A diver shines a light up to the surface of a flat glass-bottomed boat at an angle of 37◦ relative to the normal. If the indices of refraction of air, water, and glass are 1.0, 1.33, and 1.4 respectively, at what angle does the light leave the glass (relative to its normal)? Answer in units of ◦ .
Answers
Answer:
Approximately [tex]53^{\circ}[/tex], assuming that the upper and lower surfaces of the glass on this boat are parallel.
Explanation:
Assume that the upper and lower surfaces of the glass at the bottom of this ship are parallel. Refer to the diagram attached. The two normals would also be parallel to each other.
The following angles would be alternate interior angles between the two normals:
The angle at which the light enters the glass, andThe angle at which the light leaves the glass.Since the two normals are parallel to each other, these two angles would have the same value. Let [tex]\theta_{\text{glass}}[/tex] denote the value of both of these angles.
Let [tex]\theta_{\text{src}}[/tex] denotes the angle at which a beam of light leaves the original medium (angle of incidence.) Let [tex]\theta_{\text{dst}}[/tex] denote the angle at which this beam of light enters the new medium.
Let [tex]n_\text{src}[/tex] and [tex]n_\text{dst}[/tex] denote the refractive indices of the original and the new medium, respectively. By Snell's Law:
[tex]\begin{aligned}\frac{\sin(\theta_{\text{dst}})}{\sin(\theta_{\text{src}})} = \frac{n_{\text{src}}}{n_{\text{dst}}}\end{aligned}[/tex].
Let [tex]\theta_{\text{water}}[/tex] denote the angle at which the beam of light in this question leaves the water. Let [tex]\theta_{\text{air}}[/tex] denote the angle at which this beam of light enters the air. It is given that [tex]\theta_{\text{water}} = 37^{\circ}[/tex], while [tex]\theta_{\text{air}}[/tex] is the value that needs to be found.
Let [tex]n_{\text{air}}[/tex], [tex]n_{\text{water}}[/tex], and [tex]n_{\text{glass}}[/tex] denote the refractive index of air, water, and glass, respectively. By Snell's Law:
[tex]\begin{aligned}\frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})} = \frac{n_{\text{water}}}{n_{\text{glass}}}\end{aligned}[/tex].
[tex]\begin{aligned}\frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} = \frac{n_{\text{glass}}}{n_{\text{air}}}\end{aligned}[/tex].
Thus:
[tex]\begin{aligned} & \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \frac{\sin(\theta_{\text{glass}})}{\sin(\theta_{\text{water}})}\times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{glass}})} \\ =\; & \frac{n_{\text{water}}}{n_{\text{glass}}}\times \frac{n_{\text{glass}}}{n_{\text{air}}} \\ =\; & \frac{n_{\text{water}}}{n_{\text{air}}}\end{aligned}[/tex].
Since [tex]\theta_{\text{water}} = 37^{\circ}[/tex]:
[tex]\begin{aligned} & \sin(\theta_{\text{air}})\\ =\; & \sin(\theta_{\text{water}}) \times \frac{\sin(\theta_{\text{air}})}{\sin(\theta_{\text{water}})} \\ =\; & \sin(\theta_{\text{water}})\times \frac{n_{\text{water}}}{n_{\text{air}}} \\ =\; & \sin(37^{\circ}) \times \frac{1.33}{1.0} \\ \approx \; & 0.800 \end{aligned}[/tex].
Therefore:
[tex]\begin{aligned}\theta_{\text{air}} &= \arcsin(\sin(\theta_{\text{air}})) \\ & \approx \arcsin(0.800) \\ &\approx 53^{\circ} \end{aligned}[/tex].
In other words, this beam of light would leave the glass at approximately [tex]53^{\cic}[/tex] from the normal.
Related Questions
2. Height at point A is 30.0 meters with a cart mass of 200.0 kg initially at rest. Point B is at a height of 25.0 meters. Find the KE and PE at points A and B along with the velocity at point B assuming no friction. Show Your Work
Answers
At maximum height, velocity is zero and kinetic energy will be zero.
