HIV can be contracted from contact with bloodborne pathogens.
Other bloodborne diseases are HBV, malaria, syphilis and brucellosis
What are bloodborne pathogens?Bloodborne pathogens can be defined as those microorganisms or pathogenic organisms that cause disease and are present in human blood.
Blood borne pathogens can also be contacted through the following means
Se- xual contactNeedle contactIn conclusion; HIV can be contracted from contact with bloodborne pathogens.
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Angel hits a ball with a ball. The action is the ball . What what is reaction force?
When Angel hits a ball with the ball. As the action is a ball as it is hitted. The reaction force is the force exerted on another ball.
Newton’s third law of motion describes the two forces, action and reaction forces. This states that for every action force, there is an equal and opposite reaction force.
As Angel hits a ball with another ball, the action is the ball as it is hit. The ball exerts a force on the ball. This is the action force. The ball exerts an equal and opposite force on the bat, which is known as the reaction force.
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A railroad cart with a mass of m1 = 11.6 t is at rest at the top of an h = 10.9 m high hump yard hill.
After it is pushed very slowly over the edge, it starts to roll down. At the bottom it hits another cart originally at rest with a mass of m2 = 23.2 t. The bumper mechanism locks the two carts together. What is the final common speed of the two carts? (Neglect losses due to rolling friction of the carts. The letter t stands for metric ton in the SI system.)
The final common speed of the two carts will be 69.3 m/sec.The momentum conservation principle is applied.
What is the law of conservation of momentum?According to the law of conservation of momentum, the momentum of the body before the collision is always equal to the momentum of the body after the collision.
Unit conversion:
1 metric tons = 1000 kg
Given data;
m₁= 11.6 metric ton =11600 kg
m₂ = 23.2 metric ton = 23200 kg
Let v represent the combined velocity of the two carts once they are connected, and let u represent the starting velocity of cart 1 when it reaches the bottom.
Considering energy conservation;
[tex]\rm m_1 g h = \frac{1}{2} m_1 \times u^2 \\\\ u^2 = 2gh\\\\ u^2 = 2 \times 9.8 \times 10.6 \\\\ u = 207.972 \ m/s[/tex]
From the conservation of momentum principle;
[tex]\rm m_1 \times u = (m_1 + m_2) v\\\\ 11600 \times 207.972 = (11600 + 23200) \times v \\\\ v = 69.3 \ m/s[/tex]
Hence, the final common speed of the two carts will be 69.3 m/sec.
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Waves can carry either ____ or __________ energy?
Answer:
ways can carry either __machanical___ or electromagnetic energy
A force of looN acts upwards on a mass of 50 kg, another of
80N acts on the Same Mass downwards. Calculate the acceleration?
of the body and in which direction will be th acceleration?
Answer:
a force of acts on a body of mass 50 kg for 10 sec when the first of acting on the body the body covers 80 and in the next 10 second
Answer:
a = 0.4 ms⁻²
Explanation:
• First calculate the resultant force on the body:
If we consider upwards to be the positive direction and downwards to be the negative direction, then the resultant force will be:
F = +100 + (-80)
= +20 N
The resultant force is positive, so it will act upwards.
• Next calculate the acceleration:
F = ma
a = F/m
a = 20/ 50
a = 0.4 ms⁻²
As the force is acting upwards, the acceleration will also be upwards.
The volume of the water in the graduated cylinder rose as some of the water was displaced by the table tennis ball. Find the volume of the ball using the formula
Vb = Vf – Vi
where Vb is the volume of the ball, Vf is the final volume of the water, and Vi is the initial volume of the water. Record the volume of the ball in Table A of your Student Guide.
What is the volume of the table tennis ball?
cm3
The approximate volume of table tennis ball is 80 cm³
What is volume?Volume is defined as the amount of space occupied by the three dimensional object. S I unit of volume is m³ or cm³.
To find the volume of tennis ball using graduated cylinder.
Step 1 - Fill the graduated cylinder half or full.
Step 2 - Mark the initial volume of the water i.e. 100 cm³ (Vi)
Step 3 - Put the tennis ball in the graduated cylinder. Some of the water was displaced by the table tennis ball.
