3. (3, 5) and (k, 9), slope = 1/2
Linear relationships unit 3 lesson 10 grade 8 openuprespurces

The value of AOB and BOC based in the information given in the circle will be 53°.

From the information given, the central angle is the angle that the vertex is at the center of the circle.

It was stated that OB bisects AOC. Therefore, since AOB is 53°, BOC is also 53°.

The value of AOC will now be:

= AOB + BOC

= 53° + 53°

= 106°

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Answer: You have already given the answer in the question! You can make a small shoe box.

The equation of the line in point-slope form is: C. y − 5 = −(x − 2).

A line with a slope (m) and a point (a, b) is represented in point-slope form as, y - b = m(x - a).

Slopes of perpendicular lines are negative reciprocals of each other. Find the slope of the line in the graph given as follows:

Slope (m) = rise/run = 3 units/3 units = 1

Negative reciprocal of 1 is -1.

The slope of the line would be m = -1.

Substitute m = -1 and (a, b) = (2, 5) into y - b = m(x - a) to wrote the equation:

y - 5 = -1(x - 2)

y − 5 = −(x − 2)

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Answer:

879.6452 cm

Step-by-step explanation:

The curved surface area of a cylinder is calculated using the formula, curved surface area of cylinder = 2πrh, where 'r' is the radius and 'h' is the height of the cylinder.

diameter = 2r

14=2(r)

7=r

2(π)(7)(20) cm

2(3.14159)(7)(20)

879.6452

Let's check

Remove root over and simplify 1+cot²Ø

Putting root over

Sin can be found also along with csc

Answer:

5

Step-by-step explanation:

Given expression:

[tex]\dfrac{6^{n+2}-6^n}{6^{n+1}+6^n}[/tex]

[tex]\textsf{Apply exponent rule} \quad a^{b+c}=a^b \cdot a^c[/tex]

[tex]\implies \dfrac{6^n6^2-6^n}{6^n6^1+6^n}[/tex]

Factor:

[tex]\implies \dfrac{6^n(6^2-1)}{6^n(6^1+1)}[/tex]

Cancel [tex]6^n[/tex] :

[tex]\implies \dfrac{(6^2-1)}{(6^1+1)}[/tex]

Simplify:

[tex]\implies \dfrac{36-1}{6+1}[/tex]

[tex]\implies \dfrac{35}{7}[/tex]

[tex]\implies 5[/tex]

Answer:

finished this question is from matric it is very easy

Answer:

(x - 8x)²

(x - 8x) (x - 8x).

using the identity

( a - b) ² = a² + b² - 2ab

a = x

b = 8x

x² + 64x - 16x²

a)The total inside length of the curved ends of the track will be 25.13 meters

b)The total distance around the inside of the track will be 275.13 meters

c)The area inside the track is 10050 square meters.

The space occupied by any two-dimensional figure in a plane is called the area. The space occupied by the circle in a two-dimensional plane is called the area of the circle.

Given that:-

A stadium has a central rectangular area 125m long by 80m wide. there are two semi-circular ends. a running track goes all the way around.

a) what is the total inside length of the curved ends of the track?

The length of the curved track means it is a perimeter of the circle so the radius of the semicircle will be 4 meters.

So the length will be = π r + πr = 2 πr

                                  = 2 x π x 4 = 25.13

b) what is the total distance around the inside of the track?

The total distance of the track will be the sum of the length of the two semicircles and the longer side of the rectangle.

Total length = 125 + 125 + 25.13

                     = 275.13 meters

c) what is the area inside of the track?

The area will be equal to the area of the two semicircular tracks and the rectangular track.

Total Area = Area of semicircle + Area of semicircle + Area of rectangle

                  = ( π/2 ) r² + (π/2) r² + ( L x W )

                  =  π  r² + (  L x W)

                  = π ( 4 )² + ( 125 x 8 )

                  = 10050.26 square meters.

Therefore the total inside length of the curved ends of the track will be 25.13 meters. The total distance around the inside of the track will be 275.13 meters. The area inside the track is 10050 square meters.

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[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:m\overbrace{DB}= 90 \degree[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex] \qquad \tt \rightarrow \: m \overbrace{DB} + m \overbrace{TB} = 180 \degree[/tex]

[ linear pair ]

[tex] \qquad \tt \rightarrow \: m \overbrace{DB} + 90 \degree = 180 \degree[/tex]

[tex] \qquad \tt \rightarrow \: m \overbrace{DB} = 180 \degree - 90 \degree[/tex]

[tex] \qquad \tt \rightarrow \: m \overbrace{DB} = 90 \degree[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

The two equivalent equations are d₁= 2a/d₂ and d₂= 2a/d₁ , Option 2 and 5 is the right answer.

Rhombus is a quadrilateral with all the sides equal to each other.

