The foci of the hyperbola represented by (0, –6) and (0, 6). Then the correct option is B.
What is a hyperbola?The hyperbola is the locus of a point such that the difference of distance from point P to two non-movable points. These two points are called foci of hyperbola.
The equation of the parabola is given below.
5y² – 4x² – 80 = 0
Then the equation can be written as
y² / 4 – x² / 5 – 4 = 0
y² / 16 – x² / 20 = 1
Then the value of eccentricity will be
a² = 16 and b² = 20
Then we have
e = √[1 + (b² / a²)]
e = √[1 + (20 / 16)]
e = 1.5
Then the focus of the parabola will be
⇒ (0, ±ae)
⇒ (0, ± 4 x 1.5)
⇒ (0, ±6)
⇒ (0, –6) and (0, 6)
Then the correct option is B.
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A snack bar offers chili and/or cheese on its hot dogs for an additional fee.
The owner kept track of the hot dog orders over the course of a week. His
data are shown in a relative frequency table.
Answer:
the answer is c. the row is chili, the column is no cheese
Find the principal needed now (the present value) in order to get $10,000 after 15 years, compounded
semiannually at a rate of 5%.
Answer:
10000×(1+5%)^(15×2)=43219.4238
Choose the letter of the equation for
the graph.
The graphed trigonometric function is the one in option a.
Which is the equation of the graph?The key parts that we can see on the graph are:
The midline is y = 1.From this we know that the correct option is either a or b.
at x = 0, f(x) = 0.Now we can evaluate options a and b in x = 0 and see which one is equal to zero.
for a:
y = sin(0 - pi/2) + 1 = sin(-pi/2) + 1 = -1 + 1 = 0
for b:
y = cos(0 + pi/2) + 1 = 0 + 1 = 1
Then we can see that option a is the correct option.
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How much will 1,000.00 amount to in 2 years at 13%2% simple interest
In a recent year, 17.7% of all registered doctors were female. If there were 54,400 female registered doctors that year, what was the total number of registered doctors?
Answer:
The total number of registered doctors in this year are 307345.
Step-by-step explanation:
Let the total number of doctors who registered in this year are x
Given that the total number of female doctors in total registered doctors are 54400
According to the question 17.7 percent of the total registered doctors are the female doctors
Hence the total number of registered doctors who are females are 17.7% of x
which is written as 17.7*x÷100
According to the question 17.7x÷100= 54400
as we are given that the total number of female doctors are 54400
now
17.7x = 54400×100
x= 54400×100÷17.7
x= 307344.633 ≈ 307345
Therefore there are 307345 doctors who registered that year.
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Another day, another math problem 3
If f(x)=x²+2 and g(x)=x²+5 then the domain of the (fog) (x) is (-∞,∞).
Given the f(x)=x²+2 and g(x)=x²+5
We have to find the domain of the (fog) (x)
The domain of a function is the set of all possible inputs for the function. For example, the domain of f(x)=x² is all real numbers, and the domain of g(x)=1/x is all real numbers except for x=0.
then,(fog) (x)= (x²+5)²+ 2
=x⁴+25+10x²+2
= x⁴+27+10x²
Now on any real value of x the value of (fog) (x) exists therefore (fog) (x) can take all the values of the real number.
So domain (fog) (x)= (-∞,∞).
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(correct answers only)
A sailfish is swimming after a herring in a straight line at 11.8 m/s and begins to accelerate at 6.39 m/s². How long does it take for the sailfish to reach the herring if it is 55.0 m away?
(unit=s)
According to second equation of kinematics
s=ut+1/2at²55=11.8t+1/2(6.39)t²110=23.6t+6.39t²6.39t²+23.6t-110=0Take positive value
t=2.7sAnswer:
2.7 s (1 d.p.)