K.E(A) = 0
P.E(A) = mgh = 200 x 9.8 x 30 = 58,800 J
K.E(B) = P.E(A) - P.E(B)
K.E(B) = 58,800 J - (200 x 9.8 x 25)
K.E(B) = 58,800 J - 49,000 J
K.E(B) = 9,800 J
Velocity at point BK.E = ¹/₂mv²
v² = 2K.E/m
v² = (2 x 9800)/(200)
v² = 98
v = √98
v = 9.9 m/s
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how many times bigger is the radius of a helium atom then the radius of an alpha particle
Answers
The radius of a helium atom 4.8 times bigger then the radius of an alpha particle.
What is alpha particle?The structure of alpha particles, also known as alpha rays and alpha radiation, is similar to that of the helium-4 nucleus and has been made up of two protons as well as two neutrons bonded together.
What is helium?For welding metals like aluminum, helium was utilized as an inert gas environment. It is also employed in rocket propulsion.
The radius of a helium atom 4.8 times bigger then the radius of an alpha particle. More precisely than it's ever been, the diameter of the helium atom's nucleus, the alpha particle, had also been measured. Outcomes just point to a size of 1.6782 femtometers, 4.8 times more accurate than earlier readings.
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Select. The star cycle that is accurate
Answers
One stellar-mass star, red giants, white dwarfs, or planetary nebulae will make up the correct star cycle. Option C is correct.
What is the solar system?The satellites of the planet, countless comets, asteroids, and meteoroids, as well as the interplanetary medium, make up the solar system.
The complete question is;
"Choose the correct star life cycle.
A. Supernova, star as well as red giant, the nebula is incorrect.
B. Nebula, white dwarf, planetary nebula That is incorrect.
C. Planetary nebula, red giant, white dwarf, and star with a single stellar mass That is true!
D. Nebula, a star of one stellar mass, is not correct. It is correct if the star had four or more stellar masses."
Star of one stellar mass, red giant, white dwarf, and planetary nebula make up the proper life cycle.
Hence option C is correct.
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It is important that a frame of reference
Answers
Answer:
enable us to take in a wide variety of information, and process it based on our past experience and values.
Explanation:
A sinewave has a period (duration of one cycle) of 460 μs. What is the corresponding frequency of this sinewave in kHz, expressed to three significant figures (see Study Note 7.1 in the Using numbers (maths) booklet)?
If the frequency of the sinewave is now reduced by a factor of 4.25, what will be the new period value? Express your answer in ms to three significant figures.
Note: in the second part of this question, to avoid rounding errors in your calculations, use the full frequency value from the first part, not the rounded value to three significant figures.
Answers
Answer:
See below
Explanation:
Frequency = 1 / period
= 1 / 460 X 10^-6
2173.91 Hz = ~ 2.17 Khz
2.17391 kHz / 4.25 = .511 kHz <====new frequency
period = 1/frequency
= 1955 microseconds =1.96 ms
Answer:
2.17 kHz1.96 msExplanation:
You want to know the frequency in kHz of a sine wave with a period of 460 μs, and its period if the frequency is reduced by a factor of 4.25.
UnitsWhen you are interested in the frequency in kHz, it is convenient to use milliseconds (ms) to express the period. Milliseconds and kilohertz are inverse units.
The period of the given sine wave can be expressed in milliseconds as ...
460 μs = 460×(0.001 ms) = 0.460 ms
FrequencyThe frequency of the wave is 1/(0.460 ms) ≈ 2.17 kHz.
PeriodBecause period and frequency are reciprocals of each other, reducing the frequency by a factor of 4.25 increases the period by the same factor.
The new period is 4.25×0.460 ms = 1.96 ms.
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The heat capacity of nickel is 0.444 J/(g · °C). Calculate the amount of heat needed to raise the temperature of 18 g of nickel from 20 °C to 66 °C. Now imagine those same joules were used instead to accelerate the same mass of nickel from rest. What would be the final speed, in m/s?
