Answer:
It is solved on a graph
Step-by-step explanation:
A quadratic graphical solution.
Use the graph to write the inequality that represents the shaded region
Answer:
4/2 is the wrong answer
Step-by-step explanation:
because it is
-11-(-5)
————-
2x3
is an example of
A. a numerical equation
B. a numerical expression
C. an algebraic expression
D. an algebraic equation
Answer:
B.a numerical expression
pls solve this question
Answer:
[tex] {( \sqrt{ {x}^{ - 3} }) }^{5} = ({( {x}^{ - 3}) }^{ \frac{1}{2} } ) ^{5} \\ \\ = {x}^{ - 3 \times \frac{1}{2} \times 5} = {x}^{ - \frac{15}{2} } = \frac{1}{ {x}^{ \frac{15}{2} } } [/tex]
Or ;
[tex] {( \sqrt{ {x}^{ - 3} } )}^{5} = {( \sqrt{ \frac{1}{ {x}^{3} }} })^{5} = ( { \frac{ \sqrt{1} }{ \sqrt{ {x}^{3} } } })^{5} \\ \\ = ( { \frac{1}{ \sqrt{x} \sqrt{ {x}^{2} } } })^{5} = ({ \frac{1}{ x\sqrt{x} }})^{5} \\ \\ = ( \frac{ {(1)}^{5} }{ {x}^{5} ( \sqrt{x} )^{5} } ) = \frac{1}{ {x}^{5} \times {x}^{ \frac{1}{2} \times 5 } } \\ \\ = \frac{1}{ {x}^{5} \times {x}^{ \frac{5}{2} } } = \frac{1}{ {x}^{5} \sqrt{ {x}^{5} } } \\ \\ = \frac{1}{ {x}^{5} \sqrt{ {x}^{4} {x}^{1} } } = \frac{1}{ {x}^{5} \sqrt{x} \sqrt{( { {x}^{2} })^{2} } } \\ \\ = \frac{1}{ {x}^{5} {x}^{2} \sqrt{x} } = \frac{1}{ {x}^{7} \sqrt{x} } = \frac{ \sqrt{x} }{ {x}^{8} } [/tex]
Graphing a exponential decay function
The process of Graphing a exponential decay function is shown in detail below.
There are two types of exponential equations: exponential decay and exponential growth. The fundamental shape of an exponential function and its corresponding graphs must be understood in order to fully comprehend the distinctions between exponential growth and decay. The fundamental distinction between the two is that in an exponential decay connection, the output values rise quickly as the input value rises, but in an exponential growth relationship, the output rises noticeably faster as the input value rises. Furthermore, neither of the two functions is linear, hence their rate of change is not constant. What distinguishes one equation from the other when they both have the same precise form, y = abx?
The value of the constant "b" is the fundamental factor in deciding whether the exponential function is one of growth or decay:
If function y = ab^x and b > 1then the function is an exponential growth function.If the function y = ab^x and 0<b<1 then the function is an exponential decay function. As noted before, "b" can never be exactly 1.In this way we can graph a exponential decay function
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hi i really need help with this it is due tonight
Answer:
[tex]1)\text{ Friday}\\2)\text{ }7:00\\3a)\text{ }0\\3b)\text{ }4\\3c)\text{ }0\\4a)\text{ }6\\4b)\text{ }4\\4c)\text{ }2[/tex]
Find the volume of the sphere of 5m
What is the equation of the line that passes through the points (5,3) and (9,-13)?
The equation of the line that passes through the given points is y= -4x+23.
Linear FunctionA line can be represented by a linear function. The standard form for the linear equation is: ax+b , for example, y=2x+7. Where:
a= the slope
b=constant term that represents the y-intercept.
From the stardard form equation:
For point (5,3) : 3=5a+b ( equation 1)For point (9,-13) : -13=9a+b (equation 2)Solving the system for equations 1 and 2.