Step-by-step explanation:
Use the Constant Acceleration Equations where:
s = displacement in metersu = initial speed in m/sv = final speed in m/sa = acceleration in m/s²t = time in s (seconds)Given:
s = 55 mu = 11.8 m/sa = 6.39 m/s²[tex]\begin{aligned}\text{Using }s & =ut+\dfrac{1}{2}at^2\\\implies 55 & =11.8t+\dfrac{1}{2}(6.39)t^2\end{aligned}[/tex]
Rearrange the equation to equal zero:
[tex]\implies 3.195t^2+11.8t-55=0[/tex]
Quadratic Formula
[tex]x=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}\quad\textsf{when }\:ax^2+bx+c=0[/tex]
Use the quadratic equation to solve for t:
[tex]\implies a=3.195, \quad b=11.8, \quad c=-55[/tex]
[tex]\implies t=\dfrac{-11.8 \pm \sqrt{11.8^2-4(3.195)(-55)} }{2(3.195)}[/tex]
[tex]\implies t=2.694780675, -6.388051411[/tex]
As time is positive:
[tex]\implies t=2.694780675... \:\text{s}[/tex]
[tex]\implies t=2.7 \: \text{s (1 d.p.)}[/tex]
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How does understanding of 5 x 12 = 60 help to solve for the product of 5
x 120? Explain in words
Answer:
c6
Step-by-step explanation:
justjustcancacanjustadda0totheproduct of5cxwewtogetthesameresultasx1totoandtimes
3) Number: 640,700
the value of 4 in this number is 40,000
Number: 64,070
the value of 4 in this number is 4,000
So, times greater: 40,000 ÷ 4,000 = 10 times greater.
4)
The multiplication, 5 × 12 = 60. So, 5 × 120 = 600.
There is an extra zero at the very last of the result as '120' was multiplied with 5 instead of '12' which does not have zero at last which changes the result.
Similar cases with: 5 × 10 = 50. So, 5 × 100 = 500.
(a) Solve the following formula for b.
1
A = Zab
6
(b) Evaluate b when A= 18 and a = 5
1
(a) The formula A = ab solved for b is b =
6
(b) Evaluate b when A= 18 and a =
5
b = (Type an integer or a simplified fraction.)
Answer:
J Trump has to be a great day of school and I have a great
Step-by-step explanation:
you thank you thank you thank you thank you thank you thank you thank you thank you thank you thank you for your loss of school and I have a great day of school ii
NEED HELP ASAP !!
Which equations are equivalent to 2 + 2 12-x1=1? Check all that apply.
Answer:
[tex]\frac{2}{3}|2-x|=\frac{1}{15}[/tex]
Step-by-step explanation:
[tex]\frac{1}{5} + \frac{2}{3} |2-x| = \frac{4}{15} \\\\\frac{1}{5}*(\frac{3}{3}) = \frac{3}{15}\\\\\frac{3}{15}-\frac{3}{15} + \frac{2}{3}|2-x| =\frac{4}{15}-\frac{3}{15}\\\\\frac{2}{3}|2-x|=\frac{1}{15}[/tex]
On January 1, 2021, Princess Corporation leased equipment to King Company. The lease term is 12 years. The first payment of $716,000 was made on January 1, 2021. The equipment cost Princess Corporation $5,188,466. The present value of the lease payments is $5,588,516. The lease is appropriately classified as a sales-type lease. Assuming the interest rate for this lease is 9%, how much interest revenue will Princess record in 2022 on this lease? (Round your answer to the nearest whole dollar amount.)
The amount of the interest revenue that Princess will record in 2022 on this lease is:$413,553.82.
Interest revenue
First step
Lease value payments after first payment:
Lease value payments= $5,588,516- $716,000
Lease value payments= $4,872,516
Second step
Lease value payments after second payment:
Lease value payments=$4,872,516+ ($4,872,516×9%) - $716,000
Lease value payments=$4,872,516+$438,526.44-$716,000
Lease value payments=$4,595,042.44
Third step
2022 Interest revenue=$4,643,787.6×9%
2022 Interest revenue=$413,553.8196
2022 Interest revenue=$413,553.82 (Approximately)
Therefore the amount of the interest revenue that Princess will record in 2022 on this lease is:$413,553.82.
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Evaluate the expression. 7^14/7^15 Evaluate the expression . 714 715
Answer:
1/7
Step-by-step explanation:
Alternative Form: 0.142857, 7^-1
A woman bought some large frames for $10 each and some small frames for $4 each at a closeout sale. If she bought 22 frames for $106, find how many of each type she bought.
