Which phrase describes a feature of a Mercator projection? is least commonly used sizes most features to scale presents longitude lines as parallel shows most accurately near the prime meridian

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In a galvanic cell, the oxidation and reduction of metals occurs at the electrodes. There are two electrodes in a very cell, one in each half-cell. The cathode is where reduction takes place and oxidation takes place at the anode.

Answer:

Alkane

Alkene

Alkyne

Explanation:

Alkane=1 bond (Saturated hydrocarbon)

Alkene= 2 bonds (Unsaturated hydrocarbon)

Alkyne= triple bonds (Unsaturated hydrocarbon)

Formula of Alkane = CnH2n+2

Formula of Alkene = CnH2n

Formula of Alkyne = CnH2n-2

Answer:

they stick together as a group and that they berly fought or argue

Answer:first get a jar

Explanation:

Patrick that’s a jokers side special

Answer:

Independent: whether or not there was fertilizer in water

Dependent: height of plants

Explanation:

In an experiment, there is an independent and a dependent variable. The independent variable is what is changed in the experiment. The dependent variable is what is measured.

In this experiment, 10 tomato plants are given fertilizer in the water, while 10 other tomato plants are given regular water. Everything else is kept constant, and the heights are measured at the end of the week.

The independent variable is what is being changed. In this experiment, the only thing being manipulated is the fertilizer. One group of the plants is given fertilizer, while the other is not. Therefore, the independent variable is whether or not there was fertilizer in the water.

The dependent variable is what is being measured. In this experiment, the thing that is being measured is the height of the plants. Therefore, the dependent variable is the height of the plants.

Answer:

may be the first one is a producer

Answer: C.) Xe

Explanation: To figure out the answer go to the Noble Gas Family and count down 5 elements.

According to the electronic configuration the symbol which would be included in the noble gas notation for an element that had valence electrons in the 5 s subshell is xenon  .

Electronic configuration is defined as the distribution of electrons which are present in an atom or molecule in atomic or molecular orbitals.It describes how each electron moves independently in an orbital.

Knowledge of electronic configuration is necessary for understanding the structure of periodic table.It helps in understanding the chemical properties of elements.

Elements undergo chemical reactions in order to achieve stability. Main group elements obey the octet rule in their electronic configuration while the transition elements follow the 18 electron rule. Noble elements have valence shell complete in ground state and hence are said to be stable.

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Answer:

1) 1.39 grams H2O2

2) 0.933 grams Fe

Explanation:

Step 1: Data given

Volume of oxygen = 0.460 L

STP = 1 atm and 273 K

Step 2: The balanced equation

2H2O2(aq) → 2H2O(l) + O2(g)

Step 3: Calculate the number of moles O2

p*V = n*R*T

⇒with p= the pressure = 1 atm

⇒with V = the volume = 0.460 L

⇒with n = the number of moles = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 273 K

n = (p*V)/(R*T)

n = (1 * 0.460)/ (0.08206*273)

n = 0.0205 moles moles

Step 4: Calculate moles H2O2

For 2 moles H2O we'll have 2 moles H2O and 1 mol O2

For 0.0205 moles O2 we'll need 2*0.0205 = 0.041 moles H2O2

Step 5: Calculate mass H2O2

Mass H2O2 = moles H2O2 * molar mass H2O2

Mass H2O2 = 0.041 moles * 34.01 g/mol

Mass H2O2 = 1.39 grams

Step 1: Data given

Volume of hydrogen = 0.500 L

STP = 1 atm and 273 K

Step 2: The balanced equation

3Fe(s) + 4H2O(l) → Fe3O4(s) + 4H2(g)

Step 3: Calculate the moles of H2

p**V = n*R*T

⇒with p= the pressure = 1 atm

⇒with V = the volume = 0.500 L

⇒with n = the number of moles = TO BE DETERMINED

⇒with R = the gas constant = 0.08206 L*atm/mol*K

⇒with T = the temperature = 273 K

n = (p*V) / '*T)

n = (1 * 0.500) / (0.08206 * 273)

n = 0.0223 moles

Step 4: Calculate moles Fe

For 3 moles Fe we need 4 moles H2O to produce 1 mol Fe3O4 and 4 moles H2

For 0.0223 moles H2 we'll need 0.0223 *3/4 = 0.0167 moles Fe

Step 5: Calculate mass of Fe

Mass Fe = moles Fe * atomic mass Fe

Mass Fe = 0.0167 moles * 55.845 g/mol

Mass Fe = 0.933 grams Fe

1. The mass of the hydrogen peroxide should be 1.39 grams H2O2.

2) The mass of the iron should be 0.933 grams Fe.

