Cos(5 π/3)=___
A. √3/2
B. -√2/2
C. 1/2
D. √2/2
Answer:
i think the answer is C. 1/2
Graph of y = log(-x)?
Answer:
lklklkj
Step-by-step explanation:
67890-
Please help! Consider the function y = 9-x^2, where x ≥ 3
What is the inverse of the function? What is the domain of the inverse? Show all of your work
(hint: swap x and y in the domain as well as the function)
Using it's concept, it is found that the inverse function is [tex]y = \sqrt{9 - x}[/tex], and the domain is [tex]x \leq 9[/tex].
How to find the inverse function?The inverse of a function y = f(x) is found exchanging x and y and isolating y. The domain of the inverse is the range of the original function f(x).
In this problem, the function is:
y = 9 - x²
Then, we exchange and isolate y, hence:
[tex]x = 9 - y^2[/tex]
[tex]y² = 9 - x[/tex]
[tex]y = \sqrt{9 - x}[/tex]
The domain is [tex]9 - x \geq 0 \rightarrow x \leq 9[/tex], as looking at the graph of y = 9 - x², the range is [tex]y \leq 9[/tex].
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Marcia bought a car for £34500 and sold it for £29700. what was her percentage loss?
can i have an explanation please :)
Answer:
cost of car = 34500
selling price = 29700
amount of loss = 34500 - 29700 = 4800
loss percentage = (loss amount ÷ cost price ) * 100
= 13.913 ≈ 14% loss
Select the two binomials that are factors of 49x^2 - 36
A. 7x + 12
B. 7x - 3
C. 7x + 6
D. 7x - 6
By definition of the subtraction of squares, the binomial 49 · x² - 36 have the following two factors: 7 · x + 6, 7 · x - 6 (Correct choices: C, D)
How to find the factors of subtraction of squares
A subtraction of squares is a binomial which satisfies the following property:
a² - b² = (a - b) · (a + b) (1)
If we know that a² = 49 · x² and b² = 36, then we have the following factors:
49 · x² - 36 = (7 · x - 6) · (7 · x + 6)
By definition of the subtraction of squares, the binomial 49 · x² - 36 have the following two factors: 7 · x + 6, 7 · x - 6 (Correct choices: C, D)
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Determine whether the given differential equation is exact. If it is exact, solve it. (tan(x)-sin(x)sin*y))dx+cos(x)cos(y)dy=0 g
The differential equation
[tex]M(x,y) \, dx + N(x,y) \, dy = 0[/tex]
is considered exact if [tex]M_y = N_x[/tex] (where subscripts denote partial derivatives). If it is exact, then its general solution is an implicit function [tex]f(x,y)=C[/tex] such that [tex]f_x=M[/tex] and [tex]f_y=N[/tex].
We have
[tex]M = \tan(x) - \sin(x) \sin(y) \implies M_y = -\sin(x) \cos(y)[/tex]
[tex]N = \cos(x) \cos(y) \implies N_x = -\sin(x) \cos(y)[/tex]
and [tex]M_y=N_x[/tex], so the equation is indeed exact.
Now, the solution [tex]f[/tex] satisfies
[tex]f_x = \tan(x) - \sin(x) \sin(y)[/tex]
Integrating with respect to [tex]x[/tex], we get
[tex]\displaystyle \int f_x \, dx = \int (\tan(x) - \sin(x) \sin(y)) \, dx[/tex]
[tex]\implies f(x,y) = -\ln|\cos(x)| + \cos(x) \sin(y) + g(y)[/tex]
and differentiating with respect to [tex]y[/tex], we get
[tex]f_y = \cos(x) \cos(y) = \cos(x) \cos(y) + \dfrac{dg}{dy}[/tex]
[tex]\implies \dfrac{dg}{dy} = 0 \implies g(y) = C[/tex]
Then the general solution to the exact equation is
[tex]f(x,y) = \boxed{-\ln|\cos(x)| + \cos(x) \sin(y) = C}[/tex]
What is the value of x?
Enter your answer in the box.