Answer:
19 small frames and 3 large frames
Step-by-step explanation:
follows the steps in the attached
The repeating decimal z=0.142857142857142857 as fraction
Answer:
[tex] \frac{1}{7} [/tex]
Which of these could be the graph of F(x) = log₂ x?
A
A. Graph A
B. Graph B
C. Graph C
D. Graph D
The graph of the function is shown in the attached image.
Use the grouping method to factor this polynomial completely.
4x³ + 8x²+3x+6
O A. (4x2 + 2)(x+3)
OB. (4x2+2)(x+2)
O C. (4x²+3)(x+3)
D. (4x² + 3)(x + 2)
Answer:
D. [tex](4x^2 + 3)(x + 2)[/tex]
Step-by-step explanation:
Hello!
We can group the first two terms and the last two terms and factor each group.
Factor by Grouping[tex]4x^3 + 8x^2 + 3x + 6[/tex][tex](4x^3 + 8x^2) + (3x + 6)[/tex][tex]4x^2(x + 2) + 3(x + 2)[/tex]Now we can combine the like factors:
[tex](4x^2 + 3)(x + 2)[/tex]The answer is Option D.
Given 2 (x+3) - 4x = x
Prove = 2
Complete the proof. Provide reasons for 1-6 below.
step-by-step explanation:
#1: simplify both sides of the equation.
2(x+3)−4x=x
(2)(x)+(2)(3)+−4x=x
2x+6+−4x=x
(2x+−4x)+(6)=x
−2x+6=x
−2x+6=x
***
#2: subtract x from both sides.
−2x+6−x=x−x
−3x+6=0
***
#3: subtract 6 from both sides.
−3x+6−6=0−6
−3x=−6
***
step 4: divide both sides by -3.
−3x/-3 = -6/-3
solution x = 2
a) Write VW as a column vector.
b) Write WV as a column vector.
c) Write a sentence to explain what you notice about
your answers.
W
V
Answer:
vector VW= w - v
vector WV= v - w
Step-by-step explanation:
there are no figures to solve the question so i'll just write the formula..
vector VW= w - v
vector WV= v - w
How to find x and y
he value of x and y from the given figure are 49/5 and 49/15
Similarity theorem of trianglesFrom the given similar triangles, the following expression is true
21/30 = 7/15 = k
Also, x/21 = y/7 = 7/15
Equate
x/21 = 7/15
15x = 7 * 21
5x = 7 * 7
x = 49/5
Similarly
y/7 = 7/15
15y = 49
y = 49/15
Hence the value of x and y from the given figure are 49/5 and 49/15
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Which expression is equivalent to 2x² - x + ?
O A
O
B
C
D
²(x - 2)²
2
IN
2 X-
16
Answer: [tex]2\left(x-\frac{1}{4} \right)^{2}[/tex]
Step-by-step explanation:
[tex]2x^{2}-x+\frac{1}{8}\\\\=2\left(x^{2}-\frac{1}{2}x \right)+\frac{1}{8}\\\\=2\left(\left(x-\frac{1}{4} \right)^{2}-\frac{1}{16} \right)+\frac{1}{8}\\\\=2\left(x-\frac{1}{4} \right)^{2}-\frac{1}{8}+\frac{1}{8}\\\\=\boxed{2\left(x-\frac{1}{4} \right)^{2}}[/tex]
Jakub wants to build a new shed.
The area of the shed is 37 m².
The width of the shed is 5 m.
What is the length of the shed?
3
Answer:
74 mStep-by-step explanation:
Jakub wants to build a new shed.
The area of the shed is 37 m².
The width of the shed is 5 m.
What is the length of the shed?
to find the side, having the area, you need to use the inverse formula Area = W * L
so
L = A: W
L = 37 : 5 = 7.4 m
If the area of the shed is 37 m²,width of the shed is 5 m as a result the length of the shed will be 7.4 m.
What is a rectangle?It is defined as two-dimensional geometry in which the angle between the adjacent sides is 90 degrees. It is a type of quadrilateral. The area occupied by the rectangle in two-dimensional planner geometry.
The area of a rectangle can be calculated using the following formula:
Rectangle area = length x width
It is given that, the area of the shed is 37 m². The width of the shed is 5 m.
