelength of 1.7m?
Answer:
19.55 m/s
Explanation:
Here is HOW to get the answer:
Speed = wavelength * freq
= 1.7 * 11.5 = 19.55 m / s
The force exerted on the tires of a car that directly accelerate it along a road is exerted by the
The force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.
What is force?Force is defined as the product of mass and acceleration of an object.
Friction is defined as the force that resists the movement of an object over another.
Therefore, the force exerted on the tires of a car that directly accelerate it along a road is exerted by the road friction.
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A particle moves along a straight line such that its acceleration is a=(4t^2-2)
The velocity of the particle moving along the straight line at any time, t is determined as v = 4t³/3 - 2t + C.
What is the velocity of the particle?
The velocity of an object is the rate of change of displacement with time. It is also the integral of acceleration of the object.
a = 4t² - 2
v = ∫a
v = 4t³/3 - 2t + C
Thus, the velocity of the particle moving along the straight line at any time, t is determined as v = 4t³/3 - 2t + C.
Complete question:
A particle moves along a straight line such that its acceleration is a=(4t^2-2). Find its velocity at any time, t.
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The chart lists four different kinds of atoms.
A chart titled Different Kinds of Atoms with the entries calcium, gold, argon, iodine.
What is true about all of these atoms?
They cannot be solids.
They are the largest units of matter.
They are the only types of atoms that exist.
They cannot be divided and still keep the properties of the element.
They cannot be divided and still keep the properties of the element true about all of these atoms. Option D is corect.
What is an atom?The atom consists of matter that may be split without releasing electrical charges.
It's also the smallest unit of matter with chemical element features. As a result, the atom is the fundamental unit of science.
In the nucleus proton and the neutron is exists. The condition of the atom to be electrically neutral is that the number of the proton and electron should be the same.
They cannot be separated while still maintaining the element's characteristics for each and every one of these atoms.
Hence, option D is corect.
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Answer:
The correct answer is d, they cannot be divided and still keep the properties of the element.
Explanation:
You're welcome :)
im
Complete the sentence to describe what a wave is and what it does.
E§
A wave is a
that carries
from one place to another.
Hope this helps.
Good luck ✅.
Question 4 of 25
Which two chemical equations are balanced?
A. Na+ MgCl₂ → NaCl + Mg
B. 2LIOH + H₂S → Li₂S + 2H₂O
C. AgNO3 + NaCl → NaNO3 + AgCl
-
D. 3PBr3 + 2Cl2 → 3PCl3 + 2Br2
Answer:
To check whether a chemical equation is balanced or not we usually look if elements on the product side are numerically equal to the reactant side or not.
A. Na + MgCl₂ → NaCl + Mg
Reactant Product
Na = 1 1
Mg = 1 1
Cl = 2 1
Unbalanced
B. 2LiOH + H₂S → Li₂S + 2H₂O
Reactant Product
Li = 2 2
S = 1 1
O = 2 2
H = 4 4
Balanced
C. AgNO₃ + NaCl → NaNO₃ + AgCl
Reactant Product
Ag = 1 1
N = 1 1
Na = 1 1
Cl = 1 1
O = 3 3
Balanced
D. 3PBr₃ + 2Cl₂ → 3PCl₃ + 2Br₂
Reactant Product
P = 3 3
Br = 9 4
Cl = 4 9
Unbalanced
Therefore, equations B and C are balanced chemical equations.
help in solving this question please
(question is on the picture )
Answer:
Jesus
Explanation:
he is the way
durning which type of process does pressure remain consistent
A.Isothermal
B.isolated
C.Adiabatic
D.Isobaric
Answer:
[tex]\fbox {D. Isobaric}[/tex]
Explanation:
The process during which pressure remains constant is called an isobaric process.
1) Two students are making their way to school. One has a bike and the other
is on foot. If the student on foot is going at a speed of 3 m/s and they make
it to school in 30 s, how far away was the school?
To find how far away the school is:
3m/s * 30 s = 90m
Hope it helps!
Avery sees a UFO out her bedroom window and calls to report it to the police. She says, "The UFO moved 20.0 m east, 10.0 m north, and 30.0 m west before it disappeared." What was the displacement of the UFO while Avery was watching?
Answer:
10^2 + 10^2 = x^2
x = 14.2 m NW
How to add two on/off switches that can change the brightness of the light in circuit a without turning it off
Answer:
ressistor
Explanation:
The Voyager spacecraft is moving at 17 000 m/s. How far will it travel in one year? Give your answer in km.
Explanation:
first change m/s to km/hr and time 1 year to hour b/c we are asked the to give in km. so,
v=17,000 m/s = 17000×3600/1000 = 61,200 km/hr
t= 1 year= 365 days =365day×24 hr/day = 8,760hr
therefore, V = s/t from this s = v×t =61200×8760 =536,112,000 Km
The reason galaxies that are distant from our galaxy move away from our galaxy more rapidly than those that are near is:
The reason galaxies that are distant from our galaxy move away from our galaxy more rapidly is more space expands between us and distant galaxies.