...°
AP Calculus AB Question from A, P .E* X
(Will give branliest if correct)
If g(x) = 3 · x - 1 and [tex]f(x) = \sqrt{9-x^{2}}[/tex], then the domain of the division of f(x) by g(x) is equal to the following composite interval: [-3, 1/3) ∪ (1/3, 3] (Correct choice: A)
What is the domain of a function as a result of a binary operator
Binary operators are operators that involves two functions, there are four binary operators: (i) Addition, (ii) Subtraction, (iii) Multiplication, (iv) Division. First, we determine the domains of the functions f(x) and g(x):
f(x):
Domain - [-3, 3]
g(x):
Domain - (- ∞, + ∞)
If we divide f(x) by g(x), then we must take g(x) = 0 into account, since it leads to indetermination. In this case, x = 1/3. Then, the domain of the resulting function:
(f/g)(x):
Domain - [-3, 1/3) ∪ (1/3, 3]
If g(x) = 3 · x - 1 and [tex]f(x) = \sqrt{9-x^{2}}[/tex], then the domain of the division of f(x) by g(x) is equal to the following composite interval: [-3, 1/3) ∪ (1/3, 3] (Correct choice: A)
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Given the matrices A and B shown below, find -A + 1/3B
Step-by-step explanation:
1. first multiply -1 times all elements of matrix A
2. then multiply 1/3 by all elements of matrix B
3. then add each corresponding entries to get the result.
from step 1. matrix A will be
-4 -2. -1. -3
-2. 0. 1. -3
step 2. matrix B will be
3. -1. -2. -4
3. -10. 10. -1
add each corresponding elements to get
-1. -3. -3. -7
1. -10 11. -4
This is direct proportion .
I need help in question 2 only one of the questions then I can do the rest tysm
Il give
Answer:
(a) 2.5
Step-by-step explanation:
(a) Since y is directly proportional to x we can write y and x in terms of the following equation:
y = cx where c is a constant
and c = y/x ...(1)
or,
x = y/c ...(2)
For (a)
y = 8 when x = 2 ==> c = y/x = 8/2 =4 from (1)
From (2) we get x = 10/4 = 2.5
The other questions can be solved in a similar fashion
How many other states have a similar law? all 50 states 48 states 40 other states 52 states
Answer:
all 50 states
Step-by-step explanation:
Why is it just as likely that the cube will show an even number as an odd number?
What is the additive inverse of x=-1317, and verify -(-x) = x ?
Answer:
1317 is the additive inverse of x = -1317.
Step-by-step explanation:
Additive inverse of a number which when added to the original number gives zero as the result.
Additive inverse of x = -1317
-1317 + 1317 = 0
1317 is the additive inverse of x = -1317.
Verification of -(-x) = x
L. H. S
-(-x) = -{-(-1317)}
= - 1317
R. H. S
x = -1317
Thus, L.H.S. = R.H.S
-(-x) = x
Verified
Type the correct answer in the box
Answer:
[tex]log\boxed{7}[/tex]
Step-by-step explanation:
[tex]log\frac{14}{3}+log\frac{11}{5}-log\frac{22}{15}[/tex][tex]=log\bigg(\frac{14}{3}*\frac{11}{5}\bigg)-log\frac{22}{15}[/tex][tex]=log\bigg(\frac{14*11}{3*5}\bigg)-log\frac{22}{15}[/tex][tex]=log\bigg(\frac{154}{15}\bigg)-log\frac{22}{15}[/tex][tex]=log\bigg(\frac{154}{15}\div\frac{22}{15}\bigg)[/tex][tex]=log\bigg(\frac{154}{15}\times\frac{15}{22}\bigg)[/tex][tex]=log\bigg(\frac{154}{22}\bigg)[/tex][tex]=log\boxed{7}[/tex]3 *(x-7)*(x+7)-(x-1)*(3x+2)=13
The value of x will be 158. The value of x is obtained by simplifying the equation.
What is the equation?A mathematical statement consisting of an equal symbol between two algebraic expressions with the same value is known as an equation.