Since

Volume of oxygen = 0.460 L

STP = 1 atm and 273 K

Now The balanced equation

2H2O2(aq) → 2H2O(l) + O2(g)

Now the number of moles O2

p*V = n*R*T

Here p= the pressure = 1 atm

V = the volume = 0.460 L

n = the number of moles = ?

R = the gas constant = 0.08206 L*atm/mol*K

T = the temperature = 273 K

Now

n = (p*V)/(R*T)

n = (1 * 0.460)/ (0.08206*273)

n = 0.0205 moles moles

Now  moles H2O2 should be

For 2 moles H2O we'll have 2 moles H2O and 1 mol O2

So,

For 0.0205 moles O2 we'll need 2*0.0205 = 0.041 moles H2O2

Now mass H2O2

Mass H2O2 = moles H2O2 * molar mass H2O2

Mass H2O2 = 0.041 moles * 34.01 g/mol

Mass H2O2 = 1.39 grams

2. The mass of the iron should be

Since

Volume of hydrogen = 0.500 L

STP = 1 atm and 273 K

Now

The balanced equation

3Fe(s) + 4H2O(l) → Fe3O4(s) + 4H2(g)

Now the moles of H2

p**V = n*R*T

Here

p= the pressure = 1 atm

V = the volume = 0.500 L

n = the number of moles = ?

R = the gas constant = 0.08206 L*atm/mol*K

T = the temperature = 273 K

So,

n = (p*V) / '*T)

n = (1 * 0.500) / (0.08206 * 273)

n = 0.0223 moles

Now Calculate moles Fe

For 3 moles Fe we need 4 moles H2O to produce 1 mol Fe3O4 and 4 moles H2

So,

For 0.0223 moles H2 we'll need 0.0223 *3/4 = 0.0167 moles Fe

Now the mass of Fe

Mass Fe = moles Fe * atomic mass Fe

Mass Fe = 0.0167 moles * 55.845 g/mol

Mass Fe = 0.933 grams Fe

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A) 4

pH=-log[H+]

pH=-log(10^-4)

B) Weaker

pH of orange juice=4

pH of coffee=5

An acid with pH of 4 is stronger than a pH of 5

C) 7, neither/neutral

pH of water=7

Answer:

The answer is 80!

Explanation:

A prism is a three dimensional solid object in which the two ends are identical. It is the combination of the flat faces, identical bases and equal cross sections. The volume of the prism is 819 cm³.

A prism is a polyhedron with two parallel congruent faces called the bases that are polygons. The volume of a three dimensional solid is the amount of space it occupies. The volume is measured in cubic units. The volume can be denoted in m³, cm³, ft³, etc.

The volume of a prism is the area of the base times the height. The equation used to calculate the volume is:

Volume = Base area × Height

Here the rectangle has 9cm length and 7cm width. Then the area is:

Area = 9 × 7 = 63 cm²

The height of prism = 13 cm

Then the volume is:

V = 63 × 13 = 819 cm³

Thus the volume of the prism is 819 cm³.

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Your question is incomplete most probably your full question was

What is volume of the rectangular prism with length 9cm, width 7cm and height  13 cm?

Answer: D. 4,6,4

Explanation:

The valence electron is the electron found in the outermost shell of an atom, and participates in bond formation.

For the following element, the valence electron can be noticed when we write the electronic configuration of each element.

Silicon =  1s2 2s2 2P6 3s2 3p2

Sulphur = 1s2 2s2 2P6 3s2 3p4

Germanium =  1s2 2s2 2P6 3s2 3p6 3d10 4s2 4p2

Answer:

SO4^2- is the oxidizing agent.

l^- is the reducing agent.

Explanation:

SO4^2- + I^- + H^+ —> H2S + I2 + H2O

To know which is the oxiding agent or the reducing agent, let us calculate the change in oxidation number of each element. This is illustrated below:

Note: the oxidation number of Hydrogen (H) is always +1 except in hydride where it is -1.

The oxidation number of Oxygen (O) is always -2 except in peroxide where it -1

For S:

SO4 = -2

S + 4O = -2

O = - 2

S =.?

S + (4 x -2) = -2

S - 8 = -2

Collect like terms

S = -2 + 8

S = +6

H2S = 0

2H + S = 0

H = +1

S =..?

