Answer:
655 people would need to be surveyed.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the zscore that has a pvalue of [tex]1 - \frac{\alpha}{2}[/tex].
In this question, we have that:
[tex]\pi = 0.68[/tex]
The margin of error is:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
90% confidence level
So [tex]\alpha = 0.1[/tex], z is the value of Z that has a pvalue of [tex]1 - \frac{0.1}{2} = 0.95[/tex], so [tex]Z = 1.645[/tex].
How many people would need to be surveyed for a 90% confidence interval to ensure the margin of error would be less than 3%?
We need to survey n adults.
n is found when M = 0.03. So
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]0.03 = 1.645\sqrt{\frac{0.68*0.32}{n}}[/tex]
[tex]0.03\sqrt{n} = 1.645\sqrt{0.68*0.32}[/tex]
[tex]\sqrt{n} = \frac{1.645\sqrt{0.68*0.32}}{0.03}[/tex]
[tex](\sqrt{n})^{2} = (\frac{1.645\sqrt{0.68*0.32}}{0.03})^{2}[/tex]
[tex]n = 654.3[/tex]
Rounding up
655 people would need to be surveyed.
A water cooler holds 15 liters of sports drink. Approximately how many gallons is this
TWO PLANES INTERSECT IN A
A. point
B. Ray
C. Line
D. Line segments
Answer:
c. line
Step-by-step explanation:
the intersection of two planes is called a line
Answer:
Hello dear,
two planes intersect and forms line
so yaa your answer is C)
Hope I helped you ;)
please thank me !!!
satsriakal ji
A small-business Web site contains 100 pages and 60%, 30%, and 10% of the pages contain low, moderate, and high graphic content, respectively. A sample of four pages is selected without replacement, and X and Y denote the number of pages with moderate and high graphics output in the sample. Determine: a. fxy(x, y) b. fx(x) c. E(X) d. fyß(y) e. E(Y | X = 3) g. Are X and Y independent?
Answer:
Step-by-step explanation:
Given that:
A small-business Web site contains 100 pages and 60%, 30%, and 10% of the pages contain low, moderate, and high graphic content, respectively.
. A sample of four pages is selected without replacement,
Let X and Y denote the number of pages with moderate and high graphics output in the sample
We are meant to determine
a) [tex]f_{XY}(x, y)[/tex] from the given data in the question;
However; the probability mass function can be expressed via the relation:
[tex]f_{XY}(x,y) = \dfrac{(^{30} _x ) ( ^{10} _y ) (^{60} _ {4-x-y} ) }{ ( ^{100}_4)}[/tex]
We can now have a table shown as :
[tex]X|Y[/tex] 0 1 2 3 4 Total [tex]f_X(x)[/tex]
0 0.1244 0.0873 0.02031 0.0018 0.0001 0.234
1 0.2618 0.13542 0.02066 0.00092 0 0.419
2 0.1964 0.0666 0.00499 0 0 0.268
3 0.0621 0.01035 0 0 0 0.073
4 0.0069 0 0 0 0 0.007
Total [tex]F_Y(y)[/tex] 0.6516 0.2996 0.0460 0.0028 0.0001 1
b) [tex]f_X(x)[/tex]
The marginal distribution definition of [tex]f_X(x)[/tex][tex]= P(X=x)[/tex]
[tex]f_X(x)[/tex] [tex]= \sum P(X=x, Y=y)[/tex]
From the table above ; the corresponding values of [tex]f_X(x)[/tex] are :
X 0 1 2 3 4
[tex]f_X(x)[/tex] 0.234 0.419 0.268 0.073 0.007
( since [tex]f_X(x)[/tex] represent the vertical column)
c) E(X)
By using the expression [tex]E(x) = \sum ^4 _{x= 0} x f_X(x)[/tex]
we have:
E(X) = [tex]0*0.234+1*0.419+ 2*0.268+3*0.073+4*0.007[/tex]
E(X) = 0 + 0.419 + 0.536 + 0.218 + 0.028
E(X) = 1.202
d) fyß(y)
Using the thesis of conditional Probability; we have :
[tex]P(A|B) = \dfrac{ P(A,B) }{ P(B) }[/tex]
The conditional probability for the mass function is then:
[tex]f_{Y|X=3}(y) = \dfrac{f_{XY}(3,y)}{f_{X}(x)}[/tex]
where;
[tex]f_X(3) = 0.0725[/tex]
values of [tex]f_{XY} (3,y)[/tex] for every y ∈ (0,1,2,3,4)
Therefore; the mass function is:
[tex]Y|{_X_3}:\left[\begin{array}{ccccc}0&1&2&3&4\\0.857&0.143&0&0&0\\ \end{array}\right][/tex]
e) E(Y | X = 3)
By using the expression [tex]E(Y|X=3) = \sum ^4 _{y= 0} y f_{y \beta} \ (y|x)[/tex]
we have:
⇒ [tex]0 * 0.857 + 1*0.143 +0 +0+0[/tex]
= 0.143
The value of E(Y | X = 3) = 0.143
g) Are X and Y independent?