Hints:
The formula for kinetic energy is: Ek=1/2 mv^2
For joules needed for heating, use the mass in grams, but for kinetic energy, convert the mass to kilograms.
Round your answer to the nearest whole number.
Answers
The final speed of the nickel at the given quantity of heat is determined as 202.1 m/s.
Final speed of the nickelApply the principle of conservation of energy.
Q = mcΔθ
Q = (18)(0.444)(66 - 20)
Q = 367.63 J
Q = K.E = ¹/₂mv²
2K.E = mv²
v = √(2K.E/m)
where;
v is the final speedv = √(2 x 367.63)/(0.018))
v = 202.1 m/s
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Object A attracts object B with a gravitational force of 10 newtons from a given distance. If the distance between the two objects is doubled, what is the new force of attraction between them?
Answers
Answer:
20 Newtons
Explanation:
10× 2
Answer: A.
2.5 newtons
Explanation: edmentum
Using Hooke's law, what happens when the displacement is tripled?
Answers
If the displacement is tripled then the spring force also is tripled.
What is Hooke's law?The amount of force required to stretch or compress the spring is known as the spring force. Its unit is Newton(N).
Froom the hooks law;
F = kx
Where,
F is the applied force
x is the displacement in case 1
Case 2;
x'=3x
F'=kx'
F'=3KX
F'=3x'
Where,
x' is the displacement when the force is tripled
F' is the force in the case2
Hence, if the displacement is tripled then the spring force also be tripled.
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(2.) Jerry first walks 5m to East, then 6m to N 60 E, then, she walks 16m to N30'W, 3 finally turns he face and moves 3V3m to south. What is her displacement and direction?
Answers
The displacement is determined to be 5.11 m after every direction is plotted on the page.
What is displacement?Displacement is defined as the shortest distance between the two points.
The steps in which Jerry walks;
5m to East
6m to N 60' E,
16m to N30'W,
Turn
3√3 m to the south.
Each and every direction is plotted on the page and obtained that the displacement is found as 5.11 m.
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what’s better csp or pv ?
Answers
Answer:
CSP
Explanation:
CSP systems store energy through Thermal Energy Storage technologies (TES), so power can be used when there isn't enough sunlight. PV systems, however, can't store thermal energy because they use direct sunlight, rather than heat. For this reason, CSP systems are better for energy storage and efficiency.
(The question and setup are below)
Answers
The gauge pressure at bottom of vaccine solution will be 16 kPa
Positive pressure is another name for gauge pressure. When a system's internal pressure exceeds that of its surroundings, it is said to be under positive pressure. Any leak that develops in the positively pressured system will therefore escape into the outside world. In contrast, a negative pressure chamber draws air into it.
Given As seen in the illustration, a syringe is held vertically. The container carries a 3 cm tall column of vaccine solution and has an open inner diameter of 1 cm. The needle contains a 2 cm column of vaccine solution and has an open inner diameter of 0.5 mm. At the needle's open end, the solution is exposed to the air. The vaccination solution has a density of 1200 kg/m3.
We have to find the gauge pressure at bottom of vaccine solution
Since the 5N force is applied to vaccine solution the pressure exerted will be much more
Hence the gauge pressure at bottom of vaccine solution will be 16 kPa
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Which statement describes how upwelling occurs
Answers
The statement best describes how upwelling occurs is Upwelling causes nutrients, minerals, and tiny organisms to rise. The correct option is C.
What is upwelling?Upwelling occurs when winds push surface water away from the shore and deeper water rises to fill the gap.
The upwelling is a cycle that shows up in the water bodies all over the planet. This cycle is basically addressing the ascending of the virus waters towards the surface where there's hotter environment, subsequently hotter water also.
With the ascent of the virus waters towards the surface, everything with it ascend also. The virus waters are plentiful in supplements and minerals, as well as minuscule creatures, like the Phyto-microscopic fishes.
This is a cycle that is vital for the presence of the environments in the bigger water bodies.
Thus, the correct option is C.
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One endpoint of a line segment is (1, 2) and the midpoint of the line segment is
(−1, 4). What is the other endpoint?