2(1) + S = 0

2 + S = 0

Collect like terms

S = 0 - 2

S = -2

The oxidation number of S changes from +6 to -2

For I:

I = - 1

I = 0

The oxidation of I changes from -1 to 0.

Since the oxidation number of S changes from +6 to -2 i.e reduce, therefore SO4^2- is the oxidizing agent.

The oxidation number of I changes from -1 to 0 ie increased. Therefore, l^- is the reducing agent.

Answer:

Four main processes erode the destructive waves; hydraulic action, compression, abrasion and attrition. Hydraulic Action is the sheer force of water crashing off the coastline causing the material to dislodge and be carried away by the sea.

Answer:

a

Explanation:

Answer:

1 mole of nitrogen (N2) reacts with 3 moles of hydrogen (H2) to form 2 moles of ammonia (NH3) ... 4 NH3 (g) + 5 O2 (g) --> 4 NO (g) + 6 H2O (g) ... Example: What is the molar ratio between Li and N2 in the following reaction

Explanation:

1 mole of nitrogen (N2) reacts with 3 moles of hydrogen (H2) to form 2 moles of ammonia (NH3) ... 4 NH3 (g) + 5 O2 (g) --> 4 NO (g) + 6 H2O (g) ... Example: What is the molar ratio between Li and N2 in the following reaction

Answer:

B: it allow quick conversation to others

Answer:

3. ethyne

Explanation:

Highest ratio of hydrogen to carbon? I'm not sure I found it on the internet but the answer is right

Answer:

7.8

Explanation:

pH + pOH = 14

pOH = 14 - 6.2

= 7.8

Answer:

The answer is D..i.e phosphate. it consists of 1p and 4oxygen atoms

[tex]PO_4^{3-}[/tex]  is a polyatomic ion. Hence, option D is correct.

What is a polyatomic ion?

Polyatomic ions are ions which consist of more than one atom.

The prefix poly- means many, so a polyatomic ion is an ion that contains more than one atom. This differentiates polyatomic ions from monatomic ions, which contain only one atom.

[tex]PO_4^{3-}[/tex] is a chemical derivative of phosphoric acid with a chemical name Phosphate. Phosphate is also called Phosphate ion or Orthophosphate.

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Answer:

It will produce 44 grams of carbon dioxide

Explanation:

Step 1: Data given

MAss of CaCO3 = 100 grams

Molar mass of CaCO3 = 100.09 g/mol

Mass of CaO produced = 56 grams

Molar mass of CaO = 56.08 g/mol

Step 2: The balanced equation

CaCO3 → CaO + CO2

Step 3: Calculate moles CaCO3

Moles CaCO3 = mass CaCO3 / molar mass CaCO3

Moles CaCO3 = 100 grams / 100.09 g/mol

Moles CaCO3 = 1.00 moles

Step 4: Calculate moles CaO

Moles CaO = 56 grams / 56.08 g/mol

Moles CaO = 1.00 moles

Step 5: Calculate moles CO2

For 1 mol CaCO3 we'll have 1 mol 1 mol CaO and 1 mol CO2

Step 6: Calculate mass CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 1.00 moles * 44.0 g/mol

Mass CO2 = 44 grams

It will produce 44 grams of carbon dioxide

Answer:

gasoline

Explanation:

Answer:

The site at which the lander would have the greatest amount of gravitational potential energy is X

Explanation:

The formula for gravitational potential is given as follows;

[tex]PE_G = m \times g \times \Delta H[/tex]

Where:

g = Acceleration due to gravity

m = Mass of the lander

ΔH = Height above surface

Landing site --- Height above surface --- Acceleration due to gravity

W                        32                                    1.6

x                          16                                    3.7

Y                         35                                    1.6

Z                         12                                     3.7

Therefore, we have;

For site W

[tex]PE_G = m \times 1.6 \times 32 = 51.2 \cdot m[/tex]

For site X

[tex]PE_G = m \times 3.7 \times 16= 59.2 \cdot m[/tex]

For site Y

[tex]PE_G = m \times 1.6 \times 35 = 56 \cdot m[/tex]

For site Z

[tex]PE_G = m \times 3.7 \times 12 = 44.4 \cdot m[/tex]

Hence the site at which the lander would have the greatest amount of gravitational potential energy is X with [tex]PE_G[/tex] = 59.2·m.