It is given that d₁ and d₂ are the lengths of the diagonals.

and Area = a

a = (1/2) d₁ * d₂

       d₁ * d₂ = 2a

       It can be written as

        d₁= 2a/d₂

a = (1/2) d₁ * d₂

        d₂= 2a/d₁

Therefore Option 2 and 5 are the correct answer.

The options of this question are:

1.  d₁=2Ad₂

2. d₁= 2A/d₂

3. d₂= d₁/2A

4. d₁= 2A/d₂

5. d₂= 2A/d₁

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[tex]\frac{log 25}{log 8}[/tex] is the expression Devonte used the change of base formula to approximate log Subscript 8 Baseline 25.

Given that, Devonte used the change of base formula to approximate log Subscript 8 Baseline 25.

We need to determine the expression did Devonte use.

The change of base formula says [tex]log_{a} b=\frac{log_{c}b }{log_{c}a}[/tex]. It means to change the base of a logarithm logb b a, we just use division [tex]\frac{log a}{log b}[/tex] where these logarithms can have any positive number as a base.

Now, log Subscript 8 Baseline 25 [tex]=log_{8}25[/tex]

[tex]=\frac{log_{10}25 }{log_{10}8}=\frac{log 25}{log 8}[/tex]

Therefore, [tex]\frac{log 25}{log 8}[/tex] is the expression Devonte used the change of base formula to approximate log Subscript 8 Baseline 25.

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Answer:

D

Step-by-step explanation:

Answer:

No, it's not.

Answer:

[tex]\mathsf {y =\frac{15}{7}x }[/tex] < [tex]\mathsf {y=\frac{13}{6}x }[/tex] < [tex]\mathsf {y=\frac{11}{5}x }[/tex] < [tex]\mathsf {y=\frac{21}{9}x }[/tex] < [tex]\mathsf {y= \frac{19}{8}x}[/tex]

Step-by-step explanation:

Finding the unit rate of the graph :

Now, the equations with greater unit rates (in increasing order) are :

Answer:

-15

Step-by-step explanation:

-13-2= -15

(to check:2+ -15= -13)

[tex]\huge\text{Hey there!}[/tex]

[tex]\mathsf{2 + [blank] = -13}[/tex]

[tex]\large\textbf{CONVERT TO: }[/tex]

[tex]\mathsf{2 + b = -13}[/tex]

[tex]\mathsf{b + 2 = -13}[/tex]

[tex]\large\textbf{SUBTRACT 2 to BOTH SIDES: }[/tex]

[tex]\mathsf{b + 2 - 2 = -13 - 2}[/tex]

[tex]\large\textbf{SIMPLIFY IT!}[/tex]

[tex]\mathsf{b = -13 - 2}[/tex]

[tex]\mathsf{b = -15}[/tex]

[tex]\huge\text{Therefore, the mystery number is: \boxed{\mathsf{-15}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

Answer:

45 feet

Step-by-step explanation:

if 1 cm = 3 ft, we can scale up the drawing from there.

We are multiplying each cm by 3, and considering that length to be 3 feet.

If we had 2 cm, (multiply both by 3) we would have 6 feet.

So, if we had 15 cm, we also need to convert this scale length into actual length. We do this by multiplying

15 × 3 = 45

So, we know that the actual length of the playground in feet is 45 feet.

Answer:

x° = 47°

Step-by-step explanation:

The sum of the measurements of three interior Angles in a triangle is 180°.This is known as angle sum property.Same case is here.

78°,55° and x° are interior angles here.

So,

Solving for x°,

Hence,the value of x° is 47°.

Problem 10

The two functions are inverses of each other. Why? Because we can think of f(x) = (x-7)/(-2) as y = (x-7)/(-2).

Swap x and y to get x = (y-7)/(-2). Solving for y leads to y = -2x+7 showing that g(x) = -2x+7 is the inverse of f(x) = (x-7)/(-2). This process can be done in reverse to get the same result.

===================================================

Problem 11

y = a(6)^(t/2)

y = a( 6^(1/2) )^t

y = a(2.4494897)^t

y = a( b )^t

where b = 6^(1/2) = 2.4494897 approximately

Set b equal to 1+r and solve for r

1+r = 2.4494897

r = 2.4494897-1

r = 1.4494897

This rounds to about r = 1.45

The r value is the decimal form of the percentage, which means we move the decimal point over two spots to the right to get 145% approximately

Answers:

The equation is roughly y = a(1 + 1.4494897)^t

The growth rate is approximately 145%

===================================================

Problem 12

You have the correct answer. Nice work.

===================================================

Problem 13

You are very close to the correct answer. However, you're missing the base of the log.

The answer should be [tex]\log_{49}(343) = \frac{3}{2}[/tex]. So you'll need to write in a small "49" under the log.

The general rule is that exponential equations in the form [tex]b^x = y[/tex] are equivalent to the log version of [tex]\log_{b}(y) = x[/tex]. For each equation, b is the base. The idea of logs is to isolate the exponent.

The option third ∠R ≅ ∠V is correct because line segment RS and UV are parallel which is crossed by a transversal RV.

