Answer
T-axis of his graph should go from 0 to at least 720, and the h-axis of his graph should go from 0 to at least 40.
Explanation
We know form our problem that is the total pay, is the number of hours, and $18 is the rate per hour, so putting it all into an equation we get:
We also know that James works between 25 and 40 hours each week, so we can replace the number of hours in our equation to get how much he can make per week:
- For
- For
Now we know that he can make between $450 and $720 working between 25 and 40 hours per week. So, to best show this information the T-axis should go from 0 to at least 720; otherwise, we won't be able to show values between $450 and $720. Similarly, the h-axis should go form 0 to at least 40; otherwise, we wont be able to show values between 25 and 40 hours.
find x with two triangles
Answer:
x=12
Step-by-step explanation:
Given that there is only one expression given in each triangle, if we only use the information in a single triangle, there is no way to set up an equation that we could solve to find the expression. (For this situation, at best we could use the triangle sum theorem to say that the three angles in one triangle added to 180°, but since we don't know the other two angles, that's 3 unknowns with only 1 equation... that's not solvable)
The only way to solve this problem is to make a relationship of some sort between the two triangles.
Proving a relationship between triangles - option 1
You may have a theorem about the Third angles of two triangles... "Given two arbitrary triangles, [tex]\triangle ABC[/tex] and [tex]\triangle D E F[/tex], if [tex]\angle A \cong \angle D[/tex] and [tex]\angle B \cong \angle E[/tex], then [tex]\angle C \cong \angle F[/tex] "
If you have this, then the third angles are congruent.
In a more general situation of a similar problem (one in which you don't know two of the angles to begin with), it might be easier to prove triangle congruence, or triangle similarity.
Other Relationships between triangles
There are two main relationships between triangles: similarity and congruence.
Most people learn about congruence first.
In the situation for this problem, the two triangles happen to be congruent (we'll prove it shortly), which implies that all corresponding angles between shapes are congruent (and all corresponding sides between shapes are congruent).
For the purpose of solving for things related to angles, proving that the two triangles are similar is enough to know that angles between triangles are congruent (sides wouldn't necessarily be equal, but would be proportional, and since we're not solving for anything related to side lengths, proving that the triangles are similar would be enough).
Proving a relationship between triangles - option 2 - congruence
Notice that the triangle on top has two angles with markings (a single mark, and a double mark), and one side with a marking (a single tick). These three pieces are in a configuration of ASA (the side is between the two angles).
Looking at the bottom triangle, it also has angles and sides with corresponding markings, and they are also in an ASA configuration.
Thus, by ASA congruence, these triangles are congruent triangles.
Knowing the triangles are congruent (even though we only used 3 parts), the rest of the corresponding parts (including the third angles) are also congruent.
Proving a relationship between triangles - option 3 - Similarity
For similarity, the process is similar to proving congruence, however the theorems we have for proving similarity are different.
SSS, SAS, or AA similarity.
Since the triangles in our problem do have two angles that are congruent, by AA similarity, the triangles are "similar".
Knowing the triangles are similar (even though we only used 2 parts), the last set of corresponding angles are also congruent.
Building our equation
Since the third angle of each triangle is congruent, by definition of congruent angles, the measures of each of those two angles are equal, and so we can build an equation knowing that the two expressions are equal to each other:
[tex]3x-7=2x+5[/tex]
Solving for x
From there, we need some algebraic properties equality to solve for x.
Subtract 2x from both sides...
[tex](3x-7)-2x=(2x+5)-2x\\x-7=5[/tex]
add 7 to both sides...
[tex](x-7)+7=(5)+7\\x=12[/tex]
Extension
Knowing the value for x, we could solve for the measure of the angles, if that had been requested. Simply substitute 12 back into the expressions for the angle measure (the results should be the same for both angles, since they were congruent angles)
[tex]3(12)-7\\36-7\\29[/tex] [tex]2(12)+5\\24+5\\29[/tex]
So, if we had been asked, the measure of the angle is 29°
In the fall, you charge people $8 for going to their house to rake leaves, then
$5 for every hour you rake. If you make $38 one day, how many hours did you
spend raking?
Need number 5 answered please!!!