To Check if X and Y independent; Let assume if [tex]f_{XY}(x,y) = f_X(x)f_{Y}(y)[/tex] ; then we can say that X and Y are independent.
From the above previous table :
[tex]f_{(XY)} (0.4) = 0.0001[/tex]
[tex]f_X (0)[/tex] = 0.1244 + 0.087268+0.02031+ 0.001836 + 0.0001
[tex]f_X (0)[/tex] = 0.234
[tex]f_X (4)=0.0001 +0+0 \\ \\ = 0.001[/tex]
[tex]f_{X}(0) f_Y(4) = 0.234*0.0001[/tex]
[tex]f_{X}(0) f_Y(4) = 0.00002[/tex]
We conclude that [tex]f_{(XY)} (0.4) \neq f_X(0) f_Y(y)[/tex]; As such X and Y are said to be non - independent.
Which of the following describes the function x^3-8
Answer:
Is there any options if so just repost with the options and i will answer it
Step-by-step explanation:
An OSU senior is studying for exams in psychology and economics. The student has time to read 50 pages of psychology and 10 pages of economics. Or, in the same amount of time the student could read 30 pages of psychology and 70 pages of economics. How many pages of economics can the student read instead of reading just 1 page of psychology
Answer:
3 Pages
Step-by-step explanation:
Let the pages of economics read = eLet the pages of psychology read = pLet the total time taken on each instance=tIn the first instance, the student has time to read 50 pages of psychology and 10 pages of economics.
t=50p+10eThe student could read 30 pages of psychology and 70 pages of economics.
t=30p+70eSince the two situations take the same amount of time, we have:
50p+10e=30p+70e
Collect like terms
50p-30p=70e-10e
20p=60e
Divide both sides by 20
p=3e
Therefore, in the time it will take the student to read 1 page of psychology, the student can read 3 pages of economics.
Is a measure of 22 inches "far away" from a mean of 16 inches? As someone with knowledge of statistics, you answer "it depends" and request the standard deviation of the underlying data. (a) Suppose the data come from a sample whose standard deviation is 2 inches. How many standard deviations is 22 inches from 16 inches? (b) Is 22 inches far away from a mean of 16 inches? (c) Suppose the standard deviation of the underlying data is 4 inches. Is 22 inches far away from a mean of 16 inches?
Answer:
a) 3 standard deviations above 16
b) More than 2 standard deviations of the mean, so yes, 22 inches is faw away from the mean of 16 inches.
c) Less than 2 standard deviations, so not far away.
Step-by-step explanation:
Z-score:
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
If Z < -2 or Z > 2, X is considered to be far away from the mean.
In this question, we have that:
[tex]\mu = 16[/tex]
(a) Suppose the data come from a sample whose standard deviation is 2 inches. How many standard deviations is 22 inches from 16 inches?
This is Z when [tex]X = 22, \sigma = 2[/tex].
So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{22 - 16}{2}[/tex]
[tex]Z = 3[/tex]
So 22 inches is 3 standard deviations fro 16 inches.
(b) Is 22 inches far away from a mean of 16 inches?