Identity used;
(x+a)(x-a) = x² - a²
Given expression;
3(x-7)(x+7) - (x-1)(3x+2) = 13
Solving the equation step by step;
[tex]\rm 3(x^2 - 7^2 ) - [x(3x+2)-1(3x+2) ]= 13\\\\ 3x^ 2 -147 -[3x^2 +2x -3x-2] = 13 \\\\ 3x^2 -147 -[3x^2 -x-2] = 13\\\\ 3x^2-147-3x^2 +x+2 = 13 \\\\ x= 13+145 \\\\ x= 158[/tex]
Hence, the value of x will be 158.
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What is the range of the relation in the table below?
The range of the relation is {0, 2, 4}
How to determine the range?The range of the relation are the y values
From the table, we have:
y values = 0, 2, 4, 2, 0
Remove the repetition
y values = 0, 2, 4
Hence, the range of the relation is {0, 2, 4}
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Price of an article is marked 40% above the cost price and sold with 15% discount including 10% VAT at Rs. 26,894. Find the cost price, marked price and profit percentage.
Step-by-step explanation:
here is your answer. where are you from
The cost price is Rs22600, the marked price is Rs31640 and the Profit percentage is 19%.
What is the percentage?The percentage is defined as a given amount in every hundred. It is a fraction with 100 as the denominator percentage is represented by the one symbol %.
For example, if you say 678, we must also know the whole number, but if you say 80%, it becomes evident. The percentage is the same as the amount of that value but ranges from 1 to 100.
Let's say
Cost of article = c
Given,
Marked 40% above the cost price and sold with 15% discount including 10% VAT at Rs. 26,894
1.4c - 0.15×(1.4c) = 26894
c = Rs 22600
So,
Marked price = 1.40c = Rs 31640
Profit percentage = ( 26894 - 22600)22600 = 19%.
Hence cost price is Rs22600, the marked price is Rs31640 and the Profit percentage is 19%.
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I want to verify my work answer for the below SSAT question.
Thank you
Cindy throws a rock in the air. The rock's height, y, in feet, with respect to time, x, in seconds can be modeled by the function y=-2x^2+10x+28. When does the rock hit the ground in seconds
My work:
y=-2x^2+10x+28
0= -2(x^2-5x-14) (While knowing that the zero is supposed to be there, I don't understand why 0= -2(x^2-5x-14) )
(x-7)(x+2)
(-7,+2)
I put 2 as the answer, but when checking it was 7?
What part did I do wrong?
Answer:
7
Step-by-step explanation:
You were correct in setting the equation equal to 0 because the problem is asking for when the rock hits the ground and in this problem, you may assume that the ground is y=0, unless the problem says otherwise.
Ok so where you went wrong is that when you factored out and got
(x-7)(x+2), which is correct, you forgot to set these equal to zero (because your actual equation is set to zero). So you should have
x-7 = 0
and
x+2 = 0
and this gives the actual answers +7 and -2. And since time cant be negative its 7 seconds.
This was a silly mistake and happens a lot more often than you think, so I wouldn't worry too much but make sure you practice more, better to lose points on harder questions than easy ones.
Good luck with your exam !
Answer:
7 seconds
Step-by-step explanation:
Given function:
[tex]y=-2x^2+10x+28[/tex]
where:
y = height above the ground (in feet)x = time (in seconds)To find the time when the rock hits the ground, set the equation to zero and solve for x.
First, simplify by factoring out the common term -2:
[tex]\implies -2(x^2-5x-14)=0[/tex]
Divide both sides by -2:
[tex]\implies x^2-5x-14=0[/tex]
To factor a quadratic in the form [tex]ax^2+bx+c[/tex], find two numbers that multiply to ac and sum to b.
[tex]\implies ac=1 \cdot -14=-14[/tex]
[tex]\implies b=-5[/tex]
Therefore, the two numbers that multiply to -14 and sum to -5 are: -7 and 2
Rewrite b as the sum of these two numbers:
[tex]\implies x^2-7x+2x-14=0[/tex]
Factorize the first two terms and the last two terms separately:
[tex]\implies x(x-7)+2(x-7)=0[/tex]
Factor out the common term (x - 7):
[tex]\implies (x+2)(x-7)=0[/tex]
Therefore:
[tex]\implies x+2=0 \implies x=-2[/tex]
[tex]\implies x-7=0 \implies x=7[/tex]
As time cannot be negative, the rock hits the ground in 7 seconds.
consider an investment of $6000 that earns 4.5% interest.