Answer:
-3 is a zero of the function False
-1 is a zero of the function True
1 is a zero of the function False
2 is a zero of the function True
4 is a zero of the function False
Evaluate the given function. The values of the independent variable are approximate.
f(x) = 3x² - 3x, find f(3.52) and f(-8.77)
The values of f(3.52)=26.61 and f(-8.77)=257.05
An assignment of an element from set Y to each element of set X constitutes a function from set X to set Y. The sets X and Y are collectively referred to as the function's domain and codomain, respectively.
The notation f: X→Y denotes a function, its domain, and its codomain. The value of a function at an element x of X, denoted by the symbol f(x), is referred to as the image of x under f or the value of f applied to the argument x.
The given function is f(x) = 3x²-3x =3x(x-1)
f(3.52)=3*(3.52)(3.52-1)
=26.61
f(-8.77)=3*(-8.77)(-8.77-1)
=257.05
Therefore, the values of f(3.52)=26.61 and f(-8.77)=257.05
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A farmer raises only cows and Sheep. He wants to raise no more than 16 animals, including no more than 12 sheep. He spends birr 5 to raise a cow and Br 2 to raise a sheep. He has Br 50 available for this purpose. Cows sell birr 100 and sheep birr 50. Required: How many of each animal should he raise to maximize profit? What is the maximum profit?
The maximum profit will be 956 birrs for both cows and sheep.
What is profit?The amount of money earned by any seller on the cost price is called the profit.
Given that:-
A farmer raises only cows and Sheep. He wants to raise no more than 16 animals, including no more than 12 sheep. He spends birr 5 to raise a cow and Br 2 to raise a sheep. He has Br 50 available for this purpose. Cows sell birr 100 and sheep birr 50.From the given data we can see that the total number of animals cows and sheep is 16.
C + S = 16
To raise a cow need 2 Br
To raise Sheep need 5 Br
The number of sheep is 12 and cows 4.
So the amount required to raise sheep and cows is:-
Sheeps = 12 x 2 = 24 Br
Cows = 4 x 5 = 20 Br
Total = 44 Br
The selling price of cows and sheep are 100 and 50 Br.
Cows = 100 x 4 = 400Br
Sheeps = 50 x 12 = 600 Br
Total = 1000 Br
So the profit will be calculated as follows:-
P = 1000 - 44 = 956 Br
Therefore the maximum profit will be 956 birrs for both cows and sheep.
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Determine the rank of A
Answer:
The rank of a matrix is the number of nonzero rows in the reduced matrix, so the rank is 3. option (C)
Step-by-step explanation:
Echelon Form : it is used to find the rank of matrix by reducing rows into zeros then the number of non zero rows is the rank of the matrix
[tex]\left[\begin{array}{ccccc}1&-1&5&-2&2\\2&-2&-2&5&1\\1&0&-12&9&-3\\-1&1&7&-7&1\end{array}\right][/tex]
apply row operations:
R₂= R₂ - 2 R₁
[tex]\left[\begin{array}{ccccc}1&-1&5&-2&2\\0&0&-12&9&-3\\1&0&-12&9&-3\\-1&1&7&-7&1\end{array}\right][/tex]
R₃= R₃ - R₁
[tex]\left[\begin{array}{ccccc}1&-1&5&-2&2\\0&0&-12&9&-3\\0&0&-17&11 &-5\\-1&1&7&-7&1\end{array}\right][/tex]
R₄ = R₄ +R₁
[tex]\left[\begin{array}{ccccc}1&-1&5&-2&2\\0&0&-12&9&-3\\0&0&-17&11 &-5\\0&0&12&-9 &3\end{array}\right][/tex]
R₄ = R₄ +R₃
[tex]\left[\begin{array}{ccccc}1&-1&5&-2&2\\0&0&-12&9&-3\\0&0&-17&11 &-5\\0&0&0&0 &0\end{array}\right][/tex]
we can clearly see that after performing row operations there are 3 non zero rows,
therefore the Rank of the given matrix is 3
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1/a + 1/b = 1/2 (solve for a)
Answer:
1/a+ 1/b = 1/2
Adding the fractions we get
b+a/ab=1/2
cross Multiplying the denominator we get,
b+a=ab/2
a= ab/2 -b
Answer:
a = 1/(1/2 + 1/b)
Step-by-step explanation:
1/a + 1/b = 1/2
1/a = 1/2 - 1/b
1 = a(1/2 - 1/b)
1/(1/2 + 1/b) = a
On a zip-line course, you are harnessed to a cable that travels through the treetops. You start at Platform A and zip to each of the other platforms. How far do you travel from Platform B to Platform C? Write your answer to the nearest tenth of a foot.