What is a galaxy?A galaxy is a group of millions of stars and their systems that are grouped due to gravitational forces.
According to the Big Bang theory, galaxies are expanding and separate among them.
In conclusion, the reason galaxies that are distant from our galaxy move away from our galaxy more rapidly is more space expands between us and distant galaxies.
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Answer:
the galaxies are moving as the universe keep expanding .
Explanation:
If your mass is 63.7 kg, and you are standing 7.5 m away from a boulder with
a mass of 9,750.6 kg, what is the gravitational force between you and the
boulder? Newton's law of gravitation is F
Gm m₂. The gravitational
=
gravity
constant G is 6.67 x 10-11 N-m²/kg².
A. 1.10 x 104 N
B. 7.37 x 10-7 N
C. 9.82 x 10-8 N
D. 5.52 x 10-6 N
Please help me!
Answer:
B
Explanation:
F=[tex]\frac{Gm1m2}{r^2}[/tex]
F=(6.67 x 10^-11)[tex]\frac{63.7X9,750.6}{7.5^2}[/tex]
F=7.36502254e-7
a note of frequency 200Hz has a velocity of 400m/s. what is the wavelength of the note
Answer:
[tex]\huge\boxed{\sf \lambda = 2 m}[/tex]
Explanation:
Given data:Frequency = f = 200 Hz
Velocity = v = 400 m/s
Required:Wavelength = λ = ?
Formula:v = fλ
Solution:Put the givens in the formula
400 = (200)λ
Divide 200 to both sides
400/200 = λ
2 m = λ
λ = 2 m
[tex]\rule[225]{225}{2}[/tex]
What are the characteristics of the image formed by the object?
Answer:
The image is formed by a convex lens with the object at 2F.
Image will be of same size as the objectImage will be real and upside down.Sample Response: The image created by the object is located on 2F behind the lens, real, inverted, and the same size as the actual object.
Explanation: EDGE.
a protostar will continue to collapse due to gravity until it reaches the main sequence, and then gravitational collapse will stop when _____ begins.
a protostar will continue to collapse due to gravity until it reaches the main sequence, and then gravitational collapse will stop when fusion of hydrogen begins.
What is a protostar and how does gravity affect it?A protostar serves as a very young star which is very small in mass and still developing its mass from parent molecular cloud.
However, it can be affected by gravity because , when there is not collapse on the gravity, if there is fusion of hydrogen begins in it.
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Discuss the path that light takes through the human eye
The cornea is shaped like a dome and bends light to help the eye focus. Some of this light enters the eye through an opening called the pupil (PYOO-pul). The iris (the colored part of the eye) controls how much light the pupil lets in. Next, light passes through the lens (a clear inner part of the eye).
Two 2.0-mm diameter beads, c and d, are 12mm mm apart, measured between their centers. bead c has mass 1.0 g and charge 2.5nc nc . bead d has mass 1.7g g and charge -1.0 nc. if the beads are released from rest.
a. what is the speed vc at the instant the beads collide?
b. what is the speed vd at the instant the beads collide?
The speed of Vc at the instant bead collide is 1.38 m/s and the instant speed of Vd at the instant bead collide is 0.106 m/s.
The force of attraction on the beads are due to both gravitational force and electrostatic force
As gravitational force is very weak force as compared to electrostatic force the net force will be due to electrostatic force only.
Net Force = Electrostatic force
Net Force = K q1 q2 / r²
Net Force = (9 × 10⁹) (2.5 × 10⁻⁹) (1 × 10⁻⁹) / (14 × 10⁻³) (as distance between there centre of mass is 14 mm)
Net Force = (9 × 2.5 × 10⁻⁶) / 14
Net Force = 1.6 × 10⁻⁶
For bead c
Force = Mc × Ac = 1.6 × 10⁻⁶
(1 × 10⁻³) × Ac = 1.6 × 10⁻⁶
Ac = 1.6 × 10⁻³
Acceleration of bead C is 1.6 × 10⁻³ m/s²
For bead d
Force = Md × Ad = 1.6 × 10⁻⁶
(1.7 × 10⁻³) × Ad = 1.6 × 10⁻⁶
Ad = 0.94 × 10⁻³
Acceleration of bead D is 0.94 × 10⁻³ m/s²
Let us suppose bead C travels y distance before collision
So bead D should travel 12-y distance before collision
So speed of both the beads before the collision can be find out by using newton third law of motion
For bead C
Vc² - Uc² = 2 Ac s
Vc² = 2 × 1.6 × 10⁻³ × y
Vc² = 3.2 × 10⁻³ × y
Vc = √(3.2 × 10⁻³ × y)
For bead D
Vd² - Ud² = 2 Ad s
Vd² = 2 × 0.94 × 10⁻³ × (12-y)
Vd² = 1.88 × 10⁻³ × (12-y)
Vd = √(1.88 × 10⁻³ × (12-y))
Applying energy conservation
initial = final
0 + 0 = (1/2)McVc² - (1/2)MdVd²
(1/2)McVc² = (1/2)MdVd²
McVc² = MdVd²
1 × 10⁻³ × 3.2 × 10⁻³ × y = 1.7 × 10⁻³ × 1.88 × 10⁻³ × (12-y)
3.2 × y = 3.2 × (12-y)
y = 12-y
2y = 12
y = 6
Putting the value of y in Vc and Vd
Vc = √(3.2 × 10⁻³ × y)
Vc = √(3.2 × 10⁻³ × 6)
Vc = √(19.2 × 10⁻³)
Vc = √0.0192
Vc = 1.38 m/s (approximately)
Vd = √(1.88 × 10⁻³ × (12-y))
Vd = √(1.88 × 10⁻³ × (12-6))
Vd = √(1.88 × 10⁻³ × 6)
Vd = √(11.28 × 10⁻³)
Vd = √0.01128
Vd = 0.106 m/s (approximately)
So the speed of Vc at the instant beads collide will be approximately 1.38 m/s and Vd at the instant speed the beads collide will be approximately 0.106 m/s.