3 standard deviations, more than two, so yes, 22 inches is far away from a mean of 16 inches.
(c) Suppose the standard deviation of the underlying data is 4 inches. Is 22 inches far away from a mean of 16 inches?
Now [tex]\sigma = 4[/tex]
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{22 - 16}{4}[/tex]
[tex]Z = 1.5[/tex]
1.5 standard deviations from the mean, so 22 inches is not far away from the mean.
A bank is investigating ways to entice customers to charge more on their credit cards. (Banks earn a fee from the merchant on each purchase, and hope to collect interest from the customers, as well.) A bank selects a random group of customers who are told their "cash back" will increase from 1% to 2% for all charges above a certain dollar amount each month. Of the 500 customers who were told the increase applied to charges above $1000 each month, the average increase in spending was $527 with a standard deviation of $225. Of the 500 customers who were told the increase applied to charges above $2000 each month, the average increase in spending was $439 with a standard deviation of $189. A level C = 95% confidence interval for \mu_1\:-\:\mu_2μ 1 − μ 2 is approximated by Group of answer choices (62.2, 113.8) (86.2, 120.5) (10.3, 23.8) (55.6, 67.8)
Answer:
[tex]CI = (\bar{x_{1} } - \bar{x_{2}} ) \pm MoE\\\\[/tex]
[tex]CI = (527 - 439) \pm 25.75\\\\CI = 88 \pm 25.75\\\\CI = 88 - 25.75 \:\: and \:\: 88 + 25.75\\\\CI = (62.2 \: ,\: 113.8 )[/tex]
The correct answer choice is a. (62.2, 113.8)
Step-by-step explanation:
Of the 500 customers who were told the increase applied to charges above $1000 each month, the average increase in spending was $527 with a standard deviation of $225.
Sample size = n₁ = 500
Sample mean = x₁ = $527
Standard deviation = s₁ = $225
Of the 500 customers who were told the increase applied to charges above $2000 each month, the average increase in spending was $439 with a standard deviation of $189
Sample size = n₂ = 500
Sample mean = x₂ = $439
Standard deviation = s₂ = $189
We are asked to find the 95% confidence interval for the difference between two means.
The given group of answer choices are
a. (62.2, 113.8)
b. (86.2, 120.5)
c. (10.3, 23.8)
d. (55.6, 67.8)
The confidence interval for the difference between two means is given by
[tex]CI = (\bar{x_{1} } - \bar{x_{2}} ) \pm MoE\\\\[/tex]
Where [tex]\bar{x_{1} }[/tex] and [tex]\bar{x_{2} }[/tex] are the given sample means and margin of error is given by
[tex]$ MoE = z_{\alpha/2} \cdot \sqrt{\frac{s_{1}^2}{n_1} + \frac{s_{2}^2}{n_2}} $[/tex]
The z-score corresponding to 95% confidence level is given by
Significance level = α = 1 - 0.95 = 0.05/2 = 0.025
From the z-table at α = 0.025 the z-score is 1.96
[tex]$ MoE = 1.96 \cdot \sqrt{\frac{225^2}{500} + \frac{189^2}{500}} $[/tex]
[tex]MoE = 1.96 \cdot 13.14[/tex]
[tex]MoE = 25.75[/tex]
Finally,
[tex]CI = (\bar{x_{1} } - \bar{x_{2}} ) \pm MoE\\\\[/tex]
[tex]CI = (527 - 439) \pm 25.75\\\\CI = 88 \pm 25.75\\\\CI = 88 - 25.75 \:\: and \:\: 88 + 25.75\\\\CI = (62.2 \: ,\: 113.8 )[/tex]
Therefore, the correct answer choice is a. (62.2, 113.8)
How to use z-table?
In the z-table find the probability of 0.025
Note down the value of that row, it would be 1.9.
Note down the value of that column, it would be 0.06.
Add the two numbers together.
The z-score is 1.9 + 0.06 = 1.96
Evaluate each expression. 16 5/4 x 16 1/4 / (16 1/2)/2=
Answer: the answer is 4
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
4 on edgunity 2020
Question: A box contains 160 Iphone XR's.
