Rearrange x = 3g + 2 to make g the subject.

Answer:

2/7

Step-by-step explanation:

To find the fraction that are cherry, take the number that are cherry and put that over the total number of pieces

2 cherry

----------------

7 total

The fraction that are cherry are 2/7

1 is the values are in the range of the function graphed below. Option E is corect.

The domain denotes all potential x values, while the range denotes the domain's possible y values.

The domain is the value of x which lies between the -2 ≤ x  ≤ 1.While the range shows the value of y which is equal to  1.

Hence, option E is correct

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The value of the WZ will be 28.18. The given figure is quadrilateral.

It is concerned with the geometry, region, and density of various 2D and 3D shapes.

In ΔZXY

∠Z+∠X+∠Y=180

∠Z+34°+90°=180°

∠Z = 56°

In Δ WZY

sin Θ = WZ/ZY

sin 56° = WZ/34

WZ= 28.18

Hence, the value of the WZ will be 28.18.

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The side WZ = 30.4.

The angles which lie on the alternate side of the line between two parallel lines.

Given a geometry in which ZY = 34, WY = 38, and ∠ZXY = 34°

In this geometry, opposite sides are equal.

WZ = XY and WX = ZY.....................(1)

The diagonal are perpendicular to each other.

∠XVY = 90°

Diagonal form four right angle triangles. Take ΔXVY

VY = WY/2

VY = 38/2

VY = 17

Using trigonometric property,

sin X° =  VY / XY

sin 34° = 17/XY

XY = 30.4

From equation 1, we have

WZ = 30.4

Thus, the value of WZ is 30.4.

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Answer:

A.

Step-by-step explanation:

let me know if you want an explanation :))

The time that the bus arrived Busia is given as 1.00 pm

The formula with which to solve for the time is given as

D/s = distance / by the speed.

Distance = 400km

Speed = 80km/hr

Time = 400/80

= 5 hours

Therefore the time of arrival from 8.00 am would be 1.00pm

A bus left Nairobi at 8.00am and traveled towards Busia at an average speed of 80km / hr . At 8.30 am a car left Busia for Nairobi at an average speed of 120km / hr . Given that the distance between Nairobi and Busia is 400km ​

Calculate The time the car arrived in Busia

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Answer:

what?????????????????

Answer:

this is the answer

Step-by-step explanation:

a 65

b 650

c 52

d 3

The value of AOB and BOC based in the information given in the circle will be 53°.

From the information given, the central angle is the angle that the vertex is at the center of the circle.

It was stated that OB bisects AOC. Therefore, since AOB is 53°, BOC is also 53°.

The value of AOC will now be:

= AOB + BOC

= 53° + 53°

= 106°

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What Lewis did wrong was that; He budgeted more than the maximum recommended amount of money for transportation.

We are given;

Net spendable income = $2,000 per month

Now, we see how much he has budgeted for other items such as Car payments, Gas/Oil, Insurance, License/Registration, Taxes, Maintenance/Repair.

Now, from the recommended transportation budget of between 15% - 20% of the  net spendable income, we can see that he would likely spend more than that if we add the cost of maintenance and repair.

Thus, what Lewis did wrong was that he budgeted more than the maximum recommended amount of money for transportation.

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Answer:

Step-by-step explanation:

Answer:

A. He budgeted more than the maximum recommended amount of money for transportation. PLATO (Im 100% sure

Answer:

BODMAS

[tex] {6}^{3 } + 5(4 - 2) = 216 + 5(2) \\ = 216 + 10 \\ = 226[/tex]

Answer: Answer is 226

Step-by-step explanation: Do math

The initial amount is $800.

Interest is the price you pay to borrow money or the cost you charge to lend money.

Given:

Simple interest = 1.25% = 0.0125

So, interest in half a year.

=0.0125 ÷ 2

= 0.00625

Now,

=5 / 0.00625

= 800

Hence, the initial deposit was $800

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Answer: You have already given the answer in the question! You can make a small shoe box.