Answers
It then can be stated:
[tex]\large\red\hookrightarrow \rm \large \: \:X_m \: = \: \frac{X_1 \: + \: \: X_2 }{2} \: \: \: \: \: \: \: \:... (1) \\ [/tex]
[tex]\large\red\hookrightarrow \rm \large \: \:Y_m \: = \: \frac{Y_1 \: + \: \: Y_2 }{2} \: \: \: \: \: \: \: \:... (2)\\ [/tex]
Since, Xm = -1 and X1 = 1 we can write equation (1) as
[tex]\large\purple\longrightarrow \rm \large \: \:-1 \: = \: \frac{1 \: + \: \: X_2 }{2} \: \: \: \: \: \: \: \:... (1) \\ [/tex]
[tex]\large\purple\longrightarrow \rm \large \: \:-2 \: = \:1 \: + \: X_2[/tex]
[tex]\large\purple\longrightarrow \rm \large \: \: - 2 \: - 1 \: = \: X_2[/tex]
[tex]\large\purple\longrightarrow \rm \large \: \: - 3 \: = \: X_2[/tex]
Since , Ym = 4 and Y1 = 2 we can write the equation (2) as
[tex]\large\purple\longrightarrow \rm \large \: \:4 \: = \: \frac{2 \: + \: \: Y_2 }{2} \: \: \: \: \: \: \: \:... (2)\\ [/tex]
[tex]\large\purple\longrightarrow \rm \large \: \:8 \: = \: 2 \: + \: Y_2[/tex]
[tex]\large\purple\longrightarrow \rm \large \: \:8 \: - \: 2 \: = \: Y_2[/tex]
[tex]\large\purple\longrightarrow \rm \large \: \:6 \: = \: Y_2[/tex]
Therefore the other endpoint of the line (X2, Y2) is (-3 , 6)
An asteroid is moving along a straight line. A force acts along the displacement of the asteroid and slows it down. The asteroid has a
mass of 3.8x 104 kg, and the force causes its speed to change from 6700 to 4600m/s. (a) What is the work done by the force? (b) If the
asteroid slows down over a distance of 2.4x 10 m determine the magnitude of the force.
Answers
The work done by the force is 7. 89 * 10^8 Joules and the magnitude of the force is 3. 3* 10 ^7 Newton
How to determine the work done
a. Work done = force * change in velocity = Impulse
Note that:
Force = mg
mass = 3.8x 104 kg
g = 10m/s²
Substitute into the formula for force
Force = 3.8* 10^4 * 10= 3.8* 10^5 Newton
Change in velocity = 6700 - 4600 = 2100 m/s
Work done = force *change in velocity
Work done = 3.8* 10^5 * 2100
Work done = 7. 89 * 10^8 Joules
b. Magnitude of the force = work done ÷ distance
Force = [tex]\frac{7. 89 * 10^8 }{2.4* 10}[/tex]
Force = 3. 3* 10 ^7 Newton
Therefore, the work done by the force is 7. 89 * 10^8 Joules and the magnitude of the force is 3. 3* 10 ^7 Newton
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A magnetic field is __________ at one end of a bar magnet. What one word completes the sentence?
Answers
Answer: stronger
Explanation: the poles magnetism is concentrated at the poles
A magnetic field is the strongest at one end of a bar magnet.
What is meant by magnetic field ?The region in which the force of magnetism acts around a magnetic material or a moving electric charge is known as the magnetic field.
Here,
A bar magnet can be considered as a dipole with a north pole at one end and south pole at the other.
A magnetic field can be measured leaving the dipole at the north pole and returning the magnet at the south pole. If a magnet is cut in two, two magnets or dipoles are created out of one.
The magnetic poles, the region at each end of a magnet where the external magnetic field is strongest. A bar magnet suspended in Earth's magnetic field orients itself in a north–south direction. The north-seeking pole of such a magnet, or any similar pole, is called a north magnetic pole.
Here,
A magnetic field is the strongest at one end of a bar magnet.