Gravitational energy is the power stored in an object due to the intensity of gravity or because the article is located vertically.

The correct answer is:

The site at which the lander would have the greatest amount of gravitational potential energy is X.

The correct explanation for site X is:

The gravitational energy can be calculated as the product of mass, gravitational field and height.

[tex]{\text{PE}_{\text G}&= \text{m}\; \times\text g\times \Delta\text H[/tex]

Where,

Given,

Landing site        Height above surface              Gravity

    W                                    32                                    1.6

    X                                     16                                     3.7

    Y                                     35                                     1.6

    Z                                     12                                      3.7

We can calculate Gravitational energy for all the sites as follows:

       [tex]{\text{PE}_{\text G}&= \text{m}\; \times\ 1.6\times 32 = 51.2 \text \; \times \text {m}[/tex]

       [tex]{\text{PE}_{\text G}&= \text{m}\; \times\ 3.7\times 16 = 59.2 \text \; \times \text {m}[/tex]

       [tex]{\text{PE}_{\text G}&= \text{m}\; \times\ 1.6\times 35 = 56 \text \; \times \text {m}[/tex]

       [tex]{\text{PE}_{\text G}&= \text{m}\; \times\ 3.7 \times 12= 44.4 \text \; \times \text {m}[/tex]

Therefore, the greatest amount of gravitational energy 59.2m is present on-site X.

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Answer: 25.0 L

Explanation:

For this problem, we will need to use Boyle's Law.

Boyle's Law: P₁V₁=P₂V₂

Since we are looking for V₂, we can rewrite the equation.

V₂=P₁V₁/P₂

The pressure should be in atm, so let's convert kPa to atm.

P₁=100 kPa=0.99 atm

P₂=200 kPa=1.97 atm

Now that we know the pressure in atm, we can plug it into the equation and solve.

[tex]V_{2} =\frac{(0.99 atm)(50.0L)}{1.97atm}[/tex]

[tex]V_{2} =25.0 L[/tex]

Answer: 80

Explanation:

Answer:

Jamal moved his box to storage, but Jude could not move his.

Explanation:

The force they exert needs to be higher than the force of gravity in order for them to move the boxes. Jamal's force is 60N, which is 10N above the force of gravity on the box, which is 50N. However, Jude's force is only 45N and that is lower than 50N, so he won't be able to move the box while Jamal can.

Answer:

.743 g/mL

Explanation:

Hopefully this helps :)

Answer:

(a) Formation of the carbocation is the rate-determining step (RDS)

(c) Reactions at chiral carbons proceed with inversion of stereochemistry

Explanation:

SN1 reactions arenucleophilic substitution reactions in which the rate determining step is unimolecular.

The formation of a carbocation is the rate determining step. This depends on the electrophilicity of the leaving group. Thus the SN1 reaction mechanisms is dependent on the electrophile and not the nucleophile.

Polar and acidic solvents which can assist in the formation of the carbocation speeds up the rate determining step.

If the formation of carbocation occurs at a chiral center, both retention and inversion of stereochemistry are likely to occur.

Therefore, the correct options are A and C.

Answer:

An insect would have an easier time walking on the surface of water than on the surface of ethanol.

Water's stronger intermolecular forces lead to higher surface tension.

Higher surface tension allows water to support the insect.

Answer:

An insect would have an easier time walking on the surface of water than on the surface of ethanol.

Water's stronger intermolecular forces lead to higher surface tension.

Higher surface tension allows water to support the insect.

Explanation:

Answer:

Oxidation states are used in chemistry solutions. It is a bond in which electron transfers easily from one nucleus to another nucleus.

Explanation:

Answer:

147.222

Explanation:

It's a simple conversion.

Answer:

Tests for unsaturation involves addition across the multiple bonds in the unsaturated compound.

Explanation:

In organic chemistry, we define an unsaturated compound as any compound that contains a double or triple bond. These multiple bonds are also known as pi bonds.

There are two major tests for unsaturation which shall both be discussed here.

The first test for unsaturation is by the use of bromine water. The unknown sample is passed through a solution of bromine water which normally appears reddish brown. The bromine water becomes decolorized due to addition of bromine across the multiple bond. This is a standard test for unsaturation.

Secondly, unsaturated compounds decoulourize a solution of potassium permanganate when passed through it. This alone can not be used as a distinctive test for unsaturation.

Propenoic acid will give a positive test to the both reagents showing that it contains multiple bonds, in this particular instance, a double bond.