[tex]\quad \huge \quad \quad \boxed{ \tt \:Answer }[/tex]

[tex]\qquad \tt \rightarrow \:m\overbrace{DB}= 90 \degree[/tex]

____________________________________

[tex] \large \tt Solution \: : [/tex]

[tex] \qquad \tt \rightarrow \: m \overbrace{DB} + m \overbrace{TB} = 180 \degree[/tex]

[ linear pair ]

[tex] \qquad \tt \rightarrow \: m \overbrace{DB} + 90 \degree = 180 \degree[/tex]

[tex] \qquad \tt \rightarrow \: m \overbrace{DB} = 180 \degree - 90 \degree[/tex]

[tex] \qquad \tt \rightarrow \: m \overbrace{DB} = 90 \degree[/tex]

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

To solve this problem, you will first use the Angle Sum Property to determine the value of x after creating an algebraic equation, combining like terms, and subtracting from both sides of an equation.

The Angle Sum Property states that all interior angles of a triangle will summate to 180º.

An equation can be created to find this when you are given two angles and missing a third. That third angle can be referred to as x in this scenario.

Adding the two known angles and the unknown angle will result in a sum of 180º. This means that our unknown is x and can therefore be placed in an equation:

[tex]65+42+x=180[/tex]

Combine the like terms by combining the constants on the left side of the equation using addition:

[tex]65+42+x=180[/tex]

[tex]107+x=180[/tex]

After combining like terms, subtract 107 from both sides of the equation:

[tex]107 - 107 +x = 180-107[/tex]

[tex]\boxed{x=73}[/tex]

The final answer is x = 73 degrees.

Answer:

65/8

Step-by-step explanation:

1) Turn all numbers into improper fractions: 17/2 - 3/8 = ?

2) Make all denominators the same number by finding the least common factor, which is 8. Multiply the denominator in 17/2, which is 2, by 4 to match the other denominator. And then multiply the numerator (17) by 4 as well so that the fraction still has the same value: 68/8 - 3/8 = 65/8

3) Can not simplify since there are no common factors between 65 and 8.

Answer:

[tex]x(x^2+2)[/tex]

Step-by-step explanation:

Since x is the only common term, you factor that part out using the distributive property.

Solution:

Detailed explanation:

Hii! Let's factorise this expression!

Did you see that both terms, x^3 and 2x, have an x in common? That's what we are going to factor out, by dividing x^3 and 2x by x.

x^2+2 is what we obtain.

Now, this can't be the end of the process. We also need to put parentheses around x^2+2.

(x^2+2)

Next we put that x we factored out a short while ago outside the parentheses.

x(x^2+2). Did you get it?

________

Hope I helped, best wishes & happy studies!
Please reach out if any queries arise. Thankyou!!

_______

The answer is y=|x|-13.

Answer:

y=|x|-13

Step-by-step explanation:

Answer:

879.6452 cm

Step-by-step explanation:

The curved surface area of a cylinder is calculated using the formula, curved surface area of cylinder = 2πrh, where 'r' is the radius and 'h' is the height of the cylinder.

diameter = 2r

14=2(r)

7=r

2(π)(7)(20) cm

2(3.14159)(7)(20)

879.6452

Answer:

2400

Step-by-step explanation:

Find the accumulated amount of an account if the principal amount was 5000 at 16% interest at the end of 3 years

Solution

The formula for simple interest

S.I = P *R* T/100

Where P = Principal = 5000

           R = Rate = 16%

           T = Time = 3 years

 5000 * 16 * 3/100

 50 * 16 * 3

  = 2400.

The student made an error in step 3. To correct this error, he should define side AY in terms of angle X. Pythagorean theorem relates sides x, y, z, and angle X

In Trigonometry, law of cosine (cos) is given by this mathematical expression:

cosθ = Opp/Hyp

Where:

In this scenario, we can logically deduce that the student made an error in step 3. To correct this error, he should define side AY in terms of angle X.

After correcting this error, the student can use the Pythagorean theorem to relate sides x, y, z, and angle X.