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Which statement is a true catalyst in a reaction
Answers
Answer:
it alters the rate of chemical reaction
hope it is useful
If the atmospheric pressure is 15 lb/in, what is the corresponding downward force on the top of a horizontal square area 5 inches on each side ?
Answers
The corresponding downward force on the top of a horizontal square is 375 lb.in
What is pressure?The pressure is the amount of force applied per unit area. It is represented as
Pressure p = Force/Area
If the atmospheric pressure is 15 lb/in and area 5 inches on each side is
A = 5² = 25 in²
The force applied is
15 lb/in = F /25 in²
F = 375 lb.in
Hence, the corresponding downward force on the top of a horizontal square is 375 lb.in
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a 2kg aluminum block and a6kg copper block are connected by alight string over a frictionless pulley and fixed steel block of angle 30 degree .if the coefficient of friction on the surface is 0.2,find the acceleration of the two block and the tension in the string?
Answers
(a) The acceleration of the two block is determined as 0.93 m/s².
(b) The tension in the string is 5.78 N.
Net force on the aluminum block
The net force on the aluminum block is calculated as follows;
[tex]T - \mu_a m_a g = m_a a \ --- \ (1)[/tex]
Net force on the copper blockThe net force on the copper block is calculated as follows;
[tex]m_cg sin(30) - T -\mu _cm_c gcos(30) = m_c a --- (2)[/tex]
where;
T is tension in the stringma is mass of aluminummc is mass of copperg is acceleration due to gravitySolve for T using (1) and (2)
[tex]a = g(\frac{m_c sin30\ - \ \mu _c m_c cos30 \ - \mu_ a m_a}{ma_a + m_c} )\\\\a = 9.8(\frac{6 sin30\ - \ 0.2 (6) cos30 \ - 0.2 (6)}{2 +6} )\\\\a = 0.93 \ m/s^2[/tex]
Tension in the stringFrom equation (1);
T = μm_ag + m_aa
T = 0.2(2)(9.8) + 2(0.93)
T = 5.78 N
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A car is traveling along a straight road at a velocity of 30m/s when its engine cuts off. For the next ten seconds, the car slows down, and its average acceleration is a₁. For the next five seconds, the car slows down further, and its average acceleration is a₂. The ratio of the average acceleration values is a₁/a₂=1.5. Find the velocity of the car at the end of the initial ten-second interval.
Answers
The velocity of the car at the end of the initial ten-second interval is 15a₂ + 30.
Initial velocity of the carv = u + at
after 10 seconds;
v = 30 + 10a₁ --(1)
after 5 seconds
v₂ = v + 5a₂ ---- (2)
solve (1) and (2) together
v₂ = 30 + 10a₁ + 5a₂
but a₁/a₂=1.5
a₁ = 1.5a₂
v₂ = 30 + 10(1.5a₂) + 5a₂
v₂ = 30 + 15a₂ + 5a₂
v₂ = 30 + 20a₂
from equation (2), v₂ = v + 5a₂
v + 5a₂ = 30 + 20a₂
v = 15a₂ + 30
Thus, the velocity of the car at the end of the initial ten-second interval is 15a₂ + 30.
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How is volume flow related to cross sectional area? How is it related to fluid pressure?
Answers
Answer:
A venturi meter is used to measure the flow speed of a fluid in a pipe. The meter is connected between two sections of the pipe (the figure); the cross-sectional area A of the entrance and exit of the meter matches the pipe's cross-sectional area. Between the entrance and exit, the fluid flows from the pipe with speed V and then through a narrow ''throat'' of cross-sectional area a with speed v. A manometer connects the wider portion of the meter to the narrower portion. The change in the fluid's speed is accompanied by a change Δp in the fluid's pressure, which causes a height difference h of the liquid in the two arms of the manometer. (Here Δp means pressure in the throat minus pressure in the pipe.) Let A equal 5·a. Suppose the pressure p1 at A is 2.1 atm.
Compute the values of (a) the speed V at A and (b) the speed v at a that make the pressure p2 at a equal to zero.
