The determinant of the coefficient matrix 3x+4y=0 and -2x+3y=17 is 17.
What is matrix?A collection of numbers lined up in rows and columns to form a rectangular array is called a matrix. The elements, or entries, of the matrix are the numbers.
Given:
A system of equations,
3x+4y=0
-2x+3y=17.
To find the determinant,
we will find the matrix from Cramer's rule,
A =
[tex]\left[\begin{array}{cc}3&4\\-2&3\end{array}\right][/tex]
So, determinant of matrix A
ΔA = 3 x 3 -(4 x -2)
ΔA = 9 + 8
ΔA = 17.
Therefore, the determinant is 17.
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Solve for m:-
2(m-5) = m-3
The value of m in the given equation will be 7.
Steps to solve the linear equation :
⇒2(m-5) = m-3
Bring RHS (Right hand side) terms to LHS(left hand side) of the equation,
⇒2(m-5) - (m-3) = 0
Now open the brackets,
⇒2m - 10 - m + 3 = 0
Now solve for m,
⇒2m - m - 10 + 3 = 0
⇒m - 10 + 3 = 0
⇒m - 7 = 0
Taking 7 to the RHS of the equation,
⇒m = 7
∴ The value of m is 7
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To solve for m in the equation 2(m-5) = m-3, we can start by distributing the 2 on the left side of the equation:
2m - 10 = m - 3
Next, we can add 3 to both sides of the equation to get:
2m - 10 + 3 = m
This simplifies to:
2m - 7 = m
Now we can subtract m from both sides:
2m - m - 7 = 0
This simplifies to:
m - 7 = 0
Finally, we can add 7 to both sides to solve for m:
m = 7
So the solution for m is 7.