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The quotient of 8.4x10° and a number n results in 5.6x 1027. What is the value of n?
1.5x10-18
O 1.5x10
O 1.5x10³
1.5x10¹8
Q1.
(a) Some students have designed and built an electric-powered go-kart. After testing, the
students decided to make changes to the design of their go-kart.
First design X
Final design Y
The go-kart always had the same mass and used the same motor.
The change in shape from the first design (X) to the final design (Y) will affect the top
speed of the go-kart.
Explain why.
Answer:Because if the shape gets changed it will move faster without to much weight
Explanation:
as time passes the sound wave
Answer:
Loud to soft while pitch increases
Explanation:
Sound waves shown graphically display their amplitude (height of the graph) and their wavelength (the horizontal distance from peak to peak, or valley to valley... one full cycle).
Instead of wavelength, alternatively, one can observe the frequency of the wave (how many cycles are completed for a given unit of horizontal distance) which is in an inverse relationship with the wavelength (as a wavelength gets shorter, the frequency gets higher, and as the wavelength gets longer, the frequency gets lower).
The amplitude of a wave corresponds to how loud the sound is.
The frequency of a wave corresponds to the pitch of the sound.
Notice that on the graph, the height of the graph decreases over time (the peaks get shorter and shorter). So, the sound volume will get quieter and quieter. Using terminology that matches the answer choices, the sound will start loud and get soft.
Notice that on the graph, the wavelength decreases over time (starts with a pretty long distance between peaks, and then the distance between peaks gets shorter and shorter). Alternatively, looking at frequency, notice that the frequency gets higher and higher (on the left, one finger-width doesn't is less than one full cycle, but on the right, the same finger-width is wider than multiple cycles). So, the pitch of the sound will get higher and higher.
Thus, for this graph, the sound goes from loud to soft, and the pitch increases.
where do automatically generated statements that set the properties of the labels, buttons, and forms end up?
The generated statements that set the properties of the labels, buttons, and forms end up automatically within the InitializeComponent() method.
What is InitializeComponent?The InitializeComponent method in programming is the that have code that works with codes that creates and initializes the creates and initializes the user interface objects .
Conclusively, when a statement is generated, to when set the properties of the labels , it will definitely been felt in the InitializeComponent() method automatically.
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please answer this fast
I 'll marks them brainliest answer
answer
64 is C (c) 1-Bromo-3-methylbutane
63 is D
i is secondary ii is primary
what type of modulation does the omni-directional antenna transmit?
AM and FM are the two types of modulation that an omnidirectional antenna transmit.
What is an omnidirectional antenna?An omnidirectional antenna is also referred to as an isotropic antenna and it can be defined as a type of antenna that is designed and developed to radiate equal radio power or intercept radio-frequency (RF), especially in all directions perpendicular to an axis.
In Science, there are two types of modulation that an omnidirectional antenna transmit and this include the following:
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does anyone know this whole distance and displacement concept it makes zero sense
Answer:
Distance is the total length travelled, or in other words, it is a measure of how far apart two objects are.
Displacement, on the other hand, the difference between the starting and and ending positions of an object.
For example, if a person walks 10m forwards, then 7m backwards, thereby ending up where he started, he will have travelled a distance of
10 + 7 = 17m .
But the difference between his starting and finishing positions is
10 - 7 = 3m.
If, however, the man walked 10m forwards and then 10m backwards, the distance he covered would be 10 + 10 = 20m, but the displacement would've been 0 as there would be no difference between his starting and ending positions.
Let me know if you still don't understand.
The ball is in contact with the bat for 0.001s use the equation in the box to caluclate the force exerted by the bat on the ball
Answer:
Force = 9600N
Explanation:
If this is the right question, there should have been a question before about the what the change in the momentum of the ball was. The answer to that was 9.6kg m/s. For this part, we divide this by the time taken which was 0.001s which give us the resultant force.
resultant force = change in momentum ÷ time
= 9.6kgm/s ÷ 0.001s
= 9600N