It is defined as the law to prove that the two triangles have the same shape, but it is not compulsory to have the same size. The ratio of the corresponding sides is in the same proportions and the corresponding angles are congruent.

The question is incomplete.

The complete question is in the picture, please refer to the attached picture.

We have given two triangles:

Triangle RST and Triangle VUT

AS we can see Line segment RS and UV are parallel.

Which is crossed by a transversal RV.

The angle SRV = Angle RVU

Thus, the option third ∠R ≅ ∠V is correct because line segment RS and UV are parallel which is crossed by a transversal RV.

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Answer:

c

Step-by-step explanation:

1 is the values are in the range of the function graphed below. Option E is corect.

The domain denotes all potential x values, while the range denotes the domain's possible y values.

The domain is the value of x which lies between the -2 ≤ x  ≤ 1.While the range shows the value of y which is equal to  1.

Hence, option E is correct

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Answer:

69 meters squared

Step-by-step explanation:

You can split the shape into two small rectangles by drawing a vertical line. Then, you can solve for the areas of the two rectangles separately and then add them together.

The larger rectangle would have an area of 5 * 12, or 60 m^2.
The smaller rectangle would have an area of 3 * 3, or 9 m^2.
Simply add those together and the total area would be 69 m^2.

Answer:

Area is 69 m

Step-by-step explanation:

Answer:

The decimal 0.345 expressed as a fraction is 69200 .

To solve this problem, you will first use the Angle Sum Property to determine the value of x after creating an algebraic equation, combining like terms, and subtracting from both sides of an equation.

The Angle Sum Property states that all interior angles of a triangle will summate to 180º.

An equation can be created to find this when you are given two angles and missing a third. That third angle can be referred to as x in this scenario.

Adding the two known angles and the unknown angle will result in a sum of 180º. This means that our unknown is x and can therefore be placed in an equation:

[tex]65+42+x=180[/tex]

Combine the like terms by combining the constants on the left side of the equation using addition:

[tex]65+42+x=180[/tex]

[tex]107+x=180[/tex]

After combining like terms, subtract 107 from both sides of the equation:

[tex]107 - 107 +x = 180-107[/tex]

[tex]\boxed{x=73}[/tex]

The final answer is x = 73 degrees.

Answer:

-3 + -2x5 / -4 + -1 = 5

(-3 + -2)* 5/ (-4-1) = 5.

Answer:

18

Step-by-step explanation:

The exterior angles of any regular polygon add to 360°, so the answer is 360/20 = 18

If [tex]f(x)[/tex] has a removable discontinuity at [tex]x=a[/tex], then the limit

[tex]\displaystyle \lim_{x\to a} \frac{f(x)}{x-a}[/tex]

exists and is finite.

A non-removable discontinuity at [tex]x=b[/tex] would entail a non-finite limit,

[tex]\displaystyle \lim_{x\to b} \frac{f(x)}{x-b} = \pm\infty[/tex]

or the limit does not exist (which could be due to the limits from either side of [tex]x=b[/tex] not matching or existing).

For a rational function, we want

[tex]f(x) = \dfrac{p(x)}{q(x)}[/tex]

where [tex]p[/tex] and [tex]q[/tex] are polynomials in [tex]x[/tex]. To get a removable discontinuity at [tex]x=a[/tex], both [tex]p[/tex] and [tex]q[/tex] must be divisible by [tex]x-a[/tex], and the limit of their quotient after removing these factors still exists. That is,

[tex]\displaystyle \lim_{x\to a} f(x) = \lim_{x\to a} \frac{p(x)}{q(x)} = \lim_{x\to a}  \frac{(x-a)p^*(x)}{(x-a)q^*(x)} = \lim_{x\to a} \frac{p^*(x)}{q^*(x)} = \frac{p^*(a)}{q^*(a)}[/tex]

On the flip side, we get a non-removable discontinuity [tex]x=b[/tex] if [tex]p[/tex] is not divisible by [tex]x-b[/tex], in which case

[tex]\displaystyle \lim_{x\to b} f(x) = \lim_{x\to b} \frac{p(x)}{q(x)} = \lim_{x\to b}  \frac{p(x)}{(x-b)q^*(x)} = \frac{p(b)}{0\times q^*(b)}[/tex]

and this is undefined.

Suppose [tex]f(x)[/tex] has a non-removable discontinuity at [tex]x=-5[/tex] and a removable one at [tex]x=4[/tex]. Then one such function could be

[tex]f(x) = \dfrac{x-4}{(x-4)(x+5)} = \dfrac{x-4}{x^2+x-20}[/tex]

The marked price of the projector is $50,000.

The price of the projector after the discount can be represented with:

(100 - 10%)x - 90%x = 0.90x

Where x is the marked price

The price of the projector after the VAT is : (1.13) x 0.90x = 1.02x

Difference in price = 1.02x - 0.90x = 5850

0.12x = 5850

x = 5850 / 0.12

x = $50,000

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