How long would it take for the investment
to reach $15,000 if the interest is
compounded monthly? Round your
answer to the nearest tenth.
Answer:
20.4 years (nearest tenth)
Step-by-step explanation:
Compound Interest Formula
[tex]\large \text{$ \sf A=P\left(1+\frac{r}{n}\right)^{nt} $}[/tex]
where:
A = final amountP = principal amountr = interest rate (in decimal form)n = number of times interest applied per time periodt = number of time periods elapsedGiven:
A = $15,000P = $6,000r = 4.5% = 0.045n = 12 (monthly)Substitute the given values into the formula and solve for t:
[tex]\implies \sf 15000=6000\left(1+\frac{0.045}{12}\right)^{12t}[/tex]
[tex]\implies \sf \dfrac{15000}{6000}=\left(1.00375\right)^{12t}[/tex]
[tex]\implies \sf 2.5=\left(1.00375\right)^{12t}[/tex]
[tex]\implies \sf \ln (2.5)=\ln \left(1.00375\right)^{12t}[/tex]
[tex]\implies \sf \ln (2.5)=12t \ln \left(1.00375\right)[/tex]
[tex]\implies \sf t=\dfrac{\ln (2.5)}{12 \ln (1.00375)}[/tex]
[tex]\implies \sf t=20.40017123[/tex]
Therefore, it would take 20.4 years (nearest tenth) for the investment to reach $15,000.
A hot air balloon is descending.
The height of the balloon n minutes after it starts to descend is hn
metres.
The height of the balloon (n +1) minutes after it starts to descend, hn + 1 metres, is given by
hn + 1 = K×hn
+ 20 where K is a constant.
The balloon starts to descend from a height of 1200 metres at 09 15
At 09 16 the height of the balloon is 1040 metres.
Work out the height of the balloon at 09 18
Answer:
The height of the balloon at 09 18 = 788.4 meters.
Step-by-step explanation:
As the hot air balloon is descending.
and the height of the balloon n minutes after it starts to descend is [tex]h_{n}[/tex]
meters.
The height of the balloon (n +1) minutes after it starts to descend, [tex]h_{n+1}[/tex]meters, is given by
[tex]h_{n+1}[/tex]= [tex]k *h_{n}+20\\[/tex] where K is a constant
Here the balloon starts to descend from a height of 1200 meters at 09 15
So [tex]h_{n}[/tex]=1200 meters
At 09 16 the height of the balloon is 1040 meters.
So [tex]h_{n+1}[/tex]= 1040 meters
the height of the balloon at 09 18 = [tex]h_{n+3}[/tex] meters
now [tex]h_{n+1}[/tex]= [tex]k *h_{n}+20\\[/tex]
k = [tex]\frac{h_{n+1 }-20 }{h_{n} }[/tex]
k= (1040 - 20) ÷ 1200
k = 0.85
Now [tex]h_{n+2}[/tex] = (0.85 × 1040) +20 =904 meters
Similarly [tex]h_{n+3}[/tex] = (0.85 × 904) +20 = 788.4 meters.
Therefore the height of the balloon at 09 18 = 788.4 meters.
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what is the value when 18times of the difference of 15 and 12 divided by 6
Set up a proportion to solve for x in the following similar triangles
Answer:
[tex] \frac{18}{12} = \frac{24}{x - 2} [/tex]
Name
Two-Variable Statistics
Relationship between Two Categorical Variables - Marginal and Joint Relative Frequency -
Part 2
Warm Up
Complete the table and calculate the percent for each total.
The completed table is given below,
the percentage of girls in the class is 47.62%,
the percentage of boys in the class is (100-47.62)% = 52.38%,
the percentage of students that love Math is 36.5%,
the percentage of students that love Reading is 22%, and
the percentage of students that love Science is 41.27%
To make comparison and statistical analysis easier, numerical data is systematically and logically represented in tabulations as rows and columns. Grouping relevant data together makes comparison easier and aids in statistical analysis and interpretation.