3=5a+b
-13=9a+b * (-1)
3=5a+b
13=-9a-b * (-1)
16= -4a
4= -a
a= -4
If a= -4 from equation 1, you have
3= 5 * (-4)+b
3= -20+b
b=23
Therefore, the line equation is y= -4x+23.
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Which expression is equivalent to (1−sinβ)(1+sinβ)/cos2β for all values of β for which (1−sinβ)(1+sinβ)/cos2β is defined?
Select the correct answer below:
tan2β
tanβ+secβ
tanβ
sec2β
1
Using a trigonometric identity, it is found that the equivalent expression is given by 1.
What are the trigonometric identities used to solve this question?Relating sine and cosine, we have that:
[tex]\sin^{2}{\beta} + \cos^{2}{\beta} = 1[/tex]
Then:
[tex]\cos^{2}{\beta} = 1 - \sin^{2}{\beta}[/tex]
For the tangent, we have that:
[tex]\tan{\beta} = \frac{\sin{\beta}}{\cos{\beta}}[/tex].
For the secant, we have that:
[tex]\sec{\beta} = \frac{1}{\cos{\beta}}[/tex].
In this problem, the expression is:
[tex]\frac{(1 - \sin{\beta})(1 + \sin{\beta})}{\cos^{2}{\beta}} = \frac{1 - \sin^2{\beta}}{\cos^2{\beta}} = \frac{\cos^2{\beta}}{\cos^2{\beta}} = 1[/tex]
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The surface area of a square pyramid is 189 square inches. The side length of the base is 7. What is the value of the height?
The value of the height of the prism is 8.68 inches
Surface of a square pyramidThe surface area is the sum of the area of the faces.
The formula for calculating the surface area of the pyramid is;
TSA = [tex]a^2+2a\sqrt{\frac{a^2}{4} + h^2}[/tex]
where
a is the side length. = 7in
h is the height
Substitute
[tex]189=7^2+2(7)\sqrt{\frac{7^2}{2} + h^2} \\189=49+14\sqrt{\frac{49}{2} + h^2}\\140=14\sqrt{\frac{49}{2} + h^2}\\10=\sqrt{\frac{49}{2} + h^2}\\[/tex]
Square both sides to have
100 = 49/2 + h²
h² = 100 - 49/2
h² = 151/2
h² = 75.5
h = 8.68in
Hence the value of the height of the prism is 8.68 inches
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(1 point)Let S be the part of the plane 2x+2y+z= 1 which lies in the first octant, oriented upward. Find the flux of the vector field
F = 2i+2j + 2k across the surface S.
The flux is 9.
What is Flux?Flux is the presence of a force field in a specified physical medium, or the flow of energy through a surface.
Given:
2x+2y+z= 1
F = 2i+2j + 2k
Now,
r = xi + yj + z( 1-2x-2y) K
dr/dx= i - 2k
dr/dy = j-2k
dr/dx* dr/dy
= ( i - 2k) * (j-2k)
= 2i + 2j + k
F(x)= 2i+2j + 2k
F(x). da = 4 +4 +2 = 10 dxdy
Hence, flux
= [tex]\int\limits^1_0 {\int\limits^{1-2y}_0 {10 } \, dx dy } \,[/tex]
= [tex]\int\limits^1_0[/tex] 10(1-2y) dx
= [tex]\int\limits^1_0[/tex] 10-2y
= 10(1) - (1)²
=9
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The plane has intercepts (1/2, 0, 0), (0, 1/2, 0), and (0, 0, 1). Parameterize [tex]S[/tex] by the vector function
[tex]\vec s(u,v) = \dfrac{(1-u)(1-v)}2 \, \vec\imath + \dfrac{u(1-v)}2 \, \vec\jmath + v \,\vec k[/tex]
with [tex]0\le u\le1[/tex] and [tex]0\le v\le1[/tex]. (More explicitly, we have the parameterization
[tex]\vec s(u,v) = (1-v)((1-u) p_1 + u p_2) + v p_3[/tex]
where [tex]p_i[/tex] denote the given points.)