60% of the IPhones are Forest Green.
How many IPhones are Forest Green?
Answer:
96
Step-by-step explanation:
60% * 160 = 0.6 * 160 = 96.
Answer:
None
Step-by-step explanation:
There is no Forest Green iPhone XR's only the 11 Pros have that color.
what is the solution set for the equation (x+3)(x-8)=0
Answer:
x = -3 x=8
Step-by-step explanation:
(x+3)(x-8)=0
Using the zero product property
x+3 =0 x -8 = 0
x = -3 x=8
The breaking strength of a rivet has a mean of 10,000 psi and a standard deviation of 714.2857 psi. What is the probability that the sample mean breaking strength for a random sample of 49 rivets is between 9,832 and 10,200?
Answer:
[tex] z= \frac{9832- 10000}{\frac{714.2857}{\sqrt{49}}}= -1.646[/tex]
[tex] z= \frac{10200- 10000}{\frac{714.2857}{\sqrt{49}}}= 1.96[/tex]
And we can use the normal standard distribution table or excel and we can find the probability with this difference:
[tex] P(-1.646 <z< 1.96) =P(z<1.96) -P(z<-1.646) =0.975-0.0499= 0.9251[/tex]
Then the probability that the sample mean breaking strength for a random sample of 49 rivets is between 9,832 and 10,200 is 0.9251
Step-by-step explanation:
For this case we have the following info given:
[tex] \mu = 10000[/tex] represent the mean
[tex] \sigma = 714.2857[/tex] represent the deviation
[tex] n = 49[/tex] represent the sample size selected
For this case since the sample size is large enough n>30 we have enough evidence to use the central llmit theorem and the distribution for the sample mena would be given by:
[tex] \bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}}) [/tex]
And we want to find the following probability:
[tex] P(9832 < \bar X< 10200)[/tex]
And we can use the z score formula given by:
[tex] z = \frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
And if we use the z score formula for the limits given we got:
[tex] z= \frac{9832- 10000}{\frac{714.2857}{\sqrt{49}}}= -1.646[/tex]
[tex] z= \frac{10200- 10000}{\frac{714.2857}{\sqrt{49}}}= 1.96[/tex]
And we can use the normal standard distribution table or excel and we can find the probability with this difference:
[tex] P(-1.646 <z< 1.96) =P(z<1.96) -P(z<-1.646) =0.975-0.0499= 0.9251[/tex]
Then the probability that the sample mean breaking strength for a random sample of 49 rivets is between 9,832 and 10,200 is 0.9251
Triangle XYZ is translated so that X’ is that (4,-2) which rule defines this translation?
Answer: y
Step-by-step explanation:
Jose predicted that he would sell 48 umbrellas. He actually sold 72 umbrellas.What are the values of a and b in the table below. Round to the nearest tenth if necessary
Answer:
The answer is A
Step-by-step explanation:
A car is driving at 75 kilometers per hour. How far, in meters, does it travel in 5 seconds?
75km convert to m 75x1000=75000m
converted I hour to seconds that is 3600seconds
If 75000m=3600seconds
? =5seconds
that id 75000x5=375000/3600
=104.26…metres
The distance will be 104.16 meters if the car is driving at 75 kilometers per hour.
What is the distance?Distance is a numerical representation of the distance between two items or locations. Distance refers to a physical length or an approximation based on other physics or common usage considerations.
It is given that:
A car is driving at 75 kilometers per hour.
Let x be the distance.
As we know from the distance time relation:
Distance = speed×time
Speed = 75 km/h
Speed = 75 km/(3600)seconds
Speed = 0.0208 km/s
x = 0.0208×5
x = 0.10416 km
in meters
x = 0.104x1000
x = 104.16 meters
Thus, the distance will be 104.16 meters if the car is driving at 75 kilometers per hour.
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Express the function G in the form f∘g. (Enter your answers as a comma-separated list. Use non-identity functions for
f(x) and g(x).)