Since the shed is rectangular. The length of width is found as,
Area = length × width
A = l × w
l=A/w
l=37/5
l=7.4 m
Thus, if the area of the shed is 37 m², the width of the shed is 5 m as a result the length of the shed will be 7.4 m.
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Find the domain and range of the function graphed below. Write your answers in interval notation.
Answer:
Domain: [tex](-\infty, \infty)[/tex]Range: [tex](-\infty, -1][/tex]Step-by-step explanation:
The domain is the set of x-values and the range is the set of y-values.
Pls ,see the attachment
Huilan is years 15 younger than Thomas. The sum of their ages is 73 . What is Thomas's age?
thomas age:44
huilan age: 29
Step-by-step explanation:
h = t + 15
t + t + 15 = 73
2t = 73 - 15
2t = 58
t = 29
Which of the following is the balance for a single $2.520 deposit in an account with an APR of 1.16% that compounds interest monthly and is invested for 37 years? Which of the following is the balance for a single $ 2.520 deposit in an account with an APR of 1.16 % that compounds interest monthly and is invested for 37 years ?
Answer:
The balance after 37 years is $3869.99
Step-by-step explanation:
Given:
Principal (P) = $2,520Rate of Interest (R) = 1.16%Time (t) = 37 yearsCompounds Interest Monthly (n) = 12The Amount (A),
A = P (1 + [tex]\frac{R}{100n}[/tex][tex])^{nt}[/tex] if compound n times per year
Amount (A) at 37 years,
A = ($2,520) (1 + [tex]\frac{1.16}{100(12)}[/tex][tex])^{12 x 37}[/tex]
A = ($2,520) (1 + [tex]\frac{1.16}{1,200}[/tex][tex])^{444}[/tex]
A = ($2,520) (1.00096667 [tex])^{444}[/tex]
A = ($2,520) (1.5357)
A = $3869.9944
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A photographer needs a frame for a 16 x 20 inch picture, such that the total area is 340 in^2. Calculate the width of the frame. Which of the following quadratic equations would be used when solving this?
2x^2 + 36x = 20
2x^2 + 72 = 20
4x^2 + 36x = 20
4x^2 + 72x = 20
The graph of the function f(x) is shown below.
-a
If a = 9, then find the value of
3a
f(x) d
-a
f(x) dx =
a
3a
fr f(x) dx.
-a
ROUND YOUR FINAL ANSWER TO 4 DECIMAL PLACES.
2a
3a
The integral of [tex]f(x)[/tex] over the interval [tex][-a,a][/tex] corresponds to the area of a semicircle of radius [tex]a[/tex], so
[tex]\displaystyle \int_{-a}^a f(x) \, dx = \frac{\pi a^2}2[/tex]
The integral over [tex][a,3a][/tex] corresponds to the negative area of a trapezoid with height [tex]a[/tex] and base lengths [tex]2a[/tex] and [tex]a[/tex], so
[tex]\displaystyle \int_a^{3a} f(x) \, dx = -\frac{a(2a+a)}2 = -\frac{3a^2}2[/tex]
Then combining the integrals, we have
[tex]\displaystyle \int_{-a}^{3a} f(x) \, dx = \frac{\pi a^2}2 + \left(-\frac{3a^2}2\right) = \frac{(\pi-3)a^2}2[/tex]
When [tex]a=9[/tex], the integral evaluates to
[tex]\displaystyle \int_{-9}^{27} f(x) \, dx = \frac{(\pi-3)\times81}2 \approx \boxed{5.7345}[/tex][/tex]
How do I solve this problem?
Answer:
y≤x²+4x-1.
Step-by-step explanation:
1) to define the equation of the given graph; it is y=x²+4x-1 (its vertex is (-2;-5));
2) to define inequation accorging to the given graph (the area outside of the parabola means ≤).
1) Suppose the heights of 18-year-old men are approximately normally distributed, with mean 71 inches and standard deviation 5 inches.
a)
What is the probability that an 18-year-old man selected at random is between 70 and 72 inches tall? (Round your answer to four decimal places.)
b)
If a random sample of twenty-six 18-year-old men is selected, what is the probability that the mean height x is between 70 and 72 inches? (Round your answer to four decimal places.)
c)
Compare your answers to parts (a) and (b). Is the probability in part (b) much higher? Why would you expect this?