Step 4 - Mark the Final volume of the water (Vf) i.e. 180 cm³
Step 5 = Calculate the volume by using Formula
Vb = Vf – Vi = 180 cm³ - 100 cm³ = 80 cm³
Hence the volume of tennis ball (Vb) is 80 cm³
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Answer:
40
Explanation:
The answer is not B.
Answer:
D
Explanation:
15m/ s
i hope this helps
For a physics experiment, a solid cube is suspended from a spring scale. The gravitational force exerted on the cube is 0.714 N as measured when the object is suspended from a spring scale. When the suspended cube is submerged in water (ρ = 1000 kg/m3), the scale reads 0.450 N. What is the side of this cube in cm
The side of this cube will be 2.9996 cm. The net force on the solid cube is acting upward.
What is buoyancy force?
A fluid exerts an upward force against the weight of a partly or completely submerged item. The weight of the overlying fluid causes pressure to rise with depth in a column of fluid.
Given data;
Actual weight.W=0.714 N
Apparent weight,W'=0.450 N
The density of water,ρ=1000 kg/m³
The net force on the solid cube is;
Apparent weight = actual weight - buoyancy force
Buoyancy force = Actual weight - apparent weight
F=W-W'
F = 0.714 - 0.450
F= 0.264 N
The buoyancy force(F) is found as;
F = ρgV
0.264 = 1000 × 9.81 × V
V=2.69 × 10⁺⁵
The volume of a cube is found as;
V=a³
2.69 × 10⁺⁵ m³=a³
a=0.02996 m
As we know that 1 m = 100 cm
a=2.996 cm
Hence, the side of this cube will be 2.9996 cm.
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A satellite circles the Earth in an orbit whose radius is twice the Earth’s radius. The Earth’s mass is 5.98 x 1024 kg, and its radius is 6.38 x 106 m. What is the period of the satellite?
Hello!
Recall the period of an orbit is how long it takes the satellite to make a complete orbit around the earth. Essentially, this is the same as 'time' in the distance = speed * time equation. For an orbit, we can define these quantities:
[tex]d = 2\pi r[/tex] ← The circumference of the orbit
speed = orbital speed, we will solve for this later
time = period
Therefore:
[tex]T = \frac{2\pi r}{v}[/tex]
Where 'r' is the orbital radius of the satellite.
First, let's solve for 'v' assuming a uniform orbit using the equation:
[tex]v = \sqrt{\frac{Gm}{r}}[/tex]
G = Gravitational Constant (6.67 × 10⁻¹¹ Nm²/kg²)
m = mass of the earth (5.98 × 10²⁴ kg)
r = radius of orbit (1.276 × 10⁷ m)
Plug in the givens:
[tex]v = \sqrt{\frac{(6.67*10^{-11})(5.98*10^{24})}{(1.276*10^7)}} = 5590.983 m/s[/tex]
Now, we can solve for the period:
[tex]T = \frac{2\pi (1.276*10^7)}{5590.983} =\boxed{ 14339.776 s}[/tex]
what is the formula for finding balance length
Answer:
Case 1: Balancing length when cell is shunted l1 = 150 cm = 1.5 m, Value of shunt = R = 5 ohm. Case 2: Balancing length when cell is shunted l1 = 175 cm = 1.75 m, Value of shunt = R = 10 ohm. Example 06: A cell balances against a length of 250 cm on potentiometer wire when it is shunted by a resistance of 10 ohms
Which picture shows a boat riding on a trough?
Select one:
a. A
b. B
c. C
d. D
Answer:
B
Explanation:
What is speed?
What is the difference between speed and velocity?
What could an object be doing if it is accelerating ?
What is inertia . Give an example.
What are some common forces in action ? Explain.
What are balanced forces ? Explain.
What is the relationship between work and power ?
Speed can be defined as the change in distance with respect to time.
The speed is the change in distance with the time and velocity is the change in displacement with the time. Speed is a scalar quantity having magnitude only and Velocity is a vector quantity having magnitude as well as direction.
If the velocity of the object is changing, it shows that the object is accelerating.
Inertia is a resistance of an object to resist a change in its state of motion or of rest. If a ball is rolled, it will continue rolling unless friction or something else stops it by force.
Some common forces are gravitational forces, electric forces, magnetic forces, nuclear forces, etc. Gravitational forces act between the earth and the object, it is an attraction force. Similarly, there is an electric force, which acts between the two charges, it can be attractive or repulsive.