Answer:
i dont really know what it is
According to a polling organization, 22% of adults in a large region consider themselves to be liberal. A survey asked 200 respondents to disclose their political philosophy: Conservative, Liberal, Moderate. Treat the results of the survey as a random sample of adults in this region. Do the survey results suggest the proportion is higher than that reported by the polling organization? Use an alphaequals0.01 level of significance.
Answer:
No. There is not enough evidence to support the claim that the proportion of liberals is higher than that reported by the polling organization (P-value = 0.0366).
Step-by-step explanation:
The question is incomplete: there is no information about the results of the survey. We will assume that 55 of the subjects answer "liberal", and test the claim.
This is a hypothesis test for a proportion.
The claim is that the proportion of liberals is higher than that reported by the polling organization.
Then, the null and alternative hypothesis are:
[tex]H_0: \pi=0.22\\\\H_a:\pi>0.22[/tex]
The significance level is 0.01.
The sample has a size n=200.
The sample proportion is p=0.275.
[tex]p=X/n=55/200=0.275[/tex]
The standard error of the proportion is:
[tex]\sigma_p=\sqrt{\dfrac{\pi(1-\pi)}{n}}=\sqrt{\dfrac{0.22*0.78}{200}}\\\\\\ \sigma_p=\sqrt{0.000858}=0.029[/tex]
Then, we can calculate the z-statistic as:
[tex]z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.275-0.22-0.5/200}{0.029}=\dfrac{0.053}{0.029}=1.792[/tex]
This test is a right-tailed test, so the P-value for this test is calculated as:
[tex]\text{P-value}=P(z>1.792)=0.0366[/tex]
As the P-value (0.0366) is greater than the significance level (0.01), the effect is not significant.
The null hypothesis failed to be rejected.
There is not enough evidence to support the claim that the proportion of liberals is higher than that reported by the polling organization.
Find the area of a circle with radius, r = 6.89m.
Give your answer rounded to 2 DP (2 decimal points)
The photo is attached below
Answer:
149.14 [tex]m^{2}[/tex]
Step-by-step explanation:
Area of a circle = π[tex]r^{2}[/tex]
so A = π * 6.89^2 = 149.14 (to 2d.p.)
In this diagram, BAC – EDF. If the
area of BAC = 24 in2, what is the
area of EDF?
Help please
If the area of ΔBAC = 24 in², the area of ΔEDF is 6 in².
What are similar triangles?If two triangles' angles are congruent and their corresponding sides are proportionate, they are considered similar. To put it another way, similar triangles are the same in shape but not necessarily in size. If ΔPQR and ΔMNO are two similar triangles, then we can write it as ΔPQR ∼ ΔMNO.
Statement:The square of the ratio of any pair of their respective sides is equal to the ratio of the areas of two similar triangles.
How to solve this problem?Since ΔBAC ∼ ΔEDF, we can use the above statement to find the area of ΔEDF. Let the area of ΔEDF be x in². Given that length of EF and BC is 2 in and 4 in respectively.
So, we have to solve this equation,
24/x = 4²/2²
Now, 24/x = 16/4
i.e. 24/x = 4
i.e. 4x = 24
i.e. x = 24/4 = 6
Therefore the area of ΔEDF is 6 in².