To put it another way, tabulation is the process of organizing data and presenting it in a tabular format. Depending on the type of categorization, it might be double, complicated, or simple.
The below table yields that
The total number of students is 315
The fraction of girls in the class is 150/315 = 0.4762
So, the percentage of girls in the class is 47.62%
Hence the percentage of boys in the class is (100-47.62)% = 52.38%
The fraction of students that love Math is 115/315 = 0.365
So, the percentage of students that love Math is 36.5%
The fraction of students that love Reading is 70/315 = 0.22
So, the percentage of students that love Reading is 22%
The fraction of students that love Science is 130/315 = 0.4127
So, the percentage of students that love Science is 41.27%
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The function gives the mass, m, of a radioactive substance remaining after h half-lives. Cobalt-60 has a half-life of about 5.3 years. Which equation gives the mass of a 50 mg Cobalt-60 sample remaining after 10 years, and approximately how many milligrams remain?
The equation is [tex]f(t)=50(0.5)^{\frac {10}{5.3}}[/tex] and approximately 13.52 milligram remains
How to determine the equation?The missing information in the question is:
[tex]f(t)=m(0.5)^{\frac th}[/tex]
When the mass is 50 mg, it means that:
m = 50
So, we have:
[tex]f(t)=50(0.5)^{\frac th}[/tex]
When 10 years remain in the life of the substance, it means that:
t = 10
So, we have:
[tex]f(t)=50(0.5)^{\frac {10}h}[/tex]
The half life is 5.3. So, we have
[tex]f(t)=50(0.5)^{\frac {10}{5.3}}[/tex]
Evaluate the equation
f(t) = 13.52
Hence, the required equation is [tex]f(t)=50(0.5)^{\frac {10}{5.3}}[/tex] and approximately 13.52 milligram remains
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Answer:c
Step-by-step explanation:
11. Find the amount of interest on $600, if a bank is paying 5.5% interest.
[A] $30 [B] $3.30
[C] $330
[D] $33
[E] $23
Use properties to rewrite the given equation. Which equations have the same solution as 2.3p – 10.1 = 6.5p – 4 – 0.01p? Select two options. 2.3p – 10.1 = 6.4p – 4 2.3p – 10.1 = 6.49p – 4 230p – 1010 = 650p – 400 – p 23p – 101 = 65p – 40 – p 2.3p – 14.1 = 6.4p – 4
The correct answer is option C which is 230p – 1010 = 650p – 400 – p this expression is same as of 2.3p – 10.1 = 6.5p – 4 – 0.01p.
What is an expression?
Expression in maths is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.
Given expression:-
2.3p – 10.1 = 6.5p – 4 – 0.01p
The same expression will be calculated as:-
Multiply the given expression by 100 we will get our answer.
E = 100 (s 2.3p – 10.1 = 6.5p – 4 – 0.01p )
E = 230p – 1010 = 650p – 400 – p
Therefore the correct answer is option C which is 230p – 1010 = 650p – 400 – p this expression is same as of 2.3p – 10.1 = 6.5p – 4 – 0.01p.
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One possible integer of x for which 1/4 < k/10 < 1/3 is true?
Answer:
[tex]\fbox {x = 3}[/tex]
Step-by-step explanation:
Decimal form of the lower and higher limits :
1/4 = 0.251/3 = 0.33...Hence, the best one which lies in the middle of the limits would be 0.3.
Now, equate the middle part :
x/10 = 0.3x = 3A television has increased in price by 5%
the new price is £194.25. what was the original price?
Answer:
let the original price be X
now new price = original price + increment
increment = 5 % of X = X/20
new price = 194.25
now, 194.25 = X + X / 20 = 21X / 20
X = 194.25 * 20 / 21
X = 185
original price = 185
PLEASE HURRY
Which of the following can be used to evaluate the series
e d g e
Answer:
1 55
2 455
3554
Step-by-step explanation:
nfn
When the product of 6 and the square of a number is increased by 5 times the number, the result is 4. which equation represents this situation? 6x2 5x - 4 = 0 6x2 5x 4 = 0 62x 5 x = 4 6 x2 5x = 4
Answer:
The answer would be 6x^2 + 5x - 4 = 0