Answer:
liquid
Explanation:
due to high temperatures in the magma chamber all solids liquidify on reaching the surface with colder temperatures it now solidify to form igneous rock
The vertical component of 9N is found to be four-thirds of the horizontal component.
a) Find the horizontal component.
b)Find the magnitude of the vector
Answer:
a) Let horizontal component be h
4/3×h= 9
4h = 9x3
h = 27/4
b) Magnitude = √ [9²+ (27/4)²
= 11.25
51. A balloon starts rising from the ground, vertically upwards, uniformly at the rate of 1 m s-1. At the end of 4 seconds, a body is released from the balloon. Calculate the time taken by the released body to reach the ground. 51. A balloon starts rising from the ground , vertically upwards , uniformly at the rate of 1 m s - 1 . At the end of 4 seconds , a body is released from the balloon . Calculate the time taken by the released body to reach the ground
Answer:
4s
Explanation:
when a bOdy rises into the air,the time it takes to reach a particular height is the same as the time it will take the body to fall from that height to the ground.
the 12-lead ecg shows st-segment elevation in leads v2 and v3 of ≥ 0.2 mv. what is this finding indicative of?
The 12-lead ECG test that shows st-segment elevation in leads v2 and v3 of ≥ 0.2 mv, could be a diagnostic for myocardial infarction.
What is 12 - lead ECG test?
A 12-lead electrocardiogram (ECG) is a medical test that is recorded using leads, or nodes, attached to the body.
Electrocardiograms, sometimes referred to as ECGs, capture the electrical activity of the heart and transfer it to graphed paper.
When a 12-lead ECG shows st-segment elevation in leads v2 and v3 of ≥ 0.2 mv, it could be a diagnostic for myocardial infarction.
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A ball is shot from the ground straight up into the air with initial velocity of 40 ft/sec. Assuming that the air resistance can be ignored, how high does it go
The height to which the ball attained, given the data is 7.58 m
Data obtained from the questionInitial velocity (u) = 40 ft/s = 40 × 0.3048 = 12.192 m/sFinal velocity (v) = 0 m/s (at maximum height) Acceleration due to gravity (g) = 9.8 m/s²Maximum height (h) =? How to determine the maximum heightv² = u² – 2gh (since the ball is going against gravity)
0² = 12.192² – (2 × 9.8 × h)
0 = 12.192² – 19.6h
Collect like terms
0 – 12.192² = –19.6h
–12.192² = –19.6h
Divide both side by –19.6
h = –12.192² / –19.6
h = 7.58 m
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Use the image to determine the volume of the rock.
Answer:
12 ml
Explanation:
The initial volume in the cylinder is 20 ml
adding the rock adds volume to the cylinder
the new volume is 32 ml .....the increase in volume is the volume of the rock : 32 - 20 = 12 ml volume of rock
Which of the following differentiates an audiologist from an anthropologist?
An audiologist uses empirical evidence to determine treatment.
An audiologist uses empirical evidence to determine treatment.
An audiologist examines physical characteristics of humans.
An audiologist evaluates communication methods.
An audiologist analyzes observed behaviors.
The statement that differentiates an audiologist from an anthropologist is that an audiologist examines physical characteristics of humans. That is option C.
Who is an audiologist?Audiologist is an individual that specializes in the diagnosis, treatment and management of hearing loss and balance disorders in adults and children.
An anthropologist is also an individual that studied the past and present experiences of individuals.
Therefore, the statement that differentiates an audiologist from an anthropologist is that an audiologist examines physical characteristics of humans.
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Particles q1, 92, and q3 are in a straight line.
Particles q1 = -5.00 x 10-6 C,q2 = -5.00 x 10-6 C,
and q3 = -5.00 x 10-6 C. Particles q₁ and q2 are
separated by 0.500 m. Particles q2 and q3 are
separated by 0.500 m. What is net force on 93?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-5.00 x 10-6 C
91
0.500 m-
-5.00 x 10-6 C
92
-5.00 x 10-6 C
93
0.500 m-
The answer to the question is 1.125 Newton
Formula for electrostatic force is F = ( K q1 q2 )/ r²
where q1 and q2 represent the charges and r represents the distance between them and the value of K is 9 × 10⁹.