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Given cot ø = 4/3. Find the other two reciprocal trigonometic ratios. 1) scs 2) sec
Answer:
csc ø = 5/3 ; sec ø = 5/4
Step-by-step explanation:
cot ø = adj/opp
adj = 4
opp = 3
after that, we must find the hypotenuse by using phytagoras theorem
hpy² = adj² + opp²
hpy² = 4² + 3²
hpy² = 25
hpy = 5
now let's find the other
csc ø (not scs) = hyp/opp = 5/3
sec ø = hyp/adj = 5/4
Little Equipment for Hire is a subsidiary in the Giant Machinery and currently under the liquidation plan due to the severe contraction of operation due to corona virus. The company plans to pay total dividend of $2.5 million now and $ 7.5 million one year from now as a liquidating dividend. The required rate of return for shareholders is 12%. Calculate the current value of the firm’s equity in total and per share if the firm has 1.5 million shares outstanding. (4 marks)
Complete Question:
The Giant Machinery has the current capital structure of 65% equity and 35% debt. Its net income in the current year is $250 000. The company is planning to launch a project that will requires an investment of $175 000 next year. Currently the share of Giant machinery is $25/share. Required: a. How much dividend Giant Machinery can pay its shareholders this year and what is dividend payout ratio of the company. Assume the Residual Dividend Payout Policy applies? b. If the company is paying a dividend of $2.50/share and tomorrow the stock will go ex-dividend. Calculate the ex-dividend price tomorrow morning. Assuming the tax on dividend is 15%? c. Little Equipment for Hire is a subsidiary in the Giant Machinery and currently under the liquidation plan due to the severe contraction of operation due to corona virus. The company plans to pay total dividend of $2.5 million now and $ 7.5 million one year from now as a liquidating dividend. The required rate of return for shareholders is 12%. Calculate the current value of the firm’s equity in total and per share if the firm has 1.5 million shares outstanding?
Answer:
a) Total dividend for the current year = $136,250
Dividend Payout Ratio = 0.545
b) Ex-dividend price = $22.875
c) Total current value = $9,196,428.57
Current value per share = $6.13
Step-by-step explanation:
a) Equity = 65%
Debt = 35%
Net Income for year 0 = $250,000
proposed Investment for year 1= $175,000
Current price = $25/share
Tax on dividend = 15%
Total dividend for year 0 = 250000 - (65% of 175000)
Total dividend for year 0= 250000 - 113750
Total dividend for the current year = $136,250
Dividend Payout Ratio = total dividends/ total earning
Dividend Payout Ratio = 136250/250000
Dividend Payout Ratio = 0.545
b) Dividend = $2.5/ share
Ex-dividend price = current price - Dividend * (1-tax on dividend)
Substituting the appropriate values:
Ex-dividend price = 25 - 2.5 * (1-15%)
Ex-dividend price = 25 - 2.125
Ex-dividend price = $22.875
c) Current value of the firm = Dividend paid in year 0 + (Dividend to be paid in year 1/discount rate)
Dividend paid in year 0 = $2,500,000
Dividend to be paid in year 1 = $7,500,000
Discount rate = 12%
Total current value = 2,500,000 + (7,500,000 / 1.12)
Total current value = $9,196,428.57
Numbe of shares = 1,500,000
Current value per share = Total current value / number of shares
Current value per share = 9,196,428.57/1,500,000
Current value per share = $6.13
Please answer this correctly
Answer:
=3651 km^2
Step-by-step explanation:
The rectangle at the top is 11 km by 32 km
The area is 11*32 =352
The rectangle at the bottom is 9 km by 11 km
The area is 9*11 = 99
Add the two areas together
352+99 =451 km^2
(X+3)/6=5/4 what is x
Answer:
x = 9/2
Step-by-step explanation:
(x+3)/6=5/4
(x+3)/6*6=5/4*6
x+3=30/4
x+3-3=30/4-3
x=9/2
The pressure p(in lbs/in^2) that a 160 pound persons shoe exerts on the ground when walking varies inversely with the area A(in in^2) of the sole of the shoe when the shoes have a sole area of 40 in^2 The pressure is 4 lbs/in^2 find equation that relates these variables
A=
Answer:
[tex]A = \dfrac{40}{P}[/tex]
Step-by-step explanation:
Pressure [tex]p(in lbs/in^2)[/tex] varies inversely with the area [tex]A(in$ in^2)[/tex] of the sole of the shoe.
This is written as:
[tex]P \propto \frac{1}{A}\\ $Introducing the constant of variation$\\P = \dfrac{k}{A}[/tex]
When:
[tex]When: A= 40 in^2, P =4 lbs/in^2\\$Substituting into the equation\\P = \dfrac{k}{A}\\4 = \dfrac{k}{40}\\$Cross multiply\\k=4*40\\k=160\\Therefore, the equation that connect these variables is given as:\\P = \dfrac{40}{A}\\$In terms of P\\AP=40\\\\A = \dfrac{40}{P}[/tex]
What’s the correct answer for this?