The normal vector to [tex]S[/tex] is
[tex]\vec n = \dfrac{\partial\vec s}{\partial u} \times \dfrac{\partial\vec s}{\partial v} = \dfrac{1-v}2\,\vec\imath + \dfrac{1-v}2\,\vec\jmath + \dfrac{1-v}4\,\vec k[/tex]
Then the flux of [tex]\vec F = 2\,\vec\imath+2\,\vec\jmath+2\,\vec k[/tex] across [tex]S[/tex] is given by the surface integral,
[tex]\displaystyle \iint_S \vec F \cdot d\vec\sigma = \iint_S \vec F \cdot \vec n \, dA[/tex]
[tex]\displaystyle = \int_0^1 \int_0^1 \left(2\,\vec\imath+2\,\vec\jmath+2\,\vec k) \cdot \left(\frac{1-v}2\,\vec\imath + \frac{1-v}2\,\vec\jmath + \frac{1-v}4\,\vec k\right) \, du \, dv[/tex]
[tex]\displaystyle = \frac52 \int_0^1 \int_0^1 (1-v) \, du \, dv[/tex]
[tex]\displaystyle = \frac52 \int_0^1 (1-v) \, dv = \boxed{\frac54}[/tex]
On a coordinate plane, an image has points (negative 2, 2), (0, 2), (2, 0), (0, negative 2), (negative 2, negative 2).
Use the image shown and a scale factor of 1/2 to find the pre-image. Which is the pre-image of A’?
If the scale factor is 1/2. Then the coordinate of the pre-image will be (-1, 1), (0, 1), (1, 0), (0, -1), and (-1, -1).
What is a transformation of geometry?A spatial transformation is each mapping of feature shapes to itself, and it maintains some spatial correlation between figures.
Dilation does not change the shape, but changes the size of the geometry.
On a coordinate plane, an image has points (-2, 2), (0, 2), (2, 0), (0, -2), and (-2, -2).
The scale factor is 1/2. Then the coordinate of the pre-image will be
(-1, 1), (0, 1), (1, 0), (0, -1), and (-1, -1).
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Answer:D (-4) (-4)
Step-by-step explanation:
In a test of the effectiveness of garlic for lowering cholesterol, 50 subjects were treated with garlic in a processed tablet form. Cholesterol levels were measured before and after the treatment. The changes (before-after) in their levels of LDL cholesterol (in mg/dL) have a mean of3.1 and a standard deviation of 16.6. Construct a 99% confidence interval estimate of the mean net change in LDL cholesterol after the garlic treatment. What does the confidence interval suggest about the effectiveness of garlic in reducing LDL cholesterol? Click here to view a t distribution table.LOADING... Click here to view page 1 of the standard normal distribution table.LOADING... Click here to view page 2 of the standard normal distribution table.LOADING... What is the confidence interval estimate of the population mean ?
The confidence interval estimates that the confidence interval limits contain 0., suggesting that the garlic treatment did not affect the LDL cholesterol levels.
A confidence interval is a range of estimates for an unknown parameter in frequentist statistics. The 95 percent confidence level is the most common, but other levels, like 90 percent or 99 percent, are occasionally used when computing a confidence interval.
Given in a test of effectiveness of garlic for lowering cholesterol, 50 subjects were treated with garlic in a processed tablet form.Both before and after the therapy, cholesterol levels were assessed.
LDL cholesterol variations had a mean of 4.4 and a standard deviation of 19.4 (in mg/dL). The best point estimate is 4.4.
We have to find 95% confidence interval estimate of the population mean
So,
x-bar = 4.4
ME = 1.96 = 5.27
H: no difference
Ha: is a difference
We fail to reject H since 0 is in the CI.
Hence the confidence interval estimates that the confidence interval limits contain 0., suggesting that the garlic treatment did not affect the LDL cholesterol levels.
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A person draws a card from a hat. Each card is one color, with the following probabilities of being drawn: 1/25 for red, 1/20 for green, 1/15 for purple, and 1/10 for black. What is the probability of pulling a green or red card, written as a reduced fraction?