Total net force on q3 will be the summation of electrostatic force between q1 and q3 and electrostatic force between q2 and q3, as all the three charges are of same sign and lie in the same line.
Electrostatic force between q1 and q3
r will be 0.500 + 0.500 = 1 m
F = ( K q1 q3 )/ r²
F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 1²
F₁₃ = 2.25 × 10⁻¹ N
Electrostatic force between q2 and q3
r will be 0.500 m
F = ( K q1 q3 )/ r²
F = ( (9 × 10⁹ ) x (5.00 x 10⁻⁶) x (5.00 x 10⁻⁶) )/ 0.5²
F = (225 × 10⁻³) / (25 × 10⁻²)
F₂₃ = 9 × 10⁻¹ N
Total force on q3 will be F₁₃ + F₂₃
Total force on q3 = ( 2.25 × 10⁻¹ ) + (9 × 10⁻¹ ) N
Total force on q3 = ( 2.25 × 10⁻¹ ) + (9 × 10⁻¹ ) N
Total force on q3 = ( 11.25 × 10⁻¹ ) N
Total force on q3 = 1.125 N
Thus after solving we got the net force on q3 as 1.125 Newton
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what evidence did astronomers use to prove jets travel in opposite directions?
The evidence that astronomers use to prove jets travel in opposite direction is Spectral lines from a very fast moving ionized gases.
Who are the astronomers?Astronomer is a person who study astronomy which is a scientific study that has to do with space, space bodies, comets, planets, stars and so on.
Therefore, The evidence that astronomers use to prove jets travel in opposite direction is Spectral lines from a very fast moving ionized gases.
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What are two models of light? how does each model explain part of the behavior of light?
The two most successful theories of light were the corpuscular (or particle) theory of Sir Isaac Newton and the wave theory of Christian Huygens. Newton's corpuscular theory stated that light consisted of particles that travelled in straight lines.
hope it helps
2) A skier stands at rest and begins to ski downhill with an acceleration of 3.0 m/s² {downhill). What is
her displacement after 15.0 seconds?
Answer:
337.5m
Explanation:
Kinematics
Under constant acceleration, the kinematic equation holds:
[tex]s=\frac{1}{2}at^2+v_ot+s_o[/tex], where "s" is the position at time "t", "a" is the constant acceleration, "[tex]v_o[/tex]" is the initial velocity, and [tex]s_o[/tex] is the initial position.
Defining Displacement
Displacement is the difference in positions: [tex]s-s_o[/tex] or [tex]\Delta s[/tex]
[tex]s=\frac{1}{2}at^2+v_ot+s_o[/tex]
[tex]s-s_o=\frac{1}{2}at^2+v_ot[/tex]
[tex]\Delta s=\frac{1}{2}at^2+v_ot[/tex]
Using known information
Given that the initial velocity is zero ("skier stands at rest"), and zero times anything is zero, and zero plus anything remains unchanged, the equation simplifies further to the following:
[tex]\Delta s=\frac{1}{2}at^2+v_ot[/tex]
[tex]\Delta s=\frac{1}{2}at^2+(0)*t[/tex]
[tex]\Delta s=\frac{1}{2}at^2+0[/tex]
[tex]\Delta s=\frac{1}{2}at^2[/tex]
So, to find the displacement after 15 seconds, with a constant acceleration of 3.0 m/s², substitute the known values, and simplify:
[tex]\Delta s=\frac{1}{2}at^2[/tex]
[tex]\Delta s=\frac{1}{2}(3.0[\frac{m}{s^2}])(15.0[s])^2[/tex]
[tex]\Delta s=337.5[m][/tex]