Answer:
1) Antonio's statement
2) <A = 123
Step-by-step explanation:
1) Antonio's statement is incorrect. This is because the opposite angles of a quadrilateral add up to 180°. Erin was incorrect because the opposite angles of this quadrilateral are unequal.
2) 2x+7+5x-2 = 180° (opposite angles of quadrilateral)
Now
7x+5 = 180
7x = 175
x = 25
<A = 5x-2
= 5(25)-2
= 125-2
= 123
Simplify the expression 4x^3 2x^3
Answer:
Step-by-step explanation:
2 3x6
the 3 is an exponet so supost to be smaller
the answer- 2^3 x^6
i think its right
I WILL GIVE BRAINLIEST PLEASE ANSWER ASAP!!!
If the measure of angle 2 is (5 x + 14) degrees and angle 3 is (7 x minus 14) degrees, what is the measure of angle 1 in degrees?
2 lines intersect to form 4 angles. From top left, clockwise, the angles are 1, 2, 3, 4.
88 degrees
89 degrees
90 degrees
91 degrees
Answer:
<1 = 91
Step-by-step explanation:
<2 + <3 = 180
5 x + 14 + (7 x -14) = 180
Combine like terms
12x = 180
Divide by 12
12x/12 = 180/12
x =15
We want <1
<1 = <3 since they are vertical angle
<1 = 7x-14 = 7*15 -14 =105-14=91
Answer:
D, 91 degrees
Step-by-step explanation:
First, solve for x. Angles 2 and 3 add up to 180, so set up an equation:
(5x + 14) + (7x - 14) = 180
12x = 180
x = 15
Then, you know angles 1 and 2 also add up to 180, so solve for Angle 2
5(15) + 14= 89
180-89= 91, so angle 1 is 91 degrees.
Determine if two lines are parallel or perpendicular by comparing slopes
Question
Use slopes and y-intercepts to determine if the lines x = -1 and x = 0 are parallel.
Select the correct answer below:
Parallel
Not Parallel
Answer:
They are parallel because they are vertical lines, and all vertical lines are parallel.
Step-by-step explanation:
Solve for x
A) 5
B) 6
C)7
D)8
Answer:
[tex]7x+1+6x+101=180\\13x=78\\x=6[/tex]
What is the distance between the following points?
Answer:
square root of 72
Step-by-step explanation:
Answer:
(c) square root of 72
Step-by-step explanation:
khan academy answer :)
A parabola has a focus of (6,–6) and a directrix of y = –2. Which of the following could be the equation of the parabola?
Answer:
[tex]-8(y+4) =(x-6)^{2}[/tex]
Step-by-step explanation:
The standard form of a parabola is given by the following equation:
[tex](x-h)^{2} =4p(y-k)[/tex]
Where the focus is given by:
[tex]F(h,k+p)[/tex]
The vertex is:
[tex]V=(h,k)[/tex]
And the directrix is:
[tex]y-k+p=0[/tex]
Now, using the previous equations and the information provided by the problem, let's find the equation of the parabola.
If the focus is (-6,6):
[tex]F=(h,k+p)=(6,-6)[/tex]
Hence:
[tex]h=6\\\\k+p=-6\hspace{10}(1)[/tex]
And if the directrix is [tex]y=-2[/tex] :
[tex]-2-k+p=0\\\\k-p=-2\hspace{10}(2)[/tex]
Using (1) and (2) we can build a 2x2 system of equations:
[tex]k+p=-6\hspace{10}(1)\\k-p=-2\hspace{10}(2)[/tex]
Using elimination method:
(1)+(2)
[tex]k+p+k-p=-6+(-2)\\\\2k=-8\\\\k=-\frac{8}{2}=-4\hspace{10}(3)[/tex]
Replacing (3) into (1):
[tex]-4+p=-6\\\\p=-6+4\\\\p=-2[/tex]
Therefore:
[tex](x-6)^{2} =4(-2)(y-(-4)) \\\\(x-6)^{2} =-8(y+4)[/tex]
So, the correct answer is:
Option 3