Probability helps us to know the chances of an event occurring. The probability of pulling a green or red card is 9 / 100.
What is Probability?Probability helps us to know the chances of an event occurring.
P = [tex]\dfrac{Desired \ outcomes}{Posiible \ outcomes}[/tex]
The probabilities of different color cards being pulled are 1/25 for red, 1/20 for green, 1/15 for purple, and 1/10 for black Therefore, the probability of pulling a green or red card is,
Probability = 1/20 + 1/25
= (5 + 4) /100
= 9 / 100
Hence, the probability of pulling a green or red card is 9 / 100.
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For the graph y=41 find the slope
Answer:
m=0 , b=41
Step-by-step explanation:
y=41y=0x+41, y=mx +by=0x+41, m=0, b=41therefore m=0, b=41There are two boxes of cereal in the shape of rectangular prisms on a shelf. The
dimensions of each box of cereal are listed below.
. Box B has a height of 25 centimeters, a length of 19 centimeters,
and a width of 6 centimeters.
• Box A has a height of 25 centimeters, a length of 20 centimeters,
and a width of 9 centimeters.
What is the difference in volume, in cubic centimeters, between the two boxes of cereal?
A 1,650
B 3,900
C 4,500
D 7,350
Answer:
1650 Cubic Centimeters
Step-by-step explanation:
To get the volume of the cereal boxes, you must multiply their 3 dimensions together.
Box A:
25×20=500
500×9=4500
Box B:
25×19=475
475×6=2850
Now, to find the difference of these volumes, you want to subtract the smaller volume from the larger volume.
4500-2850=1650
The answer is 1650 cubic centimeters.
simplify (8x^2y^3)/(2x^4y)
Answer:
[tex]=\frac{4y^2}{x^2}[/tex]
Step-by-step explanation:
[tex]\frac{(8x^2y^3)}{(2x^4y)}[/tex]
[tex]=\frac{(8x^2y^3)}{(2x^4y)}\\[/tex]
[tex]=\frac{8y^2}{2x^2}[/tex]
[tex]=\frac{4y^2}{x^2}[/tex]
I Hope This helps :)
Gavin likes biking. He never misses a chance to go for a ride when the weather is nice. This week his goal is to bike about 65 total miles over four days. Each day, he wants to ride 1.5 times as far as he rode the day before. What does the result in part d mean?
Answer:
Total Miles he drives first day = 8 miles
Total Miles he drive second day = 12miles
Total Miles he drives third day = 18miles
Total Miles he drives fourth day = 27 miles
Step-by-step explanation:
This is a problem of linear equations in 1 variable:
The linear equations in one variable is an equation which is expressed in the form of ax + b = 0, where a and b are two integers, and x is a variable and has only one solution.
It is given in the question that ,
This week his goal is to drive bike about 65 total miles over four days. Each day, he wants to ride 1.5 times as far as he rode the day before.
Let, on the first day, he drives x miles. On second day, he drives 1.5x. On the third day, he drives 1.5(1.5x) and on the fourth day, he drives 1.5(1.5(1.5x)).
So the equation is :
x +1.5x + 1.5(1.5x) + 1.5(1.5(1.5x)) = 65miles
x + 1.5x + 2.25x + 3.375x = 65miles
8.125x = 65 miles
x = 65/8.125 miles
x = 8 miles
so after solving the equation we get, on the first day Gavin drives 8 miles
similarly, on the second day he drives 12miles
on third day 18 miles
and on the fourth day 27miles
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In the figure below, lines I and mare parallel. What is the value of x?