The forces that are opposite in direction and equal in size, are known as balanced forces. This can be explained as forces acting horizontal, and the forces are balanced, so the left-sided forces and right-sided forces must be equal.
Power can be defined as the measure of the amount of work that can be done in a given amount of time. Power is work done per unit time.
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Lester plays middle linebacker for dices football team. During one play, he made the following movements. First, he back-pedaled in the southern direction for 2.6 meters
Answer:
Explanation:
missing info .....
The glucometer applies a potential difference of 0.90 volts across a blood sample. The glucose concentration of the blood sample is 0.98 grams/litre. Determine the current in the blood sample.
The amount of current in the blood sample is determined as 0.12 A.
Current in the blood
The current in the blood is calculated by applying Ohm's law as shown below;
V = IR
where;
V is voltageI is currentR is resistanceFrom resistivity chart corresponding to 0.98 g/L, resistance, R = 7.4
I = V/R
I = 0.9 /7.4
I = 0.12 A
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A spaceprobe in outer space is flying with a constant speed of 1.795 km/s. The probe has a payload of 1635.0 kg and it carries 4092.0 kg of rocket fuel. The rocket engines of the probe are capable of expelling propellant at a speed of 4.161 km/s. Then the rocket engines are fired up. How fast will the spaceprobe travel when all the rocket fuel is used up?
The speed by which the spaceprobe travels when all the rocket fuel is used up will be 29.262 m/sec.
What is the law of conservation of linear momentum?
According to the law of conservation of linear momentum before the collision is equal to the momentum after the collision. These laws state how momentum gets conserved.
Unit conversion;
1 km/sec = 1000 m/sec
Given data;
Spaceprobe speed = 1.795 km/s = 1795 m /sec
Probe mass = 635.0 kg
Fuel mass = 4092.0 kg
Expelled propellent velocity = 4.161 km/s = 41461 m/sec
From the momentum conservation principle;
[tex]\rm P_i = P_f \\\\ (m_p+m_f)v_i = m_pV - m_fv_p \\\\ V = \frac{(635+4092)1795+4092 \times 41461}{635} \\\\ V = 280540.7 \ m/sec \\\\ V = 28.05 m/sec[/tex]
Hence, the speed by which the spaceprobe travels when all the rocket fuel is used up will be 29.262 m/sec.
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A car moves with the speed of 40km/hr for the first half distance and 60km/hr for second half distance.find average speed of car?
Answer:
50km/h
Explanation:
average = (a + b) / 2
average = (60 + 40) / 2
average = 50
Particles q1, q2, and q3 are in a straight line.
Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C,
and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are
separated by 0.500 m. Particles q2 and q3 are
separated by 0.250 m. What is the net force on q2?
The net force on q2 will be 1.35 N
A force in physics is an effect that has the power to alter an object's motion. A mass-containing object's velocity can vary, or accelerate, as a result of a force. Intuitively, a push or a pull can also be used to describe force. Being a vector quantity, a force has both magnitude and direction.
Given Particles q1, q2, and q3 are in a straight line. Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C, and q3 = -2.50 x 10-6 C. Particles q₁ and q2 are separated by 0.500 m. Particles q2 and q3 are separated by 0.250 m.
We have to find the net force on q2
At first we will find Force due to q1
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²
F = 450 × 10⁻³
F₁ = 0.45 N (+)
Now we will find Force due to q2
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²
F = 1800 × 10⁻³
F₂ = 1.8 N (-)
So net force (F) will be
F = F₂ - F₁
F = 1.8 - 0.45
F = 1.35 N
Hence the net force on q2 will be 1.35 N
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Becky races Tom down the street .Becky , initially at a stop,takes 5.5 s to reach 30 m/s . What accelerated?
Becky's acceleration is 5.45 [tex]ms^2[/tex].
Acceleration = [tex]\frac{v-u}{t}[/tex]
where v= final velocity , u= initial velocity , t= time taken
according to the question :
initial veocity = 0 (it is at stop initially)
final velocity = 30m/s
time taken = 5.5 s
according to the formula acceleration = [tex]\frac{30-0}{5.5}[/tex]=[tex]5.45[/tex]
Hence Becky's acceleration is 5.45 [tex]ms^2[/tex].