The distance between B and C is 26.926 units.
What is distance formula?The distance between coordinate P(x1 , y1) and coordinate Q(x2 , y2) is calculated using the distance formula: d = √[(x2 - x1)² + (y2 - y1)²]
The zip-line course distance from platform A to platform F are given
Coordinates of B = (-25, -20)
coordinates of C = (-15, 5)
Now, the distance between B and C is
= `√(5-(-20))² +((-15)-(-25))²
=√25² + 10²
= √725
= 26.926 units.
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The table shows values for a quadratic function.
X
y
0
2
3
18
4
32
50
6
72
What is the average rate of change for this function for the interval from x = 2
to x = 4?
16
A
5
The average rate of change for this function for the interval from x = 2
to x = 4 is 20
How to determine the average rate of change?The function is given as:
x y
0 18
2 32
3 50
4 72
The average rate of change at the interval from x = 2 to x = 4 is calculated using:
m = (f(4) - f(2))/(4 - 2)
Using the table values, we have:
m = (72 - 32)/(4 - 2)
Evaluate
m = 20
Hence, the average rate of change is 20
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Consider all seven-digit numbers that can be created from the digits 0-9 where the first and last digits must be odd and no digit can
repeat. What is the probability of choosing a random number that starts with 5 from this group? Enter a fraction or round your answer to
4 decimal places, if necessary.
Answer:
1/4 or 0.25
Step-by-step explanation:
The total possibilities of any 7 digit number using 0-9 is :
9×10×10×10×10×10×10=9000000
To work out the total possibilities in this question :
We look at the conditions :
The first digit can only be 5 numbers :
1 , 3 , 5 , 7 , 9
Now we subtract 5 from 9 :
9-5 = 4
Since no repeats for 2 , 3 , 4, 5, 6:
9 , 8 , 7 , 6 , 5,
5 possibilities for the last digit :
Total possibilities for this code :
4 × 9 × 8 × 7 × 6 × 5 × 5 = 302400
If it begins with 5 that is only 1 possibility for the first digit
1 × 9 × 8 × 7 × 6 × 5 × 5 = 75600
Now we make a fraction :
75600÷302400
Dividing top and bottom by 75600 gives you 1/4 or 0.25
Hope this helped and have a good day
Answer:
Step-by-step explanation:
Comment
The first digit and the last digit are both odd. That tells you that so far what you have is one of 5 digits for the first digit and and one of 4 for the last digit. 4 because you can't repeat the first digit.
5, , , , , ,4
2 digits are gone 8 remain.
5* 8 * 7* 6* 5* 4* 4 = 134400
Part 2
Only one number can go at the beginning, and that is a 5. Everything else remains the same.
1 * 8 * 7 * 6 *5 * 4 * 4 = 26880
P(picking a number beginning with a 5 is 25880 /13440) = 0.2
Equations Of Parabolas (Conics) Unscramble
The match is shown in the picture for the function of a parabola and the graph of a parabola.
What is a parabola?It is defined as the graph of a quadratic function that has something bowl-shaped.
As we know the standard form of the parabola is:
y = a(x - h)² + k
If a > 0 (parabola opens upwards)
If a < 0 (parabola opens downwards)
or
x = a(y - h)² + k
If a > 0 (parabola opens right side)
If a < 0 (parabola opens left side)
Here (h, k) is the vertex of the parabola and a is the leading term.
Thus, the match is shown in the picture for the function of a parabola and the graph of a parabola.
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Find the equation of the line through point
(2, 2) and parallel to y= x+4.