1
(4x13)
X=
m
(2x + 37)
[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]
[tex]\qquad \tt \rightarrow \: x = 25°[/tex]
____________________________________
[tex] \large \tt Solution \: : [/tex]
[tex]\qquad \tt \rightarrow \: 4x - 13 = 2x + 37[/tex]
[ Alternate Exterior Angle ]
[tex]\qquad \tt \rightarrow \: 4x - 2x = 37 + 13[/tex]
[tex]\qquad \tt \rightarrow \: 2x = 50[/tex]
[tex]\qquad \tt \rightarrow \: x = \cfrac{50}{2} [/tex]
[tex]\qquad \tt \rightarrow \: x = 25 \degree[/tex]
Answered by : ❝ AǫᴜᴀWɪᴢ ❞
What are your top 3 theorems in higher mathematics? Why do you like them the most?
My theorems include the Pythagoras theorem, midpoint theorem, and angle bisector theorem.
How to illustrate the theorem?The Pythagoras theorem is used to find the length in a right angle.
The midpoint theorem states that the line segment in a triangle is parallel to the third side and is half the length.
The angle bisector theorem is concerned with the lengths of the two segments that the triangle side is divided into by a line which bisects the opposite angle.
I like them because they're important when solving triangle related problems.
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The blue dot is at what value on the number line -3 -1
Answer:
It's +2
Step-by-step explanation:
As the positive occurs on the right side of the negatives in the number line so if we keep extending on the right side so we get +2
PLS HELP PLS In the diagram below, ΔABC ≅ ΔDEF. Complete the statement ∠A ≅
Answer:
∠A ≅ ∠D
Step-by-step explanation:
When writing a triangle congruency like ΔABC ≅ ΔDEF, the angles are congurent based on the orders listed. For example the first angle A is congruent with the first angle of the other triangle D.
∠A ≅ ∠D
∠B ≅ ∠E
∠C ≅ ∠F
You are the operations manager for an airline and you are considering a higher fare level for passengers in aisle seats. How many randomly selected air passengers must you survey? Assume that you want to be 90% confident that the sample percentage is within 1.5 percentage points of the true population percentage. Complete parts (a) and (b) below. Assume that nothing is known about the percentage of passengers who prefer aisle seats.
Using the z-distribution, it is found that 3,007 passengers must be surveyed.
What is a confidence interval of proportions?A confidence interval of proportions is given by:
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which:
[tex]\pi[/tex] is the sample proportion.z is the critical value.n is the sample size.The margin of error is given by:
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In this problem, we have a 90% confidence level, hence[tex]\alpha = 0.9[/tex], z is the value of Z that has a p-value of [tex]\frac{1+0.9}{2} = 0.95[/tex], so the critical value is z = 1.645.
In this problem, we desired a margin of error of M = 0.015, with no prior estimate, hence [tex]\pi = 0.5[/tex], then we solve for n to find the minimum sample size.
[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
[tex]0.015 = 1.645\sqrt{\frac{0.5(0.5)}{n}}[/tex]
[tex]0.015\sqrt{n} = 1.645(0.5)[/tex]
[tex]\sqrt{n} = \frac{1.645(0.5)}{0.015}[/tex]
[tex](\sqrt{n})^2 = \left(\frac{1.645(0.5)}{0.015}\right)^2[/tex]
n = 3007.
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need some help asap, giving brainliest
Answer:
16.19
Step-by-step explanation:
Use the cosine rule:
[tex]\sqrt{a^{2} +b^{2} -2abcosy} \\\\\sqrt{16^{2} +20^{2} -(2)(16)(20)cos(52)} \\\\\\= 16.19cm[/tex]
translate algebra 2 to standard form
Adding 2x to both sides, we get [tex]\boxed{2x+y=5}[/tex]
The law of cosines is a² + b² - 2abcosC = c². Find the value of 2abcosC.
A. 20
B. 40
C. 37
D. -40
Answer:
C
Step-by-step explanation:
a = 4
b = 5
c = 2
C = arccos((a² + b² - c²) / 2ab)
C = arccos((16 + 25 - 4) / 2(4)(5))
C = arccos(37 / 40)
C = 22.33°
2abcosC
2(4)(5)cos(22.33)
40(0.925)
37
Option C is correct, if the law of cosines is a² + b² - 2abcosC = c² then the value of 2abcosC is 37.