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2. A man pushes on a piano with mass 180 kg; it slides at constant velocity down a ramp that is inclined at 19.0° above the horizontal floor. Neglect any friction acting on the piano. Calculate the magnitude of the force applied by the man if he pushes (a) parallel to the incline and (b) parallel to the floor.
Answer: See below
Explanation:
Part (a):
As the velocity of the piano is constant, the net force on the piano is zero. The friction is also zero.
Here, F is the force applied by the man towards the inclined plane, mg is the weight of the piano and N is the normal force.
Applying Newton's law we get,
[tex]F = mg\sin \theta[/tex]
Substituting we get,
[tex]F &= \left( {180\;{\rm{kg}}} \right) \times \left( {9.8\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}} \right) \times \sin 19.0^\circ \\ &= 574.3\;{\rm{N}}[/tex]
Therefore, the force is 574.3 N
Part (b)
Here, the force F is applied parallel to the floor.
The friction is zero.
Applying Newton's law we get,
[tex]F\cos \theta &= mg\sin \theta \\ F &= mg\tan \theta[/tex]
Substituting we get,
[tex]F &= \left( {180\;{\rm{kg}}} \right) \times \left( {9.8\;{\rm{m/}}{{\rm{s}}^{\rm{2}}}} \right) \times \tan 19.0^\circ \\ &= 607.4\;{\rm{N}}[/tex]
Therefore, the force is 607.4 N
Which object has the least thermal energy?
Answer:
2kg brick
Explanation:
2kg brick at 25 degrees.
Answer: A 2kg brick at 20*C
Explanation:
What is the wavelength of a compression wave with a speed of 500 m/s and a frequency of 250 Hz?
Use this formula: λ = s/f
Select one:
a. 2 m
b. 1.25 m
c. 250 m
d. 750 m
Answer:
a (2m)
Explanation:
according to wavelenght = speed / frequency,
the wavelength is 2 m
Which refers to a material that causes a wave to bounce off of it?
A. absorber
B. reflector
C. conductor
D. insulator
Answer:
the answer to the question is a reflector
One support of the behavioral perspective is how B. F. Skinner’s ideas have brought to light how the __________ and __________ influence personality.
One support of the behavioral perspective is how B. F. skinner’s ideas have brought to light how the environment and learning influence personality.
What is the behavioral perspective?The behavioral perspective on personality and individual variations places an emphasis on quantifiable behaviors influenced by the environment and the results that follow.
The theoretical aim of behaviorism is the prediction and control of behavior given its natural science methodology.
Skinner's theories have made it clear how learning and the environment affect personality, which is one argument in favor of the behavioral approach.
One support of the behavioral perspective is how B. F. skinner’s ideas have brought to light how the environment and learning influence personality.
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Particles q1, 92, and q3 are in a straight line.
Particles q1 = -5.00 x 10-6 C,q2 = +2.50 x 10-6 C,
and q3= -2.50 x 10-6 C. Particles q1 and q2 are
separated by 0.500 m. Particles q and q3 are
separated by 0.250 m. What is the net force on q2?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
-5.00 x 10-6 C
91
0.500 m
+2.50 x 10-6 C
+92
-2.50 x 10-6 C
93
0.250 m
Answer:
-1.35 N
Explanation:
Force due to q1
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.5²F = 450 × 10⁻³F = 0.45 N (+)Force due to q2
F = 9 × 10⁹ × 5 × 10⁻⁶ × 2.5 × 10⁻⁶ / 0.25²F = 1800 × 10⁻³F = 1.8 N (-)Net Force
0.45 - 1.8-1.35 NWhat can a line graph be used to do?
A. Make predictions
B. Make comparisons
C. Identify positive correlation
D. Identify negative correlation
Answer:
B
Explanation:
i's 100% paset bro.....
What is the current in a circuit that is powered by a 6.0 V battery and
connected in series by a 2.0 Ω resistor and a 12.0 Ω resistor?
A. 0.50 A
B. 3.0 A
C. 84.0 A
D. 0.43 A
Answer:
D. 0.43 A
Explanation:
First you will find the total resistance which is
R=R¹+R²
R=2+12
R= 14 ohms
I = V/R
I = CURRENT
V= VOLTAGE
R = RESISTANCE
I= 6/14
I =0.43 A
The following table contains financial information for Trumpter Inc. before closing entries:
Cash
Supplies
Prepaid Rent
Salaries Expense
Equipment
Service Revenue
Miscellaneous Expenses
Dividends
Accounts Payable
Common Stock
Retained Earnings
$13,100
6,000
3,800
5,000
65,900
28,000
20,100
4,000
3,100
66,100
20,700
What is the amount of Trumpter's total assets?