(c) Compute the corresponding volume flow rate if the diameter at A is 4.0 cm.The phenomenon that occurs at a when p2 falls to nearly zero is known as cavitation. Please assume that the fluid is water. The water vaporizes into small bubbles.
A spring is compressed by 0.0880 m and is used to launch an object horizontally with a speed of 2.76 m/s. If the object were attached
to the spring, at what angular frequency (in rad/s) would it oscillate?
Answers
Answer:
Approximately [tex]3.14\; {\rm rad \cdot s^{-1}}[/tex].
Explanation:
Fact: the angular velocity [tex]\omega[/tex] of a simple harmonic oscillator is the ratio between the maximum velocity [tex]v_{\text{max}}[/tex] and the maximum displacement [tex]x_\text{max}[/tex] of this oscillator. In other words:
[tex]\begin{aligned} \omega &= \frac{v_{\text{max}}}{x_{\text{max}}}\end{aligned}[/tex].
Derivation of the previous equation:
Let [tex]A[/tex] denote the amplitude of this oscillation, and let [tex]\omega[/tex] denote the angular velocity.
The displacement of the oscillator at time [tex]t[/tex] would be:
[tex]x(t) = A\, \sin(\omega\, t)[/tex].
The maximum displacement of this oscillator would be [tex]x_\text{max} = A[/tex].
The velocity of this oscillator at time [tex]t[/tex] is the derivative of displacement with respect to time:
[tex]\begin{aligned} v(t) &= \frac{d}{d t}\, [x(t)] \\ &= \frac{d}{d t} [A\, \sin(\omega\, t)] \\ &= A\, \omega\, \cos(\omega\, t)\end{aligned}[/tex].
The maximum velocity of this oscillator would be [tex]v_\text{max} = A\, \omega[/tex].
Notice that dividing [tex]v_\text{max} = A\, \omega[/tex] by [tex]x_\text{max} = A[/tex] would give:
[tex]\displaystyle \frac{v_\text{max}}{x_\text{max}} = \frac{A\, \omega}{A} = \omega[/tex].
It is given that [tex]v_\text{max} = 2.76\; {\rm m\cdot s^{-1}}[/tex] while [tex]x_\text{max} = 0.0880\; {\rm m}[/tex]. Therefore:
[tex]\begin{aligned} \omega &= \frac{v_{\text{max}}}{x_{\text{max}}} \\ &= \frac{2.76\; {\rm m\cdot s^{-1}}}{0.0880\; {\rm m}} \\ &\approx 3.14\; {\rm s^{-1}}\end{aligned}[/tex].
(Radians per second.)
Using the terminal velocity from Q2 and the other necessary values given previously, calculate C for the coffee filter. Show all your work—you may use the equation editor or insert a picture of your handwritten work. What are the units for C?
terminal velocity from Q2 is 0.85 m/s
Answers
The drag coefficient (C) is determined from terminal velocity, density of the medium, projected area and mass of the object.
What is terminal velocity?
Terminal velocity is the constant speed of a freely falling object when the resistance of the medium through which it is falling prevents further acceleration.
The magnitude of terminal velocity is calculated as;
[tex]V_T = \sqrt{\frac{2mg}{\rho A C} }[/tex]
where;
m is mass of the objectg is acceleration due to gravityρ is the density of the medium (coffee)C is drag coefficientA is projected areaThus, the drag coefficient (C) is determined from terminal velocity, density of the medium, projected area and mass of the object.
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A baseball is thrown at angle of 65 degrees with an initial velocity of 45 m/s. How long will the baseball remain in the air?
Assume yi = yf =0 m
G= -9.81 m/s^2
A) 4.15 seconds
B) 8.31 seconds
C) 9.37 seconds
D) 1.44 seconds
Answers
The time for which the baseball remains in the air will be 9.37 sec. Option C is correct.
What is the maximum height achieved in projectile motion?It is the height achieved by the body when a body is thrown at the same angle and the body is attaining the projectile motion.