Answer:
The equation of a parallel line is y = x
Step-by-step explanation:
Parallel lines have the same slope
hence the new lines slope is = 1
The equation of the line is written in the slope-intercept form,
y = mx + b
where m represents the slope
b represents the y-intercept
where the format of a point is (x, y)
Given:
through point (2, 2) parallel to y = x + 4we need to find b, y = 1x + b
we can plug in the point (2, 2)
2 = 1(2) + b
2 = 2 + b
0 = b
Hence, the equation of the line through point
(2, 2) and parallel to y = x+4 is y = x
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A ship leaves port at 1 pm traveling north at the speed of 30 miles/hour .at 3 pm the ship adjusts its course20° eastward. Sketch a diagram to show the path the ship moved and the distance the ship is from the port. And how far the ship is from the port at 4pm?
The ship is 88.8 miles far from the port at 4 pm.
Given,
The displacement from 1 to 3 in the afternoon.
D1 = 30 miles/hr × 2 hr
= 60 miles to the north
The displacement from 3 till 4 in the afternoon.The ship changes its course 20 degrees eastward at 3 o'clock.
Therefore, D2 = 30 miles/hr × 1 hr
= 30 miles to the 20° north eastward
By combining two vectors, the resulting displacement:
D = √((D1 ₊ D2 × cos(20°))² ₊ (D2 × sin(20°))²
D = √((60 ₊ 30 × cos (20°))² ₊ (30 × sin(20°))²
D = 88.8 miles
Hence the ship is 88.8 miles far away from the port at 4 pm.
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Which of the following is a solution to the equation x[tex]x^{2}[/tex]– 6x + 5 = 0?
Answer:
[tex]\huge\boxed{\sf x =5 \ \ \ OR \ \ \ x = 1}[/tex]
Step-by-step explanation:
Given equation:[tex]x^2-6x+5=0[/tex]
Using mid-term break formulaMultiply -5 and -1 gives +5 (side term) and adding them gives -6 (mid term).So, split -6 into -5 and -1[tex]x^2-5x-x+5=0\\\\Take \ common\\\\x(x-5)-1(x-5)=0\\\\Take \ (x-5) \ common\\\\(x-5)(x-1)=0[/tex]
Either,
x - 5 = 0 OR x - 1 = 0
x = 5 OR x = 1[tex]\rule[225]{225}{2}[/tex]
(a) Solve the following formula for b.
1
A = ab
(b) Evaluate b when A= 18 and a =
6/5
1
(a) The formula A = ab solved for b is b = 3X
6
(b) Evaluate b when A= 18 and a = 5
b = (Type an integer or a simplified fraction.)
Answer:
a. b = 2A/a
b. 30
Step-by-step explanation:
a. to solve for b:
[tex]A = 1/2 ab[/tex]
multiply both sides by 2
[tex]2A = ab[/tex]
divide both sides by a
[tex]2A/a=b[/tex]
so b = 2A/a
b. using the equation b = 2A/a
[tex]b = 2*18/(6/5)\\= 36/(6/5)\\= 30[/tex]
The graphs of three functions are shown. Which statements accurately compare the functions on the graph? Select two options. The square root and quadratic function share a y-intercept. The square root and absolute value function share an x-intercept. The range of the square root and quadratic function are the same. The range of the square root and absolute value function are the same. The quadratic function and the absolute value function have a minimum while the square root function has a maximum.
The following statements accurately compare the three functions on the graph: option A and C.
How to interpret the graph?In Geometry, the following statements are true about the graph of a function:
The x-intercepts of two or more functions are the same when their curves meet the x-axis at the same point. The y-intercepts of two or more functions are the same when their curves meet the y-axis at the same point. The ranges of two or more functions are the same when they all have the same vertical extension. The absolute value function and square root function both have the same minimum i.e at lower end of their range.By critically observing the graph of a function, we can logically deduce that the following statements accurately compare the three functions on the graph:
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Use the Factor Theorem to determine whether x−1 is a factor of 4x^3−6x^2+2x+1.
sin theta = 1/4, tan theta > 0
Find cos theta/2
Answer:
Step-by-step explanation:
sin θ=1/4,tan θ>0
so θ lies in first quadrant.