The Total assets based on the given table is $88,800.
What are assets?An asset refers to a resource owned by an individual or company which has tangible value and whose value is expected to rise in the future.
The Total assets based on the table = Cash + Supplies + Prepaid rent + Equipment
Total assets = 13,100 + 6,000 + 3,800 + 65,900
Total assets = $88,800
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The wavelength of the wave pictured below is... Select one: a. 1 cm b. 1.5 cm c. 2 cm d. 3 cm
Answer:
D. 3 cm
Wavelength is the distance between two crests or two troughs.
In the given picture, the distance between two adjacent crests is 3 cm.
Hence, the wavelength is 3 cm.
Which of the following causes a car's passenger to lean in the direction
opposite the direction in which the car is turning?
OA. Friction
OB. Inertia
OC. Centripetal acceleration
OD. Centripetal force
Explanation:
This case is inertia.
Mass is directly proportional to inertia
A car traveling at 120km/h towards west makes a right turn and travel north without changing its speed .120km/h120km/h.Using a vector diagram.Finding the magnitude and direction of the resultant velocity of the car
The magnitude and direction of the resultant velocity of the car will be 169.70 km/h and 45°.
What is a vector?The quantity which has magnitude, direction and follows the law of vector addition is called a vector.
A car traveling at 120 km/h towards west makes a right turn and travel north without changing its speed.
Then the magnitude (R) will be
R² = 120² + 120²
R² = 28800
R = 169.70 km / h
Then the direction of the resultant velocity will be
tan θ = 120 / 120
tan θ = 1
tan θ = tan 45°
θ = 45°
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. Two planets, both of mass m, are separated by a distance d. Their relative velocity is negligible, and there is an inertial frame in which both planets are essentially at rest. The gravitational potential u(r) at the position r in the presence of the two planets, located at R1 and R2, is given as u(r) = − Gm R1 −r − Gm R2 −r . This problem takes place far out in space and there are no other massive objects in the vicinity of the two planets. (a) Draw a graph of u as a function of position (r) along the line between the two planets. (b) There are space stations Alpha and Beta located on the line between the planets. Both space stations are at rest with respect to the planets. Alpha is at distance d 4 from planet 1 and Beta is at distance d 3 from planet 2. A projectile of mass m is fired from station Alpha, with its velocity v pointing directly at planet 2. What is the minimum speed v which will permit the projectile to reach station Beta?
(a) A graph of u as a function of position (r) along the line between the two planets is attached below.
(b) The minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]
What is gravitational potential energy?If an object is lifted, work is done against gravitational force. The object gains energy.
Given are two planets, both of mass m, are separated by a distance d. Their relative velocity is negligible, and there is an inertial frame in which both planets are essentially at rest. The gravitational potential u(r) at the position r in the presence of the two planets, located at R1 and R2, is given as
u(r) = − (Gm /R1 −r) − (Gm / R2 −r) .
This problem takes place far out in space and there are no other massive objects in the vicinity of the two planets
(a) A graph of u (r) versus position (r) along the line between the two planets is attached in answer.
(b) There are space stations Alpha and Beta located on the line between the planets. Both space stations are at rest with respect to the planets. Alpha is at distance d 4 from planet 1 and Beta is at distance d 3 from planet 2. A projectile of mass m is fired from station Alpha, with its velocity v pointing directly at planet 2.
The range of the projectile is given by R = v²sin2θ / g
g = gravitational acceleration of Earth
If g = g(p) for planet , range R = v²sin2θ / g(p)..................(1)
The gravitational force of attraction = weight force
Gm² /d² = m g(p)
g(p) = Gm/d².........................(2)
For R = d/3, from equation (1), we have
d/3 = v²sin2θ / g(p)
Plug the expression for g(p) , we get
v = √ [Gm/3dsin2θ ]
For velocity to be minimum, sin2θ =1
So, the minimum velocity will be
v = √ [Gm/3d]
Thus, the minimum speed v which will permit the projectile to reach station Beta is √ [Gm/3d]
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