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2) The three ways of naming an angle are by the letter at the vertex, by placing a number or variable inside the angle, or by two letters with the vertex letter placed in the middle.

3) [tex]\angle WXY, \angle YXZ, \angle WXZ[/tex]

4) [tex]X[/tex]

Answer:

(1,2.5)

Step-by-step explanation:

On the graph, the (-1,7) lies in the top right grid. The (3,-2) lies in the bottom left grid. If you use a graphing calculator, the middle is hard to find but you will find (1, 2.5) or (1, 5/2).

Answer:

x= -7, y= -5 and

x= 2, y= 13

This may also be written as (-7, -5) and (2, 13).

Step-by-step explanation:

Start by labelling the two given equations:

y= x² +7x -5 -----(1)

2x -y= -9 -----(2)

Let's solve by substitution!

Making y the subject of formula in equation (2):

From (2): y= 2x +9 -----(3)

Substitute (3) into (1):

2x +9= x² +7x -5

x² +7x -5 -2x -9= 0

x² +5x -14= 0

Factorise:

(x +7)(x -2)= 0

x +7= 0 or x -2= 0

x= -7 or x= 2

Find the respective values of y.

Substitute into (1):

y= (-7)² +7(-7) -5 or y= (2)² +7(2) -5

y= 49 -49 -5 or y= 4 +14 -5

y= -5 or y= 13

Thus, the solutions are (-7, -5) and (2, 13).

Answer:

(0, 4) and (-1, 0)

Step-by-step explanation:

Given system of equations:

[tex]\begin{cases}y=2x^2+6x+4\\y=-4x^2+4\end{cases}[/tex]

Solve by substitution

Substitute the first equation into the second:

[tex]\implies 2x^2+6x+4=-4x^2+4[/tex]

Add 4x² to both sides:

[tex]\implies 2x^2+6x+4+4x^2=-4x^2+4+4x^2[/tex]

[tex]\implies 6x^2+6x+4=4[/tex]

Subtract 4 from both sides:

[tex]\implies 6x^2+6x+4-4=4-4[/tex]

[tex]\implies 6x^2+6x=0[/tex]

Factor out 6x from the left side:

[tex]\implies 6x(x+1)=0[/tex]

Therefore:

[tex]\implies 6x=0 \implies x=0[/tex]

[tex]\implies x+1=0 \implies x=-1[/tex]

To find the y-coordinates of the found x-values, substitute the found values of x into one of the equations:

[tex]x=0 \implies -4(0)^2+4=4 \implies (0,4)[/tex]

[tex]x=-1\implies -4(-1)^2+4=0\implies (-1,0)[/tex]

Therefore, the solutions to the system of equations are:

(0, 4) and (-1, 0)

Answer:

Solutions:

a) x = 0, y = 4 ⇒ (0, 4)

b) x = -1, y = 0 ⇒ (-1, 0)

Step-by-step explanation:

Given system of equations:

a) y = 2x² + 6x + 4

b) y = -4x² + 4

1. Substitute the value of y in the second equation into the first equation:

⇒ -4x² + 4 = 2x² + 6x + 4

2. Solve for x:

⇒ -4x² + 4 = 2x² + 6x + 4 [subtract 4 from both sides]

⇒ -4x² + 4 - 4 = 2x² + 6x + 4 - 4

⇒ -4x² = 2x² + 6x [subtract 2x² from both sides]

⇒ -4x² - 2x² = 2x² - 2x² + 6x

⇒ -6x² = 6x [subtract 6x from both sides]

⇒ -6x² - 6x = 6x - 6x

⇒ -6x² - 6x = 0 [factor out -6x from the equation]

⇒ -6x(x + 1) = 0

Two cases:

a)

⇒ -6x = 0 [divide both sides by -6]        

⇒ -6x ÷ -6 = 0 ÷ -6

⇒ x = 0

b)

⇒ x + 1 = 0 [subtract 1 from both sides]

⇒ x + 1 - 1 = 0 - 1

⇒ x = -1

3. Find the value of y by substituting the found x values into one of the given equations:

a) x = 0:

⇒ y = -4x² + 4

⇒ y = -4(0)² + 4

⇒ y = -4(0) + 4

⇒ y = = 0 + 4

⇒ y = 4

coordinate: (0, 4)

b) x = -1:

⇒ y = -4x² + 4

⇒ y = -4(-1)² + 4

⇒ y = -4(1) + 4

⇒ y = -4 + 4

⇒ y = 0

coordinate: (-1, 0)

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Answer:

(x - 8x)²

(x - 8x) (x - 8x).

using the identity

( a - b) ² = a² + b² - 2ab

a = x

b = 8x

x² + 64x - 16x²

Answer:

[tex]\fbox {DF = 20}[/tex]

Step-by-step explanation:

Given :

Step 1 : Find RT

Step 2 : Find SF

Step 3 : Find RY

Step 4 : Find TY

Step 5 : Find DF

Answer:

DF = 20

Step-by-step explanation:

Triangle SDF has side lengths SD, DF, SF.

Triangle RTY has side lengths

RT = (9/4)SD

RY = (9/4)SF

TY = (9/4)DF

"SF is 2 less than RT" Given

SF = RT - 2

SF = (9/4)SD - 2

"SD = 8" Given

SF = (9/4)(8) - 2

SF = 16

"TY is 9 more than RY" Given

TY = RY + 9

(9/4)DF = (9/4)SF + 9

(9/4)DF = (9/4)(16) + 9

(9/4)DF = 45

DF = 45 × 4/9

DF = 20

Answer:

each one is double the one before it so in year 5...

3912*2=7824

Hope This Helps!!!

Answer:

7824

Step-by-step explanation:

Answer:

no

Step-by-step explanation:

the bet displays 3 hexagonal bases when in the figure there is only 2 bases.

Answer:

No.

Step-by-step explanation:

Examples of three-dimensional figures are: Cuboid, Cube, Cylinder, Sphere, Pyramid, and a Cone.

If [tex]f(x)[/tex] has a removable discontinuity at [tex]x=a[/tex], then the limit

[tex]\displaystyle \lim_{x\to a} \frac{f(x)}{x-a}[/tex]

exists and is finite.

A non-removable discontinuity at [tex]x=b[/tex] would entail a non-finite limit,

[tex]\displaystyle \lim_{x\to b} \frac{f(x)}{x-b} = \pm\infty[/tex]

or the limit does not exist (which could be due to the limits from either side of [tex]x=b[/tex] not matching or existing).

For a rational function, we want

[tex]f(x) = \dfrac{p(x)}{q(x)}[/tex]

where [tex]p[/tex] and [tex]q[/tex] are polynomials in [tex]x[/tex]. To get a removable discontinuity at [tex]x=a[/tex], both [tex]p[/tex] and [tex]q[/tex] must be divisible by [tex]x-a[/tex], and the limit of their quotient after removing these factors still exists. That is,

[tex]\displaystyle \lim_{x\to a} f(x) = \lim_{x\to a} \frac{p(x)}{q(x)} = \lim_{x\to a}  \frac{(x-a)p^*(x)}{(x-a)q^*(x)} = \lim_{x\to a} \frac{p^*(x)}{q^*(x)} = \frac{p^*(a)}{q^*(a)}[/tex]

On the flip side, we get a non-removable discontinuity [tex]x=b[/tex] if [tex]p[/tex] is not divisible by [tex]x-b[/tex], in which case

[tex]\displaystyle \lim_{x\to b} f(x) = \lim_{x\to b} \frac{p(x)}{q(x)} = \lim_{x\to b}  \frac{p(x)}{(x-b)q^*(x)} = \frac{p(b)}{0\times q^*(b)}[/tex]

and this is undefined.

Suppose [tex]f(x)[/tex] has a non-removable discontinuity at [tex]x=-5[/tex] and a removable one at [tex]x=4[/tex]. Then one such function could be

[tex]f(x) = \dfrac{x-4}{(x-4)(x+5)} = \dfrac{x-4}{x^2+x-20}[/tex]