Find the determinant of the coefficient matrix 3x+4y=0 -2x+3y=17

Answers

Answer 1

The determinant of the coefficient matrix 3x+4y=0 and -2x+3y=17 is 17.

What is matrix?

A collection of numbers lined up in rows and columns to form a rectangular array is called a matrix. The elements, or entries, of the matrix are the numbers.

Given:

A system of equations,

3x+4y=0

-2x+3y=17.

To find the determinant,

we will find the matrix from Cramer's rule,

A =

[tex]\left[\begin{array}{cc}3&4\\-2&3\end{array}\right][/tex]

So, determinant of matrix A

ΔA = 3 x 3 -(4 x -2)

ΔA = 9 + 8

ΔA  = 17.

Therefore, the determinant is 17.

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Related Questions

Solve for m:-
2(m-5) = m-3

Answers

The value of m in the given equation will be 7.

Steps to solve the linear equation :

⇒2(m-5) = m-3

Bring RHS (Right hand side) terms to LHS(left hand side) of the equation,

⇒2(m-5) - (m-3) = 0

Now open the brackets,

⇒2m - 10 - m + 3  = 0

Now solve for m,

⇒2m - m - 10 + 3 = 0

⇒m - 10 + 3 = 0

⇒m - 7 = 0

Taking 7 to the RHS of the equation,

⇒m = 7

∴ The value of m is 7

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To solve for m in the equation 2(m-5) = m-3, we can start by distributing the 2 on the left side of the equation:

2m - 10 = m - 3

Next, we can add 3 to both sides of the equation to get:

2m - 10 + 3 = m

This simplifies to:

2m - 7 = m

Now we can subtract m from both sides:

2m - m - 7 = 0

This simplifies to:

m - 7 = 0

Finally, we can add 7 to both sides to solve for m:

m = 7

So the solution for m is 7.

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