What is Trigonometry?Trigonometry is a branch of mathematics that studies relationships between side lengths and angles of triangles.
We have from law of cosines that a² + b² - 2abcosC = c²
We have to find the value of 2abcosC.
Now let us find the value of C
C = arccos((a² + b² - c²) / 2ab)
C = arccos((16 + 25 - 4) / 2(4)(5))
C = arccos(37 / 40)
C = 22.33°
Now plug in the value of C in 2abcosC.
2abcosC
=2(4)(5)cos(22.33)
=40(0.925)
=37
Hence, option C is correct, if the law of cosines is a² + b² - 2abcosC = c² then the value of 2abcosC is 37.
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graph f(x)= x if x < 2, 2 if x ≥ 2
The graph is shown below:
What is graph?A graph is a mathematical diagram which shows the relationship between two or more sets of numbers or measurements.
Given function: f(x) = x
We have to draw the graph for the function ,f(x) =x with two cases.
For x<2 and for x ≥ 2
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Find the value of: (4/5)^1 A. 4/5 B. 1 C. 0 D. 16/25
Answer:
A. 4/5
Step-by-step explanation:
Answer:
4/5 (option a)
Step-by-step explanation:
by following the exponent rule of [tex]a^1 = a[/tex], we know that
[tex](\frac{4}{5} )^1[/tex] = [tex]\frac{4}{5}[/tex]
So, the value of
[tex]\frac{4}{5}^{1}[/tex] is 4/5
Help me pleaseeeeeeeeeeeeeeeeeeeeee
Answer:
A
Step-by-step explanation:
[tex]s=\frac{a+b+c}{2}[/tex]
multiply both sides by 2
[tex]2s = a + b +c[/tex]
substract b and c from both sides to get a by itself
[tex]a = 2s - (b + c)\\a = 2s - b - c[/tex]
so the answer is A.
Which of the following is the given function's
average rate of change on the interval
Sx≤1?
Answer: 2
Step-by-step explanation:
[tex]g(-2)=-2\\\\g(1)=4\\\\\frac{g(-2)-g(1)}{-2-1}=\frac{-2-4}{-3}=\boxed{2}[/tex]
The cost of renting a car is $46/week plus $0.25/mile traveled during that week. An equation to represent the cost would be y=46+0.25x, where x is the number of miles traveled.
a. What is your cost if you travel 57 miles?
The cost is $ ____________.
b. If your cost was $65.00, how many miles were you charged for traveling?
You were charged for traveling ____________ miles.
c. Suppose you have a maximum of $100 to spend for the car rental. What would be the maximum number of miles you could travel?
The maximum number of miles you could travel is ____________ miles.
Answer:
A. $60.25
B. 76 miles
C. 216 miles
Step-by-step explanation:
x is miles
y is total amount spent
For A, 57 miles is the x value. Plug that in to x.
y= 46 + .25(57)
y= 60.25
For B, the total is the y. So plug 65 in for y.
65 = 46 + .25x Subtract 46 from both sides
19 = .25x Divide by .25
76 = x
For C, the maximum you can spend is $100. Plug that in for y.
100 = 46 + .25x Subtract 46 from both sides
54 = .25x Divide by .25
216 = x
The answer for part a is $60.25, for part b the answer is 76 miles, and for part c the answer is 216 miles.
What is a function?It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
The equation to represent the cost would be y=46+0.25x
x is the number of miles.
a) What is your cost if you travel 57 miles?
Plug x = 57 in the above equation:
y = 46 + 0.25(57)
y = $60.25
b) If your cost was $65.00, how many miles were you charged for traveling?
Plug y = 65 in the equation:
65 = 46 + 0.25x
x = 76 miles
c) Suppose you have a maximum of $100 to spend for the car rental. What would be the maximum number of miles you could travel?
Plug y = 100 in the equation:
100 = 46 + 0.25x
x = 216 miles
Thus, the answer for part a is $60.25, for part b the answer is 76 miles, and for part c the answer is 216 miles.
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