cos θ=√(1-sin²θ)=√(1-(1/4)²)=√(1-1/16)=√(15/16)=√15/4
[tex]2cos^2 \frac{\theta}{2} =1+cos \theta[/tex]
[tex]2~cos^2\frac{\theta}{2} =1+\frac{\sqrt{15} }{4} =\frac{4+\sqrt{15}}{4} \\cos~\frac{\theta}{2} =\sqrt{\frac{4+\sqrt{15} }{4 \times 2} } \\cos\frac{\theta}{2} =\frac{\sqrt{8+2\sqrt{15}} }{4}[/tex]
Help mee with this question pls I don’t understand
Answer:
a) Cat
b) 4 (unless there is a key that says otherwise)
c) 3 more people
Step-by-step explanation:
a) It has the least number of shapes (only 5)
b) Cat has 1 small square which stands for 1 person and 4 small squares put together make a big square so a big square is 4 people. Unless a key says that a small square is more or less 1, then it should be 4.
c) If one big square is 4 people, then there are 10 people for giraffes and 7 people for dogs. 10 - 7 = 3 more people.
2x+3y=7
2x - 3y = 4
Its asking me to find x
Input 1,2,3,4,5, n output 2,-1,-4,-7, ?please help me find the linear function!
Answer:
f(x) = -3x + 5
Step-by-step explanation:
The slope of the function is -3 as the outputs decrease by three for each iteration.
The constant is 5 and can be determined if you plug in 1 as an x value and solve for c in an equation like this: -3(1) + c = 2
What is the value of x in angle E? Show and explain your work.
PLEASE HELP!! ANSWER AND EXPLANATION NEEDED URGENTLY!!
Using it's concept, it is found that the probability that the button is either pink or blue is:
[tex]p = \frac{26}{29}[/tex]
What is a probability?A probability is given by the number of desired outcomes divided by the number of total outcomes.
In this problem, we have that:
There are x yellow buttons.There are y blue bottons.There are z pink buttons.There are six times as many pink buttons as yellow books, hence:
z = 6x.
Considering the ratio of yellow buttons to blue buttons, we have that:
[tex]\frac{x}{y} = \frac{3}{8}[/tex]
3y = 8x
[tex]y = \frac{8x}{3}[/tex]
The total number of buttons is given by:
[tex]T = x + \frac{8x}{3} + 6x[/tex]
[tex]T = \frac{29x}{3}[/tex]
The number of pink or blue is given by:
[tex]y + z = \frac{8x}{3} + 6x = \frac{26x}{3}[/tex]
Hence the probability is given by:
[tex]p = \frac{\frac{26x}{3}}{\frac{29x}{3}} = \frac{26}{29}[/tex]
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1.8(1.1x−1.3)−1.88=−24.02
The solution will be x= -10
Simplifying the given expression
[tex]1.8(1.1x - 1.3) - 1.88 = - 24.02[/tex]
Step1: Convert decimal to fraction
[tex]1.8( \frac{11x}{10} - 1.3) - 1.88 = - 24.02[/tex]
[tex]1.8( \frac{11x}{10} - \frac{13}{10} ) - 1.88 = - 24.02[/tex]
[tex]\frac{18}{10} ( \frac{11x}{10} - \frac{13}{10} ) - 1.88 = - 24.02[/tex]
Step2: Make denominator common
[tex]\frac{18}{10} ( \frac{11x - 13}{10}) - 1.88 = - 24.02[/tex]
Step3: Simplifying the fraction
[tex]\frac{9}{5} ( \frac{11x - 13}{10}) - 1.88 = - 24.02[/tex]
Step4: Make denominator common
[tex] \frac{9(11x - 13)}{5 \times 10} - \frac{1.88 \times 50}{50} = - 24.02[/tex]
[tex] \frac{9(11x - 13)}{50} - \frac{94}{50} = - 24.02[/tex]
[tex] \frac{9(11x - 13 - 94)}{50} = - 24.02[/tex]
[tex] \frac{99x - 117 - 94}{50} = - 24.02[/tex]
Step5: Simplifying
[tex] \frac{99x - 211}{50} = - 24.02[/tex]
[tex] 99x - 211 = - 24.02 \times 50[/tex]
[tex] 99x - 211 = - 1201[/tex]
[tex] 99x = - 1201 + 211[/tex]
[tex] 99x = - 990[/tex]
[tex] x = \frac{ - 990}{99} [/tex]
[tex]x = - 10[/tex]
Hence, the solution x=-10
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Solve for x. Please help me!!