From Newton's first equation of motion;
[tex]\rm v_y= u_y+gt \\\\ 0 = usin \theta - gt \\\\ t = \frac{u sin\theta }{g}\\\\t = 4.68 \ sec[/tex]
The time the baseball remains in the air will be twice the time he travels for one side motion;
T' = 2t
T'=2 × 4.68 sec
T'= 9.37 sec
Hence for 9.37 sec, the baseball willl remains in the air. Option C is correct.
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There are several ways to model a compound one type of model is shown what is the chemical formula for the molecule modeled
Answers
C4H9O2 C4H8O C3H8O2is the answer
An object is located 26.0 cm from a concave lens with f = -54.0 cm. What is its magnification?
Answers
Answer:
28
Explanation:
Or from this equation, when we can write the magnification of talents is F times F plus the object distance knowledge, substitute the value to find out the magnification and that equals minus 54 centimeters Over -54 minus 26 centimeters. And we got the magnification of the image produced by The lens is 0.675.
Ross training for a half marathon which is 13.1 miles long. Within four months he has progressed to an 11 mile practice run if Ross takes two months off from training what will likely occur?
Answers
If Ross takes two months off from training, his fitness level will reduce in comparison to what it was two months ago.
In as little as 3–4 weeks after beginning strength training, Ross will probably experience weight increase, energy loss, diminished balance, diminished strength (making it tougher to carry out daily tasks), and overall fewer fitness levels.Many people mistakenly believe they lose muscle mass far more quickly than they actually do because their muscles' ability to store water and glycogen is declining.A decrease in strength and muscle mass, with beginners experiencing a smaller decline in strength than experienced lifters.Ross will experience Increased VO2 Max from exercise. VO2 Max is almost completely lost in people who train at lower intensities.learn more about fitness here: https://brainly.com/question/13490156
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A bike accelerates uniformly from rest to a speed of 10 m/s over a distance of 50 m. (a) Determine the acceleration of the bike. (b) how long will take to do that?
Answers
Answer:
a) 0.2m/s
b) 5m/s
Explanation:
a) acceleration=∆v/∆t
v=10
t=50
10/50=1/5
=0.2m/s
b) time= d/s
d=50m
s=10
50/10
=5m/s
Answer:
See below
Explanation:
Average speed = (0+ 10)/2 = 5 m/s
then to cover 50 m will take 50 m / 5 m/s = 10 seconds
change in velocity/ change in time = acceleration = 10/10 = 1 m/s^2
use ideas of electromagnetic induction to explain how the input voltage is transformed into an output voltage
Answers
With the help of a transformer input voltage is transformed into an output voltage
What is induced voltage?Electromagnetic induction is what causes the induced voltage. Electromagnetic induction is the process of generating emf (induced voltage) by subjecting a conductor to a magnetic field.
In this case, a magnet is pushed in and out of a wire coil attached to a high-resistance voltmeter.
Typically, a transformer's primary winding is attached to the input voltage source and changes electrical power into a magnetic field.
The secondary winding's role is to turn this alternating magnetic field into electricity, generating the necessary output voltage.
Hence with the help of a transformer input voltage is transformed into an output voltage.
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Question 2 of 10
Which two types of energy does a book have as it falls to the floor?
Answers
The practice of science can answer only scientific questions. And scientific
questions guide the design of investigations. What must be true of the
possible answers to a scientific question?
OA. They could be shown to be false by evidence.
B. They are at odds with established scientific theories.
C. They support an established scientific theory.
OD. They do not require the use of physical measurements.
SUBMIT
Answers
Evidence might be used to demonstrate their falsity. must apply to all potential solutions to a scientific topic.Option A is correct.
What is a Scientific hypothesis?A scientific hypothesis is the main element in the scientific method and experiment.
It is said that a hypothesis is a scientific hypothesis. The majority must agree on it, or it must be done after thorough experimentation.
Only scientific inquiries can have their answers provided by scientific endeavor. Scientific concerns have an impact on the research's design as well.
Evidence might be used to demonstrate their falsity. must apply to all potential solutions to a scientific question.
Hence option A is correct.
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