!) The probability in part (b) is much higher because the mean is larger for the x distribution.
!!) The probability in part (b) is much lower because the standard deviation is smaller for the x distribution.
!!!) The probability in part (b) is much higher because the standard deviation is smaller for the x distribution.
!!!!) The probability in part (b) is much higher because the mean is smaller for the x distribution.
!!!!!) The probability in part (b) is much higher because the standard deviation is larger for the x distribution.
2) Let x be a random variable that represents the level of glucose in the blood (milligrams per deciliter of blood) after a 12 hour fast. Assume that for people under 50 years old, x has a distribution that is approximately normal, with mean = 66 and estimated standard deviation = 45. A test result x < 40 is an indication of severe excess insulin, and medication is usually prescribed.
a)
What is the probability that, on a single test, x < 40? (Round your answer to four decimal places.)
b)
Suppose a doctor uses the average x for two tests taken about a week apart. What can we say about the probability distribution of x? Hint: See Theorem 6.1.
!) The probability distribution of x is approximately normal with x = 66 and x = 45.
!!) The probability distribution of x is approximately normal with x = 66 and x = 22.50.
!!!) The probability distribution of x is approximately normal with x = 66 and x = 31.82.
!!!!) The probability distribution of x is not normal.
c) What is the probability that x < 40? (Round your answer to four decimal places.)
d) Repeat part (b) for n = 3 tests taken a week apart. (Round your answer to four decimal places.)
e) Repeat part (b) for n = 5 tests taken a week apart. (Round your answer to four decimal places.)
f) Compare your answers to parts (a), (b), (c), and (d). Did the probabilities decrease as n increased?
Yes
NO
g) Explain what this might imply if you were a doctor or a nurse.
!) The more tests a patient completes, the weaker is the evidence for lack of insulin.
!!) The more tests a patient completes, the stronger is the evidence for lack of insulin.
!!!) The more tests a patient completes, the weaker is the evidence for excess insulin.
!!!!) The more tests a patient completes, the stronger is the evidence for excess insulin.
Answer:
Suppose the heights of 18-year-old men are approximately normally distributed, with mean 71 inches and standard deviation 4 inches.
(a) What is the probability that an 18-year-old man selected at random is between 70 and 72 inches tall? (Round your answer to four decimal places.)
z1 = (70-71)/4 = -0.25
z2 = (72-71/4 = 0.25
P(70<X<72) = p(-0.25<z<0.25) = 0.1974
Answer: 0.1974
(b) If a random sample of thirteen 18-year-old men is selected, what is the probability that the mean height x is between 70 and 72 inches? (Round your answer to four decimal places.)
z1 = (70-71)/(4/sqrt(13)) = -0.9014
z2 = (72-71/(4/sqrt(13)) = 0.9014
P(70<X<72) = p(-0.9014<z<0.9014) = 0.6326
Answer: 0.6326
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A flower garden is shaped like a circle. Its diameter is 24yd . A ring-shaped path goes around the garden. Its outer edge is a circle with diameter 30yd.
==========================================================
Explanation:
We have two concentric circles. Think of a bulls-eye on a dart board. The inner circle is the garden itself. The outer circle is the garden plus the surrounding pathway. What we're interested in is the area of the outer ring, which is the area of the garden path only.
To find this ring area, we'll need to find the area of each circle.
A = area of the smaller circle
A = pi*r^2
A = pi*12^2
A = 144pi
Notice how I took half of the 24 yard diameter to get the radius of 12 yards.
B = area of the larger circle
B = pi*r^2
B = pi*15^2
B = 225pi
Subtract the two results
C = area of the outer ring, aka the garden path only
C = B - A
C = 225pi - 144pi
C = (225-144)pi
C = 81pi
We're told to use 3.14 in place of pi
C = 81*pi
C = 81*3.14
C = 254.34
The garden path has an area of roughly 254.34 square yards.
1 bag of sand covers 8 square yards.
So we'll need (254.34)/(8) = 31.7925 = 32 bags of sand