Answer:
64 degrees
Step-by-step explanation:
90-32=58
180-58-58=64
Answer:
x = 64°
Step-by-step explanation:
supplementary angles is two angles whose sum is 180° (straight line)
90 + 32 = 122°
To find angle A,
A + 122 = 180
subtract 122 from both sides,
A + 122 - 122 = 180 - 122
A = 58°
This is an isosceles triangle, two angles are equal in measure (A and B). These angles lie opposite to the equal sides.
A triangles angles add up to 180°
58° + 58° + x° = 180°
116° + x = 180°
116 - 116 + x = 180 - 116
x = 64°
Elian's credit card had a balance of $132.20 on April 1. On April 5, he charged $74.50. On April 18, he made a payment of $52. On April 22, hecharged $18.75 and did not use the credit card the rest of the month. What was his average daily balance? $166.76 $173.45 $206.70 $179.86
Answer:
I iitiriririrrifjjrjr idiocy jdkthink 179.86
Find the perimeter of the following polygon. Be sure to include the correct unit in your answer. 19 cm 15 cm 14 cm 9 cm
Assume the random variable X has a binomial distribution with the given probability of obtaining a success. Find the following probability, given the number of trials and the probability of obtaining a success. Round your answer to four decimal places.
P ( X > 2 ) , n = 5 , p = 0.7
The value of the probability P(x > 2) is 0.8369
How to evaluate the probability?The given parameters are:
n = 5
p =0.7
The probability is calculated as:
[tex]P(x) = ^nC_x *p^x * (1 - p)^x[/tex]
Using the complement rule, we have:
P(x > 2) = 1 - P(0) - P(1) - P(2)
Where:
[tex]P(0) = ^5C_0 *0.7^0 * (1 - 0.7)^5[/tex]
P(0) = 1 *1 * (1 - 0.7)^5 = 0.00243
[tex]P(1) = ^5C_1 *0.7^1 * (1 - 0.7)^4[/tex]
P(1) = 5 *0.7^1 * (1 - 0.7)^4 = 0.02835
[tex]P(2) = ^5C_2 *0.7^2 * (1 - 0.7)^3[/tex]
P(2) = 10 *0.7^2 * (1 - 0.7)^3 = 0.1323
Recall that:
P(x > 2) = 1 - P(0) - P(1) - P(2)
So, we have:
P(x > 2) = 1 - 0.00243 - 0.02835 - 0.1323
Evaluate
P(x > 2) = 0.83692
Approximate
P(x > 2) = 0.8369
Hence, the value of the probability P(x > 2) is 0.8369
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The reverse of the number 129 is 921, and these add to 1050, which is divisible by 30.
How many three-digit numbers have the property that, when added to their reverse,
the sum is divisible by 30?
Answer:
Step-by-step explanation:
Write the number as [tex]abc[/tex] and use the divisibility rules for 10 and 3. From the rule for 10, we know that the last digit of [tex]abc+cba[/tex] is [tex]o[/tex], hence [tex]a+c=10[/tex]. Thus the options are [tex]a=1[/tex] & [tex]c=9[/tex], [tex]a=2[/tex], & [tex]c=8[/tex], etc.
From the rule for 3, namely that the digit sum must be divisible by 3, we find that [tex]2a+2b+2c=20+2b[/tex] is divisible by [tex]3[/tex]. By hand it's easy to check that [tex]b=2,5,8[/tex] are the only options that work.
So there are 9 choices for [tex]a[/tex] and [tex]c[/tex] and [tex]3[/tex] for [tex]b[/tex] , giving 27 total.
Which of the following is the difference of two squares?
A. 100m^2+9n^2
B.9x^2-12y^2
C. 16g-49h
D. 25a^2-36b^6
The difference of two squares expression is (d) 25a^2-36b^6
How to determine the difference of two squares?The difference of two squares is represented as:
x^2 - y^2
Where x and y are perfect square expressions.
From the list of options, we have:
25a^2-36b^6
The terms of the above expression are perfect squares
i.e.
25a^2 = (5a)^2
36b^6 = (6b^3)^2
Hence, the difference of two squares expression is (d) 25a^2-36b^6
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